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{{task}}
''Reduce'' is a function or method that is used to take the values in an array or a list and apply a function to successive members of the list to produce (or reduce them to), a single value.
;Task: Show how ''reduce'' (or ''foldl'' or ''foldr'' etc), work (or would be implemented) in your language.
;See also:
- Wikipedia article: [[wp:Fold (higher-order function)|Fold]]
- Wikipedia article: [[wp:Catamorphism|Catamorphism]]
11l
print((1..3).reduce((x, y) -> x + y))
print((1..3).reduce(3, (x, y) -> x + y))
print([1, 1, 3].reduce((x, y) -> x + y))
print([1, 1, 3].reduce(2, (x, y) -> x + y))
{{out}}
6
9
5
7
ABAP
This works in ABAP version 7.40 and above.
report z_catamorphism.
data(numbers) = value int4_table( ( 1 ) ( 2 ) ( 3 ) ( 4 ) ( 5 ) ).
write: |numbers = { reduce string(
init output = `[`
index = 1
for number in numbers
next output = cond string(
when index eq lines( numbers )
then |{ output }, { number } ]|
when index > 1
then |{ output }, { number }|
else |{ output } { number }| )
index = index + 1 ) }|, /.
write: |sum(numbers) = { reduce int4(
init result = 0
for number in numbers
next result = result + number ) }|, /.
write: |product(numbers) = { reduce int4(
init result = 1
for number in numbers
next result = result * number ) }|, /.
data(strings) = value stringtab( ( `reduce` ) ( `in` ) ( `ABAP` ) ).
write: |strings = { reduce string(
init output = `[`
index = 1
for string in strings
next output = cond string(
when index eq lines( strings )
then |{ output }, { string } ]|
when index > 1
then |{ output }, { string }|
else |{ output } { string }| )
index = index + 1 ) }|, /.
write: |concatenation(strings) = { reduce string(
init text = ``
for string in strings
next text = |{ text } { string }| ) }|, /.
{{out}}
numbers = [ 1, 2, 3, 4, 5 ]
sum(numbers) = 15
product(numbers) = 120
strings = [ reduce, in, ABAP ]
concatenation(strings) = reduce in ABAP
Ada
with Ada.Text_IO;
procedure Catamorphism is
type Fun is access function (Left, Right: Natural) return Natural;
type Arr is array(Natural range <>) of Natural;
function Fold_Left (F: Fun; A: Arr) return Natural is
Result: Natural := A(A'First);
begin
for I in A'First+1 .. A'Last loop
Result := F(Result, A(I));
end loop;
return Result;
end Fold_Left;
function Max (L, R: Natural) return Natural is (if L > R then L else R);
function Min (L, R: Natural) return Natural is (if L < R then L else R);
function Add (Left, Right: Natural) return Natural is (Left + Right);
function Mul (Left, Right: Natural) return Natural is (Left * Right);
package NIO is new Ada.Text_IO.Integer_IO(Natural);
begin
NIO.Put(Fold_Left(Min'Access, (1,2,3,4)), Width => 3);
NIO.Put(Fold_Left(Max'Access, (1,2,3,4)), Width => 3);
NIO.Put(Fold_Left(Add'Access, (1,2,3,4)), Width => 3);
NIO.Put(Fold_Left(Mul'Access, (1,2,3,4)), Width => 3);
end Catamorphism;
{{out}}
1 4 10 24
Aime
integer s;
s = 0;
list(1, 2, 3, 4, 5, 6, 7, 8, 9).ucall(add_i, 1, s);
o_(s, "\n");
{{Out}}
45
ALGOL 68
# applies fn to successive elements of the array of values #
# the result is 0 if there are no values #
PROC reduce = ( []INT values, PROC( INT, INT )INT fn )INT:
IF UPB values < LWB values
THEN # no elements #
0
ELSE # there are some elements #
INT result := values[ LWB values ];
FOR pos FROM LWB values + 1 TO UPB values
DO
result := fn( result, values[ pos ] )
OD;
result
FI; # reduce #
# test the reduce procedure #
BEGIN print( ( reduce( ( 1, 2, 3, 4, 5 ), ( INT a, b )INT: a + b ), newline ) ) # sum #
; print( ( reduce( ( 1, 2, 3, 4, 5 ), ( INT a, b )INT: a * b ), newline ) ) # product #
; print( ( reduce( ( 1, 2, 3, 4, 5 ), ( INT a, b )INT: a - b ), newline ) ) # difference #
END
{{out}}
+15
+120
-13
AppleScript
{{Trans|JavaScript}}
Iteratively implemented '''foldl''' and '''foldr''', using the same argument sequence as in the corresponding JavaScript array methods '''reduce()''' and '''reduceRight()'''.
(Note that to obtain first-class functions from user-defined AppleScript handlers, we have to 'lift' them into script objects).
-- CATAMORPHISMS --------------------------------------------------
-- the arguments available to the called function f(a, x, i, l) are
-- a: current accumulator value
-- x: current item in list
-- i: [ 1-based index in list ] optional
-- l: [ a reference to the list itself ] optional
-- foldl :: (a -> b -> a) -> a -> [b] -> a
on foldl(f, startValue, xs)
tell mReturn(f)
set v to startValue
set lng to length of xs
repeat with i from 1 to lng
set v to |λ|(v, item i of xs, i, xs)
end repeat
return v
end tell
end foldl
-- the arguments available to the called function f(a, x, i, l) are
-- a: current accumulator value
-- x: current item in list
-- i: [ 1-based index in list ] optional
-- l: [ a reference to the list itself ] optional
-- foldr :: (a -> b -> a) -> a -> [b] -> a
on foldr(f, startValue, xs)
tell mReturn(f)
set v to startValue
set lng to length of xs
repeat with i from lng to 1 by -1
set v to |λ|(v, item i of xs, i, xs)
end repeat
return v
end tell
end foldr
-- OTHER FUNCTIONS DEFINED IN TERMS OF FOLDL AND FOLDR ------------
-- concat :: [[a]] -> [a] | [String] -> String
on concat(xs)
script append
on |λ|(a, b)
a & b
end |λ|
end script
if length of xs > 0 and class of (item 1 of xs) is string then
set unit to ""
else
set unit to {}
end if
foldl(append, unit, xs)
end concat
-- product :: Num a => [a] -> a
on product(xs)
script
on |λ|(a, b)
a * b
end |λ|
end script
foldr(result, 1, xs)
end product
-- sum :: Num a => [a] -> a
on sum(xs)
script
on |λ|(a, b)
a + b
end |λ|
end script
foldl(result, 0, xs)
end sum
-- TEST -----------------------------------------------------------
on run
set xs to {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
{sum(xs), product(xs), concat(xs)}
--> {55, 3628800, "10987654321"}
end run
-- GENERIC FUNCTION -----------------------------------------------
-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn
{{out}}
{55, 3628800, "10987654321"}
Bracmat
( ( fold
= f xs init first rest
. !arg:(?f.?xs.?init)
& ( !xs:&!init
| !xs:%?first ?rest
& !f$(!first.fold$(!f.!rest.!init))
)
)
& out
$ ( fold
$ ( (=a b.!arg:(?a.?b)&!a+!b)
. 1 2 3 4 5
. 0
)
)
& (product=a b.!arg:(?a.?b)&!a*!b)
& out$(fold$(product.1 2 3 4 5.1))
);
Output:
15
120
BBC BASIC
DIM a(4)
a() = 1, 2, 3, 4, 5
PRINT FNreduce(a(), "+")
PRINT FNreduce(a(), "-")
PRINT FNreduce(a(), "*")
END
DEF FNreduce(arr(), op$)
REM!Keep tmp, arr()
LOCAL I%, tmp
tmp = arr(0)
FOR I% = 1 TO DIM(arr(), 1)
tmp = EVAL("tmp " + op$ + " arr(I%)")
NEXT
= tmp
{{out}}
15
-13
120
C
#include <stdio.h>
typedef int (*intFn)(int, int);
int reduce(intFn fn, int size, int *elms)
{
int i, val = *elms;
for (i = 1; i < size; ++i)
val = fn(val, elms[i]);
return val;
}
int add(int a, int b) { return a + b; }
int sub(int a, int b) { return a - b; }
int mul(int a, int b) { return a * b; }
int main(void)
{
int nums[] = {1, 2, 3, 4, 5};
printf("%d\n", reduce(add, 5, nums));
printf("%d\n", reduce(sub, 5, nums));
printf("%d\n", reduce(mul, 5, nums));
return 0;
}
{{out}}
15
-13
120
C++
#include <iostream>
#include <numeric>
#include <functional>
#include <vector>
int main() {
std::vector<int> nums = { 1, 2, 3, 4, 5 };
auto nums_added = std::accumulate(std::begin(nums), std::end(nums), 0, std::plus<int>());
auto nums_other = std::accumulate(std::begin(nums), std::end(nums), 0, [](const int& a, const int& b) {
return a + 2 * b;
});
std::cout << "nums_added: " << nums_added << std::endl;
std::cout << "nums_other: " << nums_other << std::endl;
}
{{out}}
nums_added: 15
nums_other: 30
C#
var nums = Enumerable.Range(1, 10);
int summation = nums.Aggregate((a, b) => a + b);
int product = nums.Aggregate((a, b) => a * b);
string concatenation = nums.Aggregate(String.Empty, (a, b) => a.ToString() + b.ToString());
Console.WriteLine("{0} {1} {2}", summation, product, concatenation);
Clojure
For more detail, check Rich Hickey's [http://clojure.com/blog/2012/05/08/reducers-a-library-and-model-for-collection-processing.html blog post on Reducers].
; Basic usage
> (reduce * '(1 2 3 4 5))
120
; Using an initial value
> (reduce + 100 '(1 2 3 4 5))
115
Common Lisp
; Basic usage
> (reduce #'* '(1 2 3 4 5))
120
; Using an initial value
> (reduce #'+ '(1 2 3 4 5) :initial-value 100)
115
; Using only a subsequence
> (reduce #'+ '(1 2 3 4 5) :start 1 :end 4)
9
; Apply a function to each element first
> (reduce #'+ '((a 1) (b 2) (c 3)) :key #'cadr)
6
; Right-associative reduction
> (reduce #'expt '(2 3 4) :from-end T)
2417851639229258349412352
; Compare with
> (reduce #'expt '(2 3 4))
4096
D
void main() {
import std.stdio, std.algorithm, std.range, std.meta, std.numeric,
std.conv, std.typecons;
auto list = iota(1, 11);
alias ops = AliasSeq!(q{a + b}, q{a * b}, min, max, gcd);
foreach (op; ops)
writeln(op.stringof, ": ", list.reduce!op);
// std.algorithm.reduce supports multiple functions in parallel:
reduce!(ops[0], ops[3], text)(tuple(0, 0.0, ""), list).writeln;
}
{{out}}
"a + b": 55
"a * b": 3628800
min(T1,T2,T...) if (is(typeof(a < b))): 1
max(T1,T2,T...) if (is(typeof(a < b))): 10
gcd(T): 1
Tuple!(int,double,string)(55, 10, "12345678910")
DCL
$ list = "1,2,3,4,5"
$ call reduce list "+"
$ show symbol result
$
$ numbers = "5,4,3,2,1"
$ call reduce numbers "-"
$ show symbol result
$
$ call reduce list "*"
$ show symbol result
$ exit
$
$ reduce: subroutine
$ local_list = 'p1
$ value = f$integer( f$element( 0, ",", local_list ))
$ i = 1
$ loop:
$ element = f$element( i, ",", local_list )
$ if element .eqs. "," then $ goto done
$ value = value 'p2 f$integer( element )
$ i = i + 1
$ goto loop
$ done:
$ result == value
$ exit
$ endsubroutine
{{out}}
$ @catamorphism
RESULT == 15 Hex = 0000000F Octal = 00000000017
RESULT == -5 Hex = FFFFFFFB Octal = 37777777773
RESULT == 120 Hex = 00000078 Octal = 00000000170
=={{header|Déjà Vu}}== This is a foldl:
reduce f lst init:
if lst:
f reduce @f lst init pop-from lst
else:
init
!. reduce @+ [ 1 10 200 ] 4
!. reduce @- [ 1 10 200 ] 4
{{out}}
215
-207
EchoLisp
;; rem : the foldX family always need an initial value
;; fold left a list
(foldl + 0 (iota 10)) ;; 0 + 1 + .. + 9
→ 45
;; fold left a sequence
(lib 'sequences)
(foldl * 1 [ 1 .. 10])
→ 362880 ;; 10!
;; folding left and right
(foldl / 1 ' ( 1 2 3 4))
→ 8/3
(foldr / 1 '(1 2 3 4))
→ 3/8
;;scanl gives the list (or sequence) of intermediate values :
(scanl * 1 '( 1 2 3 4 5))
→ (1 1 2 6 24 120)
Elena
ELENA 4.x :
import system'collections;
import system'routines;
import extensions;
import extensions'text;
public program()
{
var numbers := new Range(1,10).summarize(new ArrayList());
var summary := numbers.accumulate(new Variable(0), (a,b => a + b));
var product := numbers.accumulate(new Variable(1), (a,b => a * b));
var concatenation := numbers.accumulate(new StringWriter(), (a,b => a.Printable + b.Printable));
console.printLine(summary," ",product," ",concatenation)
}
{{out}}
55 362880 12345678910
Elixir
iex(1)> Enum.reduce(1..10, fn i,acc -> i+acc end)
55
iex(2)> Enum.reduce(1..10, fn i,acc -> i*acc end)
3628800
iex(3)> Enum.reduce(10..-10, "", fn i,acc -> acc <> to_string(i) end)
"109876543210-1-2-3-4-5-6-7-8-9-10"
Erlang
{{trans|Haskell}}
-module(catamorphism).
-export([test/0]).
test() ->
Nums = lists:seq(1,10),
Summation =
lists:foldl(fun(X, Acc) -> X + Acc end, 0, Nums),
Product =
lists:foldl(fun(X, Acc) -> X * Acc end, 1, Nums),
Concatenation =
lists:foldr(
fun(X, Acc) -> integer_to_list(X) ++ Acc end,
"",
Nums),
{Summation, Product, Concatenation}.
Output:
{55,3628800,"12345678910"}
=={{header|F_Sharp|F#}}==
In the REPL:
> let nums = [1 .. 10];;
val nums : int list = [1; 2; 3; 4; 5; 6; 7; 8; 9; 10]
> let summation = List.fold (+) 0 nums;;
val summation : int = 55
> let product = List.fold (*) 1 nums;;
val product : int = 3628800
> let concatenation = List.foldBack (fun x y -> x + y) (List.map (fun i -> i.ToString()) nums) "";;
val concatenation : string = "12345678910"
Factor
{ 1 2 4 6 10 } 0 [ + ] reduce .
{{out}}
23
Forth
Forth has three traditions for iterating over the members of a data structure. Under the first, the data structure has words that help you navigate over it and normal Forth looping structures are used. Under the second, the data structure has dedicated looping words and you supply the code that's run for each member. Under the third, the data structure has a loop-over-members word that accepts a function to be run against each member.
There's no need to distinguish between the different kinds of looping ("this one collects function returns into a list; this one threads an accumulator between the function-calls; this one threads two accumulators through the function-calls; this one expects no return values whatsoever from the function-calls") because in Forth all that the looping words have to do is make the data stack available for the function's use. When that's the case, all of these variations, that are so important in other languages, are functionally equivalent.
Although it's possible to have a generic higher-order word that can operate under all kinds of data structures -- this just requires that one settle on an object system and then derive a collections library from it -- this is rarely done. Typically each data structure has its own looping words.
To demonstrate the above points we'll just loop over the bytes of a string.
Some helper words for these examples:
: lowercase? ( c -- f )
[char] a [ char z 1+ ] literal within ;
: char-upcase ( c -- C )
dup lowercase? if bl xor then ;
Using normal looping words:
: string-at ( c-addr u +n -- c )
nip + c@ ;
: string-at! ( c-addr u +n c -- )
rot drop -rot + c! ;
: type-lowercase ( c-addr u -- )
dup 0 ?do
2dup i string-at dup lowercase? if emit else drop then
loop 2drop ;
: upcase ( 'string' -- 'STRING' )
dup 0 ?do
2dup 2dup i string-at char-upcase i swap string-at!
loop ;
: count-lowercase ( c-addr u -- n )
0 -rot dup 0 ?do
2dup i string-at lowercase? if rot 1+ -rot then
loop 2drop ;
Briefly, a variation:
: next-char ( a +n -- a' n' c -1 ) ( a 0 -- 0 )
dup if 2dup 1 /string 2swap drop c@ true
else 2drop 0 then ;
: type-lowercase ( c-addr u -- )
begin next-char while
dup lowercase? if emit else drop then
repeat ;
Using dedicated looping words:
: each-char[ ( c-addr u -- )
postpone BOUNDS postpone ?DO
postpone I postpone C@ ; immediate
\ interim code: ( c -- )
: ]each-char ( -- )
postpone LOOP ; immediate
: type-lowercase ( c-addr u -- )
each-char[ dup lowercase? if emit else drop then ]each-char ;
: upcase ( 'string' -- 'STRING' )
2dup each-char[ char-upcase i c! ]each-char ;
: count-lowercase ( c-addr u -- n )
0 -rot each-char[ lowercase? if 1+ then ]each-char ;
Using higher-order words:
: each-char ( c-addr u xt -- )
{: xt :} bounds ?do
i c@ xt execute
loop ;
: type-lowercase ( c-addr u -- )
[: dup lowercase? if emit else drop then ;]
each-char ;
\ producing a new string
: upcase ( 'string' -- 'STRING' )
dup cell+ allocate throw -rot
[: ( new-string-addr c -- new-string-addr )
upcase over c+! ;] each-char $@ ;
: count-lowercase ( c-addr u -- n )
0 -rot [: lowercase? if 1+ then ;] each-char ;
In these examples COUNT-LOWERCASE updates an accumulator, UPCASE (mostly) modifies the string in-place, and TYPE-LOWERCASE performs side-effects and returns nothing to the higher-order word.
Fortran
If Fortran were to offer the ability to pass a parameter "by name", as is used in [[Jensen's_Device#Fortran|Jensen's device]], then the code might be something like
SUBROUTINE FOLD(t,F,i,ist,lst)
INTEGER t
BYNAME F
DO i = ist,lst
t = F
END DO
END SUBROUTINE FOLD !Result in temp.
temp = a(1); CALL FOLD(temp,temp*a(i),i,2,N)
Here, the function manifests as the expression that is the second parameter of subroutine FOLD, and the "by name" protocol for parameter F means that within the subroutine whenever there is a reference to F, its value is evaluated afresh in the caller's environment using the current values of ''temp'' and ''i'' as modified by the subroutine - they being passed by reference so that changes within the subroutine affect the originals. An evaluation for a different function requires merely another statement with a different expression.
Fortran however does not provide such a facility. Any parameter that is an expression is evaluated once in the caller's environment, the result placed in temporary storage, and the address of that storage location is passed to the subroutine. Repeated references to that parameter will elicit the same value. But there is special provision for passing a function to a routine, involving the special word EXTERNAL. For every different function in mind, one must diligently supply a name, and work through the overhead of declaring each such function. There is an additional word, INTRINSIC, for use when an intrinsic function (such as SIN) is to be passed as such a parameter since it will appear as its name only, and with the absence of the (...) that would be used for the function's parameters when in an arithmetic expression, it would otherwise be taken as being the name of an ordinary variable.
Here is such an arrangement, in the style of F77 though somewhat affected by F90 in that the END statement names the routine being ended. Similarly, to abate petty complaints about the types of the functions being undeclared, explicit types are specified, though unselecting the compiler diagnostic for that would match the habits of earlier compilers. Also in F90 is the MODULE protocol which involves rather more organised checking of types and additional facilities for arrays [[Array_length#Fortran|so that N need not be passed]] because secret additional parameters do so.
However, only programmer diligence in devising functions with the correct type of result and the correct type and number of parameters will evade mishaps. Note that the EXTERNAL statement does not specify the number or type of parameters. If the function is invoked multiple times within a subroutine, the compiler may check for consistency. This may cause trouble when [[Leonardo_numbers#Fortran|some parameters are optional]] so that different invocations do not match.
The function's name is used as a working variable within the function (as well as it holding the function's value on exit) so that the expression F(IFOLD,A(I)) is ''not'' a recursive invocation of function IFOLD because there are no (parameters) appended to the function's name. Earlier compilers did not allow such usage so that a separate working variable would be required.
INTEGER FUNCTION IFOLD(F,A,N) !"Catamorphism"...
INTEGER F !We're working only with integers.
EXTERNAL F !This is a function, not an array.
INTEGER A(*) !An 1-D array, of unspecified size.
INTEGER N !The number of elements.
INTEGER I !A stepper.
IFOLD = 0 !A default value.
IF (N.LE.0) RETURN !Dodge silly invocations.
IFOLD = A(1) !The function is to have two arguments.
IF (N.EQ.1) RETURN !So, if there is only one element, silly.
DO I = 2,N !Otherwise, stutter along the array.
IFOLD = F(IFOLD,A(I)) !Applying the function.
END DO !On to the next element.
END FUNCTION IFOLD!Thus, F(A(1),A(2)), or F(F(A(1),A(2)),A(3)), or F(F(F(A(1),A(2)),A(3)),A(4)), etc.
INTEGER FUNCTION IADD(I,J)
INTEGER I,J
IADD = I + J
END FUNCTION IADD
INTEGER FUNCTION IMUL(I,J)
INTEGER I,J
IMUL = I*J
END FUNCTION IMUL
INTEGER FUNCTION IDIV(I,J)
INTEGER I,J
IDIV = I/J
END FUNCTION IDIV
INTEGER FUNCTION IVID(I,J)
INTEGER I,J
IVID = J/I
END FUNCTION IVID
PROGRAM POKE
INTEGER ENUFF
PARAMETER (ENUFF = 6)
INTEGER A(ENUFF)
PARAMETER (A = (/1,2,3,4,5,6/))
INTEGER MSG
EXTERNAL IADD,IMUL,IDIV,IVID !Warn that these are the names of functions.
MSG = 6 !Standard output.
WRITE (MSG,1) ENUFF,A
1 FORMAT ('To apply a function in the "catamorphic" style ',
1 "to the ",I0," values ",/,(20I3))
WRITE (MSG,*) "Iadd",IFOLD(IADD,A,ENUFF)
WRITE (MSG,*) "Imul",IFOLD(IMUL,A,ENUFF)
WRITE (MSG,*) "Idiv",IFOLD(IDIV,A,ENUFF)
WRITE (MSG,*) "Ivid",IFOLD(IVID,A,ENUFF)
END PROGRAM POKE
Output:
To apply a function in the "catamorphic" style to the 6 values
1 2 3 4 5 6
Iadd 21
Imul 720
Idiv 0
Ivid 6
FreeBASIC
' FB 1.05.0 Win64
Type IntFunc As Function(As Integer, As Integer) As Integer
Function reduce(a() As Integer, f As IntFunc) As Integer
'' if array is empty or function pointer is null, return 0 say
If UBound(a) = -1 OrElse f = 0 Then Return 0
Dim result As Integer = a(LBound(a))
For i As Integer = LBound(a) + 1 To UBound(a)
result = f(result, a(i))
Next
Return result
End Function
Function add(x As Integer, y As Integer) As Integer
Return x + y
End Function
Function subtract(x As Integer, y As Integer) As Integer
Return x - y
End Function
Function multiply(x As Integer, y As Integer) As Integer
Return x * y
End Function
Function max(x As Integer, y As Integer) As Integer
Return IIf(x > y, x, y)
End Function
Function min(x As Integer, y As Integer) As Integer
Return IIf(x < y, x, y)
End Function
Dim a(4) As Integer = {1, 2, 3, 4, 5}
Print "Sum is :"; reduce(a(), @add)
Print "Difference is :"; reduce(a(), @subtract)
Print "Product is :"; reduce(a(), @multiply)
Print "Maximum is :"; reduce(a(), @max)
Print "Minimum is :"; reduce(a(), @min)
Print "No op is :"; reduce(a(), 0)
Print
Print "Press any key to quit"
Sleep
{{out}}
Sum is : 15
Difference is :-13
Product is : 120
Maximum is : 5
Minimum is : 1
No op is : 0
Go
package main
import (
"fmt"
)
func main() {
n := []int{1, 2, 3, 4, 5}
fmt.Println(reduce(add, n))
fmt.Println(reduce(sub, n))
fmt.Println(reduce(mul, n))
}
func add(a int, b int) int { return a + b }
func sub(a int, b int) int { return a - b }
func mul(a int, b int) int { return a * b }
func reduce(rf func(int, int) int, m []int) int {
r := m[0]
for _, v := range m[1:] {
r = rf(r, v)
}
return r
}
{{out}}
15
-13
120
Groovy
Groovy provides an "inject" method for all aggregate classes that performs a classic tail-recursive reduction, driven by a closure argument. The result of each iteration (closure invocation) is used as the accumulated valued for the next iteration. If a first argument is provided as well as a second closure argument, that first argument is used as a seed accumulator for the first iteration. Otherwise, the first element of the aggregate is used as the seed accumulator, with reduction iteration proceeding across elements 2 through n.
def vector1 = [1,2,3,4,5,6,7]
def vector2 = [7,6,5,4,3,2,1]
def map1 = [a:1, b:2, c:3, d:4]
println vector1.inject { acc, val -> acc + val } // sum
println vector1.inject { acc, val -> acc + val*val } // sum of squares
println vector1.inject { acc, val -> acc * val } // product
println vector1.inject { acc, val -> acc<val?val:acc } // max
println ([vector1,vector2].transpose().inject(0) { acc, val -> acc + val[0]*val[1] }) //dot product (with seed 0)
println (map1.inject { Map.Entry accEntry, Map.Entry entry -> // some sort of weird map-based reduction
[(accEntry.key + entry.key):accEntry.value + entry.value ].entrySet().toList().pop()
})
{{out}}
28
140
5040
7
84
abcd=10
Haskell
main :: IO ()
main =
putStrLn . unlines $
[ show . foldr (+) 0 -- sum
, show . foldr (*) 1 -- product
, foldr ((++) . show) "" -- concatenation
] <*>
[[1 .. 10]]
{{Out}}
55
3628800
12345678910
and the generality of folds is such that if we replace all three of these (function, identity) combinations ((+), 0), ((*), 1) ((++), "") with the Monoid operation '''mappend''' (<>) and identity '''mempty''', we can still obtain the same results:
import Data.Monoid
main :: IO ()
main =
let xs = [1 .. 10]
in (putStrLn . unlines)
[ (show . getSum . foldr (<>) mempty) (Sum <$> xs)
, (show . getProduct . foldr (<>) mempty) (Product <$> xs)
, (show . foldr (<>) mempty) (show <$> xs)
, (show . foldr (<>) mempty) (words
"Love is one damned thing after each other")
]
{{Out}}
55
3628800
"12345678910"
"Loveisonedamnedthingaftereachother"
Also available are ''foldl1'' and ''foldr1'' which implicitly take first element as starting value. However they are not safe as they fail on empty lists.
''Prelude'' folds work only on lists, module ''Data.Foldable'' a typeclass for more general fold - interface remains the same.
=={{header|Icon}} and {{header|Unicon}}==
Works in both languages:
procedure main(A)
write(A[1],": ",curry(A[1],A[2:0]))
end
procedure curry(f,A)
r := A[1]
every r := f(r, !A[2:0])
return r
end
Sample runs:
->cata + 3 1 4 1 5 9
+: 23
->cata - 3 1 4 1 5 9
-: -17
->cata \* 3 1 4 1 5 9
*: 540
->cata "||" 3 1 4 1 5 9
||: 314159
J
'''Solution''':
'''Example''':
```j
+/ 1 2 3 4 5
15
*/ 1 2 3 4 5
120
!/ 1 2 3 4 5 NB. "n ! k" is "n choose k"
45
Insert * into 1 2 3 4 5 becomes 1 * 2 * 3 * 4 * 5 evaluated right to left
1 * 2 * 3 * 20
1 * 2 * 60
1 * 120
120
What are the implications for -/ ? For %/ ?
Java
{{works with|Java|8}}
import java.util.stream.Stream;
public class ReduceTask {
public static void main(String[] args) {
System.out.println(Stream.of(1, 2, 3, 4, 5).mapToInt(i -> i).sum());
System.out.println(Stream.of(1, 2, 3, 4, 5).reduce(1, (a, b) -> a * b));
}
}
{{out}}
15
120
JavaScript
ES5
var nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
function add(a, b) {
return a + b;
}
var summation = nums.reduce(add);
function mul(a, b) {
return a * b;
}
var product = nums.reduce(mul, 1);
var concatenation = nums.reduce(add, "");
console.log(summation, product, concatenation);
Note that the JavaScript Array methods include a right fold ( '''.reduceRight()''' ) as well as a left fold:
(function (xs) {
'use strict';
// foldl :: (b -> a -> b) -> b -> [a] -> b
function foldl(f, acc, xs) {
return xs.reduce(f, acc);
}
// foldr :: (b -> a -> b) -> b -> [a] -> b
function foldr(f, acc, xs) {
return xs.reduceRight(f, acc);
}
// Test folds in both directions
return [foldl, foldr].map(function (f) {
return f(function (acc, x) {
return acc + (x * 2).toString() + ' ';
}, [], xs);
});
})([0, 1, 2, 3, 4, 5, 6, 7, 8, 9]);
{{Out}}
["0 2 4 6 8 10 12 14 16 18 ",
"18 16 14 12 10 8 6 4 2 0 "]
ES6
var nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
console.log(nums.reduce((a, b) => a + b, 0)); // sum of 1..10
console.log(nums.reduce((a, b) => a * b, 1)); // product of 1..10
console.log(nums.reduce((a, b) => a + b, '')); // concatenation of 1..10
jq
jq has an unusual and unusually powerful "reduce" control structure. A full description is beyond the scope of this short article, but an important point is that "reduce" is stream-oriented. Reduction of arrays is however trivially achieved using the ".[]" filter for converting an array to a stream of its values.
The simplest use of "reduce" can be illustrated by this definition of "factorial":
def factorial: reduce range(2;.+1) as $i (1; . * $i);
If the input is a non-negative integer, n, this will compute n!.
To understand how this works, consider "3|factorial". The computation starts by setting the implicit state variable to 1; range(2;4) will generate the sequence of values (2,3). The variable $i is set to each value in the stream in turn so that the state variable is multiplied by 2 (". * $i") and then by 3. Notice that since range/2 produces a stream, no array is ever constructed.
For a more complex illustration, see [[Sorting_algorithms/Strand_sort#jq|Strand sort]].
The "reduce" operator is typically used within a map/reduce framework, but the implicit state variable can be any JSON entity, and so "reduce" is also a general-purpose iterative control structure, the only limitation being that it does not have the equivalent of "break". For that, the "foreach" control structure in recent versions of jq can be used.
Julia
{{Works with|Julia 1.2}}
println([reduce(op, 1:5) for op in [+, -, *]])
println([foldl(op, 1:5) for op in [+, -, *]])
println([foldr(op, 1:5) for op in [+, -, *]])
{{out}}
[15, -13, 120]
[15, -13, 120]
[15, 3, 120]
Kotlin
fun main(args: Array<String>) {
val a = intArrayOf(1, 2, 3, 4, 5)
println("Array : ${a.joinToString(", ")}")
println("Sum : ${a.reduce { x, y -> x + y }}")
println("Difference : ${a.reduce { x, y -> x - y }}")
println("Product : ${a.reduce { x, y -> x * y }}")
println("Minimum : ${a.reduce { x, y -> if (x < y) x else y }}")
println("Maximum : ${a.reduce { x, y -> if (x > y) x else y }}")
}
{{out}}
Array : 1, 2, 3, 4, 5
Sum : 15
Difference : -13
Product : 120
Minimum : 1
Maximum : 5
Logtalk
The Logtalk standard library provides implementations of common meta-predicates such as fold left. The example that follow uses Logtalk's native support for lambda expressions to avoid the need for auxiliary predicates.
:- object(folding_examples).
:- public(show/0).
show :-
integer::sequence(1, 10, List),
write('List: '), write(List), nl,
meta::fold_left([Acc,N,Sum0]>>(Sum0 is Acc+N), 0, List, Sum),
write('Sum of all elements: '), write(Sum), nl,
meta::fold_left([Acc,N,Product0]>>(Product0 is Acc*N), 1, List, Product),
write('Product of all elements: '), write(Product), nl,
meta::fold_left([Acc,N,Concat0]>>(number_codes(N,NC), atom_codes(NA,NC), atom_concat(Acc,NA,Concat0)), '', List, Concat),
write('Concatenation of all elements: '), write(Concat), nl.
:- end_object.
{{out}}
| ?- folding_examples::show.
List: [1,2,3,4,5,6,7,8,9,10]
Sum of all elements: 55
Product of all elements: 3628800
Concatenation of all elements: 12345678910
yes
LOLCODE
{{trans|C}}
HAI 1.3
HOW IZ I reducin YR array AN YR size AN YR fn
I HAS A val ITZ array'Z SRS 0
IM IN YR loop UPPIN YR i TIL BOTH SAEM i AN DIFF OF size AN 1
val R I IZ fn YR val AN YR array'Z SRS SUM OF i AN 1 MKAY
IM OUTTA YR loop
FOUND YR val
IF U SAY SO
O HAI IM array
I HAS A SRS 0 ITZ 1
I HAS A SRS 1 ITZ 2
I HAS A SRS 2 ITZ 3
I HAS A SRS 3 ITZ 4
I HAS A SRS 4 ITZ 5
KTHX
HOW IZ I add YR a AN YR b, FOUND YR SUM OF a AN b, IF U SAY SO
HOW IZ I sub YR a AN YR b, FOUND YR DIFF OF a AN b, IF U SAY SO
HOW IZ I mul YR a AN YR b, FOUND YR PRODUKT OF a AN b, IF U SAY SO
VISIBLE I IZ reducin YR array AN YR 5 AN YR add MKAY
VISIBLE I IZ reducin YR array AN YR 5 AN YR sub MKAY
VISIBLE I IZ reducin YR array AN YR 5 AN YR mul MKAY
KTHXBYE
{{out}}
15
-13
120
Lua
table.unpack = table.unpack or unpack -- 5.1 compatibility
local nums = {1,2,3,4,5,6,7,8,9}
function add(a,b)
return a+b
end
function mult(a,b)
return a*b
end
function cat(a,b)
return tostring(a)..tostring(b)
end
local function reduce(fun,a,b,...)
if ... then
return reduce(fun,fun(a,b),...)
else
return fun(a,b)
end
end
local arithmetic_sum = function (...) return reduce(add,...) end
local factorial5 = reduce(mult,5,4,3,2,1)
print("Σ(1..9) : ",arithmetic_sum(table.unpack(nums)))
print("5! : ",factorial5)
print("cat {1..9}: ",reduce(cat,table.unpack(nums)))
{{out}}
Σ(1..9) : 45
5! : 120
cat {1..9}: 123456789
M2000 Interpreter
Module CheckIt {
Function Reduce (a, f) {
if len(a)=0 then Error "Nothing to reduce"
if len(a)=1 then =Array(a) : Exit
k=each(a, 2, -1)
m=Array(a)
While k {
m=f(m, array(k))
}
=m
}
a=(1, 2, 3, 4, 5)
Print "Array", a
Print "Sum", Reduce(a, lambda (x,y)->x+y)
Print "Difference", Reduce(a, lambda (x,y)->x-y)
Print "Product", Reduce(a, lambda (x,y)->x*y)
Print "Minimum", Reduce(a, lambda (x,y)->if(x<y->x, y))
Print "Maximum", Reduce(a, lambda (x,y)->if(x>y->x, y))
}
CheckIt
{{out}}
Array 1 2 3 4 5
Sum 15
Difference -13
Product 120
Minimum 1
Maximum 5
Maple
The left fold operator in Maple is foldl, and foldr is the right fold operator.
nums := seq( 1 .. 10 );
nums := 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
> foldl( `+`, 0, nums ); # compute sum using foldl
55
> foldr( `*`, 1, nums ); # compute product using foldr
3628800
Compute the horner form of a (sorted) polynomial:
foldl( (a,b) ->a*T+b, op(map2(op,1,[op( 72*T^5+37*T^4-23*T^3+87*T^2+44*T+29 )])));
((((72 T + 37) T - 23) T + 87) T + 44) T + 29
=={{header|Mathematica}} / {{header|Wolfram Language}}==
Fold[f, x, {a, b, c, d}]
{{Out}}
f[f[f[f[x, a], b], c], d]
Maxima
lreduce(f, [a, b, c, d], x0);
/* (%o1) f(f(f(f(x0, a), b), c), d) */
lreduce("+", [1, 2, 3, 4], 100);
/* (%o1) 110 */
min
{{works with|min|0.19.3}}
(1 2 3 4) 0 '+ reduce puts! ; sum
(1 2 3 4) 1 '* reduce puts! ; product
{{out}}
10
24
Nemerle
The Nemerle.Collections namespace defines FoldLeft, FoldRight and Fold (an alias for FoldLeft) on any sequence that implements the IEnumerable[T] interface.
def seq = [1, 4, 6, 3, 7];
def sum = seq.Fold(0, _ + _); // Fold takes an initial value and a function, here the + operator
Nim
import sequtils
block:
let
numbers = @[5, 9, 11]
addition = foldl(numbers, a + b)
substraction = foldl(numbers, a - b)
multiplication = foldl(numbers, a * b)
words = @["nim", "is", "cool"]
concatenation = foldl(words, a & b)
block:
let
numbers = @[5, 9, 11]
addition = foldr(numbers, a + b)
substraction = foldr(numbers, a - b)
multiplication = foldr(numbers, a * b)
words = @["nim", "is", "cool"]
concatenation = foldr(words, a & b)
=={{header|Oberon-2}}== {{Works with| oo2c Version 2}}
MODULE Catamorphism;
IMPORT
Object,
NPCT:Tools,
NPCT:Args,
IntStr,
Out;
TYPE
BinaryFunc= PROCEDURE (x,y: LONGINT): LONGINT;
VAR
data: POINTER TO ARRAY OF LONGINT;
i: LONGINT;
PROCEDURE Sum(x,y: LONGINT): LONGINT;
BEGIN
RETURN x + y
END Sum;
PROCEDURE Sub(x,y: LONGINT): LONGINT;
BEGIN
RETURN x - y;
END Sub;
PROCEDURE Mul(x,y: LONGINT): LONGINT;
BEGIN
RETURN x * y;
END Mul;
PROCEDURE Reduce(x: ARRAY OF LONGINT; f: BinaryFunc): LONGINT;
VAR
i,res: LONGINT;
BEGIN
res := x[0];i := 1;
WHILE (i < LEN(x)) DO;
res := f(res,x[i]);
INC(i)
END;
RETURN res
END Reduce;
PROCEDURE InitData(VAR x: ARRAY OF LONGINT);
VAR
i, j: LONGINT;
res: IntStr.ConvResults;
aux: Object.CharsLatin1;
BEGIN
i := 0;j := 1;
WHILE (j <= LEN(x)) DO
aux := Tools.AsString(Args.Get(j));
IntStr.StrToInt(aux^,x[i],res);
IF res # IntStr.strAllRight THEN
Out.String("Incorrect format for data at index ");Out.LongInt(j,0);Out.Ln;
HALT(1);
END;
INC(j);INC(i)
END
END InitData;
BEGIN
IF Args.Number() = 1 THEN
Out.String("Invalid number of arguments. ");Out.Ln;
HALT(0)
ELSE
NEW(data,Args.Number() - 1);
InitData(data^);
Out.LongInt(Reduce(data^,Sum),0);Out.Ln;
Out.LongInt(Reduce(data^,Sub),0);Out.Ln;
Out.LongInt(Reduce(data^,Mul),0);Out.Ln
END
END Catamorphism.
{{out}}
1
-11
-14400
Objeck
use Collection;
class Reducer {
function : Main(args : String[]) ~ Nil {
values := IntVector->New([1, 2, 3, 4, 5]);
values->Reduce(Add(Int, Int) ~ Int)->PrintLine();
values->Reduce(Mul(Int, Int) ~ Int)->PrintLine();
}
function : Add(a : Int, b : Int) ~ Int {
return a + b;
}
function : Mul(a : Int, b : Int) ~ Int {
return a * b;
}
}
Output
15
120
OCaml
# let nums = [1;2;3;4;5;6;7;8;9;10];;
val nums : int list = [1; 2; 3; 4; 5; 6; 7; 8; 9; 10]
# let sum = List.fold_left (+) 0 nums;;
val sum : int = 55
# let product = List.fold_left ( * ) 1 nums;;
val product : int = 3628800
Oforth
reduce is already defined into Collection class :
[ 1, 2, 3, 4, 5 ] reduce(#max)
[ "abc", "def", "gfi" ] reduce(#+)
PARI/GP
reduce(f, v)={
my(t=v[1]);
for(i=2,#v,t=f(t,v[i]));
t
};
reduce((a,b)->a+b, [1,2,3,4,5,6,7,8,9,10])
{{works with|PARI/GP|2.8.1+}}
fold((a,b)->a+b, [1..10])
Pascal
{{works with|Free Pascal}} Should work with many pascal dialects
program reduce;
type
// tmyArray = array of LongInt;
tmyArray = array[-5..5] of LongInt;
tmyFunc = function (a,b:LongInt):LongInt;
function add(x,y:LongInt):LongInt;
begin
add := x+y;
end;
function sub(k,l:LongInt):LongInt;
begin
sub := k-l;
end;
function mul(r,t:LongInt):LongInt;
begin
mul := r*t;
end;
function reduce(myFunc:tmyFunc;a:tmyArray):LongInt;
var
i,res : LongInt;
begin
res := a[low(a)];
For i := low(a)+1 to high(a) do
res := myFunc(res,a[i]);
reduce := res;
end;
procedure InitMyArray(var a:tmyArray);
var
i: LongInt;
begin
For i := low(a) to high(a) do
begin
//no a[i] = 0
a[i] := i + ord(i=0);
write(a[i],',');
end;
writeln(#8#32);
end;
var
ma : tmyArray;
BEGIN
InitMyArray(ma);
writeln(reduce(@add,ma));
writeln(reduce(@sub,ma));
writeln(reduce(@mul,ma));
END.
output
-5,-4,-3,-2,-1,1,1,2,3,4,5
1
-11
-1440
Perl
Perl's reduce function is in a standard package.
use List::Util 'reduce';
# note the use of the odd $a and $b globals
print +(reduce {$a + $b} 1 .. 10), "\n";
# first argument is really an anon function; you could also do this:
sub func { $b & 1 ? "$a $b" : "$b $a" }
print +(reduce \&func, 1 .. 10), "\n"
Perl 6
{{works with|Rakudo|2018.03}} Any associative infix operator, either built-in or user-defined, may be turned into a reduce operator by putting it into square brackets (known as "the reduce metaoperator") and using it as a list operator. The operations will work left-to-right or right-to-left automatically depending on the natural associativity of the base operator.
my @list = 1..10;
say [+] @list;
say [*] @list;
say [~] @list;
say min @list;
say max @list;
say [lcm] @list;
{{out}}
55
3628800
12345678910
1
10
2520
In addition to the reduce metaoperator, a general higher-order function, reduce, can apply any appropriate function. Reproducing the above in this form, using the function names of those operators, we have:
my @list = 1..10;
say reduce &infix:<+>, @list;
say reduce &infix:<*>, @list;
say reduce &infix:<~>, @list;
say reduce &infix:<min>, @list;
say reduce &infix:<max>, @list;
say reduce &infix:<lcm>, @list;
Phix
{{trans|C}}
function add(integer a, integer b)
return a + b
end function
function sub(integer a, integer b)
return a - b
end function
function mul(integer a, integer b)
return a * b
end function
function reduce(integer rid, sequence s)
object res = s[1]
for i=2 to length(s) do
res = call_func(rid,{res,s[i]})
end for
return res
end function
?reduce(routine_id("add"),tagset(5))
?reduce(routine_id("sub"),tagset(5))
?reduce(routine_id("mul"),tagset(5))
{{out}}
15
-13
120
PicoLisp
(de reduce ("Fun" "Lst")
(let "A" (car "Lst")
(for "N" (cdr "Lst")
(setq "A" ("Fun" "A" "N")) )
"A" ) )
(println
(reduce + (1 2 3 4 5))
(reduce * (1 2 3 4 5)) )
(bye)
PowerShell
'Filter' is a more common sequence function in PowerShell than 'reduce' or 'map', but here is one way to accomplish 'reduce':
1..5 | ForEach-Object -Begin {$result = 0} -Process {$result += $_} -End {$result}
{{Out}}
15
Prolog
SWI-Prolog has native foldl in version 6.3.1
Module lambda was written by '''Ulrich Neumerkel''' and can be found there http://www.complang.tuwien.ac.at/ulrich/Prolog-inedit/lambda.pl
:- use_module(library(lambda)).
% foldl is now a predicate of SWI-Prolog 6.3.1
%
catamorphism :-
numlist(1,10,L),
foldl(\XS^YS^ZS^(ZS is XS+YS), L, 0, Sum),
format('Sum of ~w is ~w~n', [L, Sum]),
foldl(\XP^YP^ZP^(ZP is XP*YP), L, 1, Prod),
format('Prod of ~w is ~w~n', [L, Prod]),
string_to_list(LV, ""),
foldl(\XC^YC^ZC^(string_to_atom(XS, XC),string_concat(YC,XS,ZC)),
L, LV, Concat),
format('Concat of ~w is ~w~n', [L, Concat]).
{{out}}
?- catamorphism.
Sum of [1,2,3,4,5,6,7,8,9,10] is 55
Prod of [1,2,3,4,5,6,7,8,9,10] is 3628800
Concat of [1,2,3,4,5,6,7,8,9,10] is 12345678910
true.
Python
# Python 2.X
>>> from operator import add
>>> listoflists = [['the', 'cat'], ['sat', 'on'], ['the', 'mat']]
>>> help(reduce)
Help on built-in function reduce in module __builtin__:
reduce(...)
reduce(function, sequence[, initial]) -> value
Apply a function of two arguments cumulatively to the items of a sequence,
from left to right, so as to reduce the sequence to a single value.
For example, reduce(lambda x, y: x+y, [1, 2, 3, 4, 5]) calculates
((((1+2)+3)+4)+5). If initial is present, it is placed before the items
of the sequence in the calculation, and serves as a default when the
sequence is empty.
>>> reduce(add, listoflists, [])
['the', 'cat', 'sat', 'on', 'the', 'mat']
>>>
Additional example
# Python 3.X
from functools import reduce
from operator import add, mul
nums = range(1,11)
summation = reduce(add, nums)
product = reduce(mul, nums)
concatenation = reduce(lambda a, b: str(a) + str(b), nums)
print(summation, product, concatenation)
R
Sum the numbers in a vector:
Reduce('+', c(2,30,400,5000))
5432
Put a 0 between each pair of numbers:
Reduce(function(a,b){c(a,0,b)}, c(2,3,4,5))
2 0 3 0 4 0 5
Generate all prefixes of a string:
Reduce(paste0, unlist(strsplit("freedom", NULL)), accum=T)
"f" "fr" "fre" "free" "freed" "freedo" "freedom"
Filter and map:
Reduce(function(x,acc){if (0==x%%3) c(x*x,acc) else acc}, 0:22,
init=c(), right=T)
0 9 36 81 144 225 324 441
Racket
#lang racket
(define (fold f xs init)
(if (empty? xs)
init
(f (first xs)
(fold f (rest xs) init))))
(fold + '(1 2 3) 0) ; the result is 6
REXX
This REXX example is modeled after the Perl 6 example (it is NOT a translation).
Also, a '''list''' and '''show''' function were added, although they aren't a catamorphism, as they don't produce or reduce the values to a ''single'' value, but are included here to help display the values in the list.
/*REXX program demonstrates a method for catamorphism for some simple functions. */
@list= 1 2 3 4 5 6 7 8 9 10
say 'list:' fold(@list, "list")
say ' sum:' fold(@list, "+" )
say 'prod:' fold(@list, "*" )
say ' cat:' fold(@list, "||" )
say ' min:' fold(@list, "min" )
say ' max:' fold(@list, "max" )
say ' avg:' fold(@list, "avg" )
say ' GCD:' fold(@list, "GCD" )
say ' LCM:' fold(@list, "LCM" )
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
fold: procedure; parse arg z; arg ,f; z = space(z); BIFs= 'MIN MAX LCM GCD'
za= translate(z, f, ' '); zf= f"("translate(z, ',' , " ")')'
if f== '+' | f=="*" then interpret "return" za
if f== '||' then return space(z, 0)
if f== 'AVG' then interpret "return" fold(z, '+') "/" words(z)
if wordpos(f, BIFs)\==0 then interpret "return" zf
if f=='LIST' | f=="SHOW" then return z
return 'illegal function:' arg(2)
/*──────────────────────────────────────────────────────────────────────────────────────*/
GCD: procedure; $=; do j=1 for arg(); $= $ arg(j)
end /*j*/
parse var $ x z .; if x=0 then x= z /* [↑] build an arg list.*/
x= abs(x)
do k=2 to words($); y= abs( word($, k)); if y=0 then iterate
do until _=0; _= x // y; x= y; y= _
end /*until*/
end /*k*/
return x
/*──────────────────────────────────────────────────────────────────────────────────────*/
LCM: procedure; $=; do j=1 for arg(); $= $ arg(j)
end /*j*/
x= abs(word($, 1)) /* [↑] build an arg list.*/
do k=2 to words($); != abs(word($, k)); if !=0 then return 0
x= x*! / GCD(x, !) /*GCD does the heavy work*/
end /*k*/
return x
{{out|output|:}}
list: 1 2 3 4 5 6 7 8 9 10
sum: 55
prod: 3628800
cat: 12345678910
min: 1
max: 10
avg: 5.5
GCD: 1
LCM: 2520
Ring
n = list(10)
for i = 1 to 10
n[i] = i
next
see " +: " + cat(10,"+") + nl+
" -: " + cat(10,"-") + nl +
" *: " + cat(10,"*") + nl +
" /: " + cat(10,"/") + nl+
" ^: " + cat(10,"^") + nl +
"min: " + cat(10,"min") + nl+
"max: " + cat(10,"max") + nl+
"avg: " + cat(10,"avg") + nl +
"cat: " + cat(10,"cat") + nl
func cat count,op
cat = n[1]
cat2 = ""
for i = 2 to count
switch op
on "+" cat += n[i]
on "-" cat -= n[i]
on "*" cat *= n[i]
on "/" cat /= n[i]
on "^" cat ^= n[i]
on "max" cat = max(cat,n[i])
on "min" cat = min(cat,n[i])
on "avg" cat += n[i]
on "cat" cat2 += string(n[i])
off
next
if op = "avg" cat = cat / count ok
if op = "cat" decimals(0) cat = string(n[1])+cat2 ok
return cat
Ruby
The method inject (and it's alias reduce) can be used in several ways; the simplest is to give a methodname as argument:
# sum:
p (1..10).inject(:+)
# smallest number divisible by all numbers from 1 to 20:
p (1..20).inject(:lcm) #lcm: lowest common multiple
The most versatile way uses a accumulator object (memo) and a block. In this example Pascal's triangle is generated by using an array [1,1] and inserting the sum of each consecutive pair of numbers from the previous row.
p row = [1]
10.times{p row = row.each_cons(2).inject([1,1]){|ar,(a,b)| ar.insert(-2, a+b)} }
# [1]
# [1, 1]
# [1, 2, 1]
# [1, 3, 3, 1]
# [1, 4, 6, 4, 1]
# [1, 5, 10, 10, 5, 1]
# [1, 6, 15, 20, 15, 6, 1]
# etc
Run BASIC
for i = 1 to 10 :n(i) = i:next i
print " +: ";" ";cat(10,"+")
print " -: ";" ";cat(10,"-")
print " *: ";" ";cat(10,"*")
print " /: ";" ";cat(10,"/")
print " ^: ";" ";cat(10,"^")
print "min: ";" ";cat(10,"min")
print "max: ";" ";cat(10,"max")
print "avg: ";" ";cat(10,"avg")
print "cat: ";" ";cat(10,"cat")
function cat(count,op$)
cat = n(1)
for i = 2 to count
if op$ = "+" then cat = cat + n(i)
if op$ = "-" then cat = cat - n(i)
if op$ = "*" then cat = cat * n(i)
if op$ = "/" then cat = cat / n(i)
if op$ = "^" then cat = cat ^ n(i)
if op$ = "max" then cat = max(cat,n(i))
if op$ = "min" then cat = min(cat,n(i))
if op$ = "avg" then cat = cat + n(i)
if op$ = "cat" then cat$ = cat$ + str$(n(i))
next i
if op$ = "avg" then cat = cat / count
if op$ = "cat" then cat = val(str$(n(1))+cat$)
end function
+: 55
-: -53
*: 3628800
/: 2.75573205e-7
^: 1
min: 1
max: 10
avg: 5.5
cat: 12345678910
Rust
fn main() {
println!("Sum: {}", (1..10).fold(0, |acc, n| acc + n));
println!("Product: {}", (1..10).fold(1, |acc, n| acc * n));
let chars = ['a', 'b', 'c', 'd', 'e'];
println!("Concatenation: {}",
chars.iter().map(|&c| (c as u8 + 1) as char).collect::<String>());
}
{{out}}
Sum: 45
Product: 362880
Concatenation: bcdef
Scala
object Main extends App {
val a = Seq(1, 2, 3, 4, 5)
println(s"Array : ${a.mkString(", ")}")
println(s"Sum : ${a.sum}")
println(s"Difference : ${a.reduce { (x, y) => x - y }}")
println(s"Product : ${a.product}")
println(s"Minimum : ${a.min}")
println(s"Maximum : ${a.max}")
}
Scheme
Implementation
reduce implemented for a single list:
(define (reduce fn init lst)
(do ((val init (fn (car rem) val)) ; accumulated value passed as second argument
(rem lst (cdr rem)))
((null? rem) val)))
(display (reduce + 0 '(1 2 3 4 5))) (newline) ; => 15
(display (reduce expt 2 '(3 4))) (newline) ; => 262144
Using SRFI 1
There is also an implementation of fold and fold-right in SRFI-1, for lists.
These take a two-argument procedure: (lambda (value acc) ...) where value is the next value in the list, and acc is the accumulated value. The initial value is used for the first value of acc.
> (import (srfi 1))
> (fold + 0 '(1 2 3 4 5))
15
> (fold expt 2 '(3 4)) ; => (expt 4 (expt 3 2))
262144
> (fold-right expt 2 '(3 4)) ; => (expt 3 (expt 4 2))
43046721
More than one list may be folded over, when the function is passed one item from each list plus the accumulated value:
> (fold + 0 '(1 2 3) '(4 5 6)) ; add up all the numbers in all the lists
21
Sidef
say (1..10 -> reduce('+'));
say (1..10 -> reduce{|a,b| a + b});
Standard ML
- val nums = [1,2,3,4,5,6,7,8,9,10];
val nums = [1,2,3,4,5,6,7,8,9,10] : int list
- val sum = foldl op+ 0 nums;
val sum = 55 : int
- val product = foldl op* 1 nums;
val product = 3628800 : int
Swift
let nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
print(nums.reduce(0, +))
print(nums.reduce(1, *))
print(nums.reduce("", { $0 + String($1) }))
{{out}}
55
3628800
12345678910
Tailspin
It is probably easier to just write the whole thing as an inline transform rather than create a utility.
[1..5] -> (@: $(1); $(2..-1)... -> @: $@ + $; $@!) -> '$;
' -> !OUT::write
[1..5] -> (@: $(1); $(2..-1)... -> @: $@ - $; $@!) -> '$;
' -> !OUT::write
[1..5] -> (@: $(1); $(2..-1)... -> @: $@ * $; $@!) -> '$;
' -> !OUT::write
{{out}}
15
-13
120
If you really want to make a utility, it could look like this:
templates fold@{op:}
@: $(1);
$(2..-1)... -> @: [$@, $] -> op;
$@ !
end fold
templates add
$(1) + $(2) !
end add
templates mul
$(1) * $(2) !
end mul
[1..5] -> fold@{op:add} -> '$;
' -> !OUT::write
[1..5] -> fold@{op:mul} -> '$;
' -> !OUT::write
{{out}}
15
120
Tcl
Tcl does not come with a built-in fold command, but it is easy to construct:
proc fold {lambda zero list} {
set accumulator $zero
foreach item $list {
set accumulator [apply $lambda $accumulator $item]
}
return $accumulator
}
Demonstrating:
set 1to5 {1 2 3 4 5}
puts [fold {{a b} {expr {$a+$b}}} 0 $1to5]
puts [fold {{a b} {expr {$a*$b}}} 1 $1to5]
puts [fold {{a b} {return $a,$b}} x $1to5]
{{out}}
15
120
x,1,2,3,4,5
Note that these particular operations would more conventionally be written as:
puts [::tcl::mathop::+ {*}$1to5]
puts [::tcl::mathop::* {*}$1to5]
puts x,[join $1to5 ,]
But those are not general catamorphisms.
VBA
Public Sub reduce()
s = [{1,2,3,4,5}]
Debug.Print WorksheetFunction.Sum(s)
Debug.Print WorksheetFunction.Product(s)
End Sub
WDTE
Translated from the JavaScript ES6 example with a few modifications.
import 'arrays';
let s => import 'stream';
let str => import 'strings';
# Sum of [1, 10]:
let nums => [1; 2; 3; 4; 5; 6; 7; 8; 9; 10];
a.stream nums -> s.reduce 0 + -- io.writeln io.stdout;
# As an alternative to an array, a range stream can be used. Here's the product of [1, 11):
s.range 1 11 -> s.reduce 1 * -- io.writeln io.stdout;
# And here's a concatenation:
s.range 1 11 -> s.reduce '' (str.format '{}{}') -- io.writeln io.stdout;
Wortel
You can reduce an array with the !/ operator.
!/ ^+ [1 2 3] ; returns 6
If you want to reduce with an initial value, you'll need the @fold operator.
@fold ^+ 1 [1 2 3] ; returns 7
{{out}}
55
3628800
12345678910
zkl
Most sequence objects in zkl have a reduce method.
T("foo","bar").reduce(fcn(p,n){p+n}) //--> "foobar"
"123four5".reduce(fcn(p,c){p+(c.matches("[0-9]") and c or 0)}, 0) //-->11
File("foo.zkl").reduce('+(1).fpM("0-"),0) //->5 (lines in file)
ZX Spectrum Basic
{{trans|BBC_BASIC}}
10 DIM a(5)
20 FOR i=1 TO 5
30 READ a(i)
40 NEXT i
50 DATA 1,2,3,4,5
60 LET o$="+": GO SUB 1000: PRINT tmp
70 LET o$="-": GO SUB 1000: PRINT tmp
80 LET o$="*": GO SUB 1000: PRINT tmp
90 STOP
1000 REM Reduce
1010 LET tmp=a(1)
1020 FOR i=2 TO 5
1030 LET tmp=VAL ("tmp"+o$+"a(i)")
1040 NEXT i
1050 RETURN