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This means it might contain formatting issues, incorrect code, conceptual problems, or other severe issues.
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{{task|Arithmetic operations}}
;Task: Provide code that produces a list of numbers which is the nth order forward difference, given a non-negative integer (specifying the order) and a list of numbers.
The first-order forward difference of a list of numbers '''A''' is a new list '''B''', where Bn = An+1 - An.
List '''B''' should have one fewer element as a result.
The second-order forward difference of '''A''' will be:
tdefmodule Diff do
def forward(arr,i\\1) do
forward(arr,[],i)
end
def forward([_|[]],diffs,i) do
if i == 1 do
IO.inspect diffs
else
forward(diffs,[],i-1)
end
end
def forward([val1|[val2|vals]],diffs,i) do
forward([val2|vals],diffs++[val2-val1],i)
end
end
The same as the first-order forward difference of '''B'''.
That new list will have two fewer elements than '''A''' and one less than '''B'''.
The goal of this task is to repeat this process up to the desired order.
For a more formal description, see the related [http://mathworld.wolfram.com/ForwardDifference.html Mathworld article].
;Algorithmic options:
- Iterate through all previous forward differences and re-calculate a new array each time.
- Use this formula (from [[wp:Forward difference|Wikipedia]]): ::: ::: ([[Pascal's Triangle]] may be useful for this option.)
Ada
with Ada.Text_Io;
with Ada.Float_Text_Io; use Ada.Float_Text_Io;
with Ada.containers.Vectors;
procedure Forward_Difference is
package Flt_Vect is new Ada.Containers.Vectors(Positive, Float);
use Flt_Vect;
procedure Print(Item : Vector) is
begin
if not Item.Is_Empty then
Ada.Text_IO.Put('[');
for I in 1..Item.Length loop
Put(Item => Item.Element(Positive(I)), Fore => 1, Aft => 1, Exp => 0);
if Positive(I) < Positive(Item.Length) then
Ada.Text_Io.Put(", ");
end if;
end loop;
Ada.Text_Io.Put_line("]");
else
Ada.Text_IO.Put_Line("Empty List");
end if;
end Print;
function Diff(Item : Vector; Num_Passes : Natural) return Vector is
A : Vector := Item;
B : Vector := Empty_Vector;
begin
if not A.Is_Empty then
for I in 1..Num_Passes loop
for I in 1..Natural(A.Length) - 1 loop
B.Append(A.Element(I + 1) - A.Element(I));
end loop;
Move(Target => A, Source => B);
end loop;
end if;
return A;
end Diff;
Values : array(1..10) of Float := (90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0);
A : Vector;
begin
for I in Values'range loop
A.Append(Values(I)); -- Fill the vector
end loop;
Print(Diff(A, 1));
Print(Diff(A, 2));
Print(Diff(A, 9));
Print(Diff(A, 10));
print(Diff(A, 0));
end Forward_Difference;
{{out}}
[-43.0, 11.0, -29.0, -7.0, 10.0, 23.0, -50.0, 50.0, 18.0]
[54.0, -40.0, 22.0, 17.0, 13.0, -73.0, 100.0, -32.0]
[-2921.0]
Empty List
[90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0]
ALGOL 68
{{works with|ALGOL 68|Revision 1 - no extensions to language used}}
{{works with|ALGOL 68G|Any - tested with release [http://sourceforge.net/projects/algol68/files/algol68g/algol68g-1.18.0/algol68g-1.18.0-9h.tiny.el5.centos.fc11.i386.rpm/download 1.18.0-9h.tiny]}} {{wont work with|ELLA ALGOL 68|Any (with appropriate job cards) - tested with release [http://sourceforge.net/projects/algol68/files/algol68toc/algol68toc-1.8.8d/algol68toc-1.8-8d.fc9.i386.rpm/download 1.8-8d] - due to extensive use of FORMATted transput}}
main:(
MODE LISTREAL = [1:0]REAL;
OP - = (LISTREAL a,b)LISTREAL: (
[UPB a]REAL out;
FOR i TO UPB out DO out[i]:=a[i]-b[i] OD;
out
);
FORMAT real fmt=$zzz-d.d$;
FORMAT repeat fmt = $n(UPB s-1)(f(real fmt)",")f(real fmt)$;
FORMAT list fmt = $"("f(UPB s=1|real fmt|repeat fmt)")"$;
FLEX [1:0] REAL s := (90, 47, 58, 29, 22, 32, 55, 5, 55, 73);
printf((list fmt,s,$";"l$));
TO UPB s-1 DO
s := s[2:] - s[:UPB s-1];
printf((list fmt,s,$";"l$))
OD
)
{{out}}
( 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0);
( -43.0, 11.0, -29.0, -7.0, 10.0, 23.0, -50.0, 50.0, 18.0);
( 54.0, -40.0, 22.0, 17.0, 13.0, -73.0, 100.0, -32.0);
( -94.0, 62.0, -5.0, -4.0, -86.0, 173.0, -132.0);
( 156.0, -67.0, 1.0, -82.0, 259.0, -305.0);
( -223.0, 68.0, -83.0, 341.0, -564.0);
( 291.0, -151.0, 424.0, -905.0);
( -442.0, 575.0,-1329.0);
( 1017.0,-1904.0);
(-2921.0);
ALGOL W
begin
% calculate forward differences %
% sets elements of B to the first order forward differences of A %
% A should have bounds 1 :: n, B should have bounds 1 :: n - 1 %
procedure FirstOrderFDifference ( integer array A( * )
; integer array B( * )
; integer value n
) ;
for i := 2 until n do B( i - 1 ) := A( i ) - A( i - 1 );
integer array v ( 1 :: 10 );
integer array diff( 1 :: 9 );
integer vPos, length;
% construct the initial values array %
vPos := 1;
for i := 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 do begin
v( vPos ) := i;
vPos := vPos + 1
end for_i ;
% calculate and show the differences %
i_w := 5; % set output format %
length := 10;
for order := 1 until length - 1 do begin
FirstOrderFDifference( v, diff, length );
length := length - 1;
write( order, ": " ); for i := 1 until length do writeon( diff( i ) );
for i := 1 until length do v( i ) := diff( i )
end for_order
end.
{{out}}
1 : -43 11 -29 -7 10 23 -50 50 18
2 : 54 -40 22 17 13 -73 100 -32
3 : -94 62 -5 -4 -86 173 -132
4 : 156 -67 1 -82 259 -305
5 : -223 68 -83 341 -564
6 : 291 -151 424 -905
7 : -442 575 -1329
8 : 1017 -1904
9 : -2921
APL
{{works with|Dyalog APL}}{{trans|J}}
list ← 90 47 58 29 22 32 55 5 55 73
fd ← {⍺=0:⍵⋄(⍺-1)∇(1↓⍵)-(¯1↓⍵)}
1 fd list
¯43 11 ¯29 ¯7 10 23 ¯50 50 18
2 fd list
54 ¯40 22 17 13 ¯73 100 ¯32
AppleScript
{{Trans|JavaScript}}
-- FORWARD DIFFERENCE -------------------------------------------------------- -- forwardDifference :: Int -> [Int] -> [Int] on forwardDifference(n, xs) set lng to length of xs -- atLength :: [Int] -> Bool script atLength property fullLength : lng property ndx : n on |λ|(ds) (atLength's fullLength) - (length of ds) ≥ atLength's ndx end |λ| end script -- fd :: [Int] -> [Int] script fd on |λ|(xs) script minus on |λ|(a, b) a - b end |λ| end script zipWith(minus, tail(xs), xs) end |λ| end script |until|(atLength, fd, xs) end forwardDifference -- TEST ---------------------------------------------------------------------- on run set xs to {90, 47, 58, 29, 22, 32, 55, 5, 55, 73} script test on |λ|(n) intercalate(" -> [", ¬ {{n}} & intercalate(", ", forwardDifference(n, xs))) & "]" end |λ| end script intercalate(linefeed, map(test, enumFromTo(1, 9))) end run -- GENERIC FUNCTIONS --------------------------------------------------------- -- enumFromTo :: Int -> Int -> [Int] on enumFromTo(m, n) if m > n then set d to -1 else set d to 1 end if set lst to {} repeat with i from m to n by d set end of lst to i end repeat return lst end enumFromTo -- intercalate :: Text -> [Text] -> Text on intercalate(strText, lstText) set {dlm, my text item delimiters} to {my text item delimiters, strText} set strJoined to lstText as text set my text item delimiters to dlm return strJoined end intercalate -- map :: (a -> b) -> [a] -> [b] on map(f, xs) tell mReturn(f) set lng to length of xs set lst to {} repeat with i from 1 to lng set end of lst to |λ|(item i of xs, i, xs) end repeat return lst end tell end map -- min :: Ord a => a -> a -> a on min(x, y) if y < x then y else x end if end min -- Lift 2nd class handler function into 1st class script wrapper -- mReturn :: Handler -> Script on mReturn(f) if class of f is script then f else script property |λ| : f end script end if end mReturn -- tail :: [a] -> [a] on tail(xs) if length of xs > 1 then items 2 thru -1 of xs else {} end if end tail -- until :: (a -> Bool) -> (a -> a) -> a -> a on |until|(p, f, x) set mp to mReturn(p) set v to x tell mReturn(f) repeat until mp's |λ|(v) set v to |λ|(v) end repeat end tell return v end |until| -- zipWith :: (a -> b -> c) -> [a] -> [b] -> [c] on zipWith(f, xs, ys) set lng to min(length of xs, length of ys) set lst to {} tell mReturn(f) repeat with i from 1 to lng set end of lst to |λ|(item i of xs, item i of ys) end repeat return lst end tell end zipWith
{{Out}}
1 -> [-43, 11, -29, -7, 10, 23, -50, 50, 18]
2 -> [54, -40, 22, 17, 13, -73, 100, -32]
3 -> [-94, 62, -5, -4, -86, 173, -132]
4 -> [156, -67, 1, -82, 259, -305]
5 -> [-223, 68, -83, 341, -564]
6 -> [291, -151, 424, -905]
7 -> [-442, 575, -1329]
8 -> [1017, -1904]
9 -> [-2921]
AutoHotkey
contributed by Laszlo on the ahk [http://www.autohotkey.com/forum/post-276470.html#276470 forum]
MsgBox % diff("2,3,4,3",1)
MsgBox % diff("2,3,4,3",2)
MsgBox % diff("2,3,4,3",3)
MsgBox % diff("2,3,4,3",4)
diff(list,ord) { ; high order forward differences of a list
Loop %ord% {
L =
Loop Parse, list, `, %A_Space%%A_Tab%
If (A_Index=1)
p := A_LoopField
Else
L .= "," A_LoopField-p, p := A_LoopField
list := SubStr(L,2)
}
Return list
}
AWK
#!/usr/bin/awk -f
BEGIN {
if (p<1) {p = 1};
}
function diff(s, p) {
n = split(s, a, " ");
for (j = 1; j <= p; j++) {
for(i = 1; i <= n-j; i++) {
a[i] = a[i+1] - a[i];
}
}
s = "";
for (i = 1; i <= n-p; i++) s = s" "a[i];
return s;
}
{
print diff($0, p);
}
Using Pascal's triangle:
#!/usr/bin/awk -f
BEGIN {
if (p<1) {p = 1};
}
function diff(s, p) {
# pascal triangled with sign changes
b[1] = (p%2) ? 1 : -1;
for (j=1; j < p; j++) {
b[j+1] = -b[j]*(p-j)/j;
};
n = split(s, a, " ");
s = "";
for (j = 1; j <= n-p+1; j++) {
c = 0;
for(i = 1; i <= p; i++) {
c += b[i]*a[j+i-1];
}
s = s" "c;
}
return s;
}
{
print diff($0, p);
}
{{out}}
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=1
1 1 2 3 -3 -2 -1 -1
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=2
0 1 1 -6 1 1 0
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=3
1 0 -7 7 0 -1
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=4
-1 -7 14 -7 -1
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=5
-6 21 -21 6
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=6
27 -42 27
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=7
-69 69
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=8
138
$ echo '0 1 2 4 7 4 2 1 0' | ./diff.awk -v p=9
BBC BASIC
{{works with|BBC BASIC for Windows}}
DIM A(9)
A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0
PRINT "Original array: " FNshowarray(A())
PROCforward_difference(1, A(), B())
PRINT "Forward diff 1: " FNshowarray(B())
PROCforward_difference(2, A(), C())
PRINT "Forward diff 2: " FNshowarray(C())
PROCforward_difference(9, A(), D())
PRINT "Forward diff 9: " FNshowarray(D())
END
DEF PROCforward_difference(n%, a(), RETURN b())
LOCAL c%, i%, j%
DIM b(DIM(a(),1) - n%)
FOR i% = 0 TO DIM(b(),1)
b(i%) = a(i% + n%)
c% = 1
FOR j% = 1 TO n%
c% = -INT(c% * (n% - j% + 1) / j% + 0.5)
b(i%) += c% * a(i% + n% - j%)
NEXT
NEXT
ENDPROC
DEF FNshowarray(a())
LOCAL i%, a$
FOR i% = 0 TO DIM(a(),1)
a$ += STR$(a(i%)) + ", "
NEXT
= LEFT$(LEFT$(a$))
{{out}}
Original array: 90, 47, 58, 29, 22, 32, 55, 5, 55, 73
Forward diff 1: -43, 11, -29, -7, 10, 23, -50, 50, 18
Forward diff 2: 54, -40, 22, 17, 13, -73, 100, -32
Forward diff 9: -2921
C
#include <iostream> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; /* handle two special cases */ if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } /* first order diff goes from x->y, later ones go from y->y */ for (j = 0; j < order; j++, x = y) for (i = 0, len--; i < len; i++) y[i] = x[i + 1] - x[i]; y = realloc(y, sizeof(double) * len); return y; } int main(void) { double *y, x[] = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; int i, len = sizeof(x) / sizeof(x[0]); y = fwd_diff(x, len, 1); for (i = 0; i < len - 1; i++) printf("%g ", y[i]); putchar('\n'); return 0; }
Use method with Pascal triangle, binomial coefficients are pre-computed
#include <stdio.h> int* binomCoeff(int n) { int *b = calloc(n+1,sizeof(int)); int j; b[0] = n%2 ? -1 : 1; for (j=1 ; j<=n; j++) b[j] = -b[j-1]*(n+1-j)/j; return(b); }; main () { double array[] = { 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 }; size_t lenArray = sizeof(array)/sizeof(array[0]); int p = 4; // order int *b = binomCoeff(p); // pre-compute binomial coefficients for order p int j, k; // compute p-th difference for (k=0 ; k < lenArray; k++) for (array[k] *= b[0], j=1 ; j<=p; j++) array[k] += b[j] * array[k+j]; free(b); // resulting series is shorter by p elements lenArray -= p; for (k=0 ; k < lenArray; k++) printf("%f ",array[k]); printf("\n"); }
C#
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence.Skip(1).Zip(sequence, (next, current) => next - current); default: return ForwardDifference(ForwardDifference(sequence), order - 1u); } } static void Main() { IEnumerable<int> sequence = new[] { 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 }; do { Console.WriteLine(string.Join(", ", sequence)); } while ((sequence = ForwardDifference(sequence)).Any()); } }
{{out}}
90, 47, 58, 29, 22, 32, 55, 5, 55, 73
-43, 11, -29, -7, 10, 23, -50, 50, 18
54, -40, 22, 17, 13, -73, 100, -32
-94, 62, -5, -4, -86, 173, -132
156, -67, 1, -82, 259, -305
-223, 68, -83, 341, -564
291, -151, 424, -905
-442, 575, -1329
1017, -1904
-2921
C++
{{works with|g++|4.1.2 20061115 (prerelease) (SUSE Linux)}}
This code uses a separate function to do a first-order forward difference, which is then called several times for calculating n-th order forward difference. No error checking is implemented.
#include <vector> #include <iterator> #include <algorithm> // calculate first order forward difference // requires: // * InputIterator is an input iterator // * OutputIterator is an output iterator // * The value type of InputIterator is copy-constructible and assignable // * The value type of InputIterator supports operator - // * The result type of operator- is assignable to the value_type of OutputIterator // returns: The iterator following the output sequence template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { // special case: for empty sequence, do nothing if (first == last) return dest; typedef typename std::iterator_traits<InputIterator>::value_type value_type; value_type temp = *first++; while (first != last) { value_type temp2 = *first++; *dest++ = temp2 - temp; temp = temp2; } return dest; } // calculate n-th order forward difference. // requires: // * InputIterator is an input iterator // * OutputIterator is an output iterator // * The value type of InputIterator is copy-constructible and assignable // * The value type of InputIterator supports operator - // * The result type of operator- is assignable to the value_type of InputIterator // * The result type of operator- is assignable to the value_type of OutputIterator // * order >= 0 // returns: The iterator following the output sequence template<typename InputIterator, typename OutputIterator> OutputIterator nth_forward_difference(int order, InputIterator first, InputIterator last, OutputIterator dest) { // special case: If order == 0, just copy input to output if (order == 0) return std::copy(first, last, dest); // second special case: If order == 1, just forward to the first-order function if (order == 1) return forward_difference(first, last, dest); // intermediate results are stored in a vector typedef typename std::iterator_traits<InputIterator>::value_type value_type; std::vector<value_type> temp_storage; // fill the vector with the result of the first order forward difference forward_difference(first, last, std::back_inserter(temp_storage)); // the next n-2 iterations work directly on the vector typename std::vector<value_type>::iterator begin = temp_storage.begin(), end = temp_storage.end(); for (int i = 1; i < order-1; ++i) end = forward_difference(begin, end, begin); // the final iteration writes directly to the output iterator return forward_difference(begin, end, dest); } // example usage code #include <iostream> int main() { double array[10] = { 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 }; // this stores the results in the vector dest std::vector<double> dest; nth_forward_difference(1, array, array+10, std::back_inserter(dest)); // output dest std::copy(dest.begin(), dest.end(), std::ostream_iterator<double>(std::cout, " ")); std::cout << std::endl; // however, the results can also be output as they are calculated nth_forward_difference(2, array, array+10, std::ostream_iterator<double>(std::cout, " ")); std::cout << std::endl; nth_forward_difference(9, array, array+10, std::ostream_iterator<double>(std::cout, " ")); std::cout << std::endl; nth_forward_difference(10, array, array+10, std::ostream_iterator<double>(std::cout, " ")); std::cout << std::endl; nth_forward_difference(0, array, array+10, std::ostream_iterator<double>(std::cout, " ")); std::cout << std::endl; // finally, the results can also be written into the original array // (which of course destroys the original content) double* end = nth_forward_difference(3, array, array+10, array); for (double* p = array; p < end; ++p) std::cout << *p << " "; std::cout << std::endl; return 0; }
{{out}}
-43 11 -29 -7 10 23 -50 50 18
54 -40 22 17 13 -73 100 -32
-2921
90 47 58 29 22 32 55 5 55 73
-94 62 -5 -4 -86 173 -132
Note the empty line indicating the empty sequence for order 10.
Using Standard Template Library
#include <iostream> #include <numeric> // Calculate the Forward Difference of a series if integers showing each order // // Nigel Galloway. August 20th., 2012 // int main() { int x[] = {NULL,-43,11,-29,-7,10,23,-50,50,18}; const int N = sizeof(x) / sizeof(int) - 1; for (int ord = 0; ord < N - 1; ord++) { std::adjacent_difference(x+1, x + N + 1 - ord, x); for (int i = 1; i < N - ord; i++) std::cout << x[i] << ' '; std::cout << std::endl; } return 0; }
{{out}}
54 -40 22 17 13 -73 100 -32
-94 62 -5 -4 -86 173 -132
156 -67 1 -82 259 -305
-223 68 -83 341 -564
291 -151 424 -905
-442 575 -1329
1017 -1904
-2921
Usually one will not want the intermediate results, in which case the following is sufficient:
#include <iostream> #include <numeric> // Calculate the Forward Difference of a series if integers // // Nigel Galloway. August 20th., 2012 // int main() { int x[] = {NULL,-43,11,-29,-7,10,23,-50,50,18}; const int N = sizeof(x) / sizeof(int) - 1; for (int ord = 0; ord < N - 1; ord++) std::adjacent_difference(x+1, x + N + 1 - ord, x); std::cout << x[1] << std::endl; return 0; }
{{out}}
-2921
===Using Pascal's Triangle===
#include <iostream> #include <algorithm> // Calculate the Forward Difference of a series if integers using Pascal's Triangle // For this example the 9th line of Pascal's Triangle is stored in P. // // Nigel Galloway. August 20th., 2012 // int main() { const int P[] = {1,-8,28,-56,70,-56,28,-8,1}; int x[] = {-43,11,-29,-7,10,23,-50,50,18}; std::transform(x, x + sizeof(x) / sizeof(int), P, x, std::multiplies<int>()); std::cout << std::accumulate(x, x + sizeof(x) / sizeof(int), 0) << std::endl; return 0; }
{{out}}
-2921
Clojure
(defn fwd-diff [nums order] (nth (iterate #(map - (next %) %) nums) order))
CoffeeScript
forward_difference = (arr, n) ->
# Find the n-th order forward difference for arr using
# a straightforward recursive algorithm.
# Assume arr is integers and n <= arr.length.
return arr if n == 0
arr = forward_difference(arr, n-1)
(arr[i+1] - arr[i] for i in [0...arr.length - 1])
arr = [-1, 0, 1, 8, 27, 64, 125, 216]
for n in [0..arr.length]
console.log n, forward_difference arr, n
{{out}}
> coffee forward_difference.coffee
0 [ -1, 0, 1, 8, 27, 64, 125, 216 ]
1 [ 1, 1, 7, 19, 37, 61, 91 ]
2 [ 0, 6, 12, 18, 24, 30 ]
3 [ 6, 6, 6, 6, 6 ]
4 [ 0, 0, 0, 0 ]
5 [ 0, 0, 0 ]
6 [ 0, 0 ]
7 [ 0 ]
8 []
Common Lisp
(defun forward-difference (list) (mapcar #'- (rest list) list)) (defun nth-forward-difference (list n) (setf list (copy-list list)) (loop repeat n do (map-into list #'- (rest list) list)) (subseq list 0 (- (length list) n)))
D
Basic Version
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow in { assert(level >= 0 && level < data.length); } body { auto result = data.dup; foreach (immutable i; 0 .. level) foreach (immutable j, ref el; result[0 .. $ - i - 1]) el = result[j + 1] - el; result.length -= level; return result; } void main() { import std.stdio; const data = [90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5]; foreach (immutable level; 0 .. data.length) forwardDifference(data, level).writeln; }
{{out}}
[90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5]
[-43.5, 11, -29, -7, 10, 23, -50, 50, 18.5]
[54.5, -40, 22, 17, 13, -73, 100, -31.5]
[-94.5, 62, -5, -4, -86, 173, -131.5]
[156.5, -67, 1, -82, 259, -304.5]
[-223.5, 68, -83, 341, -563.5]
[291.5, -151, 424, -904.5]
[-442.5, 575, -1328.5]
[1017.5, -1903.5]
[-2921]
Alternative Version
Same output.
import std.stdio, std.algorithm, std.range, std.array; auto forwardDifference(Range)(Range d, in int level) pure { foreach (immutable _; 0 .. level) d = d.zip(d.dropOne).map!(a => a[0] - a[1]).array; return d; } void main() { const data = [90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5]; foreach (immutable level; 0 .. data.length) forwardDifference(data, level).writeln; }
Using Vector Operations
forwardDifference mutates the array in-place (same output):
import std.stdio; T[] forwardDifference(T)(T[] s, in int n) pure nothrow @nogc { foreach (immutable i; 0 .. n) s[0 .. $ - i - 1] = s[1 .. $ - i] - s[0 .. $ - i - 1]; return s[0 .. $ - n]; } void main() { immutable A = [90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5]; foreach (immutable level; 0 .. A.length) forwardDifference(A.dup, level).writeln; }
Short Functional Version
Same output:
void main() { import std.stdio, std.range; auto D = [90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5]; writefln("%(%s\n%)", recurrence!q{ (a[n - 1][0 .. $ - 1] = a[n - 1][1 .. $] - a[n - 1][0 .. $ - 1])[0 .. $] }(D) .take(D.length)); }
Dart
List forwardDifference(List _list) { for (int i = _list.length - 1; i > 0; i--) { _list[i] = _list[i] - _list[i - 1]; } _list.removeRange(0, 1); return _list; } void mainAlgorithms() { List _intList = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73]; for (int i = _intList.length - 1; i >= 0; i--) { List _list = forwardDifference(_intList); print(_list); } }
{{out}}
Restarted application in 1,143ms.
flutter: [-43, 11, -29, -7, 10, 23, -50, 50, 18]
flutter: [54, -40, 22, 17, 13, -73, 100, -32]
flutter: [-94, 62, -5, -4, -86, 173, -132]
flutter: [156, -67, 1, -82, 259, -305]
flutter: [-223, 68, -83, 341, -564]
flutter: [291, -151, 424, -905]
flutter: [-442, 575, -1329]
flutter: [1017, -1904]
flutter: [-2921]
flutter: []
E
pragma.enable("accumulator")
/** Single step. */
def forwardDifference(seq :List) {
return accum [] for i in 0..(seq.size() - 2) {
_.with(seq[i + 1] - seq[i])
}
}
/** Iterative implementation of the goal. */
def nthForwardDifference1(var seq :List, n :(int >= 0)) {
for _ in 1..n { seq := forwardDifference(seq) }
return seq
}
/** Imperative implementation of the goal. */
def nthForwardDifference2(seq :List, n :(int >= 0)) {
def buf := seq.diverge()
def finalSize := seq.size() - n
for lim in (finalSize..!seq.size()).descending() {
for i in 0..!lim {
buf[i] := buf[i + 1] - buf[i]
}
}
return buf.run(0, finalSize)
}
? def sampleData := [90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
> for n in 0..10 {
> def r1 := nthForwardDifference1(sampleData, n)
> require(r1 == nthForwardDifference2(sampleData, n))
> println(r1)
> }
EchoLisp
Using the built-in function '''iterate''' which, given a function f and n, returns the function f°f°f....°f .
(define (Δ-1 list) (for/list ([x (cdr list)] [y list]) (- x y))) (define (Δ-n n) (iterate Δ-1 n)) ((Δ-n 9) '(90 47 58 29 22 32 55 5 55 73)) → (-2921)
Elixir
defmodule Diff do def forward(list,i\\1) do forward(list,[],i) end def forward([_],diffs,1), do: IO.inspect diffs def forward([_],diffs,i), do: forward(diffs,[],i-1) def forward([val1,val2|vals],diffs,i) do forward([val2|vals],diffs++[val2-val1],i) end end Enum.each(1..9, fn i -> Diff.forward([90, 47, 58, 29, 22, 32, 55, 5, 55, 73],i) end)
{{out}}
[-43, 11, -29, -7, 10, 23, -50, 50, 18]
[54, -40, 22, 17, 13, -73, 100, -32]
[-94, 62, -5, -4, -86, 173, -132]
[156, -67, 1, -82, 259, -305]
[-223, 68, -83, 341, -564]
[291, -151, 424, -905]
[-442, 575, -1329]
[1017, -1904]
[-2921]
Erlang
-module(forward_difference). -export([difference/1, difference/2]). -export([task/0]). -define(TEST_DATA,[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]). difference([X|Xs]) -> {Result,_} = lists:mapfoldl(fun (N_2,N_1) -> {N_2 - N_1, N_2} end, X, Xs), Result. difference([],_) -> []; difference(List,0) -> List; difference(List,Order) -> difference(difference(List),Order-1). task() -> io:format("Initial: ~p~n",[?TEST_DATA]), [io:format("~3b: ~p~n",[N,difference(?TEST_DATA,N)]) || N <- lists:seq(0,length(?TEST_DATA))], ok.
{{out}}
80> forward_difference:task().
Initial: [90,47,58,29,22,32,55,5,55,73]
0: [90,47,58,29,22,32,55,5,55,73]
1: [-43,11,-29,-7,10,23,-50,50,18]
2: [54,-40,22,17,13,-73,100,-32]
3: [-94,62,-5,-4,-86,173,-132]
4: [156,-67,1,-82,259,-305]
5: [-223,68,-83,341,-564]
6: [291,-151,424,-905]
7: [-442,575,-1329]
8: [1017,-1904]
9: [-2921]
10: []
ok
Factor
USING: kernel math math.vectors sequences ;
IN: rosetacode
: 1-order ( seq -- seq' )
[ rest-slice ] keep v- ;
: n-order ( seq n -- seq' )
dup 0 <=
[ drop ] [ [ 1-order ] times ] if ;
( scratchpad ) { 90.5 47 58 29 22 32 55 5 55 73.5 } 4 n-order . { 156.5 -67 1 -82 259 -304.5 }
Forth
: forward-difference
dup 0
?do
swap rot over i 1+ - 0
?do dup i cells + dup cell+ @ over @ - swap ! loop
swap rot
loop -
;
create a
90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 ,
: test a 10 9 forward-difference bounds ?do i ? loop ;
test
Fortran
{{works with|Fortran|90 and later}}
MODULE DIFFERENCE
IMPLICIT NONE
CONTAINS
SUBROUTINE Fdiff(a, n)
INTEGER, INTENT(IN) :: a(:), n
INTEGER :: b(SIZE(a))
INTEGER :: i, j, arraysize
b = a
arraysize = SIZE(b)
DO i = arraysize-1, arraysize-n, -1
DO j = 1, i
b(j) = b(j+1) - b(j)
END DO
END DO
WRITE (*,*) b(1:arraysize-n)
END SUBROUTINE Fdiff
END MODULE DIFFERENCE
PROGRAM TEST
USE DIFFERENCE
IMPLICIT NONE
INTEGER :: array(10) = (/ 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 /)
INTEGER :: i
DO i = 1, 9
CALL Fdiff(array, i)
END DO
END PROGRAM TEST
{{out}}
-43 11 -29 -7 10 23 -50 50 18
54 -40 22 17 13 -73 100 -32
-94 62 -5 -4 -86 173 -132
156 -67 1 -82 259 -305
-223 68 -83 341 -564
291 -151 424 -905
-442 575 -1329
1017 -1904
-2921
=={{header|F_Sharp|F#}}== Straightforward recursive solution
let rec ForwardDifference input n = match n with | _ when input = [] || n < 0 -> [] // If there's no more input, just return an empty list | 0 -> input // If n is zero, we're done - return the input | _ -> ForwardDifference // otherwise, recursively difference.. (input.Tail // All but the first element |> Seq.zip input // tupled with itself |> Seq.map (fun (a, b) -> b-a) // Subtract the i'th element from the (i+1)'th |> Seq.toList) (n-1) // Make into a list and do an n-1 difference on it
Go
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)-ord] }
{{out}}
[90 47 58 29 22 32 55 5 55 73]
[-2921]
Haskell
forwardDifference xs = zipWith (-) (tail xs) xs nthForwardDifference xs n = iterate forwardDifference xs !! n > take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73]) [[90,47,58,29,22,32,55,5,55,73], [-43,11,-29,-7,10,23,-50,50,18], [54,-40,22,17,13,-73,100,-32], [-94,62,-5,-4,-86,173,-132], [156,-67,1,-82,259,-305], [-223,68,-83,341,-564], [291,-151,424,-905], [-442,575,-1329], [1017,-1904], [-2921]]
HicEst
REAL :: n=10, list(n)
list = ( 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 )
WRITE(Format='i1, (i6)') 0, list
DO i = 1, n-1
ALIAS(list,1, diff,n-i) ! rename list(1 ... n-i) with diff
diff = list($+1) - diff ! $ is the running left hand array index
WRITE(Format='i1, (i6)') i, diff
ENDDO
END
{{out}}
0 90 47 58 29 22 32 55 5 55 73
1 -43 11 -29 -7 10 23 -50 50 18
2 54 -40 22 17 13 -73 100 -32
3 -94 62 -5 -4 -86 173 -132
4 156 -67 1 -82 259 -305
5 -223 68 -83 341 -564
6 291 -151 424 -905
7 -442 575 -1329
8 1017 -1904
9 -2921
=={{header|Icon}} and {{header|Unicon}}==
procedure main(A) # Compute all forward difference orders for argument list
every order := 1 to (*A-1) do showList(order, fdiff(A, order))
end
procedure fdiff(A, order)
every 1 to order do {
every put(B := [], A[i := 2 to *A] - A[i-1])
A := B
}
return A
end
procedure showList(order, L)
writes(right(order,3),": ")
every writes(!L," ")
write()
end
{{out|A sample run}}
->fdiff 3 1 4 1 5 9 2 6 3
1: -2 3 -3 4 4 -7 4 -3
2: 5 -6 7 0 -11 11 -7
3: -11 13 -7 -11 22 -18
4: 24 -20 -4 33 -40
5: -44 16 37 -73
6: 60 21 -110
7: -39 -131
8: -92
->
IDL
Standard IDL library function TS_diff(X,k,[/double]):
print,(x = randomu(seed,8)*100)
15.1473 58.0953 82.7465 16.8637 97.7182 59.7856 17.7699 74.9154
print,ts_diff(x,1)
-42.9479 -24.6513 65.8828 -80.8545 37.9326 42.0157 -57.1455 0.000000
print,ts_diff(x,2)
-18.2967 -90.5341 146.737 -118.787 -4.08316 99.1613 0.000000 0.000000
print,ts_diff(x,3)
72.2374 -237.271 265.524 -114.704 -103.244 0.000000 0.000000 0.000000
J
Of the many ways to code this in J, a particularly concise solution is:
fd=: 2&(-~/\)
Alternatively, to reduce the number of J primitives, use:
fd=: }. - }: ^:
(which is also elegant, because the open-ended power conjunction reads like "to the power of anything").
For example:
list=: 90 47 58 29 22 32 55 5 55 73 NB. Some numbers
1 fd list
_43 11 _29 _7 10 23 _50 50 18
2 fd list
54 _40 22 17 13 _73 100 _32
J is array oriented, so you can even ask for more than one forward difference at a time (i.e. N can be a list, instead of a single number):
1 2 3 fd list NB. First, second, and third forward differences (simultaneously)
43 _11 29 7 _10 _23 50 _50 _18
54 _40 22 17 13 _73 100 _32 0
94 _62 5 4 86 _173 132 0 0
a: fd list NB. All forward differences
90 47 58 29 22 32 55 5 55 73
43 _11 29 7 _10 _23 50 _50 _18 0
54 _40 22 17 13 _73 100 _32 0 0
94 _62 5 4 86 _173 132 0 0 0
156 _67 1 _82 259 _305 0 0 0 0
223 _68 83 _341 564 0 0 0 0 0
291 _151 424 _905 0 0 0 0 0 0
442 _575 1329 0 0 0 0 0 0 0
1017 _1904 0 0 0 0 0 0 0 0
2921 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
Java
{{works with|Java|1.5+}}
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); System.out.println(Arrays.toString(dif(a, 10))); //let's test System.out.println(Arrays.toString(dif(a, 11))); System.out.println(Arrays.toString(dif(a, -1))); System.out.println(Arrays.toString(dif(a, 0))); } public static double[] dif(double[] a, int n) { if (n < 0) return null; // if the programmer was dumb for (int i = 0; i < n && a.length > 0; i++) { double[] b = new double[a.length - 1]; for (int j = 0; j < b.length; j++){ b[j] = a[j+1] - a[j]; } a = b; //"recurse" } return a; } }
{{out}} [-43.0, 11.0, -29.0, -7.0, 10.0, 23.0, -50.0, 50.0, 18.0] [54.0, -40.0, 22.0, 17.0, 13.0, -73.0, 100.0, -32.0] [-2921.0] [] [] null [90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0]
JavaScript
ES6
(() => { 'use strict'; // forwardDifference :: [Int] -> [Int] const forwardDifference = (n, xs) => { const fd = xs => zipWith((a, b) => a - b, tail(xs), xs); return until( m => m.index < 1, m => ({ index: m.index - 1, list: fd(m.list) }), { index: n, list: xs } ) .list; }; // GENERIC FUNCTIONS --------------------------------------- // zipWith :: (a -> b -> c) -> [a] -> [b] -> [c] const zipWith = (f, xs, ys) => { const ny = ys.length; return (xs.length <= ny ? xs : xs.slice(0, ny)) .map((x, i) => f(x, ys[i])); }; // until :: (a -> Bool) -> (a -> a) -> a -> a const until = (p, f, x) => { const go = x => p(x) ? x : go(f(x)); return go(x); }; // tail :: [a] -> [a] const tail = xs => xs.length ? xs.slice(1) : undefined; // TEST ---------------------------------------------------- // range :: Int -> Int -> [Int] const range = (m, n) => Array.from({ length: Math.floor(n - m) + 1 }, (_, i) => m + i); // show :: a -> String const show = x => JSON.stringify(x); // Sample const test = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73]; return range(1, 9) .map(x => `${x} ${show(forwardDifference(x, test))}`) .join('\n'); })();
{{Out}}
1 [-43,11,-29,-7,10,23,-50,50,18]
2 [54,-40,22,17,13,-73,100,-32]
3 [-94,62,-5,-4,-86,173,-132]
4 [156,-67,1,-82,259,-305]
5 [-223,68,-83,341,-564]
6 [291,-151,424,-905]
7 [-442,575,-1329]
8 [1017,-1904]
9 [-2921]
jq
{{works with|jq|1.4}}
# If n is a non-negative number and if input is
# a (possibly empty) array of numbers,
# emit an array, even if the input list is too short:
def ndiff(n):
if n==0 then .
elif n == 1 then . as $in | [range(1;length) | $in[.] - $in[.-1]]
else ndiff(1) | ndiff(n-1)
end;
'''Example''':
def s: [90, 47, 58, 29, 22, 32, 55, 5, 55, 73];
range(0;12) as $i | (s|ndiff($i))
{{out}}
$ jq -c -n -f forward-difference.jq [90,47,58,29,22,32,55,5,55,73] [-43,11,-29,-7,10,23,-50,50,18] [54,-40,22,17,13,-73,100,-32] [-94,62,-5,-4,-86,173,-132] [156,-67,1,-82,259,-305] [-223,68,-83,341,-564] [291,-151,424,-905] [-442,575,-1329] [1017,-1904] [-2921] [] []
Julia
{{works with|Julia|0.6}}
Using the built-in diff
function, which returns the 1st forward difference:
ndiff(A::Array, n::Integer) = n < 1 ? A : diff(ndiff(A, n-1)) s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] println.(collect(ndiff(s, i) for i in 0:9))
{{out}}
[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
[-43, 11, -29, -7, 10, 23, -50, 50, 18]
[54, -40, 22, 17, 13, -73, 100, -32]
[-94, 62, -5, -4, -86, 173, -132]
[156, -67, 1, -82, 259, -305]
[-223, 68, -83, 341, -564]
[291, -151, 424, -905]
[-442, 575, -1329]
[1017, -1904]
[-2921]
K4
fd:1_-':
To compute the ''n''th forward difference, call as:
In order to obtain all intermediate results, call as:
```k4>n fd\</lang
{{out|Examples}}
```txt
fd 1 2 4 7 11 16
1 2 3 4 5
2 fd/1 2 4 7 11 16
1 1 1 1
3 fd\1 2 4 7 11 16
(1 2 4 7 11 16;1 2 3 4 5;1 1 1 1;0 0 0)
Kotlin
// version 1.1.2 fun forwardDifference(ia: IntArray, order: Int): IntArray { if (order < 0) throw IllegalArgumentException("Order must be non-negative") if (order == 0) return ia val size = ia.size if (size == 0) return ia // same empty array if (order >= size) return intArrayOf() // new empty array var old = ia var new = old var count = order while (count-- >= 1) { new = IntArray(old.size - 1) for (i in 0 until new.size) new[i] = old[i + 1] - old[i] old = new } return new } fun printArray(ia: IntArray) { print("[") for (i in 0 until ia.size) { print("%5d".format(ia[i])) if (i < ia .size - 1) print(", ") } println("]") } fun main(args: Array<String>) { val ia = intArrayOf(90, 47, 58, 29, 22, 32, 55, 5, 55, 73) for (order in 0..ia.size) { val fd = forwardDifference(ia, order) print("%2d".format(order) + ": ") printArray(fd) } }
{{out}}
0: [ 90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
1: [ -43, 11, -29, -7, 10, 23, -50, 50, 18]
2: [ 54, -40, 22, 17, 13, -73, 100, -32]
3: [ -94, 62, -5, -4, -86, 173, -132]
4: [ 156, -67, 1, -82, 259, -305]
5: [ -223, 68, -83, 341, -564]
6: [ 291, -151, 424, -905]
7: [ -442, 575, -1329]
8: [ 1017, -1904]
9: [-2921]
10: []
Lasso
#!/usr/bin/lasso9
define forwardDiff(values, order::integer=1) => {
!#order ? return #values->asArray
local(result = array)
iterate(#values) => {
loop_count < #values->size ?
#result->insert(#values->get(loop_count+1) - #values->get(loop_count))
}
#order > 1 ? #result = forwardDiff(#result, #order-1)
return #result
}
local(data = (:90, 47, 58, 29, 22, 32, 55, 5, 55, 73))
with x in generateSeries(0, #data->size-1)
do stdoutnl(#x + ': ' + forwardDiff(#data, #x))
{{out}}
0: array(90, 47, 58, 29, 22, 32, 55, 5, 55, 73)
1: array(-43, 11, -29, -7, 10, 23, -50, 50, 18)
2: array(54, -40, 22, 17, 13, -73, 100, -32)
3: array(-94, 62, -5, -4, -86, 173, -132)
4: array(156, -67, 1, -82, 259, -305)
5: array(-223, 68, -83, 341, -564)
6: array(291, -151, 424, -905)
7: array(-442, 575, -1329)
8: array(1017, -1904)
9: array(-2921)
Logo
to fwd.diff :l
if empty? :l [output []]
if empty? bf :l [output []]
output fput (first bf :l)-(first :l) fwd.diff bf :l
end
to nth.fwd.diff :n :l
if :n = 0 [output :l]
output nth.fwd.diff :n-1 fwd.diff :l
end
show nth.fwd.diff 9 [90 47 58 29 22 32 55 5 55 73]
[-2921]
Lua
function dif(a, b, ...) if(b) then return b-a, dif(b, ...) end end function dift(t) return {dif(unpack(t))} end print(unpack(dift{1,3,6,10,15}))
M2000 Interpreter
Function Diff(a()) get an array by value (a shallow copy)
Form 80, 40
Module Forward_difference {
Print $(0,6) ' 6 characters column
Dim a(), b()
a()=(90,47,58,29,22,32,55,5,55,73)
Function Diff(a()) {
for i=0 to len(a())-2: a(i)=a(i+1)-a(i):Next i
Dim a(len(a())-1) ' redim one less
=a()
}
Print "Original:","",a()
b()=a() ' copy a() to b()
k=1
While len(b())>1 {
b()=Diff(b()) ' copy returned array to b()
Print "Difference ";k;":",b()
k++
}
}
Forward_difference
{{out}}
Original: 90 47 58 29 22 32 55 5 55 73 Difference 1: -43 11 -29 -7 10 23 -50 50 18 Difference 2: 54 -40 22 17 13 -73 100 -32 Difference 3: -94 62 -5 -4 -86 173 -132 Difference 4: 156 -67 1 -82 259 -305 Difference 5: -223 68 -83 341 -564 Difference 6: 291 -151 424 -905 Difference 7: -442 575 -1329 Difference 8: 1017 -1904 Difference 9: -2921=={{header|Mathematica}} / {{header|Wolfram Language}}== Built-in function: ```Mathematica i={3,5,12,1,6,19,6,2,4,9}; Differences[i] ``` {{out|gives back}} ```Mathematica {2, 7, -11, 5, 13, -13, -4, 2, 5} ``` The nth difference can be done as follows: ```Mathematica i={3,5,12,1,6,19,6,2,4,9}; Differences[i,n] ``` =={{header|MATLAB}} / {{header|Octave}}== This is a built-in function. X is the list of numbers, n is the order of the forward difference. ```MATLAB Y = diff(X,n); ``` {{out}} 1st order forward difference. ```txt diff([1 2 3 4 5]) ans = 1 1 1 1 ``` ## Maxima ```maxima ldiff(u, n) := block([m: length(u)], for j thru n do u: makelist(u[i + 1] - u[i], i, 1, m - j), u); ``` ## NetRexx ```NetRexx /* NetRexx************************************************************* * Forward differences * 18.08.2012 Walter Pachl derived from Rexx **********************************************************************/ Loop n=-1 To 11 differences('90 47 58 29 22 32 55 5 55 73',n) End method differences(a,n) public static --arr=Rexx[11] -- array must be declared (zero based) arr='' -- alternative: indexed string m=a.words Select When n<0 Then Say 'n is negative:' n '<' 0 When n>m Then Say 'n is too large:' n '>' m Otherwise Do Loop i=1 To m arr[i]=a.word(i) End Loop i = 1 to n t = arr[i] Loop j = i+1 to m u = arr[j] arr[j] = arr[j]-t t = u end end ol='' Loop i=n+1 to m ol=ol arr[i] End Say n ol End End ``` Output is the same as for Rexx ## Nial Define forward difference for order 1 ```nial fd is - [rest, front] ``` {{out}} forward difference of 4th order ```nial b := 90 47 58 29 22 32 55 5 55 73 4 fold fd b = 156 -67 1 -82 259 -305 ``` ## Nim ```nim proc dif(s): seq[int] = result = newSeq[int](s.len-1) for i, x in s[1..s.high]: result[i] = x - s[i] proc difn(s, n): seq[int] = if n > 0: difn(dif(s), n-1) else: s const s = @[90, 47, 58, 29, 22, 32, 55, 5, 55, 73] echo difn(s, 0) echo difn(s, 1) echo difn(s, 2) ``` {{out}} ```txt @[90, 47, 58, 29, 22, 32, 55, 5, 55, 73] @[-43, 11, -29, -7, 10, 23, -50, 50, 18] @[54, -40, 22, 17, 13, -73, 100, -32] ``` ## Objeck {{trans|Java}} ```objeck bundle Default { class Test { function : Main(args : String[]) ~ Nil { a := [90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0]; Print(Diff(a, 1)); Print(Diff(a, 2)); Print(Diff(a, 9)); } function : Print(a : Float[]) ~ Nil { if(a <> Nil) { '['->Print(); each(i : a) { a[i]->Print(); ','->Print(); }; ']'->PrintLine(); }; } function : Diff(a : Float[], n : Int) ~ Float[] { if (n < 0) { return Nil; }; for(i := 0; i < n & a->Size() > 0; i += 1;) { b := Float->New[a->Size() - 1]; for(j := 0; j < b->Size(); j += 1;){ b[j] := a[j+1] - a[j]; }; a := b; }; return a; } } } ``` ## OCaml ```ocaml let rec forward_difference = function a :: (b :: _ as xs) -> b - a :: forward_difference xs | _ -> [] let rec nth_forward_difference n xs = if n = 0 then xs else nth_forward_difference (pred n) (forward_difference xs) ``` {{out}} ```txt # nth_forward_difference 9 [90; 47; 58; 29; 22; 32; 55; 5; 55; 73];; - : int list = [-2921] ``` ## Oforth ```Oforth : forwardDiff(l) l right(l size 1 -) l zipWith(#-) ; : forwardDiffN(n, l) l #[ forwardDiff dup println ] times(n) ; ``` {{out}} ```txt 10 [ 90, 47, 58, 29, 22, 32, 55, 5, 55, 73] forwardDiffN [-43, 11, -29, -7, 10, 23, -50, 50, 18] [54, -40, 22, 17, 13, -73, 100, -32] [-94, 62, -5, -4, -86, 173, -132] [156, -67, 1, -82, 259, -305] [-223, 68, -83, 341, -564] [291, -151, 424, -905] [-442, 575, -1329] [1017, -1904] [-2921] [] ``` ## PARI/GP ```parigp fd(v)=vector(#v-1,i,v[i+1]-v[i]); ``` ## Pascal ```pascal Program ForwardDifferenceDemo(output); procedure fowardDifference(list: array of integer); var b: array of integer; i, newlength: integer; begin newlength := length(list) - 1; if newlength > 0 then begin setlength(b, newlength); for i := low(b) to high(b) do begin b[i] := list[i+1] - list[i]; write (b[i]:6); end; writeln; fowardDifference(b); end; end; var a: array [1..10] of integer = (90, 47, 58, 29, 22, 32, 55, 5, 55, 73); begin fowardDifference(a); end. ``` {{out}} ```txt :> ./ForwardDifference -43 11 -29 -7 10 23 -50 50 18 54 -40 22 17 13 -73 100 -32 -94 62 -5 -4 -86 173 -132 156 -67 1 -82 259 -305 -223 68 -83 341 -564 291 -151 424 -905 -442 575 -1329 1017 -1904 -2921 ``` ## Perl ```perl sub dif { my @s = @_; map { $s[$_+1] - $s[$_] } 0 .. $#s-1 } @a = qw<90 47 58 29 22 32 55 5 55 73>; while (@a) { printf('%6d', $_) for @a = dif @a; print "\n" } ``` {{out}} ```txt -43 11 -29 -7 10 23 -50 50 18 54 -40 22 17 13 -73 100 -32 -94 62 -5 -4 -86 173 -132 156 -67 1 -82 259 -305 -223 68 -83 341 -564 291 -151 424 -905 -442 575 -1329 1017 -1904 -2921 ``` ## Perl 6 {{works with|Rakudo Star|2010-07}}
Here we use signature matching to bind both an entire array and a version missing the head.
The Z- operator is a zip metaoperator with a minus to subtract the two lists pairwise.
It's almost a shame to define difn, since the series and subscript are hardly longer than the call itself would be, and arguably more self-documenting than the name of the function would be.
```perl6
sub dif(@array [$, *@tail]) { @tail Z- @array }
sub difn($array, $n) { ($array, &dif ... *)[$n] }
```
## Phix
```Phix
function fwd_diff_n(sequence s, integer order)
if order>=length(s) then ?9/0 end if
for i=1 to order do
for j=1 to length(s)-1 do
s[j] = s[j+1]-s[j]
end for
s = s[1..-2]
end for
return s
end function
constant s = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}
for i=1 to 9 do
?fwd_diff_n(s,i)
end for
```
{{out}}
```txt
{-43,11,-29,-7,10,23,-50,50,18}
{54,-40,22,17,13,-73,100,-32}
{-94,62,-5,-4,-86,173,-132}
{156,-67,1,-82,259,-305}
{-223,68,-83,341,-564}
{291,-151,424,-905}
{-442,575,-1329}
{1017,-1904}
{-2921}
```
## PHP
```php
rand()->int());
$this->spec(forwardDiff($expected))->shouldEqual(array());
}
function _should_give_diff_of_two_elem_as_single_elem() {
$twoNums = array($this->rand()->int(), $this->rand()->int());
$expected = array($twoNums[1] - $twoNums[0]);
$this->spec(forwardDiff($twoNums))->shouldEqual($expected);
}
function _should_compute_correct_forward_diff_for_longer_arrays() {
$diffInput = array(10, 2, 9, 6, 5);
$expected = array(-8, 7, -3, -1);
$this->spec(forwardDiff($diffInput))->shouldEqual($expected);
}
function _should_apply_more_than_once_if_specified() {
$diffInput = array(4, 6, 9, 3, 4);
$expectedAfter1 = array(2, 3, -6, 1);
$expectedAfter2 = array(1, -9, 7);
$this->spec(forwardDiff($diffInput, 1))->shouldEqual($expectedAfter1);
$this->spec(forwardDiff($diffInput, 2))->shouldEqual($expectedAfter2);
}
function _should_return_array_unaltered_if_no_times() {
$this->spec(forwardDiff($expected = array(1,2,3), 0))->shouldEqual($expected);
}
}
```
## PicoLisp
```PicoLisp
(de fdiff (Lst)
(mapcar - (cdr Lst) Lst) )
(for (L (90 47 58 29 22 32 55 5 55 73) L (fdiff L))
(println L) )
```
{{out}}
```txt
(90 47 58 29 22 32 55 5 55 73)
(-43 11 -29 -7 10 23 -50 50 18)
(54 -40 22 17 13 -73 100 -32)
(-94 62 -5 -4 -86 173 -132)
(156 -67 1 -82 259 -305)
(-223 68 -83 341 -564)
(291 -151 424 -905)
(-442 575 -1329)
(1017 -1904)
(-2921)
```
## PL/I
```PL/I
/* Forward differences. */ /* 23 April 2010 */
differences: procedure options (main);
declare a(10) fixed(10) static initial
(7, 3, 9, 250, 300, 4, 68, 72, 154, 601);
declare (i, j, m, n, t, u) fixed binary;
m = hbound(a,1);
get (n); if n > m then signal error;
put skip edit (a) (F(7));
do i = 1 to n;
t = a(i);
do j = i+1 to m;
u = a(j);
a(j) = a(j) - t;
t = u;
end;
put skip edit (a) (F(7));
end;
put skip edit ((a(i) do i = n+1 to m)) (F(9));
end differences;
```
## Pop11
```pop11
define forward_difference(l);
lvars res = [], prev, el;
if l = [] then
return([]);
endif;
front(l) -> prev;
for el in back(l) do
cons(el - prev, res) -> res;
el -> prev;
endfor;
rev(res);
enddefine;
define nth_difference(l, n);
lvars res = l, i;
for i from 1 to n do
forward_difference(res) -> res;
endfor;
res;
enddefine;
```
## PowerShell
```PowerShell
function Forward-Difference( [UInt64] $n, [Array] $f )
{
$flen = $f.length
if( $flen -gt [Math]::Max( 1, $n ) )
{
0..( $flen - $n - 1 ) | ForEach-Object {
$l=0;
for( $k = 0; $k -le $n; $k++ )
{
$j = 1
for( $i = 1; $i -le $k; $i++ )
{
$j *= ( ( $n - $k + $i ) / $i )
}
$l += $j * ( 1 - 2 * ( ( $n - $k ) % 2 ) ) * $f[ $_ + $k ]
}
$l
}
}
}
Forward-Difference 2 1,2,4,5
```
## PureBasic
```PureBasic
Procedure forward_difference(List a())
If ListSize(a()) <= 1
ClearList(a()): ProcedureReturn
EndIf
Protected NewList b()
CopyList(a(), b())
LastElement(a()): DeleteElement(a())
SelectElement(b(), 1)
ForEach a()
a() - b(): NextElement(b())
Next
EndProcedure
Procedure nth_difference(List a(), List b(), n)
Protected i
CopyList(a(), b())
For i = 1 To n
forward_difference(b())
Next
EndProcedure
Procedure.s display(List a())
Protected output.s
ForEach a()
output + Str(a()) + ","
Next
ProcedureReturn RTrim(output,",")
EndProcedure
DataSection
;list data
Data.i 10 ;element count
Data.i 90, 47, 58, 29, 22, 32, 55, 5, 55, 73
EndDataSection
;create and fill list
Define i
NewList a()
Read.i i
While i > 0
AddElement(a()): Read.i a(): i - 1
Wend
If OpenConsole()
NewList b()
For i = 1 To 10
nth_difference(a(), b(), i)
PrintN(Str(i) + " [" + display(b()) + "]")
Next
Print(#CRLF$ + #CRLF$ + "Press ENTER to exit"): Input()
CloseConsole()
EndIf
```
{{out}}
```txt
1 [43,-11,29,7,-10,-23,50,-50,-18]
2 [54,-40,22,17,13,-73,100,-32]
3 [94,-62,5,4,86,-173,132]
4 [156,-67,1,-82,259,-305]
5 [223,-68,83,-341,564]
6 [291,-151,424,-905]
7 [442,-575,1329]
8 [1017,-1904]
9 [2921]
10 []
```
## Python
```python>>>
dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])]
>>> # or, dif = lambda s: [x-y for x,y in zip(s[1:],s)]
>>> difn = lambda s, n: difn(dif(s), n-1) if n else s
>>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
>>> difn(s, 0)
[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
>>> difn(s, 1)
[-43, 11, -29, -7, 10, 23, -50, 50, 18]
>>> difn(s, 2)
[54, -40, 22, 17, 13, -73, 100, -32]
>>> from pprint import pprint
>>> pprint( [difn(s, i) for i in xrange(10)] )
[[90, 47, 58, 29, 22, 32, 55, 5, 55, 73],
[-43, 11, -29, -7, 10, 23, -50, 50, 18],
[54, -40, 22, 17, 13, -73, 100, -32],
[-94, 62, -5, -4, -86, 173, -132],
[156, -67, 1, -82, 259, -305],
[-223, 68, -83, 341, -564],
[291, -151, 424, -905],
[-442, 575, -1329],
[1017, -1904],
[-2921]]
```
## R
```R
forwarddif <- function(a, n) {
if ( n == 1 )
a[2:length(a)] - a[1:length(a)-1]
else {
r <- forwarddif(a, 1)
forwarddif(r, n-1)
}
}
fdiff <- function(a, n) {
r <- a
for(i in 1:n) {
r <- r[2:length(r)] - r[1:length(r)-1]
}
r
}
v <- c(90, 47, 58, 29, 22, 32, 55, 5, 55, 73)
print(forwarddif(v, 9))
print(fdiff(v, 9))
```
## Racket
```Racket
#lang racket
(define (forward-difference list)
(for/list ([x (cdr list)] [y list]) (- x y)))
(define (nth-forward-difference n list)
(for/fold ([list list]) ([n n]) (forward-difference list)))
(nth-forward-difference 9 '(90 47 58 29 22 32 55 5 55 73))
;; -> '(-2921)
```
## REXX
### no error checking
The REXX version uses the same (input) numbers (for the default) as the '''Ada''' example.
This version allows a specification of the list of numbers and/or which ''order'' to process.
```rexx
/*REXX program computes the forward difference of a list of numbers. */
numeric digits 100 /*ensure enough accuracy (decimal digs)*/
parse arg e ',' N /*get a list: ε1 ε2 ε3 ε4 ··· , order */
if e=='' then e=90 47 58 29 22 32 55 5 55 73 /*Not specified? Then use the default.*/
#=words(e) /*# is the number of elements in list.*/
/* [↓] assign list numbers to @ array.*/
do i=1 for #; @.i=word(e, i)/1; end /*i*/ /*process each number one at a time. */
/* [↓] process the optional order. */
if N=='' then parse value 0 # # with bot top N /*define the default order range. */
else parse var N bot 1 top /*Not specified? Then use only 1 order*/
say right(# 'numbers:', 44) e /*display the header title and ··· */
say left('', 44)copies('─', length(e)+2) /* " " " fence. */
/* [↓] where da rubber meets da road. */
do o=bot to top; do r=1 for #; !.r=@.r; end /*r*/; $=
do j=1 for o; d=!.j; do k=j+1 to #; parse value !.k !.k-d with d !.k; end /*k*/
end /*j*/
do i=o+1 to #; $=$ !.i/1; end /*i*/
if $=='' then $=' [null]'
say right(o, 7)th(o)'─order forward difference vector =' $
end /*o*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
th: procedure; x=abs(arg(1)); return word('th st nd rd',1+x//10*(x//100%10\==1)*(x//10<4))
```
'''output''' when using the default input:
```txt
10 numbers: 90 47 58 29 22 32 55 5 55 73
──────────────────────────────
0th-order forward difference vector = 90 47 58 29 22 32 55 5 55 73
1st-order forward difference vector = -43 11 -29 -7 10 23 -50 50 18
2nd-order forward difference vector = 54 -40 22 17 13 -73 100 -32
3rd-order forward difference vector = -94 62 -5 -4 -86 173 -132
4th-order forward difference vector = 156 -67 1 -82 259 -305
5th-order forward difference vector = -223 68 -83 341 -564
6th-order forward difference vector = 291 -151 424 -905
7th-order forward difference vector = -442 575 -1329
8th-order forward difference vector = 1017 -1904
9th-order forward difference vector = -2921
10th-order forward difference vector = [null]
```
'''output''' when the '''Tcl''''s input was used: 90.5 47 58 29 22 32 55 5 55 73.5
```txt
10 numbers: 90.5 47 58 29 22 32 55 5 55 73.5
──────────────────────────────────
0th-order forward difference vector = 90.5 47 58 29 22 32 55 5 55 73.5
1st-order forward difference vector = -43.5 11 -29 -7 10 23 -50 50 18.5
2nd-order forward difference vector = 54.5 -40 22 17 13 -73 100 -31.5
3rd-order forward difference vector = -94.5 62 -5 -4 -86 173 -131.5
4th-order forward difference vector = 156.5 -67 1 -82 259 -304.5
5th-order forward difference vector = -223.5 68 -83 341 -563.5
6th-order forward difference vector = 291.5 -151 424 -904.5
7th-order forward difference vector = -442.5 575 -1328.5
8th-order forward difference vector = 1017.5 -1903.5
9th-order forward difference vector = -2921
10th-order forward difference vector = [null]
```
### with error checking
```rexx
/*REXX program computes the forward difference of a list of numbers. */
numeric digits 100 /*ensure enough accuracy (decimal digs)*/
parse arg e ',' N /*get a list: ε1 ε2 ε3 ε4 ··· , order */
if e=='' then e=90 47 58 29 22 32 55 5 55 73 /*Not specified? Then use the default.*/
#=words(e) /*# is the number of elements in list.*/
/* [↓] verify list items are numeric. */
do i=1 for #; _=word(e, i) /*process each number one at a time. */
if \datatype(_, 'N') then call ser _ "isn't a valid number"; @.i=_/1
end /*i*/ /* [↑] removes superfluous stuff. */
/* [↓] process the optional order. */
if N=='' then parse value 0 # # with bot top N /*define the default order range. */
else parse var N bot 1 top /*Not specified? Then use only 1 order*/
if #==0 then call ser "no numbers were specified."
if N<0 then call ser N "(order) can't be negative."
if N># then call ser N "(order) can't be greater than" #
say right(# 'numbers:', 44) e /*display the header (title) and ··· */
say left('', 44)copies('─', length(e)+2) /*display the header fence. */
/* [↓] where da rubber meets da road. */
do o=bot to top; do r=1 for #; !.r=@.r; end /*r*/; $=
do j=1 for o; d=!.j; do k=j+1 to #; parse value !.k !.k-d with d !.k; end /*k*/
end /*j*/
do i=o+1 to #; $=$ !.i/1; end /*i*/
if $=='' then $=' [null]'
say right(o, 7)th(o)'─order forward difference vector =' $
end /*o*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
ser: say; say '***error***'; say arg(1); say; exit 13
th: procedure; x=abs(arg(1)); return word('th st nd rd',1+x//10*(x//100%10\==1)*(x//10<4))
```
'''output''' is the same as the REXX entry above.
### with output alignment
```rexx
/*REXX program computes the forward difference of a list of numbers. */
numeric digits 100 /*ensure enough accuracy (decimal digs)*/
parse arg e ',' N /*get a list: ε1 ε2 ε3 ε4 ··· , order */
if e=='' then e=90 47 58 29 22 32 55 5 55 73 /*Not specified? Then use the default.*/
#=words(e); w=5 /*# is the number of elements in list.*/
/* [↓] verify list items are numeric. */
do i=1 for #; _=word(e, i) /*process each number one at a time. */
if \datatype(_, 'N') then call ser _ "isn't a valid number"; @.i=_/1
w=max(w, length(@.i)) /*use the maximum length of an element.*/
end /*i*/ /* [↑] removes superfluous stuff. */
/* [↓] process the optional order. */
if N=='' then parse value 0 # # with bot top N /*define the default order range. */
else parse var N bot 1 top /*Not specified? Then use only 1 order*/
if #==0 then call ser "no numbers were specified."
if N<0 then call ser N "(order) can't be negative."
if N># then call ser N "(order) can't be greater than" #
_=; do k=1 for #; _=_ right(@.k, w); end /*k*/; _=substr(_, 2)
say right(# 'numbers:', 44) _ /*display the header title and ··· */
say left('', 44)copies('─', w*#+#) /* " " " fence. */
/* [↓] where da rubber meets da road. */
do o=bot to top; do r=1 for #; !.r=@.r; end /*r*/; $=
do j=1 for o; d=!.j; do k=j+1 to #; parse value !.k !.k-d with d !.k
w=max(w, length(!.k))
end /*k*/
end /*j*/
do i=o+1 to #; $=$ right(!.i/1, w); end /*i*/
if $=='' then $=' [null]'
say right(o, 7)th(o)'─order forward difference vector =' $
end /*o*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
ser: say; say '***error***'; say arg(1); say; exit 13
th: procedure; x=abs(arg(1)); return word('th st nd rd',1+x//10*(x//100%10\==1)*(x//10<4))
```
'''output''' when using the default input:
```txt
10 numbers: 90 47 58 29 22 32 55 5 55 73
────────────────────────────────────────────────────────────
0th─order forward difference vector = 90 47 58 29 22 32 55 5 55 73
1st─order forward difference vector = -43 11 -29 -7 10 23 -50 50 18
2nd─order forward difference vector = 54 -40 22 17 13 -73 100 -32
3rd─order forward difference vector = -94 62 -5 -4 -86 173 -132
4th─order forward difference vector = 156 -67 1 -82 259 -305
5th─order forward difference vector = -223 68 -83 341 -564
6th─order forward difference vector = 291 -151 424 -905
7th─order forward difference vector = -442 575 -1329
8th─order forward difference vector = 1017 -1904
9th─order forward difference vector = -2921
10th─order forward difference vector = [null]
```
### Version 2
```rexx
/* REXX ***************************************************************
* Forward differences
* 18.08.2012 Walter Pachl derived from PL/I
**********************************************************************/
Do n=-1 To 11
Call differences '90 47 58 29 22 32 55 5 55 73',n
End
Exit
differences: Procedure
Parse Arg a,n
m=words(a)
Select
When n<0 Then Say 'n is negative:' n '<' 0
When n>m Then Say 'n is too large:' n '>' m
Otherwise Do
Do i=1 By 1 while a<>''
Parse Var a a.i a
End
Do i = 1 to n;
t = a.i;
Do j = i+1 to m;
u = a.j
a.j = a.j-t;
t = u;
end;
end;
ol=''
Do k=n+1 to m
ol=ol a.k
End
Say n ol
End
End
Return
```
{{out}} for Java's input
```txt
n is negative: -1 < 0
0 90 47 58 29 22 32 55 5 55 73
1 -43 11 -29 -7 10 23 -50 50 18
2 54 -40 22 17 13 -73 100 -32
3 -94 62 -5 -4 -86 173 -132
4 156 -67 1 -82 259 -305
5 -223 68 -83 341 -564
6 291 -151 424 -905
7 -442 575 -1329
8 1017 -1904
9 -2921
10
n is too large: 11 > 10
```
## Ring
```ring
# Project : Forward difference
s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
for p = 1 to 9
s = fwddiff(s)
showarray(s)
next
func fwddiff(s)
for j=1 to len(s)-1
s[j] = s[j+1]-s[j]
next
n = len(s)
del(s, n)
return s
func showarray(vect)
see "{"
svect = ""
for n = 1 to len(vect)
svect = svect + vect[n] + ", "
next
svect = left(svect, len(svect) - 2)
see svect
see "}" + nl
```
Output:
```txt
{-43, 11, -29, -7, 10, 23, -50, 50, 18}
{54, -40, 22, 17, 13, -73, 100, -32}
{-94, 62, -5, -4, -86, 173, -132}
{156, -67, 1, -82, 259, -305}
{-223, 68, -83, 341, -564}
{291, -151, 424, -905}
{-442, 575, -1329}
{1017, -1904}
{-2921}
```
## Ruby
This code uses new features from Ruby 1.8.7:
* Enumerable#each_cons is a new method.
* Integer#times, without a block, returns an enumerator.
{{works with|Ruby|1.8.7}}
```ruby
def dif(s)
s.each_cons(2).collect { |x, y| y - x }
end
def difn(s, n)
n.times.inject(s) { |s, | dif(s) }
end
```
{{out|Example usage}}
```ruby
p dif([1, 23, 45, 678]) # => [22, 22, 633]
p difn([1, 23, 45, 678], 2) # => [0, 611]
```
## Scala
```scala
def fdiff(xs: List[Int]) = (xs.tail, xs).zipped.map(_ - _)
def fdiffn(i: Int, xs: List[Int]): List[Int] = if (i == 1) fdiff(xs) else fdiffn(i - 1, fdiff(xs))
```
{{out|Example}}
```scala
val l=List(90,47,58,29,22,32,55,5,55,73)
(1 to 9)foreach(x=>println(fdiffn(x,l)))
```
{{out}}
```txt
List(-43, 11, -29, -7, 10, 23, -50, 50, 18)
List(54, -40, 22, 17, 13, -73, 100, -32)
List(-94, 62, -5, -4, -86, 173, -132)
List(156, -67, 1, -82, 259, -305)
List(-223, 68, -83, 341, -564)
List(291, -151, 424, -905)
List(-442, 575, -1329)
List(1017, -1904)
List(-2921)
```
## Scheme
```scheme
(define (forward-diff lst)
(if (or (null? lst) (null? (cdr lst)))
'()
(cons (- (cadr lst) (car lst))
(forward-diff (cdr lst)))))
(define (nth-forward-diff n xs)
(if (= n 0)
xs
(nth-forward-diff (- n 1)
(forward-diff xs))))
```
{{out}}
```txt
> (nth-forward-diff 9 '(90 47 58 29 22 32 55 5 55 73))
(-2921)
```
## Seed7
```seed7
$ include "seed7_05.s7i";
const func array integer: forwardDifference (in array integer: data) is func
result
var array integer: diffResult is 0 times 0;
local
var integer: index is 0;
begin
for index range 1 to pred(length(data)) do
diffResult &:= -data[index] + data[succ(index)];
end for;
end func;
const proc: main is func
local
var array integer: data is [] (90, 47, 58, 29, 22, 32, 55, 5, 55, 73);
var integer: level is 0;
var integer: number is 0;
var boolean: firstElement is TRUE;
begin
for level range 0 to length(data) do
firstElement := TRUE;
for number range data do
if not firstElement then
write(", ");
end if;
firstElement := FALSE;
write(number);
end for;
writeln;
data := forwardDifference(data);
end for;
end func;
```
{{out}}
```txt
90, 47, 58, 29, 22, 32, 55, 5, 55, 73
-43, 11, -29, -7, 10, 23, -50, 50, 18
54, -40, 22, 17, 13, -73, 100, -32
-94, 62, -5, -4, -86, 173, -132
156, -67, 1, -82, 259, -305
-223, 68, -83, 341, -564
291, -151, 424, -905
-442, 575, -1329
1017, -1904
-2921
```
## SequenceL
Solution that keeps track of intermediate values:
```sequenceL
forwardDifference(x(1), n) := forwardDifferenceHelper(x, n, [x]);
forwardDifferenceHelper(x(1), n, result(2)) :=
let
difference := tail(x) - x[1 ... size(x) - 1];
in
result when n = 0 or size(x) = 1 else
forwardDifferenceHelper(difference, n - 1, result ++ [difference]);
```
If no intermediate values are needed, the following is sufficient:
```sequenceL
forwardDifference(x(1),n) :=
x when n = 0 or size(x) = 1 else
forwardDifference(tail(x) - x[1 ... size(x) - 1], n - 1);
```
## Sidef
```ruby
func dif(arr) {
gather {
for i (0 ..^ arr.end) {
take(arr[i+1] - arr[i])
}
}
}
func difn(n, arr) {
{ arr = dif(arr) } * n
arr
}
say dif([1, 23, 45, 678]) # => [22, 22, 633]
say difn(2, [1, 23, 45, 678]) # => [0, 611]
```
## Slate
```slate
s@(Sequence traits) forwardDifference
[
s allButFirst with: s allButLast collect: #- `er
].
s@(Sequence traits) forwardDifference
"Without creating two intermediate throwaway Sequences."
[
result ::= s allButFirst.
result doWithIndex: [| :nextValue :index | result at: index infect: [| :oldValue | oldValue - (s at: index)].
result
].
s@(Sequence traits) forwardDifference: n
[
(0 below: n) inject: s into: [| :seq :_ | seq forwardDifference]
].
```
{{out|Usage}}
```slate
#data := ##(90 47 58 29 22 32 55 5 55 73).
data keysDo: [| :index | inform: (data forwardDifference: index) printString].
```
## Smalltalk
{{works with|GNU Smalltalk}}
```smalltalk
Array extend [
difference [
^self allButFirst with: self allButLast collect: [ :a :b | a - b ]
]
nthOrderDifference: n [
^(1 to: n) inject: self into: [ :old :unused | old difference ]
]
]
s := #(90 47 58 29 22 32 55 5 55 73)
1 to: s size - 1 do: [ :i |
(s nthOrderDifference: i) printNl ]
```
## SQL
{{works with|SQLite|3.13.0}}
```sql
WITH RECURSIVE
T0 (N, ITEM, LIST, NEW_LIST) AS
(
SELECT 1,
NULL,
'90,47,58,29,22,32,55,5,55,73' || ',',
NULL
UNION ALL
SELECT CASE
WHEN SUBSTR(LIST, INSTR(LIST, ',') + 1, LENGTH(LIST)) = ''
THEN N + 1
ELSE N
END,
CASE
WHEN SUBSTR(LIST, INSTR(LIST, ',') + 1, LENGTH(LIST)) <> ''
THEN SUBSTR(LIST, 1, INSTR(LIST, ',') - 1)
ELSE NULL
END,
CASE
WHEN SUBSTR(LIST, INSTR(LIST, ',') + 1, LENGTH(LIST)) = ''
THEN IFNULL(NEW_LIST || (SUBSTR(LIST, 1, INSTR(LIST, ',') - 1) - ITEM) || ',', '')
ELSE SUBSTR(LIST, INSTR(LIST, ',') + 1, LENGTH(LIST))
END,
CASE
WHEN SUBSTR(LIST, INSTR(LIST, ',') + 1, LENGTH(LIST)) <> ''
THEN IFNULL(NEW_LIST, '') || IFNULL((SUBSTR(LIST, 1, INSTR(LIST, ',') - 1) - ITEM) || ',', '')
ELSE NULL
END
FROM T0
WHERE INSTR(LIST, ',') > 0
)
SELECT N,
TRIM(LIST, ',') LIST
FROM T0
WHERE NEW_LIST IS NULL
AND LIST <> ''
ORDER BY N;
```
## Standard ML
```sml
fun forward_difference xs = ListPair.map op- (tl xs, xs)
fun nth_forward_difference n xs =
if n = 0 then
xs
else
nth_forward_difference (n-1) (forward_difference xs)
```
{{out}}
```txt
- nth_forward_difference 9 [90, 47, 58, 29, 22, 32, 55, 5, 55, 73];
val it = [~2921] : int list
```
## Stata
It's possible to implement differences using row indices. For instance, first forward differences of a variable x can be defined by:
```stata
gen y=x[_n+1]-x[_n]
```
However, it's much more natural to use [http://www.stata.com/help.cgi?tsvarlist time-series varlists]. In order to use them, it's necessary to first set a ''time'' variable, which may be simply an index variable.
```stata
* First create a dataset
clear all
set obs 100
gen i=_n
tsset i
gen x=rnormal()
* Differences
display "Difference order?" _request(k)
gen y=D${k}F${k}.x
```
## Swift
```swift>func forwardsDifference