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This means it might contain formatting issues, incorrect code, conceptual problems, or other severe issues.
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{{task|Date and time}}
;Task: Determine whether a given year is a leap year in the Gregorian calendar.
;See also:
- [[wp:Leap year|Leap year (wiki)]]
360 Assembly
This is a callable subroutine to determine whether or not a given zoned-decimal 4-digit year is a Leap Year. Leap years are "evenly divisible" by 4, except those which end in '00' and are not evenly divisible by 400. The subroutine receives two parameters: (1) a 4-digit year (CCYY) (2) an 8-byte work area The value returned in Register 15 (by convention the "return code") indicates whether the year is a Leap Year: When R15 = zero, the year is a leap year. Otherwise it is not.
LPCK CSECT
USING LPCK,15
STM 0,12,20(13) STORE CALLER REGS
LM 1,2,0(1) R1 -> CCYY, R2 -> DOUBLE-WORD WORK AREA
PACK 0(8,2),0(4,1) PACK CCYY INTO WORK AREA
CVB 0,0(2) CONVERT TO BINARY (R0 = CCYY)
SRDL 0,32 R0|R1 = CCYY
LA 2,100 R2 = 100
DR 0,2 DIVIDE CCYY BY 100: R0 = YY, R1 = CC
LTR 0,0 YY = 0? IF CCYY DIV BY 100, LY IFF DIV BY 400
BZ A YES: R0|R1 = CC; CCYY DIV BY 100, TEST CC
SRDL 0,32 NO: R0|R1 = YY; CCYY NOT DIV BY 100, TEST YY
A LA 2,4 DIVISOR = 4; DIVIDEND = YY, OR DIV BY 100 CC
DR 0,2 DIVIDE BY 4: R0 = REMAINDER, R1 = QUOTIENT
LR 15,0 LOAD REMAINDER: IF 0, THEN LEAP YEAR
LM 0,12,20(13) RESTORE REGS
BR 14
END
Sample invocation from a COBOL program:
WORKING-STORAGE SECTION. 01 FILLER. 05 YEAR-VALUE PIC 9(4). 05 WKAREA PIC X(8).
PROCEDURE DIVISION.
MOVE 1936 TO YEAR-VALUE CALL 'LPCK' USING YEAR-VALUE, WKAREA PERFORM RESULT-DISPLAY MOVE 1900 TO YEAR-VALUE CALL 'LPCK' USING YEAR-VALUE, WKAREA PERFORM RESULT-DISPLAY GOBACK.
RESULT-DISPLAY.
IF RETURN-CODE = ZERO DISPLAY YEAR-VALUE ' IS A LEAP YEAR' ELSE DISPLAY YEAR-VALUE ' IS NOT A LEAP YEAR'.
68000 Assembly
;Example
move.l #2018,d0
bsr leap_year
addi.l #28,d1 ; # days in February 2018
rts
; Leap Year
;
; Input
; d0=year
;
; Output
; d1=1 if leap year, 0 if not leap year
; zero flag clear if leap year, set if not
;
leap_year:
cmpi.l #1752,d0
ble.s not_leap_year
move.l d0,d1
lsr.l #1,d1
bcs.s not_leap_year
lsr.l #1,d1
bcs.s not_leap_year
; If we got here, year is divisible by 4.
move.l d0,d1
divu #100,d1
swap d1
tst.w d1
bne.s is_leap_year
; If we got here, year is divisible by 100.
move.l d0,d1
divu #400,d1
swap d1
tst.w d1
bne.s not_leap_year
is_leap_year:
moveq.l #1,d1
rts
not_leap_year:
moveq.l #0,d1
rts
ActionScript
public function isLeapYear(year:int):Boolean { if (year % 100 == 0) { return (year % 400 == 0); } return (year % 4 == 0); }
Ada
-- Incomplete code, just a sniplet to do the task. Can be used in any package or method.
-- Adjust the type of Year if you use a different one.
function Is_Leap_Year (Year : Integer) return Boolean is
begin
if Year rem 100 = 0 then
return Year rem 400 = 0;
else
return Year rem 4 = 0;
end if;
end Is_Leap_Year;
-- An enhanced, more efficient version:
-- This version only does the 2 bit comparison (rem 4) if false.
-- It then checks rem 16 (a 4 bit comparison), and only if those are not
-- conclusive, calls rem 100, which is the most expensive operation.
-- I failed to be convinced of the accuracy of the algorithm at first,
-- so I rephrased it below.
-- FYI: 400 is evenly divisible by 16 whereas 100,200 and 300 are not. Ergo, the
-- set of integers evenly divisible by 16 and 100 are all evenly divisible by 400.
-- 1. If a year is not divisible by 4 => not a leap year. Skip other checks.
-- 2. If a year is evenly divisible by 16, it is either evenly divisible by 400 or
-- not evenly divisible by 100 => leap year. Skip further checks.
-- 3. If a year evenly divisible by 100 => not a leap year.
-- 4. Otherwise a leap year.
function Is_Leap_Year (Year : Integer) return Boolean is
begin
return (Year rem 4 = 0) and then ((Year rem 16 = 0) or else (Year rem 100 /= 0));
end Is_Leap_Year;
-- To improve speed a bit more, use with
pragma Inline (Is_Leap_Year);
ALGOL 68
{{works with|ALGOL 68|Revision 1 - no extensions to language used}} {{works with|ALGOL 68G|Any - tested with release [http://sourceforge.net/projects/algol68/files/algol68g/algol68g-1.18.0/algol68g-1.18.0-9h.tiny.el5.centos.fc11.i386.rpm/download 1.18.0-9h.tiny]}} {{wont work with|ELLA ALGOL 68|Any (with appropriate job cards) - tested with release [http://sourceforge.net/projects/algol68/files/algol68toc/algol68toc-1.8.8d/algol68toc-1.8-8d.fc9.i386.rpm/download 1.8-8d] - due to extensive use of '''format''ted transput}}
MODE YEAR = INT, MONTH = INT, DAY = INT;
PROC year days = (YEAR year)DAY: # Ignore 1752 CE for the moment #
( month days(year, 2) = 28 | 365 | 366 );
PROC month days = (YEAR year, MONTH month) DAY:
( month | 31,
28 + ABS (year MOD 4 = 0 AND year MOD 100 /= 0 OR year MOD 400 = 0),
31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
PROC is leap year = (YEAR year)BOOL: year days(year)=366;
test:(
[]INT test cases = (1900, 1994, 1996, 1997, 2000);
FOR i TO UPB test cases DO
YEAR year = test cases[i];
printf(($g(0)" is "b("","not ")"a leap year."l$, year, is leap year(year)))
OD
)
{{out}}
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
1997 is not a leap year.
2000 is a leap year.
=={{header|Algol-M}}==
BEGIN
% COMPUTE P MOD Q %
INTEGER FUNCTION MOD(P, Q);
INTEGER P, Q;
BEGIN
MOD := P - Q * (P / Q);
END;
% RETURN NON-ZERO IF Y IS A LEAP YEAR %
INTEGER FUNCTION ISLEAP(Y);
INTEGER Y;
BEGIN
IF MOD(Y,4) <> 0 THEN % QUICK EXIT IN MOST CASES %
ISLEAP := 0
ELSE IF MOD(Y,400) = 0 THEN
ISLEAP := 1
ELSE IF MOD(Y,100) = 0 THEN
ISLEAP := 0
ELSE % NON-CENTURY DIVISIBLE BY 4 %
ISLEAP := 1;
END;
% EXERCISE THE FUNCTION %
INTEGER Y;
WRITE("TEST OF CENTURY YEARS");
FOR Y := 1600 STEP 100 UNTIL 2000 DO
BEGIN
IF ISLEAP(Y) <> 0 THEN
WRITE(Y, " IS A LEAP YEAR")
ELSE
WRITE(Y, " IS NOT A LEAP YEAR");
END;
WRITE("TEST OF CURRENT DECADE");
FOR Y := 2010 STEP 1 UNTIL 2020 DO
BEGIN
IF ISLEAP(Y) <> 0 THEN
WRITE(Y, " IS A LEAP YEAR")
ELSE
WRITE(Y, " IS NOT A LEAP YEAR");
END;
END
{{out}}
TEST OF CENTURY YEARS
1600 IS A LEAP YEAR
1700 IS NOT A LEAP YEAR
1800 IS NOT A LEAP YEAR
1900 IS NOT A LEAP YEAR
2000 IS A LEAP YEAR
TEST OF CURRENT DECADE
2010 IS NOT A LEAP YEAR
2011 IS NOT A LEAP YEAR
2012 IS A LEAP YEAR
2013 IS NOT A LEAP YEAR
2014 IS NOT A LEAP YEAR
2015 IS NOT A LEAP YEAR
2016 IS A LEAP YEAR
2017 IS NOT A LEAP YEAR
2018 IS NOT A LEAP YEAR
2019 IS NOT A LEAP YEAR
2020 IS A LEAP YEAR
ALGOL W
begin
% returns true if year is a leap year, false otherwise %
% assumes year is in the Gregorian Calendar %
logical procedure isLeapYear ( integer value year ) ;
year rem 400 = 0 or ( year rem 4 = 0 and year rem 100 not = 0 );
% some test cases %
for year := 1899, 1900, 1901, 1902, 1903, 1904, 1905, 1999, 2000, 2001, 2002, 2003, 2004 do begin
write( i_w := 1, s_w := 0
, year
, " is "
, if isLeapYear( year ) then "" else "not "
, " a leap year"
)
end for_year
end.
APL
⍝returns 1 if leapyear, 0 otherwise:
∇Z←LEAPYEAR YEAR
Z←(0=4|YEAR)∧(0=400|YEAR)∨~0=100|YEAR
∇
AppleScript
on leap_year(y) return year mod 4 is equal to 0 and (year mod 100 is not equal to 0 or year mod 400 is equal to 0) end leap_year leap_year(1900)
Arc
(= leap? (fn (year)
(if (and (is 0 (mod year 4)) (isnt 0 (mod year 100))) year
(unless (< 0 (+ (mod year 100) (mod year 400))) year))))
Output:
(map [leap? _] '(1900 1904 2000 2019 2020 2100))
;; => '( 1904 2000 2020 )
AutoHotkey
leapyear(year)
{
if (Mod(year, 100) = 0)
return (Mod(year, 400) = 0)
return (Mod(year, 4) = 0)
}
MsgBox, % leapyear(1604)
{{out}}
Returns 1 if year is a leap year
or
IsLeapYear(Year)
{
return !Mod(Year, 4) && Mod(Year, 100) || !Mod(Year, 400)
}
MsgBox % "The year 1604 was " (IsLeapYear(1604) ? "" : "not ") "a leap year"
{{out}}
The year 1600 was a leap year
The year 1601 was not a leap year
The year 1604 was a leap year
AutoIt
; AutoIt Version: 3.3.8.1
$Year = 2012
$sNot = " not"
If IsLeapYear($Year) Then $sNot = ""
ConsoleWrite ($Year & " is" & $sNot & " a leap year." & @LF)
Func IsLeapYear($_year)
Return Not Mod($_year, 4) And (Mod($_year, 100) Or Not Mod($_year, 400))
EndFunc
; == But it exists the standard UDF "Date.au3" with this function: "_IsLeapYear($Year)"
{{out}}
2012 is a leap year.
--[[User:BugFix|BugFix]] ([[User talk:BugFix|talk]]) 16:18, 16 November 2013 (UTC)
AWK
function leapyear( year )
{
if ( year % 100 == 0 )
return ( year % 400 == 0 )
else
return ( year % 4 == 0 )
}
Bash
#!/bin/bash
year=$(date +"%Y")
if (( $year % 4 == 0 ))
then
if (( $year % 400 == 0 ))
then
echo "This is a leap year"
else
if (( $year % 100 == 0 ))
then
echo "This is not a leap year"
else
echo "This is a leap year"
fi
fi
else
echo "This is not a leap year"
fi
BASIC
{{works with|QBasic}}
Note that the year% function is not needed for most modern BASICs.
DECLARE FUNCTION diy% (y AS INTEGER)
DECLARE FUNCTION isLeapYear% (yr AS INTEGER)
DECLARE FUNCTION year% (date AS STRING)
PRINT isLeapYear(year(DATE$))
FUNCTION diy% (y AS INTEGER)
IF y MOD 4 THEN
diy = 365
ELSEIF y MOD 100 THEN
diy = 366
ELSEIF y MOD 400 THEN
diy = 365
ELSE
diy = 366
END IF
END FUNCTION
FUNCTION isLeapYear% (yr AS INTEGER)
isLeapYear = (366 = diy(yr))
END FUNCTION
FUNCTION year% (date AS STRING)
year% = VAL(RIGHT$(date, 4))
END FUNCTION
An old-timey solution:
{{works with|Commodore BASIC}}
10 DEF FNLY(Y)=(Y/4=INT(Y/4))*((Y/100<>INT(Y/100))+(Y/400=INT(Y/400)))
==={{header|IS-BASIC}}===
=
## Sinclair ZX81 BASIC
=
ZX81 BASIC does not support user-defined functions, even the single-expression functions that are provided by many contemporary dialects; so we have to fake it using a subroutine and pass everything in global variables.
```basic
5000 LET L=Y/4=INT (Y/4) AND (Y/100<>INT (Y/100) OR Y/400=INT (Y/400))
5010 RETURN
An example showing how to call it:
10 INPUT Y
20 GOSUB 5000
30 PRINT Y;" IS ";
40 IF NOT L THEN PRINT "NOT ";
50 PRINT "A LEAP YEAR."
60 STOP
=
ZX Spectrum Basic
=
10 DEF FN l(y)=y/4=INT (y/4) AND y/100<>INT (y/100) OR y/400=INT (y/400)
=
BaCon
= From the Ada shortcut calculation
' Leap year
FUNCTION leapyear(NUMBER y) TYPE NUMBER
RETURN IIF(MOD(y, 4) = 0, IIF(MOD(y, 16) = 0, IIF(MOD(y, 100) != 0, TRUE, FALSE), TRUE), FALSE)
END FUNCTION
READ y
WHILE y != 0
PRINT y, ": ", IIF$(leapyear(y), "", "not a "), "leapyear"
READ y
WEND
DATA 1600, 1700, 1800, 1900, 1901, 1996, 2000, 2001, 2004, 0
{{out}}
1600: not a leapyear
1700: leapyear
1800: leapyear
1900: leapyear
1901: not a leapyear
1996: leapyear
2000: not a leapyear
2001: not a leapyear
2004: leapyear
Batch File
@echo off
::The Main Thing...
for %%x in (1900 2046 2012 1600 1800 2031 1952) do (
call :leap %%x
)
echo.
pause
exit/b
::/The Main Thing...
::The Function...
:leap
set year=%1
set /a op1=%year%%%4
set /a op2=%year%%%100
set /a op3=%year%%%400
if not "%op1%"=="0" (goto :no)
if not "%op2%"=="0" (goto :yes)
if not "%op3%"=="0" (goto :no)
:yes
echo.
echo %year% is a leap year.
goto :EOF
:no
echo.
echo %year% is NOT a leap year.
goto :EOF
::/The Function...
{{out}}
1900 is NOT a leap year.
2046 is NOT a leap year.
2012 is a leap year.
1600 is a leap year.
1800 is NOT a leap year.
2031 is NOT a leap year.
1952 is a leap year.
Press any key to continue . . .
BBC BASIC
REPEAT
INPUT "Enter a year: " year%
IF FNleap(year%) THEN
PRINT ;year% " is a leap year"
ELSE
PRINT ;year% " is not a leap year"
ENDIF
UNTIL FALSE
END
DEF FNleap(yr%)
= (yr% MOD 4 = 0) AND ((yr% MOD 400 = 0) OR (yr% MOD 100 <> 0))
Befunge
{{trans|C}}
0"2("*:3-:1-:2-:"^"-v<
v*%"d"\!%4::,,"is".:<|
>\45*:*%!+#v_ "ton"vv<
v"ear."+550<,,,,*84<$#
>"y pael a ">:#,_$:#@^
{{out}}
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
1997 is not a leap year.
2000 is a leap year.
Bracmat
( leap-year
=
. mod$(!arg.100):0
& `(mod$(!arg.400):0) { The backtick skips the remainder of the OR operation,
even if the tested condition fails. }
| mod$(!arg.4):0
)
& 1600 1700 1899 1900 2000 2006 2012:?tests
& whl
' ( !tests:%?test ?tests
& ( leap-year$!test&out$(!test " is a leap year")
| out$(!test " is not a leap year")
)
)
& ;
{{out}}
1600 is a leap year
1700 is not a leap year
1899 is not a leap year
1900 is not a leap year
2000 is a leap year
2006 is not a leap year
2012 is a leap year
C
#include <stdio.h> int is_leap_year(int year) { return (!(year % 4) && year % 100 || !(year % 400)) ? 1 : 0; } int main() { int test_case[] = {1900, 1994, 1996, 1997, 2000}, key, end, year; for (key = 0, end = sizeof(test_case)/sizeof(test_case[0]); key < end; ++key) { year = test_case[key]; printf("%d is %sa leap year.\n", year, (is_leap_year(year) == 1 ? "" : "not ")); } }
{{out}}
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
1997 is not a leap year.
2000 is a leap year.
C++
Uses C++11. Compile with g++ -std=c++11 leap_year.cpp
#include <iostream> bool is_leap_year(int year) { return year % 4 == 0 && (year % 100 != 0 || year % 400 == 0); } int main() { for (auto year : {1900, 1994, 1996, 1997, 2000}) { std::cout << year << (is_leap_year(year) ? " is" : " is not") << " a leap year.\n"; } }
{{out}}
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
1997 is not a leap year.
2000 is a leap year.
C#
using System; class Program { static void Main() { foreach (var year in new[] { 1900, 1994, 1996, DateTime.Now.Year }) { Console.WriteLine("{0} is {1}a leap year.", year, DateTime.IsLeapYear(year) ? string.Empty : "not "); } } }
{{out}}
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
2010 is not a leap year.
Clipper
Function IsLeapYear( nYear )
Return Iif( nYear%100 == 0, (nYear%400 == 0), (nYear%4 == 0) )
Clojure
(defn leap-year? [y] (and (zero? (mod y 4)) (or (pos? (mod y 100)) (zero? (mod y 400)))))
COBOL
IDENTIFICATION DIVISION.
PROGRAM-ID. leap-year.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 examples VALUE "19001994199619972000".
03 year PIC 9(4) OCCURS 5 TIMES
INDEXED BY year-index.
01 remainders.
03 400-rem PIC 9(4).
03 100-rem PIC 9(4).
03 4-rem PIC 9(4).
PROCEDURE DIVISION.
PERFORM VARYING year-index FROM 1 BY 1 UNTIL 5 < year-index
MOVE FUNCTION MOD(year (year-index), 400) TO 400-rem
MOVE FUNCTION MOD(year (year-index), 100) TO 100-rem
MOVE FUNCTION MOD(year (year-index), 4) TO 4-rem
IF 400-rem = 0 OR ((100-rem NOT = 0) AND 4-rem = 0)
DISPLAY year (year-index) " is a leap year."
ELSE
DISPLAY year (year-index) " is not a leap year."
END-IF
END-PERFORM
GOBACK
.
Using Date Intrinsic Functions
program-id. leap-yr.
*> Given a year, where 1601 <= year <= 9999
*> Determine if the year is a leap year
data division.
working-storage section.
1 input-year pic 9999.
1 binary.
2 int-date pic 9(8).
2 cal-mo-day pic 9(4).
procedure division.
display "Enter calendar year (1601 thru 9999): "
with no advancing
accept input-year
if input-year >= 1601 and <= 9999
then
*> if the 60th day of a year is Feb 29
*> then the year is a leap year
compute int-date = function integer-of-day
( input-year * 1000 + 60 )
compute cal-mo-day = function mod (
(function date-of-integer ( int-date )) 10000 )
display "Year " input-year space with no advancing
if cal-mo-day = 229
display "is a leap year"
else
display "is NOT a leap year"
end-if
else
display "Input date is not within range"
end-if
stop run
.
end program leap-yr.
{{out}}
Enter calendar year (1601 thru 9999): 2016
Year 2016 is a leap year
Enter calendar year (1601 thru 9999): 2017
Year 2017 is NOT a leap year
Enter calendar year (1601 thru 9999): 2100
Year 2100 is NOT a leap year
Enter calendar year (1601 thru 9999): 2400
Year 2400 is a leap year
Enter calendar year (1601 thru 9999): 3000
Year 3000 is NOT a leap year
Enter calendar year (1601 thru 9999): 4000
Year 4000 is a leap year
Common Lisp
(defun leap-year-p (year) (destructuring-bind (fh h f) (mapcar #'(lambda (n) (zerop (mod year n))) '(400 100 4)) (or fh (and (not h) f))))
Component Pascal
BlackBox Component Builder
MODULE LeapYear;
IMPORT StdLog, Strings, Args;
PROCEDURE IsLeapYear(year: INTEGER): BOOLEAN;
BEGIN
IF year MOD 4 # 0 THEN
RETURN FALSE
ELSE
IF year MOD 100 = 0 THEN
IF year MOD 400 = 0 THEN RETURN TRUE ELSE RETURN FALSE END
ELSE
RETURN TRUE
END
END
END IsLeapYear;
PROCEDURE Do*;
VAR
p: Args.Params;
year,done,i: INTEGER;
BEGIN
Args.Get(p);
FOR i := 0 TO p.argc - 1 DO
Strings.StringToInt(p.args[i],year,done);
StdLog.Int(year);StdLog.String(":>");StdLog.Bool(IsLeapYear(year));StdLog.Ln
END;
END Do;
END LeapYear.
Execute: ^Q LeapYear.Do 2000 2004 2013~
{{out}}
2000:> $TRUE
2004:> $TRUE
2013:> $FALSE
D
import std.algorithm; bool leapYear(in uint y) pure nothrow { return (y % 4) == 0 && (y % 100 || (y % 400) == 0); } void main() { auto good = [1600, 1660, 1724, 1788, 1848, 1912, 1972, 2032, 2092, 2156, 2220, 2280, 2344, 2348]; auto bad = [1698, 1699, 1700, 1750, 1800, 1810, 1900, 1901, 1973, 2100, 2107, 2200, 2203, 2289]; assert(filter!leapYear(bad ~ good).equal(good)); }
Using the datetime library:
import std.datetime; void main() { assert(yearIsLeapYear(1724)); assert(!yearIsLeapYear(1973)); assert(!Date(1900, 1, 1).isLeapYear); assert(DateTime(2000, 1, 1).isLeapYear); }
Dart
class Leap { bool leapYear(num year) { return (year % 400 == 0) || (( year % 100 != 0) && (year % 4 == 0)); } }
=={{header|Delphi}}/{{header|Pascal}}== Delphi has standard function IsLeapYear in SysUtils unit.
program TestLeapYear;
{$APPTYPE CONSOLE}
uses
SysUtils;
var
Year: Integer;
begin
Write('Enter the year: ');
Readln(Year);
if IsLeapYear(Year) then
Writeln(Year, ' is a Leap year')
else
Writeln(Year, ' is not a Leap year');
Readln;
end.
DWScript
function IsLeapYear(y : Integer) : Boolean;
begin
Result:= (y mod 4 = 0)
and ( ((y mod 100) <> 0)
or ((y mod 400) = 0) );
end;
const good : array [0..13] of Integer =
[1600,1660,1724,1788,1848,1912,1972,2032,2092,2156,2220,2280,2344,2348];
const bad : array [0..13] of Integer =
[1698,1699,1700,1750,1800,1810,1900,1901,1973,2100,2107,2200,2203,2289];
var i : Integer;
PrintLn('Checking leap years');
for i in good do
if not IsLeapYear(i) then PrintLn(i);
PrintLn('Checking non-leap years');
for i in bad do
if IsLeapYear(i) then PrintLn(i);
Dyalect
func isLeap(y) {
if y % 100 == 0 {
y % 400 == 0
} else {
y % 4 == 0
}
}
print(isLeap(1984))
{{out}}
true
Ela
isLeap y | y % 100 == 0 = y % 400 == 0
| else = y % 4 == 0
Elixir
leap_year? = fn(year) -> :calendar.is_leap_year(year) end IO.inspect for y <- 2000..2020, leap_year?.(y), do: y
{{out}}
[2000, 2004, 2008, 2012, 2016, 2020]
Emacs Lisp
{{trans|Scheme}}
(defun leap-year-p (year) (apply (lambda (a b c) (or a (and (not b) c))) (mapcar (lambda (n) (zerop (mod year n))) '(400 100 4))))
Erlang
-module(gregorian). -export([leap/1]). leap( Year ) -> calendar:is_leap_year( Year ).
ERRE
PROGRAM LEAP_YEAR
FUNCTION LEAP(YR%)
LEAP=(YR% MOD 4=0) AND ((YR% MOD 400=0) OR (YR% MOD 100<>0))
END FUNCTION
BEGIN
LOOP
INPUT("Enter a year: ",year%)
EXIT IF YEAR%=0
IF LEAP(year%) THEN
PRINT(year%;" is a leap year")
ELSE
PRINT(year%;" is not a leap year")
END IF
END LOOP
END PROGRAM
Euphoria
function isLeapYear(integer year)
return remainder(year,4)=0 and remainder(year,100)!=0 or remainder(year,400)=0
end function
Excel
Take two cells, say A1 and B1, in B1 type in :
=IF(OR(NOT(MOD(A1,400)),AND(NOT(MOD(A1,4)),MOD(A1,100))),"Leap Year","Not a Leap Year")
{{out}}
1900 Not a Leap Year
1954 Not a Leap Year
1996 Leap Year
2003 Not a Leap Year
2012 Leap Year
=={{header|F_Sharp|F#}}==
let isLeapYear = System.DateTime.IsLeapYear assert isLeapYear 1996 assert isLeapYear 2000 assert not (isLeapYear 2001) assert not (isLeapYear 1900)
Factor
Call ''leap-year?'' word from ''calendars'' vocabulary. For example:
USING: calendar prettyprint ;
2011 leap-year? .
Factor uses proleptic Gregorian calendar.
Forth
: leap-year? ( y -- ? )
dup 400 mod 0= if drop true exit then
dup 100 mod 0= if drop false exit then
4 mod 0= ;
Or more simply (but always computing three "mod"):
: leap-year? dup 4 mod 0= over 16 mod 0= rot 25 mod 0= not or and ;
Fortran
program leap
implicit none
write(*,*) leap_year([1900, 1996, 1997, 2000])
contains
pure elemental function leap_year(y) result(is_leap)
implicit none
logical :: is_leap
integer,intent(in) :: y
is_leap = (mod(y,4)==0 .and. .not. mod(y,100)==0) .or. (mod(y,400)==0)
end function leap_year
end program leap
{{out}}
F T F T
FreeBASIC
' version 23-06-2015
' compile with: fbc -s console
#Ifndef TRUE ' define true and false for older freebasic versions
#Define FALSE 0
#Define TRUE Not FALSE
#EndIf
Function leapyear(Year_ As Integer) As Integer
If (Year_ Mod 4) <> 0 Then Return FALSE
If (Year_ Mod 100) = 0 AndAlso (Year_ Mod 400) <> 0 Then Return FALSE
Return TRUE
End Function
' ------=< MAIN >=------
' year is a FreeBASIC keyword
Dim As Integer Year_
For Year_ = 1800 To 2900 Step 100
Print Year_; IIf(leapyear(Year_), " is a leap year", " is not a leap year")
Next
Print : Print
For Year_ = 2012 To 2031
Print Year_;
If leapyear(Year_) = TRUE Then
Print " = leap",
Else
Print " = no",
End If
If year_ Mod 4 = 3 Then Print ' lf/cr
Next
' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End
{{out}}
1800 is not a leap year
1900 is not a leap year
2000 is a leap year
2100 is not a leap year
2200 is not a leap year
2300 is not a leap year
2400 is a leap year
2500 is not a leap year
2600 is not a leap year
2700 is not a leap year
2800 is a leap year
2900 is not a leap year
2012 = leap 2013 = no 2014 = no 2015 = no
2016 = leap 2017 = no 2018 = no 2019 = no
2020 = leap 2021 = no 2022 = no 2023 = no
2024 = leap 2025 = no 2026 = no 2027 = no
2028 = leap 2029 = no 2030 = no 2031 = no
FutureBasic
include "ConsoleWindow"
// In-line C function to generate random number in range
BeginCFunction
long randomInRange( long min, long max ) {
int i = (arc4random()%(max-min+1))+min;
return (long)i;
}
EndC
toolbox fn randomInRange( long min, long max ) = long
// Leap year test function
local fn LeapYear( year as long ) as Boolean
dim as Boolean result : result = _false
if year mod 400 == 0 then result = _true : exit fn
if year mod 100 == 0 then result = _false : exit fn
if year mod 4 == 0 then result = _true : exit fn
if year mod 4 != 0 then result = _false : exit fn
end fn = result
dim as long i, y, knownLeapYear(10)
// Array of known leap years from 1980 through 2020 for control
knownLeapYear(0) = 1980 : knownLeapYear(1) = 1984 : knownLeapYear(2) = 1988
knownLeapYear(3) = 1992 : knownLeapYear(4) = 1996 : knownLeapYear(5) = 2000
knownLeapYear(6) = 2004 : knownLeapYear(7) = 2008 : knownLeapYear(8) = 2012
knownLeapYear(9) = 2016 : knownLeapYear(10) = 2020
print "Known leap years:"
for i = 0 to 9
if ( fn LeapYear( knownLeapYear(i) ) == _true )
print knownLeapYear(i); " is a leap year."
else
print knownLeapYear(i); " is a not leap year."
end if
next
print
// Random years from 1980 to 2020 to test
print "Check random years:"
for i = 0 to 20
y = fn randomInRange( 1980, 2020 )
if ( fn LeapYear( y ) == _true )
print y; " is a leap year."
else
print y; " is a not leap year."
end if
next
Output (results will vary for random years):
Known leap years:
1980 is a leap year.
1984 is a leap year.
1988 is a leap year.
1992 is a leap year.
1996 is a leap year.
2000 is a leap year.
2004 is a leap year.
2008 is a leap year.
2012 is a leap year.
2016 is a leap year.
Check random years:
1998 is a not leap year.
1987 is a not leap year.
2015 is a not leap year.
1998 is a not leap year.
2020 is a leap year.
2020 is a leap year.
2009 is a not leap year.
2020 is a leap year.
2018 is a not leap year.
2013 is a not leap year.
2003 is a not leap year.
1994 is a not leap year.
1989 is a not leap year.
1999 is a not leap year.
1984 is a leap year.
1980 is a leap year.
1998 is a not leap year.
2008 is a leap year.
1983 is a not leap year.
2007 is a not leap year.
2004 is a leap year.
Gambas
Public Sub Form_Open()
Dim dDate As Date
Dim siYear As Short = InputBox("Enter a year", "Leap year test")
Dim sMessage As String = " is a leap year."
Try dDate = Date(siYear, 02, 29)
If Error Then sMessage = " is not a leap year."
Message(siYear & sMessage)
End
Output:
2016 is a leap year.
GAP
IsLeapYear := function(n)
return (n mod 4 = 0) and ((n mod 100 <> 0) or (n mod 400 = 0));
end;
# alternative using built-in function
IsLeapYear := function(n)
return DaysInYear(n) = 366;
end;
Genie
Dialect conversion from Vala entry.
[indent=4]
/*
Leap year, in Genie
valac leapYear.gs
./leapYear
*/
init
years:array of DateYear = {1900, 1994, 1996, 1997, 2000, 2100}
for year in years
status:string = year.is_leap_year() ? "" : "not "
stdout.printf("%d is %sa leap year.\n", year, status)
{{out}}
prompt$ valac leapYear.gs
prompt$ ./leapYear
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
1997 is not a leap year.
2000 is a leap year.
2100 is not a leap year.
Go
func isLeap(year int) bool { return year%400 == 0 || year%4 == 0 && year%100 != 0 }
Groovy
Solution:
(1900..2012).findAll {new GregorianCalendar().isLeapYear(it)}.each {println it}
{{out}}
1904
1908
1912
1916
1920
1924
1928
1932
1936
1940
1944
1948
1952
1956
1960
1964
1968
1972
1976
1980
1984
1988
1992
1996
2000
2004
2008
2012
```
=={{header|GW-BASIC}}==
{{works with|PC-BASIC|any}}
```qbasic
10 ' Leap year
20 DEF FN ISLEAPYEAR(Y%) = ((Y% MOD 4 = 0) AND (Y% MOD 100 <> 0)) OR (Y% MOD 400 = 0)
95 ' *** Test ***
100 FOR I% = 1 TO 5
110 READ YEAR%
120 PRINT YEAR%; "is ";
130 IF FN ISLEAPYEAR(YEAR%) = 0 THEN PRINT "not "; ELSE PRINT "";
140 PRINT "a leap year."
150 NEXT I%
160 END
200 DATA 1900, 1994, 1996, 1997, 2000
```
{{out}}
```txt
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
1997 is not a leap year.
2000 is a leap year.
```
## Harbour
```visualfoxpro
FUNCTION IsLeapYear( nYear )
RETURN iif( nYear % 100 == 0, nYear % 400 == 0, nYear % 4 == 0 )
```
## Haskell
'''Simple version'''
```haskell
import Data.List
import Control.Monad
import Control.Arrow
leaptext x b | b = show x ++ " is a leap year"
| otherwise = show x ++ " is not a leap year"
isleapsf j | 0==j`mod`100 = 0 == j`mod`400
| otherwise = 0 == j`mod`4
```
'''Algorithmic'''
```haskell
isleap = foldl1 ((&&).not).flip map [400, 100, 4]. ((0==).).mod
```
Example using isleap
```haskell
*Main> mapM_ (putStrLn. (ap leaptext isleap)) [1900,1994,1996,1997,2000]
1900 is not a leap year
1994 is not a leap year
1996 is a leap year
1997 is not a leap year
2000 is a leap year
```
'''TDD version'''
```haskell
import Test.HUnit
isLeapYear::Int->Bool
isLeapYear y
| mod y 400 == 0 = True
| mod y 100 == 0 = False
| mod y 4 == 0 = True
| otherwise = False
tests = TestList[TestCase $ assertEqual "4 is a leap year" True $ isLeapYear 4
,TestCase $ assertEqual "1 is not a leap year" False $ isLeapYear 1
,TestCase $ assertEqual "64 is a leap year" True $ isLeapYear 64
,TestCase $ assertEqual "2000 is a leap year" True $ isLeapYear 2000
,TestCase $ assertEqual "1900 is not a leap year" False $ isLeapYear 1900]
```
## Hy
```clojure
(defn leap? [y]
(and
(= (% y 4) 0)
(or
(!= (% y 100) 0)
(= (% y 400) 0))))
```
=={{header|Icon}} and {{header|Unicon}}==
Gives leap year status for 2000,1900,2012 and any arguments you give
```Icon
procedure main(arglist)
every y := !([2000,1900,2012]|||arglist) do
write("The year ",y," is ", leapyear(y) | "not ","a leap year.")
end
procedure leapyear(year) #: determine if year is leap
if (numeric(year) % 4 = 0 & year % 100 ~= 0) | (numeric(year) % 400 = 0) then return
end
```
## J
```j
isLeap=: 0 -/@:= 4 100 400 |/ ]
```
Example use:
```j
isLeap 1900 1996 1997 2000
0 1 0 1
```
## Java
By default, [http://docs.oracle.com/javase/7/docs/api/index.html?java/util/GregorianCalendar.html java.util.GregorianCalendar] switches from Julian calendar to Gregorian calendar at 15 October 1582.
The code below uses both the GregorianCalendar class
and the algorithm from the wiki.
Both values are printed in the output.
```java
import java.util.GregorianCalendar;
import java.text.MessageFormat;
public class Leapyear{
public static void main(String[] argv){
int[] yrs = {1800,1900,1994,1998,1999,2000,2001,2004,2100};
GregorianCalendar cal = new GregorianCalendar();
for(int year : yrs){
System.err.println(MessageFormat.format("The year {0,number,#} is leaper: {1} / {2}.",
year, cal.isLeapYear(year), isLeapYear(year)));
}
}
public static boolean isLeapYear(int year){
return (year % 100 == 0) ? (year % 400 == 0) : (year % 4 == 0);
}
}
```
{{out}}
```txt
The year 1800 is leaper: false / false.
The year 1900 is leaper: false / false.
The year 1994 is leaper: false / false.
The year 1998 is leaper: false / false.
The year 1999 is leaper: false / false.
The year 2000 is leaper: true / true.
The year 2001 is leaper: false / false.
The year 2004 is leaper: true / true.
The year 2100 is leaper: false / false.
```
{{works with|Java|8}}
```java
import java.time.Year;
public class IsLeap {
public static void main(String[] args) {
System.out.println(Year.isLeap(2004));
}
}
```
## JavaScript
```javascript
var isLeapYear = function (year) { return (year % 100 === 0) ? (year % 400 === 0) : (year % 4 === 0); };
```
Or, by setting the day to the 29th and checking if the day remains
```javascript
// Month values start at 0, so 1 is for February
var isLeapYear = function (year) { return new Date(year, 1, 29).getDate() === 29; };
```
## jq
{{trans|Julia}}
```jq
def leap:
. as $y | ($y%4) == 0 and ($y < 1582 or ($y%400) == 0 or ($y%100) != 0);
```
'''Examples''':
```jq
def assert(value; f):
value as $value
| ($value|f) | if . then empty else error("assertion violation: \($value) => \(.)") end;
((2400, 2012, 2000, 1600, 1500, 1400) | assert(.; leap)),
((2100, 2014, 1900, 1800, 1700, 1499) | assert(.; leap|not))
```
{{out}}
$ jq -n -f Leap_year.jq
## Julia
{{works with|Julia|0.6}}
```julia
isleap(yr::Integer) = yr % 4 == 0 && (yr < 1582 || yr % 400 == 0 || yr % 100 != 0)
@assert all(isleap, [2400, 2012, 2000, 1600, 1500, 1400])
@assert !any(isleap, [2100, 2014, 1900, 1800, 1700, 1499])
```
## K
```K
leapyear:{(+/~x!'4 100 400)!2}
a@&leapyear'a:1900,1994,1996,1997,2000
1996 2000
```
## Kotlin
```kotlin
fun isLeapYear(year: Int) = year % 400 == 0 || (year % 100 != 0 && year % 4 == 0)
```
## Lasso
```Lasso
define isLeapYear(y::integer) => {
#y % 400 == 0 ? return true
#y % 100 == 0 ? return false
#y % 4 == 0 ? return true
return false
}
with test in array(2012,2016,1933,1900,1999,2000) do => {^
isLeapYear(#test)
'\r'
^}
```
{{out}}
```txt
true
true
false
false
false
true
```
## Liberty BASIC
### Simple method
```lb
if leap(1996)then
print "leap"
else
print "ordinary"
end if
wait
function leap(n)
leap=date$("2/29/";n)
end function
```
### Calculated method
```lb
year = 1908
select case
case year mod 400 = 0
leapYear = 1
case year mod 4 = 0 and year mod 100 <> 0
leapYear = 1
case else
leapYear = 0
end select
if leapYear = 1 then
print year;" is a leap year."
else
print year;" is not a leap year."
end if
```
## Lingo
```lingo
on isLeapYear (year)
return date(year, 2, 29).month=2
end
```
## LiveCode
```LiveCode
function isLeapYear year
return (year MOD 4 is 0) AND ((year MOD 400 is 0) OR (year MOD 100 is not 0))
end isLeapYear
command testLeapYear
set itemDelimiter to comma
put "1900,1994,1996,1997,2000" into years
repeat for each item y in years
put y && "is" && isLeapYear(y) && return after tyears
end repeat
put tyears
end testLeapYear
1900 is false
1994 is false
1996 is true
1997 is false
2000 is true
```
## LLVM
```llvm
; This is not strictly LLVM, as it uses the C library function "printf".
; LLVM does not provide a way to print values, so the alternative would be
; to just load the string into memory, and that would be boring.
$"EMPTY_STR" = comdat any
$"NOT_STR" = comdat any
$"IS_A_LEAP_YEAR" = comdat any
@main.test_case = private unnamed_addr constant [5 x i32] [i32 1900, i32 1994, i32 1996, i32 1997, i32 2000], align 16
@"EMPTY_STR" = linkonce_odr unnamed_addr constant [1 x i8] zeroinitializer, comdat, align 1
@"NOT_STR" = linkonce_odr unnamed_addr constant [5 x i8] c"not \00", comdat, align 1
@"IS_A_LEAP_YEAR" = linkonce_odr unnamed_addr constant [22 x i8] c"%d is %sa leap year.\0A\00", comdat, align 1
;--- The declaration for the external C printf function.
declare i32 @printf(i8*, ...)
; Function Attrs: noinline nounwind optnone uwtable
define i32 @is_leap_year(i32) #0 {
%2 = alloca i32, align 4 ;-- allocate a local copy of year
store i32 %0, i32* %2, align 4 ;-- store a copy of year
%3 = load i32, i32* %2, align 4 ;-- load the year
%4 = srem i32 %3, 4 ;-- year % 4
%5 = icmp ne i32 %4, 0 ;-- (year % 4) != 0
br i1 %5, label %c1false, label %c1true
c1true:
%6 = load i32, i32* %2, align 4 ;-- load the year
%7 = srem i32 %6, 100 ;-- year % 100
%8 = icmp ne i32 %7, 0 ;-- (year % 100) != 0
br i1 %8, label %c2true, label %c1false
c1false:
%9 = load i32, i32* %2, align 4 ;-- load the year
%10 = srem i32 %9, 400 ;-- year % 400
%11 = icmp ne i32 %10, 0 ;-- (year % 400) != 0
%12 = xor i1 %11, true
br label %c2true
c2true:
%13 = phi i1 [ true, %c1true ], [ %12, %c1false ]
%14 = zext i1 %13 to i64
%15 = select i1 %13, i32 1, i32 0
ret i32 %15
}
; Function Attrs: noinline nounwind optnone uwtable
define i32 @main() #0 {
%1 = alloca [5 x i32], align 16 ;-- allocate test_case
%2 = alloca i32, align 4 ;-- allocate key
%3 = alloca i32, align 4 ;-- allocate end
%4 = alloca i32, align 4 ;-- allocate year
%5 = bitcast [5 x i32]* %1 to i8*
call void @llvm.memcpy.p0i8.p0i8.i64(i8* %5, i8* bitcast ([5 x i32]* @main.test_case to i8*), i64 20, i32 16, i1 false)
store i32 0, i32* %2, align 4 ;-- store 0 in key
store i32 5, i32* %3, align 4 ;-- store 5 in end
br label %loop
loop:
%6 = load i32, i32* %2, align 4 ;-- load key
%7 = load i32, i32* %3, align 4 ;-- load end
%8 = icmp slt i32 %6, %7 ;-- key < end
br i1 %8, label %loop_body, label %exit
loop_body:
%9 = load i32, i32* %2, align 4 ;-- load key
%10 = sext i32 %9 to i64 ;-- sign extend key
%11 = getelementptr inbounds [5 x i32], [5 x i32]* %1, i64 0, i64 %10
%12 = load i32, i32* %11, align 4 ;-- load test_case[key]
store i32 %12, i32* %4, align 4 ;-- store test_case[key] as year
%13 = load i32, i32* %4, align 4 ;-- load year
%14 = call i32 @is_leap_year(i32 %13) ;-- is_leap_year(year)
%15 = icmp eq i32 %14, 1 ;-- is_leap_year(year) == 1
%16 = zext i1 %15 to i64 ;-- zero extend
%17 = select i1 %15, i8* getelementptr inbounds ([1 x i8], [1 x i8]* @"EMPTY_STR", i32 0, i32 0), i8* getelementptr inbounds ([5 x i8], [5 x i8]* @"NOT_STR", i32 0, i32 0)
%18 = load i32, i32* %4, align 4 ;-- load year
%19 = call i32 (i8*, ...) @printf(i8* getelementptr inbounds ([22 x i8], [22 x i8]* @"IS_A_LEAP_YEAR", i32 0, i32 0), i32 %18, i8* %17)
%20 = load i32, i32* %2, align 4 ;-- load key
%21 = add nsw i32 %20, 1 ;-- increment key
store i32 %21, i32* %2, align 4 ;-- store key
br label %loop
exit:
ret i32 0
}
; Function Attrs: argmemonly nounwind
declare void @llvm.memcpy.p0i8.p0i8.i64(i8* nocapture writeonly, i8* nocapture readonly, i64, i32, i1) #1
attributes #0 = { noinline nounwind optnone uwtable "correctly-rounded-divide-sqrt-fp-math"="false" "disable-tail-calls"="false" "less-precise-fpmad"="false" "no-frame-pointer-elim"="false" "no-infs-fp-math"="false" "no-jump-tables"="false" "no-nans-fp-math"="false" "no-signed-zeros-fp-math"="false" "no-trapping-math"="false" "stack-protector-buffer-size"="8" "target-cpu"="x86-64" "target-features"="+fxsr,+mmx,+sse,+sse2,+x87" "unsafe-fp-math"="false" "use-soft-float"="false" }
attributes #1 = { argmemonly nounwind }
```
{{out}}
```txt
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
1997 is not a leap year.
2000 is a leap year.
```
## Logo
```logo
to multiple? :n :d
output equal? 0 modulo :n :d
end
to leapyear? :y
output ifelse multiple? :y 100 [multiple? :y 400] [multiple? :y 4]
end
```
## Logtalk
```logtalk
leap_year(Year) :-
( mod(Year, 4) =:= 0, mod(Year, 100) =\= 0 ->
true
; mod(Year, 400) =:= 0
).
```
## LOLCODE
```lolcode
BTW Determine if a Gregorian calendar year is leap
HAI 1.3
HOW IZ I Leap YR Year
BOTH SAEM 0 AN MOD OF Year AN 4
O RLY?
YA RLY
BOTH SAEM 0 AN MOD OF Year AN 100
O RLY?
YA RLY
BOTH SAEM 0 AN MOD OF Year AN 400
O RLY?
YA RLY
FOUND YR WIN
NO WAI
FOUND YR FAIL
OIC
NO WAI
FOUND YR WIN
OIC
NO WAI
FOUND YR FAIL
OIC
IF U SAY SO
I HAS A Yearz ITZ A BUKKIT
Yearz HAS A SRS 0 ITZ 1900
Yearz HAS A SRS 1 ITZ 1904
Yearz HAS A SRS 2 ITZ 1994
Yearz HAS A SRS 3 ITZ 1996
Yearz HAS A SRS 4 ITZ 1997
Yearz HAS A SRS 5 ITZ 2000
IM IN YR Loop UPPIN YR Index WILE DIFFRINT Index AN 6
I HAS A Yr ITZ Yearz'Z SRS Index
I HAS A Not
I IZ Leap YR Yr MKAY
O RLY?
YA RLY
Not R ""
NO WAI
Not R " NOT"
OIC
VISIBLE Yr " is" Not " a leap year"
IM OUTTA YR Loop
KTHXBYE
```
{{Out}}
```txt
1900 is NOT a leap year
1904 is a leap year
1994 is NOT a leap year
1996 is a leap year
1997 is NOT a leap year
2000 is a leap year
```
## Lua
```Lua
function isLeapYear(year)
return year%4==0 and (year%100~=0 or year%400==0)
end
```
## Maple
```maple
isLeapYear := proc(year)
if not year mod 4 = 0 or (year mod 100 = 0 and not year mod 400 = 0) then
return false;
else
return true;
end if;
end proc:
```
## Mathematica
Dates are handled by built-in functions in the Wolfram Language
```Mathematica
LeapYearQ[2002]
```
=={{header|MATLAB}} / {{header|Octave}}==
MATLAB, conveniently, provides a function that returns the last day of an arbitrary month of the calendar given the year. Using the fact that February is 29 days long during a leap year, we can write a one-liner that solves this task.
```MATLAB
function TrueFalse = isLeapYear(year)
TrueFalse = (eomday(year,2) == 29);
end
```
### Using Logical and modular functions
```matlab
x = ~mod(YEAR, 4) & (mod(YEAR, 100) | ~mod(YEAR, 400))
```
## Maxima
```maxima
leapyearp(year) := is(mod(year, 4) = 0 and
(mod(year, 100) # 0 or mod(year, 400) = 0))$
```
=={{header|МК-61/52}}==
П0 1 0 0 / {x} x=0 14 ИП0 4
0 0 ПП 18 ИП0 4 ПП 18 / {x}
x=0 24 1 С/П 0 С/П
```
## Mercury
```mercury
:- pred is_leap_year(int::in) is semidet.
is_leap_year(Year) :-
( if Year mod 100 = 0 then Year mod 400 = 0 else Year mod 4 = 0 ).
```
Usage:
```mercury
:- module leap_year.
:- interface.
:- import_module io.
:- pred main(io::di, io::uo) is det.
:- implementation.
:- import_module int, list, string.
main(!IO) :-
Years = [1600, 1700, 1899, 1900, 2000, 2006, 2012],
io.write_list(Years, "", write_year_kind, !IO).
:- pred write_year_kind(int::in, io::di, io::uo) is det.
write_year_kind(Year, !IO) :-
io.format("%d %s a leap year.\n",
[i(Year), s(if is_leap_year(Year) then "is" else "is not" )], !IO).
```
## MiniScript
```MiniScript
isLeapYear = function(year)
return year%4==0 and (year % 100 or not year % 400)
end function
```
## MIPS Assembly
Pass year in a0, returns boolean in v0.
```mips
IsLeap: andi $a1, $a0, 3 #a0 is year to test
bnez $a1 NotLeap
li $a1, 100
div $a0, $a1
mfhi $a1
bnez $a1, Leap
mflo $a1
andi $a1, $a1, 3
bnez $a1, NotLeap
Leap: li $v0, 1
jr $ra
NotLeap:li $v0, 0
jr $ra
```
=={{header|Modula-2}}==
```modula2
MODULE LeapYear;
FROM FormatString IMPORT FormatString;
FROM Terminal IMPORT WriteString,ReadChar;
PROCEDURE IsLeapYear(year : INTEGER) : BOOLEAN;
BEGIN
IF year MOD 100 = 0 THEN
RETURN year MOD 400 = 0;
END;
RETURN year MOD 4 = 0
END IsLeapYear;
PROCEDURE Print(year : INTEGER);
VAR
buf : ARRAY[0..63] OF CHAR;
leap : BOOLEAN;
BEGIN
leap := IsLeapYear(year);
FormatString("Is %i a leap year? %b\n", buf, year, leap);
WriteString(buf)
END Print;
BEGIN
Print(1900);
Print(1994);
Print(1996);
Print(1997);
Print(2000);
ReadChar
END LeapYear.
```
## MUMPS
```MUMPS
ILY(X) ;IS IT A LEAP YEAR?
QUIT ((X#4=0)&(X#100'=0))!((X#100=0)&(X#400=0))
```
Usage:
```txt
USER>W $SELECT($$ILY^ROSETTA(1900):"Yes",1:"No")
No
USER>W $SELECT($$ILY^ROSETTA(2000):"Yes",1:"No")
Yes
USER>W $SELECT($$ILY^ROSETTA(1999):"Yes",1:"No")
No
```
## Neko
Translating from C
```ActionScript
/**
Leap year, in Neko
GregorianCalendar object to determine which years are leap-years.
Note that the Java library indicates that the year '''1500'''
is a leap-year as the Gregorian calendar wasn't established until 1582.
The Java library implements the Julian calendar for dates
prior to the Gregorian cut-over and leap-year rules in the Julian calendar
are different to those for the Gregorian calendar.
```NetRexx
/* NetRexx */
options replace format comments java crossref savelog symbols nobinary
years = '1500 1580 1581 1582 1583 1584 1600 1700 1800 1900 1994 1996 1997 2000 2004 2008 2009 2010 2011 2012 2100 2200 2300 2400 2500 2600'
years['l-a'] = ''
years['n-a'] = ''
years['l-j'] = ''
years['n-j'] = ''
loop y_ = 1 to years.words
year = years.word(y_)
if isLeapyear(year) then years['l-a'] = years['l-a'] year
else years['n-a'] = years['n-a'] year
if GregorianCalendar().isLeapYear(year) then years['l-j'] = years['l-j'] year
else years['n-j'] = years['n-j'] year
end y_
years['l-a'] = years['l-a'].strip
years['n-a'] = years['n-a'].strip
years['l-j'] = years['l-j'].strip
years['n-j'] = years['n-j'].strip
say ' Sample years:' years['all'].changestr(' ', ',')
say ' Leap years (algorithmically):' years['l-a'].changestr(' ', ',')
say ' Leap years (Java library) :' years['l-j'].changestr(' ', ',')
say ' Non-leap years (algorithmically):' years['n-a'].changestr(' ', ',')
say ' Non-leap years (Java library) :' years['n-j'].changestr(' ', ',')
return
-- algorithmically
method isLeapyear(year = int) public constant binary returns boolean
select
when year // 400 = 0 then ly = isTrue
when year // 100 \= 0 & year // 4 = 0 then ly = isTrue
otherwise ly = isFalse
end
return ly
method isTrue public constant binary returns boolean
return 1 == 1
method isFalse public constant binary returns boolean
return \isTrue
```
{{out}}
```txt
Sample years: 1500,1580,1581,1582,1583,1584,1600,1700,1800,1900,1994,1996,1997,2000,2004,2008,2009,2010,2011,2012,2100,2200,2300,2400,2500,2600
Leap years (algorithmically): 1580,1584,1600,1996,2000,2004,2008,2012,2400
Leap years (Java library) : 1500,1580,1584,1600,1996,2000,2004,2008,2012,2400
Non-leap years (algorithmically): 1500,1581,1582,1583,1700,1800,1900,1994,1997,2009,2010,2011,2100,2200,2300,2500,2600
Non-leap years (Java library) : 1581,1582,1583,1700,1800,1900,1994,1997,2009,2010,2011,2100,2200,2300,2500,2600
```
=={{Header|Nim}}==
```nim
import times
let year = 1980
echo isLeapYear(year)
# or
proc isLeapYear2(year): bool =
if year mod 100 == 0:
year mod 400 == 0
else: year mod 4 == 0
echo isLeapYear2(year)
```
{{out}}
```txt
true
true
```
=={{Header|Oberon-2}}==
```oberon2
PROCEDURE IsLeapYear(year: INTEGER): BOOLEAN;
BEGIN
IF year MOD 4 # 0 THEN
RETURN FALSE
ELSE
IF year MOD 100 = 0 THEN
IF year MOD 400 = 0 THEN
RETURN TRUE
ELSE
RETURN FALSE
END
ELSE
RETURN TRUE
END
END
END IsLeapYear;
```
## Objeck
```objeck
bundle Default {
class LeapYear {
function : Main(args : String[]) ~ Nil {
test_case := [1900, 1994, 1996, 1997, 2000];
each(i : test_case) {
test_case[i]->Print();
if(IsLeapYear(test_case[i])) {
" is a leap year."->PrintLine();
}
else {
" is not a leap year."->PrintLine();
};
};
}
function : native : IsLeapYear(year : Int) ~ Bool {
if(year % 4 = 0 & year % 100 <> 0) {
return true;
}
else if(year % 400 = 0) {
return true;
};
return false;
}
}
}
```
## OCaml
```ocaml
let is_leap_year ~year =
if (year mod 100) = 0
then (year mod 400) = 0
else (year mod 4) = 0
```
Using Unix Time functions:
```ocaml
let is_leap_year ~year =
let tm =
Unix.mktime {
(Unix.gmtime (Unix.time())) with
Unix.tm_year = (year - 1900);
tm_mon = 1 (* feb *);
tm_mday = 29
}
in
(tm.Unix.tm_mday = 29)
```
## Oforth
```Oforth
Date.IsLeapYear(2000)
```
## ooRexx
```ooRexx
::routine isLeapYear
use arg year
d = .datetime~new(year, 1, 1)
return d~isLeapYear
```
## OpenEdge/Progress
The DATE function converts month, day, year integers to a date data type and will set the error status if invalid values are passed.
```progress
FUNCTION isLeapYear RETURNS LOGICAL (
i_iyear AS INTEGER
):
DATE( 2, 29, i_iyear ) NO-ERROR.
RETURN NOT ERROR-STATUS:ERROR.
END FUNCTION. /* isLeapYear */
MESSAGE
1900 isLeapYear( 1900 ) SKIP
1994 isLeapYear( 1994 ) SKIP
1996 isLeapYear( 1996 ) SKIP
1997 isLeapYear( 1997 ) SKIP
2000 isLeapYear( 2000 )
VIEW-AS ALERT-BOX.
```
## Oz
```oz
declare
fun {IsLeapYear Year}
case Year mod 100 of 0 then
Year mod 400 == 0
else
Year mod 4 == 0
end
end
in
for Y in [1900 1996 1997 2000] do
if {IsLeapYear Y} then
{System.showInfo Y#" is a leap year."}
else
{System.showInfo Y#" is NOT a leap year."}
end
end
```
{{out}}
```txt
1900 is NOT a leap year.
1996 is a leap year.
1997 is NOT a leap year.
2000 is a leap year.
```
## PARI/GP
```parigp
isLeap(n)={
if(n%400==0, return(1));
if(n%100==0, return(0));
n%4==0
};
```
Alternate version:
```parigp
isLeap(n)=!(n%if(n%100,4,400))
```
{{works with|PARI/GP|2.6.0 and above}}
```parigp
isLeap(n)={
if(n%4,0,
n%100,1,
n%400,0,1
)
};
```
## Pascal
{{works with|Free Pascal}}
```pascal
program LeapYear;
uses
sysutils;//includes isLeapYear
procedure TestYear(y: word);
begin
if IsLeapYear(y) then
writeln(y,' is a leap year')
else
writeln(y,' is NO leap year');
end;
Begin
TestYear(1900);
TestYear(2000);
TestYear(2100);
TestYear(1904);
end.
```
Output:
```txt
1900 is NO leap year
2000 is a leap year
2100 is NO leap year
1904 is a leap year
```
## Perl
```Perl
sub isleap {
my $year = shift;
if ($year % 100 == 0) {
return ($year % 400 == 0);
}
return ($year % 4 == 0);
}
```
Or more concisely:
```Perl
sub isleap { !($_[0] % 100) ? !($_[0] % 400) : !($_[0] % 4) }
```
Alternatively, using functions/methods from CPAN modules:
```Perl
use Date::Manip;
print Date_LeapYear(2000);
use Date::Manip::Base;
my $dmb = new Date::Manip::Base;
print $dmb->leapyear(2000);
use DateTime;
my $date = DateTime->new(year => 2000);
print $date->is_leap_year();
```
## Perl 6
{{works with|Rakudo|2010.07}}
```perl6
say "$year is a {Date.is-leap-year($year) ?? 'leap' !! 'common'} year."
```
In Rakudo 2010.07, Date.is-leap-year is implemented as
```perl6
multi method is-leap-year($y = $!year) {
$y %% 4 and not $y %% 100 or $y %% 400
}
```
## Phix
Available as an auto-include, implemented as:
```Phix
global function is_leap_year(integer y)
return remainder(y,4)=0 and (remainder(y,100)!=0 or remainder(y,400)=0)
end function
```
## PHP
```php
date('L'):
```php
NIL
: (isLeapYear 2008)
-> T
: (isLeapYear 1600)
-> T
: (isLeapYear 1700)
-> NIL
```
## PL/I
```pli
dcl mod builtin;
dcl year fixed bin (31);
do year = 1900, 1996 to 2001;
if mod(year, 4) = 0 &
(mod(year, 100) ^= 0 |
mod(year, 400) = 0) then
put skip edit(year, 'is a leap year') (p'9999b', a);
else
put skip edit(year, 'is not a leap year') (p'9999b', a);
end;
```
{{out}}
```txt
1900 is not a leap year
1996 is a leap year
1997 is not a leap year
1998 is not a leap year
1999 is not a leap year
2000 is a leap year
2001 is not a leap year
```
## PostScript
```postscript
/isleapyear {
dup dup
4 mod 0 eq % needs to be divisible by 4
exch
100 mod 0 ne % but not by 100
and
exch
400 mod 0 eq % or by 400
or
} def
```
## PowerShell
```powershell
$Year = 2016
[System.DateTime]::IsLeapYear( $Year )
```
## Prolog
{{Works with|SWI-Prolog}}
```Prolog
leap_year(L) :-
partition(is_leap_year, L, LIn, LOut),
format('leap years : ~w~n', [LIn]),
format('not leap years : ~w~n', [LOut]).
is_leap_year(Year) :-
R4 is Year mod 4,
R100 is Year mod 100,
R400 is Year mod 400,
( (R4 = 0, R100 \= 0); R400 = 0).
```
{{out}}
```Prolog
?- leap_year([1900,1994,1996,1997,2000 ]).
leap years : [1996,2000]
not leap years : [1900,1994,1997]
L = [1900,1994,1996,1997,2000].
```
There is an handy builtin that simplifies a lot, ending up in a simple query:
```Prolog
?- findall(Y, (between(1990,2030,Y),day_of_the_year(date(Y,12,31),366)), L).
L = [1992, 1996, 2000, 2004, 2008, 2012, 2016, 2020, 2024, 2028].
```
## PureBasic
```PureBasic
Procedure isLeapYear(Year)
If (Year%4=0 And Year%100) Or Year%400=0
ProcedureReturn #True
Else
ProcedureReturn #False
EndIf
EndProcedure
```
## Python
```python
import calendar
calendar.isleap(year)
```
or
```python
def is_leap_year(year):
if year % 100 == 0:
return year % 400 == 0
return year % 4 == 0
```
Asking for forgiveness instead of permission:
```python
import datetime
def is_leap_year(year):
try:
datetime.date(year, 2, 29)
except ValueError:
return False
return True
```
## Q
```q
ly:{((0<>x mod 100) | 0=x mod 400) & 0=x mod 4} / Return 1b if x is a leap year; 0b otherwise
```
## R
```R
isLeapYear <- function(year) {
ifelse(year%%100==0, year%%400==0, year%%4==0)
}
for (y in c(1900, 1994, 1996, 1997, 2000)) {
cat(y, ifelse(isLeapYear(y), "is", "isn't"), "a leap year.\n")
}
```
{{out}}
```txt
1900 isn't a leap year.
1994 isn't a leap year.
1996 is a leap year.
1997 isn't a leap year.
2000 is a leap year.
```
## Racket
```racket
(define (leap-year? y)
(and (zero? (modulo y 4)) (or (positive? (modulo y 100)) (zero? (modulo y 400)))))
```
## Raven
```Raven
define is_leap_year use $year
$year 100 % 0 = if
$year 400 % 0 =
$year 4 % 0 =
```
## REBOL
```rebol
leap-year?: func [
{Returns true if the specified year is a leap year; false otherwise.}
year [date! integer!]
/local div?
][
either date? year [year: year/year] [
if negative? year [throw make error! join [script invalid-arg] year]
]
; The key numbers are 4, 100, and 400, combined as follows:
; 1) If the year is divisible by 4, it’s a leap year.
; 2) But, if the year is also divisible by 100, it’s not a leap year.
; 3) Double but, if the year is also divisible by 400, it is a leap year.
div?: func [n] [zero? year // n]
to logic! any [all [div? 4 not div? 100] div? 400]
]
```
## Retro
```Retro
: isLeapYear? ( y-f )
dup 400 mod 0 = [ drop -1 0 ] [ 1 ] if 0; drop
dup 100 mod 0 = [ drop 0 0 ] [ 1 ] if 0; drop
4 mod 0 = ;
```
This is provided by the standard '''calendar''' library.
## REXX
### local variables
```rexx
leapyear: procedure; parse arg yr
return yr//400==0 | (yr//100\==0 & yr//4==0)
```
===with short-circuit===
The REXX language doesn't support short-circuits, so here is a version that does a short-circuit.
```rexx
leapyear: procedure; parse arg yr
if yr//4\==0 then return 0 /*Not ÷ by 4? Not a leap year.*/
return yr//400==0 | yr//100\==0
```
### no local variables
This version doesn't need a PROCEDURE to hide local variable(s) [because there aren't any local variables],
but it does invoke the '''ARG''' BIF multiple times.
```rexx
leapyear: if arg(1)//4\==0 then return 0
return arg(1)//400==0 | arg(1)//100\==0
```
### handles 2 digit year
This REXX version has the proviso that if the year is exactly two digits,
the current century is assumed (i.e., no ''year'' windowing).
If a year below 100 is to be used, the year should have leading zeroes added (to make it four digits).
```rexx
leapyear: procedure; parse arg y /*year could be: Y, YY, YYY, YYYY*/
if y//4\==0 then return 0 /*Not ÷ by 4? Not a leap year.*/
if length(y)==2 then y=left(date('S'),2)y /*adjust for a 2─digit YY year.*/
return y//100\==0 | y//400==0 /*apply 100 and 400 year rule. */
```
## Ring
```ring
give year
leap = isLeapYear(year)
if leap true see year + " is leap year."
else see year + " is not leap year." ok
Func isLeapYear year
if (year % 400) = 0 return true
but (year % 100) = 0 return false
but (year % 4) = 0 return true
else return false ok
```
## RPG
{{works with|RPGIII|}}
```RPG
C*0N01N02N03Factor1+++OpcdeFactor2+++ResultLenDHHiLoEqComments+++++++
C *ENTRY PLIST
C PARM YEAR 40 input (year)
C PARM ISLEAP 1 output (Y/N)
C*
C MOVE 'N' ISLEAP
C YEAR CABLE1752 DONE not Gregorian
C*
C YEAR DIV 4 RESULT 40
C MVR REMAIN 40
C REMAIN CABNE0 DONE
C*
C* If we got here, year is divisible by 4.
C YEAR DIV 100 RESULT
C MVR REMAIN
C REMAIN CABNE0 LEAPYR
C*
C* If we got here, year is divisible by 100.
C YEAR DIV 400 RESULT
C MVR REMAIN
C REMAIN CABNE0 DONE
C*
C LEAPYR TAG
C MOVE 'Y' ISLEAP
C*
C DONE TAG
C SETON LR
```
## Ruby
```ruby
require 'date'
Date.leap?(year)
```
The leap? method is aliased as gregorian_leap? And yes, there is a julian_leap? method.
## Run BASIC
```runbasic
if date$("02/29/" + mid$(date$("mm/dd/yyyy"),7,4)) then print "leap year" else print "not"
```
## Rust
```rust
fn is_leap(year: i32) -> bool {
let factor = |x| year % x == 0;
factor(4) && (!factor(100) || factor(400))
}
```
=={{header|S-BASIC}}==
Since S-BASIC has no MOD operator or function, we have to supply one.
```basic
rem - compute p mod q
function mod(p, q = integer) = integer
end = p - q * (p/q)
rem - return true (-1) if y is a leap year, otherwise 0
function isleapyear(y = integer) = integer
end = mod(y,4)=0 and mod(y,100)<>0 or mod(y,400)=0
rem - exercise the function
var y = integer
print "Test of century years"
for y = 1600 to 2000 step 100
if isleapyear(y) then
print y;" is a leap year"
else
print y;" is NOT a leap year"
next y
print "Test of current half-decade"
for y = 2015 to 2020
if isleapyear(y) then
print y; " is a leap year"
else
print y; " is NOT a leap year"
next y
end
```
{{out}}
```txt
Test of century years
1600 is a leap year
1700 is NOT a leap year
1800 is NOT a leap year
1900 is NOT a leap year
2000 is a leap year
Test of current half-decade
2015 is NOT a leap year
2016 is a leap year
2017 is NOT a leap year
2018 is NOT a leap year
2019 is NOT a leap year
2020 is a leap year
```
## Scala
===JDK 7 (not recommended)===
By default, [http://docs.oracle.com/javase/7/docs/api/index.html?java/util/GregorianCalendar.html java.util.GregorianCalendar] switches from Julian calendar to Gregorian calendar at 15 October 1582.
```scala
//use Java's calendar class
new java.util.GregorianCalendar().isLeapYear(year)
```
### JDK 8
Using JSR-310 java.time.
```scala
java.time.LocalDate.ofYearDay(year, 1).isLeapYear()
```
### Implementation
For proleptic Gregorian calendar:
```scala
def isLeapYear(year:Int)=if (year%100==0) year%400==0 else year%4==0;
//or use Java's calendar class
def isLeapYear(year:Int):Boolean = {
val c = new java.util.GregorianCalendar
c.setGregorianChange(new java.util.Date(Long.MinValue))
c.isLeapYear(year)
}
```
## Scheme
```scheme
(define (leap-year? n)
(apply (lambda (a b c) (or a (and (not b) c)))
(map (lambda (m) (zero? (remainder n m)))
'(400 100 4))))
```
## Seed7
This function is part of the "time.s7i" library. It returns TRUE if the year is a leap year in the Gregorian calendar.
```seed7
const func boolean: isLeapYear (in integer: year) is
return (year rem 4 = 0 and year rem 100 <> 0) or year rem 400 = 0;
```
Original source: [http://seed7.sourceforge.net/algorith/date.htm#isLeapYear]
## Sidef
```ruby
func isleap(year) {
if (year %% 100) {
return (year %% 400);
}
return (year %% 4);
}
```
or a little bit simpler:
```ruby
func isleap(year) { year %% 100 ? (year %% 400) : (year %% 4) };
```
## Smalltalk
Smalltalk has a built-in method named isLeapYear:
```smalltalk
Date today isLeapYear.
```
## SNOBOL4
Predicate leap( ) succeeds/fails, returns nil.
```SNOBOL4
define('leap(yr)') :(end_leap)
leap eq(remdr(yr,400),0) :s(return)
eq(remdr(yr,100),0) :s(freturn)
eq(remdr(yr,4),0) :s(return)f(freturn)
end_leap
* # Test and display (with ?: kluge)
test = "output = ('10' ? (*leap(yr) 1 | 0)) ': ' yr"
yr = '1066'; eval(test)
yr = '1492'; eval(test)
yr = '1900'; eval(test)
yr = '2000'; eval(test)
end
```
{{out}}
```txt
0: 1066
1: 1492
0: 1900
1: 2000
```
## Stata
Given a dataset with a "year" variable, generate a variable "leap" which is 1 for a leap year, 0 otherwise.
```stata
gen leap = mod(year,400)==0 | mod(year,4)==0 & mod(year,100)!=0
```
See also the article '''[https://www.stata.com/support/faqs/data-management/leap-year-indicators/ How do I identify leap years in Stata?]''' by Nicholas J. Cox in Stata FAQ.
## Swift
```Swift
func isLeapYear(year:Int) -> Bool {
return (year % 100 == 0) ? (year % 400 == 0) : (year % 4 == 0)
}
print(isLeapYear(2000))
print(isLeapYear(2011))
```
{{out}}
```txt
true
false
```
## Tcl
The "classic" modulo comparison:
```tcl
proc isleap1 {year} {
return [expr {($year % 4 == 0) && (($year % 100 != 0) || ($year % 400 == 0))}]
}
isleap1 1988 ;# => 1
isleap1 1989 ;# => 0
isleap1 1900 ;# => 0
isleap1 2000 ;# => 1
```
Does Feb 29 exist in the given year? If not a leap year, the clock command will return "03-01". (This code will switch to the Julian calendar for years before 1582.)
```tcl
proc isleap2 year {
return [expr {[clock format [clock scan "$year-02-29" -format "%Y-%m-%d"] -format "%m-%d"] eq "02-29"}]
}
isleap2 1988 ;# => 1
isleap2 1989 ;# => 0
isleap2 1900 ;# => 0
isleap2 2000 ;# => 1
```
## TUSCRIPT
```tuscript
$$ MODE TUSCRIPT
LOOP year="1900'1994'1996'1997'2000",txt=""
SET dayoftheweek=DATE(number,29,2,year,number)
IF (dayoftheweek==0) SET txt="not "
PRINT year," is ",txt,"a leap year"
ENDLOOP
```
{{out}}
```txt
1900 is not a leap year
1994 is not a leap year
1996 is a leap year
1997 is not a leap year
2000 is a leap year
```
## uBasic/4tH
{{trans|BBC BASIC}}
DO
INPUT "Enter a year: "; y
IF FUNC(_FNleap(y)) THEN
PRINT y; " is a leap year"
ELSE
PRINT y; " is not a leap year"
ENDIF
LOOP
END
_FNleap Param (1)
RETURN ((a@ % 4 = 0) * ((a@ % 400 = 0) + (a@ % 100 # 0)))
```
## UNIX Shell
Original Bourne:
```sh
leap() {
if expr $1 % 4 >/dev/null; then return 1; fi
if expr $1 % 100 >/dev/null; then return 0; fi
if expr $1 % 400 >/dev/null; then return 1; fi
return 0;
}
```
Using GNU date(1):
```sh
leap() {
date -d "$1-02-29" >/dev/null 2>&1;
}
```
Defining a bash function is_leap which accepts a YEAR argument, and uses no IO redirection, nor any extra processes.
```sh
is_leap() {
local year=$(( 10#${1:?'Missing year'} ))
(( year % 4 == 0 && ( year % 100 != 0 || year % 400 == 0 ) )) && return 0
return 1
}
```
Using the cal command: ''(note that this invokes two processes with IO piped between them and is relatively heavyweight compared to the above shell functions: leap and is_leap)''
```sh
leap() {
cal 02 $1 | grep -q 29
}
```
## Ursa
This program takes a year as a command line argument.
```ursa
decl int year
set year (int args<1>)
if (= (mod year 4) 0)
if (and (= (mod year 100) 0) (not (= (mod year 400) 0)))
out year " is not a leap year" endl console
else
out year " is a leap year" endl console
end if
else
out year " is not a leap year" endl console
end if
```
Output in Bash:
```txt
$ ursa leapyear.u 1900
1900 is not a leap year
$ ursa leapyear.u 2000
2000 is a leap year
```
## Vala
```Vala
void main() {
DateYear[] years = {1900, 1994, 1996, 1997, 2000};
foreach (DateYear year in years) {
string status = year.is_leap_year() ? "" : "not ";
print("%d is %sa leap year.\n", (int) year, status);
}
}
```
## VBA
```vb
Public Function Leap_year(year As Integer) As Boolean
Leap_year = (Month(DateSerial(year, 2, 29)) = 2)
End Function
```
## VBScript
```vb
Function IsLeapYear(yr)
IsLeapYear = False
If yr Mod 4 = 0 And (yr Mod 400 = 0 Or yr Mod 100 <> 0) Then
IsLeapYear = True
End If
End Function
'Testing the function.
arr_yr = Array(1900,1972,1997,2000,2001,2004)
For Each yr In arr_yr
If IsLeapYear(yr) Then
WScript.StdOut.WriteLine yr & " is leap year."
Else
WScript.StdOut.WriteLine yr & " is NOT leap year."
End If
Next
```
{{Out}}
```txt
1900 is NOT leap year.
1972 is leap year.
1997 is NOT leap year.
2000 is leap year.
2001 is NOT leap year.
2004 is leap year.
```
## Vedit macro language
```vedit
while (#1 = Get_Num("Year: ")) {
#2 = (#1 % 4 == 0) && ((#1 % 100 != 0) || (#1 % 400 == 0))
if (#2) {
Message(" is leap year\n")
} else {
Message(" is not leap year\n")
}
}
```
The following version requires Vedit 6.10 or later:
```vedit
while (#1 = Get_Num("Year: ")) {
if (Is_Leap_Year(#1)) {
Message(" is leap year\n")
} else {
Message(" is not leap year\n")
}
}
```
## Visual Basic
{{works with|Visual Basic|VB6 Standard}}
```vb
Public Function IsLeapYear1(ByVal theYear As Integer) As Boolean
'this function utilizes documented behaviour of the built-in DateSerial function
IsLeapYear1 = (VBA.Day(VBA.DateSerial(theYear, 2, 29)) = 29)
End Function
Public Function IsLeapYear2(ByVal theYear As Integer) As Boolean
'this function uses the well-known formula
IsLeapYear2 = IIf(theYear Mod 100 = 0, theYear Mod 400 = 0, theYear Mod 4 = 0)
End Function
```
Testing:
```vb
Sub Main()
'testing the above functions
Dim i As Integer
For i = 1750 To 2150
Debug.Assert IsLeapYear1(i) Eqv IsLeapYear2(i)
Next i
End Sub
```
## Visual Basic .NET
{{trans|C#}}
```vbnet
Module Module1
Sub Main()
For Each y In {1900, 1994, 1996, Date.Now.Year}
Console.WriteLine("{0} is {1}a leap year.", y, If(Date.IsLeapYear(y), String.Empty, "not "))
Next
End Sub
End Module
```
{{out}}
```txt
1900 is not a leap year.
1994 is not a leap year.
1996 is a leap year.
2019 is not a leap year.
```
## WDTE
```WDTE>let str =
import 'strings';
let multiple of n => == (% n of) 0;
let leap year => str.format '{} is{} a leap year.' year (switch year {
multiple 400 => '';
multiple 100 => ' not';
multiple 4 => '';
default => ' not';
}) -- io.writeln io.stdout;
```
## Wortel
```wortel
@let {
isLeapYear !?{\~%%1H \~%%4H \~%%4}
!-isLeapYear @range[1900 2000]
}
```
Returns:
```txt
[1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000]
```
## X86 Assembly
Using FASM syntax. Leaf function fits nicely into your program.
```asm
align 16
; Input year as signed dword in EAX
IsLeapYear:
test eax,11b
jz .4
retn ; 75% : ZF=0, not a leap year
.4:
mov ecx,100
cdq
idiv ecx
test edx,edx
jz .100
cmp edx,edx
retn ; 24% : ZF=1, leap year
.100:
test eax,11b
retn ; 1% : ZF=?, leap year if EAX%400=0
```
## XLISP
```xlisp
(DEFUN LEAP-YEARP (YEAR)
(AND (= (MOD YEAR 4) 0) (OR (/= (MOD YEAR 100) 0) (= (MOD YEAR 400) 0))))
; Test the function
(DISPLAY (MAPCAR LEAP-YEARP '(1600 1640 1800 1928 1979 1990 2000 2004 2005 2016)))
```
{{out}}
```txt
(#T #T () #T () () #T #T () #T)
```
## XPL0
```XPL0
func LeapYear(Y); \Return 'true' if Y is a leap year
int Y;
[if rem(Y/100)=0 then return rem(Y/400)=0;
return rem(Y/4)=0;
];
```
## Yorick
This solution is vectorized and can be applied to scalar or array input.
```yorick
func is_leap(y) {
return ((y % 4 == 0) & (y % 100 != 0)) | (y % 400 == 0);
}
```
Interactive example usage:
```txt
> is_leap(1988)
1
> is_leap([1988,1989,1900,2000])
[1,0,0,1]
```
## zkl
```zkl
Time.Date.isLeapYear(1988) //-->True
T(1988,1989,1900,2000).apply(Time.Date.isLeapYear)
//-->L(True,False,False,True)
```
{{omit from|GUISS|Only the operator can read the calendar}}