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In information theory and computer science, the '''Levenshtein distance''' is a [[wp:string metric|metric]] for measuring the amount of difference between two sequences (i.e. an [[wp:edit distance|edit distance]]). The Levenshtein distance between two strings is defined as the minimum number of edits needed to transform one string into the other, with the allowable edit operations being insertion, deletion, or substitution of a single character.

;Example: The Levenshtein distance between "'''kitten'''" and "'''sitting'''" is 3, since the following three edits change one into the other, and there isn't a way to do it with fewer than three edits: ::# '''k'''itten '''s'''itten (substitution of 'k' with 's') ::# sitt'''e'''n sitt'''i'''n (substitution of 'e' with 'i') ::# sittin sittin'''g''' (insert 'g' at the end).

''The Levenshtein distance between "'''rosettacode'''", "'''raisethysword'''" is '''8'''.

''The distance between two strings is same as that when both strings are reversed.''

;Task; Implements a Levenshtein distance function, or uses a library function, to show the Levenshtein distance between "kitten" and "sitting".

• [[Longest common subsequence]]

```with Ada.Text_IO;

procedure Main is
function Levenshtein_Distance (S, T : String) return Natural is
D : array (0 .. S'Length, 0 .. T'Length) of Natural;
begin
for I in D'Range (1) loop
D (I, 0) := I;
end loop;
for I in D'Range (2) loop
D (0, I) := I;
end loop;
for J in T'Range loop
for I in S'Range loop
if S (I) = T (J) then
D (I, J) := D (I - 1, J - 1);
else
D (I, J) :=
Natural'Min
(Natural'Min (D (I - 1, J) + 1, D (I, J - 1) + 1),
D (I - 1, J - 1) + 1);
end if;
end loop;
end loop;
return D (S'Length, T'Length);
end Levenshtein_Distance;
begin
("kitten -> sitting:" &
Integer'Image (Levenshtein_Distance ("kitten", "sitting")));
("rosettacode -> raisethysword:" &
Integer'Image (Levenshtein_Distance ("rosettacode", "raisethysword")));
end Main;
```

{{out}}

```kitten -> sitting: 3
rosettacode -> raisethysword: 8
```

## Aime

{{trans|C}}

```integer
dist(data s, t, integer i, j, list d)
{
integer x;

x = d[i * (~t + 1) + j];
if (x == -1) {
if (i == ~s) {
x = ~t - j;
} elif (j == ~t) {
x = ~s - i;
} elif (s[i] == t[j]) {
x = dist(s, t, i + 1, j + 1, d);
} else {
x = dist(s, t, i + 1, j + 1, d)
.min(dist(s, t, i, j + 1, d))
.min(dist(s, t, i + 1, j, d));
x += 1;
}

d[i * (~t + 1) + j] = x;
}

x;
}

levenshtein(data s, t)
{
list d;

d.pn_integer(0, (~s + 1) * (~t + 1), -1);
dist(s, t, 0, 0, d);
}

main(void)
{
text s1, s2;

o_form("`~' to `~' is ~\n", s1 = "rosettacode", s2 = "raisethysword",
levenshtein(s1, s2));
o_form("`~' to `~' is ~\n", s1 = "kitten", s2 = "sitting",
levenshtein(s1, s2));

0;
}
```

{{Out}}

````rosettacode' to `raisethysword' is 8
`kitten' to `sitting' is 3
```

## AppleScript

### Iteration

Translation of the "fast" C-version

```set dist to findLevenshteinDistance for "sunday" against "saturday"
to findLevenshteinDistance for s1 against s2
script o
property l : s1
property m : s2
end script
if s1 = s2 then return 0
set ll to length of s1
set lm to length of s2
if ll = 0 then return lm
if lm = 0 then return ll

set v0 to {}

repeat with i from 1 to (lm + 1)
set end of v0 to (i - 1)
end repeat
set item -1 of v0 to 0
copy v0 to v1

repeat with i from 1 to ll
-- calculate v1 (current row distances) from the previous row v0

-- first element of v1 is A[i+1][0]
--   edit distance is delete (i+1) chars from s to match empty t
set item 1 of v1 to i
--  use formula to fill in the rest of the row
repeat with j from 1 to lm
if item i of o's l = item j of o's m then
set cost to 0
else
set cost to 1
end if
set item (j + 1) of v1 to min3 for ((item j of v1) + 1) against ((item (j + 1) of v0) + 1) by ((item j of v0) + cost)
end repeat
copy v1 to v0
end repeat
return item (lm + 1) of v1
end findLevenshteinDistance

to min3 for anInt against anOther by theThird
if anInt < anOther then
if theThird < anInt then
return theThird
else
return anInt
end if
else
if theThird < anOther then
return theThird
else
return anOther
end if
end if
end min3
```

### Composition of generic functions

{{Trans|JavaScript}} (ES6 version)

```-- levenshtein :: String -> String -> Int
on levenshtein(sa, sb)
set {s1, s2} to {characters of sa, characters of sb}

script
on |λ|(ns, c)
script minPath
on |λ|(z, c1xy)
set {c1, x, y} to c1xy
minimum({y + 1, z + 1, x + fromEnum(c1 is not c)})
end |λ|
end script

set {n, ns1} to uncons(ns)
scanl(minPath, n + 1, zip3(s1, ns, ns1))
end |λ|
end script

|last|(foldl(result, enumFromTo(0, length of s1), s2))
end levenshtein

-- TEST -----------------------------------------------------------------------
on run
script test
on |λ|(xs)
levenshtein(item 1 of xs, item 2 of xs)
end |λ|
end script

map(test, [["kitten", "sitting"], ["sitting", "kitten"], ¬
["rosettacode", "raisethysword"], ["raisethysword", "rosettacode"]])

--> {3, 3, 8, 8}
end run

-- GENERIC FUNCTIONS -----------------------------------------------------------

-- enumFromTo :: Enum a => a -> a -> [a]
on enumFromTo(m, n)

if intM > intN then
set d to -1
else
set d to 1
end if
set lst to {}
if class of m is text then
repeat with i from intM to intN by d
set end of lst to chr(i)
end repeat
else
repeat with i from intM to intN by d
set end of lst to i
end repeat
end if
return lst
end enumFromTo

-- foldl :: (a -> b -> a) -> a -> [b] -> a
on foldl(f, startValue, xs)
tell mReturn(f)
set v to startValue
set lng to length of xs
repeat with i from 1 to lng
set v to |λ|(v, item i of xs, i, xs)
end repeat
return v
end tell
end foldl

-- fromEnum :: Enum a => a -> Int
set c to class of x
if c is boolean then
if x then
1
else
0
end if
else if c is text then
if x ≠ "" then
id of x
else
missing value
end if
else
x as integer
end if

-- last :: [a] -> a
on |last|(xs)
if length of xs > 0 then
item -1 of xs
else
missing value
end if
end |last|

-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map

-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn

-- minimum :: [a] -> a
on minimum(xs)
script min
on |λ|(a, x)
if x < a or a is missing value then
x
else
a
end if
end |λ|
end script

foldl(min, missing value, xs)
end minimum

-- scanl :: (b -> a -> b) -> b -> [a] -> [b]
on scanl(f, startValue, xs)
tell mReturn(f)
set v to startValue
set lng to length of xs
set lst to {startValue}
repeat with i from 1 to lng
set v to |λ|(v, item i of xs, i, xs)
set end of lst to v
end repeat
return lst
end tell
end scanl

-- uncons :: [a] -> Maybe (a, [a])
on uncons(xs)
if length of xs > 0 then
{item 1 of xs, rest of xs}
else
missing value
end if
end uncons

-- zip3 :: [a] -> [b] -> [c] -> [(a, b, c)]
on zip3(xs, ys, zs)
script
on |λ|(x, i)
[x, item i of ys, item i of zs]
end |λ|
end script

map(result, items 1 thru ¬
minimum({length of xs, length of ys, length of zs}) of xs)
end zip3
```

{{Out}}

```{3, 3, 8, 8}
```

## Arc

### Waterhouse Arc

O(n * m) time, linear space, using lists instead of vectors

```(def levenshtein (str1 str2)
(withs l1  len.str1
l2  len.str2
row range0:inc.l1

(times j l2
(let next list.j
(times i l1
(push
(inc:min
car.next
((if (is str1.i str2.j) dec id) car.row)
(car:zap cdr row))
next))
(= row nrev.next)))
row.l1))
```

## AutoHotkey

{{trans|Go}}

```levenshtein(s, t){
If s =
return StrLen(t)
If t =
return strLen(s)
If SubStr(s, 1, 1) = SubStr(t, 1, 1)
return levenshtein(SubStr(s, 2), SubStr(t, 2))
a := Levenshtein(SubStr(s, 2), SubStr(t, 2))
b := Levenshtein(s,            SubStr(t, 2))
c := Levenshtein(SubStr(s, 2), t           )
If (a > b)
a := b
if (a > c)
a := c
return a + 1
}
s1 := "kitten"
s2 := "sitting"
MsgBox % "distance between " s1 " and " s2 ": " levenshtein(s1, s2)
```

It correctly outputs '3'

## AWK

Slavishly copied from the very clear AutoHotKey example.

```#!/usr/bin/awk -f

BEGIN {
a = "kitten";
b = "sitting";
d = levenshteinDistance(a, b);
p = d == 1 ? "" : "s";
printf("%s -> %s after %d edit%s\n", a, b, d, p);
exit;
}

function levenshteinDistance(s1, s2,
s1First, s2First, s1Rest, s2Rest,
distA, distB, distC, minDist) {

# If either string is empty,
# then distance is insertion of the other's characters.
if (length(s1) == 0) return length(s2);
if (length(s2) == 0) return length(s1);

# Rest of process uses first characters
# and remainder of each string.
s1First = substr(s1, 1, 1);
s2First = substr(s2, 1, 1);
s1Rest = substr(s1, 2, length(s1));
s2Rest = substr(s2, 2, length(s2));

# If leading characters are the same,
# then distance is that between the rest of the strings.
if (s1First == s2First) {
return levenshteinDistance(s1Rest, s2Rest);
}

# Find the distances between sub strings.
distA = levenshteinDistance(s1Rest, s2);
distB = levenshteinDistance(s1, s2Rest);
distC = levenshteinDistance(s1Rest, s2Rest);

# Return the minimum distance between substrings.
minDist = distA;
if (distB < minDist) minDist = distB;
if (distC < minDist) minDist = distC;
return minDist + 1; # Include change for the first character.
}

```

Example output:

```
kitten -> sitting after 3 edits

```

Alternative, much faster but also less readable lazy-evaluation version from http://awk.freeshell.org/LevenshteinEditDistance (where the above takes e.g. 0m44.904s in gawk 4.1.3 for 5 edits (length 10 and 14 strings), this takes user 0m0.004s):

```#!/usr/bin/awk -f

function levdist(str1, str2,	l1, l2, tog, arr, i, j, a, b, c) {
if (str1 == str2) {
return 0
} else if (str1 == "" || str2 == "") {
return length(str1 str2)
} else if (substr(str1, 1, 1) == substr(str2, 1, 1)) {
a = 2
while (substr(str1, a, 1) == substr(str2, a, 1)) a++
return levdist(substr(str1, a), substr(str2, a))
} else if (substr(str1, l1=length(str1), 1) == substr(str2, l2=length(str2), 1)) {
b = 1
while (substr(str1, l1-b, 1) == substr(str2, l2-b, 1)) b++
return levdist(substr(str1, 1, l1-b), substr(str2, 1, l2-b))
}
for (i = 0; i <= l2; i++) arr[0, i] = i
for (i = 1; i <= l1; i++) {
arr[tog = ! tog, 0] = i
for (j = 1; j <= l2; j++) {
a = arr[! tog, j  ] + 1
b = arr[  tog, j-1] + 1
c = arr[! tog, j-1] + (substr(str1, i, 1) != substr(str2, j, 1))
arr[tog, j] = (((a<=b)&&(a<=c)) ? a : ((b<=a)&&(b<=c)) ? b : c)
}
}
return arr[tog, j-1]
}

```

## BBC BASIC

```      PRINT "'kitten' -> 'sitting' has distance " ;
PRINT ; FNlevenshtein("kitten", "sitting")
PRINT "'rosettacode' -> 'raisethysword' has distance " ;
PRINT ; FNlevenshtein("rosettacode", "raisethysword")
END

DEF FNlevenshtein(s\$, t\$)
LOCAL i%, j%, m%, d%()
DIM d%(LENs\$, LENt\$)
FOR i% = 0 TO DIM(d%(),1)
d%(i%,0) = i%
NEXT
FOR j% = 0 TO DIM(d%(),2)
d%(0,j%) = j%
NEXT
FOR j% = 1 TO DIM(d%(),2)
FOR i% = 1 TO DIM(d%(),1)
IF MID\$(s\$,i%,1) = MID\$(t\$,j%,1) THEN
d%(i%,j%) = d%(i%-1,j%-1)
ELSE
m% = d%(i%-1,j%-1)
IF d%(i%,j%-1) < m% m% = d%(i%,j%-1)
IF d%(i%-1,j%) < m% m% = d%(i%-1,j%)
d%(i%,j%) = m% + 1
ENDIF
NEXT
NEXT j%
= d%(i%-1,j%-1)
```

'''Output:'''

```
'kitten' -> 'sitting' has distance 3
'rosettacode' -> 'raisethysword' has distance 8

```

## Bracmat

{{trans|C}} Recursive method, but with memoization.

```(levenshtein=
lev cache
.   ( lev
=   s s0 s1 t t0 t1 L a b c val key
.     (cache..find)\$(str\$!arg:?key):(?.?val)
& !val
|   !arg:(?s,?t)
& ( !s:&@(!t:? [?L)
| !t:&@(!s:? [?L)
)
& (cache..insert)\$(!key.!L)
& !L
|   !arg:(@(?:%?s0 ?s1),@(?:%?t0 ?t1))
& !s0:!t0
& lev\$(!s1,!t1)
|   lev\$(!s1,!t1):?a
& lev\$(!s,!t1):?b
& lev\$(!s1,!t):?c
& (!b:<!a:?a|)
& (!c:<!a:?a|)
& (cache..insert)\$(!key.1+!a)
& 1+!a
)
& new\$hash:?cache
& lev\$!arg);
```

{{out|Demonstrating}}

``` levenshtein\$(kitten,sitting)
3
levenshtein\$(rosettacode,raisethysword)
8
```

## C

Recursive method. Deliberately left in an inefficient state to show the recursive nature of the algorithm; notice how it would have become the Wikipedia algorithm if we memoized the function against parameters `ls` and `lt`.

```#include <stdio.h>
#include <string.h>

/* s, t: two strings; ls, lt: their respective length */
int levenshtein(const char *s, int ls, const char *t, int lt)
{
int a, b, c;

/* if either string is empty, difference is inserting all chars
* from the other
*/
if (!ls) return lt;
if (!lt) return ls;

/* if last letters are the same, the difference is whatever is
* required to edit the rest of the strings
*/
if (s[ls - 1] == t[lt - 1])
return levenshtein(s, ls - 1, t, lt - 1);

/* else try:
*      changing last letter of s to that of t; or
*      remove last letter of s; or
*      remove last letter of t,
* any of which is 1 edit plus editing the rest of the strings
*/
a = levenshtein(s, ls - 1, t, lt - 1);
b = levenshtein(s, ls,     t, lt - 1);
c = levenshtein(s, ls - 1, t, lt    );

if (a > b) a = b;
if (a > c) a = c;

return a + 1;
}

int main()
{
const char *s1 = "rosettacode";
const char *s2 = "raisethysword";
printf("distance between `%s' and `%s': %d\n", s1, s2,
levenshtein(s1, strlen(s1), s2, strlen(s2)));

return 0;
}
```

Take the above and add caching, we get (in [[C99]]):

```#include <stdio.h>
#include <string.h>

int levenshtein(const char *s, const char *t)
{
int ls = strlen(s), lt = strlen(t);
int d[ls + 1][lt + 1];

for (int i = 0; i <= ls; i++)
for (int j = 0; j <= lt; j++)
d[i][j] = -1;

int dist(int i, int j) {
if (d[i][j] >= 0) return d[i][j];

int x;
if (i == ls)
x = lt - j;
else if (j == lt)
x = ls - i;
else if (s[i] == t[j])
x = dist(i + 1, j + 1);
else {
x = dist(i + 1, j + 1);

int y;
if ((y = dist(i, j + 1)) < x) x = y;
if ((y = dist(i + 1, j)) < x) x = y;
x++;
}
return d[i][j] = x;
}
return dist(0, 0);
}

int main(void)
{
const char *s1 = "rosettacode";
const char *s2 = "raisethysword";
printf("distance between `%s' and `%s': %d\n", s1, s2,
levenshtein(s1, s2));

return 0;
}
```

## C++

```#include <string>
#include <iostream>
using namespace std;

// Compute Levenshtein Distance
// Martin Ettl, 2012-10-05

size_t uiLevenshteinDistance(const std::string &s1, const std::string &s2)
{
const size_t m(s1.size());
const size_t n(s2.size());

if( m==0 ) return n;
if( n==0 ) return m;

size_t *costs = new size_t[n + 1];

for( size_t k=0; k<=n; k++ ) costs[k] = k;

size_t i = 0;
for ( std::string::const_iterator it1 = s1.begin(); it1 != s1.end(); ++it1, ++i )
{
costs[0] = i+1;
size_t corner = i;

size_t j = 0;
for ( std::string::const_iterator it2 = s2.begin(); it2 != s2.end(); ++it2, ++j )
{
size_t upper = costs[j+1];
if( *it1 == *it2 )
{
costs[j+1] = corner;
}
else
{
size_t t(upper<corner?upper:corner);
costs[j+1] = (costs[j]<t?costs[j]:t)+1;
}

corner = upper;
}
}

size_t result = costs[n];
delete [] costs;

return result;
}

int main()
{
string s0 = "rosettacode";
string s1 = "raisethysword";
cout << "distance between " << s0 << " and " << s1 << " : "
<< uiLevenshteinDistance(s0,s1) << std::endl;

return 0;
}

```

{{out|Example output}}

```
\$ ./a.out
distance between rosettacode and raisethysword : 8

```

## C#

This is a straightforward translation of the Wikipedia pseudocode.

```using System;

namespace LevenshteinDistance
{
class Program
{
static int LevenshteinDistance(string s, string t)
{
int n = s.Length;
int m = t.Length;
int[,] d = new int[n + 1, m + 1];

if (n == 0)
{
return m;
}

if (m == 0)
{
return n;
}

for (int i = 0; i <= n; i++)
d[i, 0] = i;
for (int j = 0; j <= m; j++)
d[0, j] = j;

for (int j = 1; j <= m; j++)
for (int i = 1; i <= n; i++)
if (s[i - 1] == t[j - 1])
d[i, j] = d[i - 1, j - 1];  //no operation
else
d[i, j] = Math.Min(Math.Min(
d[i - 1, j] + 1,    //a deletion
d[i, j - 1] + 1),   //an insertion
d[i - 1, j - 1] + 1 //a substitution
);
return d[n, m];
}

static void Main(string[] args)
{
if (args.Length == 2)
Console.WriteLine("{0} -> {1} = {2}",
args[0], args[1], LevenshteinDistance(args[0], args[1]));
else
Console.WriteLine("Usage:-\n\nLevenshteinDistance <string1> <string2>");
}
}
}
```

{{out|Example output}}

```
> LevenshteinDistance kitten sitting
kitten -> sitting = 3

> LevenshteinDistance rosettacode raisethysword
rosettacode -> raisethysword = 8

```

```
identification division.
program-id. Levenshtein.

environment division.
configuration section.
repository.
function all intrinsic.

data division.
working-storage section.
77  string-a               pic x(255).
77  string-b               pic x(255).
77  length-a               pic 9(3).
77  length-b               pic 9(3).
77  distance               pic z(3).
77  i                      pic 9(3).
77  j                      pic 9(3).
01  tab.
05 filler              occurs 256.
10 filler           occurs 256.
15 costs         pic 9(3).

procedure division.
main.
move "kitten" to string-a
move "sitting" to string-b
perform levenshtein-dist

move "rosettacode" to string-a
move "raisethysword" to string-b
perform levenshtein-dist
stop run
.
levenshtein-dist.
move length(trim(string-a)) to length-a
move length(trim(string-b)) to length-b

initialize tab

perform varying i from 0 by 1 until i > length-a
move i to costs(i + 1, 1)
end-perform

perform varying j from 0 by 1 until j > length-b
move j to costs(1, j + 1)
end-perform

perform with test after varying i from 2 by 1 until i > length-a
perform with test after varying j from 2 by 1 until j > length-b
if string-a(i - 1:1) = string-b(j - 1:1)
move costs(i - 1, j - 1) to costs(i, j)
else
move min(min(costs(i - 1, j) + 1,     *> a deletion
costs(i, j - 1) + 1),    *> an insertion
costs(i - 1, j - 1) + 1)     *> a substitution
to costs(i, j)
end-if
end-perform
end-perform
move costs(length-a + 1, length-b + 1) to distance
display trim(string-a) " -> " trim(string-b) " = " trim(distance)
.

```

{{out|Output}}

```
> ./Levenshtein
kitten -> sitting = 3
rosettacode -> raisethysword = 8

```

## CoffeeScript

```levenshtein = (str1, str2) ->
# more of less ported simple algorithm from JS
m = str1.length
n = str2.length
d = []

return n  unless m
return m  unless n

d[i] = [i] for i in [0..m]
d[0][j] = j for j in [1..n]

for i in [1..m]
for j in [1..n]
if str1[i-1] is str2[j-1]
d[i][j] = d[i-1][j-1]
else
d[i][j] = Math.min(
d[i-1][j]
d[i][j-1]
d[i-1][j-1]
) + 1

d[m][n]

console.log levenshtein("kitten", "sitting")
console.log levenshtein("rosettacode", "raisethysword")
console.log levenshtein("stop", "tops")
console.log levenshtein("yo", "")
console.log levenshtein("", "yo")
```

## Common Lisp

```(defun levenshtein (a b)
(let* ((la  (length a))
(lb  (length b))
(rec (make-array (list (1+ la) (1+ lb)) :initial-element nil)))

(defun leven (x y)
(cond
((zerop x) y)
((zerop y) x)
((aref rec x y) (aref rec x y))
(t (setf (aref rec x y)
(+ (if (char= (char a (- la x)) (char b (- lb y))) 0 1)
(min (leven (1- x) y)
(leven x (1- y))
(leven (1- x) (1- y))))))))
(leven la lb)))

(print (levenshtein "rosettacode" "raisethysword"))
```

{{out}}

```8
```

## Clojure

### Recursive Version

```(defn levenshtein [str1 str2]
(let [len1 (count str1)
len2 (count str2)]
(cond (zero? len1) len2
(zero? len2) len1
:else
(let [cost (if (= (first str1) (first str2)) 0 1)]
(min (inc (levenshtein (rest str1) str2))
(inc (levenshtein str1 (rest str2)))
(+ cost
(levenshtein (rest str1) (rest str2))))))))

(println (levenshtein "rosettacode" "raisethysword"))
```

{{out}}

```8
```

### Iterative version

```(defn levenshtein [w1 w2]
(letfn [(cell-value [same-char? prev-row cur-row col-idx]
(min (inc (nth prev-row col-idx))
(inc (last cur-row))
(+ (nth prev-row (dec col-idx)) (if same-char?
0
1))))]
(loop [row-idx  1
max-rows (inc (count w2))
prev-row (range (inc (count w1)))]
(if (= row-idx max-rows)
(last prev-row)
(let [ch2           (nth w2 (dec row-idx))
next-prev-row (reduce (fn [cur-row i]
(let [same-char? (= (nth w1 (dec i)) ch2)]
(conj cur-row (cell-value same-char?
prev-row
cur-row
i))))
[row-idx] (range 1 (count prev-row)))]
(recur (inc row-idx) max-rows next-prev-row))))))
```

## Crystal

The standard library includes [https://crystal-lang.org/api/0.19.2/Levenshtein.html levenshtein] module

```require "levenshtein"
puts Levenshtein.distance("kitten", "sitting")
puts Levenshtein.distance("rosettacode", "raisethysword")

```

{{out}}

```3
8
```

{{trans|Ruby 1st version}}

```module Levenshtein

def self.distance(a, b)
a, b = a.downcase, b.downcase
costs = (0..b.size).to_a
(1..a.size).each do |i|
costs[0], nw = i, i - 1  # j == 0; nw is lev(i-1, j)
(1..b.size).each do |j|
costs[j], nw = [costs[j] + 1, costs[j-1] + 1, a[i-1] == b[j-1] ? nw : nw + 1].min, costs[j]
end
end
costs[b.size]
end

def self.test
%w{kitten sitting saturday sunday rosettacode raisethysword}.each_slice(2) do |(a, b)| #or do |pair| a, b = pair
puts "distance(#{a}, #{b}) = #{distance(a, b)}"
end
end

end

Levenshtein.test

```

{{out}}

```
distance(kitten, sitting) = 3
distance(saturday, sunday) = 3
distance(rosettacode, raisethysword) = 8

```

{{trans|Ruby 2nd version}}

```def levenshtein_distance(str1, str2)
n, m = str1.size, str2.size
max = n / 2

return 0 if n == 0 || m == 0
return n if (n - m).abs > max

d = (0..m).to_a
x = 0

str1.each_char_with_index do |char1, i|
e = i + 1

str2.each_char_with_index do |char2, j|
cost = (char1 == char2) ? 0 : 1
x = [ d[j+1] + 1, # insertion
e + 1,      # deletion
d[j] + cost # substitution
].min
d[j] = e
e = x
end

d[m] = x
end
x
end

%w{kitten sitting saturday sunday rosettacode raisethysword}.each_slice(2) do |(a, b)| #or do |pair| a, b = pair
puts "distance(#{a}, #{b}) = #{levenshtein_distance(a, b)}"
end

```

{{out}}

```
distance(kitten, sitting) = 3
distance(saturday, sunday) = 3
distance(rosettacode, raisethysword) = 8

```

## D

### Standard Version

The standard library [http://www.digitalmars.com/d/2.0/phobos/std_algorithm.html#levenshteinDistance std.algorithm] module includes a Levenshtein distance function:

```void main() {
import std.stdio, std.algorithm;

levenshteinDistance("kitten", "sitting").writeln;
}
```

{{out}}

```3
```

### Iterative Version

{{trans|Java}}

```import std.stdio, std.algorithm;

int distance(in string s1, in string s2) pure nothrow {
auto costs = new int[s2.length + 1];

foreach (immutable i; 0 .. s1.length + 1) {
int lastValue = i;
foreach (immutable j; 0 .. s2.length + 1) {
if (i == 0)
costs[j] = j;
else {
if (j > 0) {
int newValue = costs[j - 1];
if (s1[i - 1] != s2[j - 1])
newValue = min(newValue, lastValue, costs[j]) + 1;
costs[j - 1] = lastValue;
lastValue = newValue;
}
}
}

if (i > 0)
costs[\$ - 1] = lastValue;
}

return costs[\$ - 1];
}

void main() {
foreach (p; [["kitten", "sitting"], ["rosettacode", "raisethysword"]])
writefln("distance(%s, %s): %d", p[0], p[1], distance(p[0], p[1]));
}
```

### Memoized Recursive Version

{{trans|Python}}

```import std.stdio, std.array, std.algorithm, std.functional;

uint lDist(T)(in const(T)[] s, in const(T)[] t) nothrow {
alias mlDist = memoize!lDist;
if (s.empty || t.empty) return max(t.length, s.length);
if (s[0] == t[0]) return mlDist(s[1 .. \$], t[1 .. \$]);
return min(mlDist(s, t[1 .. \$]),
mlDist(s[1 .. \$], t),
mlDist(s[1 .. \$], t[1 .. \$])) + 1;
}

void main() {
lDist("kitten", "sitting").writeln;
lDist("rosettacode", "raisethysword").writeln;
}
```

## DWScript

Based on Wikipedia version

```function LevenshteinDistance(s, t : String) : Integer;
var
i, j : Integer;
begin
var d:=new Integer[Length(s)+1, Length(t)+1];
for i:=0 to Length(s) do
d[i, 0] := i;
for j:=0 to Length(t) do
d[0, j] := j;

for j:=1 to Length(t) do
for i:=1 to Length(s) do
if s[i]=t[j] then
d[i, j] := d[i-1, j-1] // no operation
else d[i,j]:=MinInt(MinInt(
d[i-1, j] +1 ,    // a deletion
d[i, j-1] +1 ),   // an insertion
d[i- 1,j-1] +1    // a substitution
);
Result:=d[Length(s), Length(t)];
end;

PrintLn(LevenshteinDistance('kitten', 'sitting'));
```

## Dyalect

```func min(x, y) {
if x < y {
x
} else {
y
}
}

func levenshtein(s, t) {
var n = s.len()
var m = t.len()
var d = Array.empty(n + 1, () => Array.empty(m + 1))

if n == 0 {
return m
}

if (m == 0) {
return n
}

for i in 0..n {
d[i][0] = i
}

for j in 0..m {
d[0][j] = j
}

for j in 1..m {
for i in 1..n {
if s[i - 1] == t[j - 1] {
d[i][j] = d[i - 1][j - 1] //no operation
}
else {
d[i][j] = min(min(
d[i - 1][j] + 1,    //a deletion
d[i][j - 1] + 1),   //an insertion
d[i - 1][j - 1] + 1 //a substitution
)
}
}
}

d[n][m]
}

func run(x, y) {
print("\(x) -> \(y) = \(levenshtein(x, y))")
}

run("rosettacode", "raisethysword")
```

{{out}}

```rosettacode -> raisethysword = 8
```

## EchoLisp

```
;; Recursive version adapted from Clojure

(define (levenshtein str1 str2 (cost 0) (rest1 0) (rest2 0) (key null))
(set! key (string-append str1 "|" str2))
(if (get 'mem key) ;; memoized ?
(get 'mem key)
;; else memoize
(putprop 'mem
(let [(len1 (string-length str1))
(len2 (string-length str2))]
(cond ((zero? len1) len2)
((zero? len2) len1)
(else
(set! cost (if (= (string-first str1) (string-first str2)) 0 1))
(set! rest1 (string-rest str1))
(set! rest2 (string-rest str2))
(min (1+ (levenshtein rest1 str2))
(1+ (levenshtein str1 rest2))
(+ cost
(levenshtein rest1 rest2 ))))))
key)))

;; 😛 127 calls with memoization
;; 😰 29737 calls without memoization
(levenshtein "kitten" "sitting") → 3

(levenshtein "rosettacode" "raisethysword") → 8

```

## Ela

This code is translated from Haskell version.

```open list

levenshtein s1 s2 = last <| foldl transform [0 .. length s1] s2
where transform (n::ns')@ns c = scanl calc (n+1) <| zip3 s1 ns ns'
where calc z (c', x, y) = minimum [y+1, z+1, x + toInt (c' <> c)]
```

Executing:

```(levenshtein "kitten" "sitting", levenshtein "rosettacode" "raisethysword")
```

{{out}}

```(3, 8)
```

## Elixir

{{trans|Ruby}}

```defmodule Levenshtein do
def distance(a, b) do
ta = String.downcase(a) |> to_char_list |> List.to_tuple
tb = String.downcase(b) |> to_char_list |> List.to_tuple
m = tuple_size(ta)
n = tuple_size(tb)
costs = Enum.reduce(0..m, %{},   fn i,acc -> Map.put(acc, {i,0}, i) end)
costs = Enum.reduce(0..n, costs, fn j,acc -> Map.put(acc, {0,j}, j) end)
Enum.reduce(0..n-1, costs, fn j, acc ->
Enum.reduce(0..m-1, acc, fn i, map ->
d = if elem(ta, i) == elem(tb, j) do
map[ {i,j} ]
else
Enum.min([ map[ {i  , j+1} ] + 1,         # deletion
map[ {i+1, j  } ] + 1,         # insertion
map[ {i  , j  } ] + 1 ])       # substitution
end
Map.put(map, {i+1, j+1}, d)
end)
end)
|> Map.get({m,n})
end
end

words = ~w(kitten sitting saturday sunday rosettacode raisethysword)
Enum.each(Enum.chunk(words, 2), fn [a,b] ->
IO.puts "distance(#{a}, #{b}) = #{Levenshtein.distance(a,b)}"
end)
```

{{out}}

```
distance(kitten, sitting) = 3
distance(saturday, sunday) = 3
distance(rosettacode, raisethysword) = 8

```

## Erlang

Here are two implementations. The first is the naive version, the second is a memoized version using Erlang's dictionary datatype.

```
-module(levenshtein).
-compile(export_all).

distance_cached(S,T) ->
{L,_} = ld(S,T,dict:new()),
L.

distance(S,T) ->
ld(S,T).

ld([],T) ->
length(T);
ld(S,[]) ->
length(S);
ld([X|S],[X|T]) ->
ld(S,T);
ld([_SH|ST]=S,[_TH|TT]=T) ->
1 + lists:min([ld(S,TT),ld(ST,T),ld(ST,TT)]).

ld([]=S,T,Cache) ->
{length(T),dict:store({S,T},length(T),Cache)};
ld(S,[]=T,Cache) ->
{length(S),dict:store({S,T},length(S),Cache)};
ld([X|S],[X|T],Cache) ->
ld(S,T,Cache);
ld([_SH|ST]=S,[_TH|TT]=T,Cache) ->
case dict:is_key({S,T},Cache) of
true -> {dict:fetch({S,T},Cache),Cache};
false ->
{L1,C1} = ld(S,TT,Cache),
{L2,C2} = ld(ST,T,C1),
{L3,C3} = ld(ST,TT,C2),
L = 1+lists:min([L1,L2,L3]),
{L,dict:store({S,T},L,C3)}
end.

```

Below is a comparison of the runtimes, measured in microseconds, between the two implementations.

```
68> timer:tc(levenshtein,distance,["rosettacode","raisethysword"]).
{774799,8} % {Time, Result}
69> timer:tc(levenshtein,distance_cached,["rosettacode","raisethysword"]).
{659,8}
70> timer:tc(levenshtein,distance,["kitten","sitting"]).
{216,3}
71> timer:tc(levenshtein,distance_cached,["kitten","sitting"]).
{213,3}

```

## ERRE

```
PROGRAM LEVENSHTEIN

!\$DYNAMIC
DIM D%[0,0]

PROCEDURE LEVENSHTEIN(S\$,T\$->RES%)
LOCAL I%,J%,M%
FOR I%=0 TO LEN(S\$) DO
D%[I%,0]=I%
END FOR
FOR J%=0 TO LEN(T\$) DO
D%[0,J%]=J%
END FOR
FOR J%=1 TO LEN(T\$) DO
FOR I%=1 TO LEN(S\$) DO
IF MID\$(S\$,I%,1)=MID\$(T\$,J%,1) THEN
D%[I%,J%]=D%[I%-1,J%-1]
ELSE
M%=D%[I%-1,J%-1]
IF D%[I%,J%-1]<M% THEN M%=D%[I%,J%-1] END IF
IF D%[I%-1,J%]<M% THEN M%=D%[I%-1,J%] END IF
D%[I%,J%]=M%+1
END IF
END FOR
END FOR
RES%=D%[I%-1,J%-1]
END PROCEDURE

BEGIN
S\$="kitten"  T\$="sitting"
PRINT("'";S\$;"' -> '";T\$;"' has distance ";)
!\$DIM D%[LEN(S\$),LEN(T\$)]
LEVENSHTEIN(S\$,T\$->RES%)
PRINT(RES%)
!\$ERASE D%

S\$="rosettacode" T\$="raisethysword"
PRINT("'";S\$;"' -> '";T\$;"' has distance ";)
!\$DIM D%[LEN(S\$),LEN(T\$)]
LEVENSHTEIN(S\$,T\$->RES%)
PRINT(RES%)
!\$ERASE D%
END PROGRAM

```

{{out}}

```
'kitten' -> 'sitting' has distance  3
'rosettacode' -> 'raisethysword' has distance  8

```

## Euphoria

Code by Jeremy Cowgar from the [http://www.rapideuphoria.com/cgi-bin/asearch.exu?gen=on&keywords=Levenshtein Euphoria File Archive].

```function min(sequence s)
atom m
m = s[1]
for i = 2 to length(s) do
if s[i] < m then
m = s[i]
end if
end for
return m
end function

function levenshtein(sequence s1, sequence s2)
integer n, m
sequence d
n = length(s1) + 1
m = length(s2) + 1

if n = 1  then
return m-1
elsif m = 1 then
return n-1
end if

d = repeat(repeat(0, m), n)
for i = 1 to n do
d[i][1] = i-1
end for

for j = 1 to m do
d[1][j] = j-1
end for

for i = 2 to n do
for j = 2 to m do
d[i][j] = min({
d[i-1][j] + 1,
d[i][j-1] + 1,
d[i-1][j-1] + (s1[i-1] != s2[j-1])
})
end for
end for

return d[n][m]
end function

? levenshtein("kitten", "sitting")
? levenshtein("rosettacode", "raisethysword")
```

{{out}}

```3
8

```

```
open System

let getInput (name : string) =
Console.Write ("String {0}: ", name)

let levDist (strOne : string) (strTwo : string) =
let strOne = strOne.ToCharArray ()
let strTwo = strTwo.ToCharArray ()

let (distArray : int[,]) = Array2D.zeroCreate (strOne.Length + 1) (strTwo.Length + 1)

for i = 0 to strOne.Length do distArray.[i, 0] <- i
for j = 0 to strTwo.Length do distArray.[0, j] <- j

for j = 1 to strTwo.Length do
for i = 1 to strOne.Length do
if strOne.[i - 1] = strTwo.[j - 1] then distArray.[i, j] <- distArray.[i - 1, j - 1]
else
distArray.[i, j] <- List.min (
[distArray.[i-1, j] + 1;
distArray.[i, j-1] + 1;
distArray.[i-1, j-1] + 1]
)
distArray.[strOne.Length, strTwo.Length]

let stringOne = getInput "One"
let stringTwo = getInput "Two"
printf "%A" (levDist stringOne stringTwo)

```

## Factor

```USING: lcs prettyprint ;
"kitten" "sitting" levenshtein .
```

{{out}}

```
3

```

## Forth

{{trans|C}}

```: levenshtein                          ( a1 n1 a2 n2 -- n3)
dup                                  \ if either string is empty, difference
if                                   \ is inserting all chars from the other
2>r dup
if
2dup 1- chars + c@ 2r@ 1- chars + c@ =
if
1- 2r> 1- recurse exit
else                             \ else try:
2dup 1- 2r@ 1- recurse -rot    \   changing first letter of s to t;
2dup    2r@ 1- recurse -rot    \   remove first letter of s;
1- 2r> recurse min min 1+      \   remove first letter of t,
then                             \ any of which is 1 edit plus
else                               \ editing the rest of the strings
2drop 2r> nip
then
else
2drop nip
then
;

s" kitten"      s" sitting"       levenshtein . cr
s" rosettacode" s" raisethysword" levenshtein . cr
```

## FreeBASIC

```' FB 1.05.0 Win64

' Uses the "iterative with two matrix rows" algorithm
' referred to in the Wikipedia article.

Function min(x As Integer, y As Integer) As Integer
Return IIf(x < y, x, y)
End Function

Function levenshtein(s As String, t As String) As Integer
' degenerate cases
If s = t Then Return 0
If s = "" Then Return Len(t)
If t = "" Then Return Len(s)

' create two integer arrays of distances
Dim v0(0 To Len(t)) As Integer  '' previous
Dim v1(0 To Len(t)) As Integer  '' current

' initialize v0
For i As Integer = 0 To Len(t)
v0(i) = i
Next

Dim cost As Integer
For i As Integer = 0 To Len(s) - 1
' calculate v1 from v0
v1(0) = i + 1

For j As Integer = 0 To Len(t) - 1
cost = IIf(s[i] = t[j], 0, 1)
v1(j + 1) = min(v1(j) + 1, min(v0(j + 1) + 1, v0(j) + cost))
Next j

' copy v1 to v0 for next iteration
For j As Integer = 0 To Len(t)
v0(j) = v1(j)
Next  j
Next i

Return v1(Len(t))
End Function

Print "'kitten' to 'sitting'            => "; levenshtein("kitten", "sitting")
Print "'rosettacode' to 'raisethysword' => "; levenshtein("rosettacode", "raisethysword")
Print "'sleep' to 'fleeting'            => "; levenshtein("sleep", "fleeting")
Print
Print "Press any key to quit"
Sleep
```

{{out}}

```
'kitten' to 'sitting'            =>  3
'rosettacode' to 'raisethysword' =>  8
'sleep' to 'fleeting'            =>  5

```

## Frink

Frink has a built-in function to calculate the Levenshtein edit distance between two strings:

```println[editDistance["kitten","sitting"]]
```

## FutureBasic

Based on Wikipedia algorithm. Suitable for Pascal strings.

```
include "ConsoleWindow"

local fn LevenshteinDistance( aStr as Str255, bStr as Str255 ) as long
dim as long m, n, i, j, min, k, l
dim as long distance( 255, 255 )

m = len(aStr)
n = len(bStr)

for i = 0 to m
distance( i, 0 ) = i
next

for j = 0 to n
distance( 0, j ) = j
next

for j = 1 to n
for i = 1 to m
if mid\$( aStr, i, 1 ) == mid\$( bStr, j, 1 )
distance( i, j ) = distance( i-1, j-1 )
else
min = distance( i-1, j   ) + 1
k   = distance( i, j - 1 ) + 1
l   = distance( i-1, j-1 ) + 1
if k < min then min = k
if l < min then min = l
distance( i, j ) = min
end if
next
next
end fn = distance( m, n )

dim as long i
dim as Str255 testStr( 5, 2 )

testStr( 0, 0 ) = "kitten"      : testStr( 0, 1 ) = "sitting"
testStr( 1, 0 ) = "rosettacode" : testStr( 1, 1 ) = "raisethysword"
testStr( 2, 0 ) = "Saturday"    : testStr( 2, 1 ) = "Sunday"
testStr( 3, 0 ) = "FutureBasic" : testStr( 3, 1 ) = "FutureBasic"
testStr( 4, 0 ) = "here's a bunch of words"
testStr( 4, 1 ) = "to wring out this code"

for i = 0 to 4
print "1st string = "; testStr( i, 0 )
print "2nd string = "; testStr( i, 1 )
print "Levenshtein distance ="; fn LevenshteinDistance( testStr( i, 0 ), testStr( i, 1 ) )
print
next

```

Output:

```
1st string = kitten
2nd string = sitting
Levenshtein distance = 3

1st string = rosettacode
2nd string = raisethysword
Levenshtein distance = 8

1st string = Saturday
2nd string = Sunday
Levenshtein distance = 3

1st string = FutureBasic
2nd string = FutureBasic
Levenshtein distance = 0

1st string = here's a bunch of words
2nd string = to wring out this code
Levenshtein distance = 18

```

## Go

WP algorithm:

```package main

import "fmt"

func main() {
fmt.Println(ld("kitten", "sitting"))
}

func ld(s, t string) int {
d := make([][]int, len(s)+1)
for i := range d {
d[i] = make([]int, len(t)+1)
}
for i := range d {
d[i][0] = i
}
for j := range d[0] {
d[0][j] = j
}
for j := 1; j <= len(t); j++ {
for i := 1; i <= len(s); i++ {
if s[i-1] == t[j-1] {
d[i][j] = d[i-1][j-1]
} else {
min := d[i-1][j]
if d[i][j-1] < min {
min = d[i][j-1]
}
if d[i-1][j-1] < min {
min = d[i-1][j-1]
}
d[i][j] = min + 1
}
}

}
return d[len(s)][len(t)]
}
```

{{out}}

```
3

```

{{trans|C}}

```package main

import "fmt"

func levenshtein(s, t string) int {
if s == "" { return len(t) }
if t == "" { return len(s) }
if s[0] == t[0] {
return levenshtein(s[1:], t[1:])
}
a := levenshtein(s[1:], t[1:])
b := levenshtein(s,     t[1:])
c := levenshtein(s[1:], t)
if a > b { a = b }
if a > c { a = c }
return a + 1
}

func main() {
s1 := "rosettacode"
s2 := "raisethysword"
fmt.Printf("distance between %s and %s: %d\n", s1, s2,
levenshtein(s1, s2))
}
```

{{out}}

```
distance between rosettacode and raisethysword: 8

```

## Groovy

```def distance(String str1, String str2) {
def dist = new int[str1.size() + 1][str2.size() + 1]
(0..str1.size()).each { dist[it][0] = it }
(0..str2.size()).each { dist[0][it] = it }

(1..str1.size()).each { i ->
(1..str2.size()).each { j ->
dist[i][j] = [dist[i - 1][j] + 1, dist[i][j - 1] + 1, dist[i - 1][j - 1] + ((str1[i - 1] == str2[j - 1]) ? 0 : 1)].min()
}
}
return dist[str1.size()][str2.size()]
}

[ ['kitten', 'sitting']: 3,
['rosettacode', 'raisethysword']: 8,
['edocattesor', 'drowsyhtesiar']: 8 ].each { key, dist ->
println "Checking distance(\${key[0]}, \${key[1]}) == \$dist"
assert distance(key[0], key[1]) == dist
}
```

{{out}}

```
Checking distance(kitten, sitting) == 3
Checking distance(rosettacode, raisethysword) == 8
Checking distance(edocattesor, drowsyhtesiar) == 8

```

``` [a] -> [a] -> Int
levenshtein s1 s2 = last \$ foldl transform [0 .. length s1] s2
where
transform ns@(n:ns1) c = scanl calc (n + 1) \$ zip3 s1 ns ns1
where
calc z (c1, x, y) = minimum [y + 1, z + 1, x + fromEnum (c1 /= c)]

main :: IO ()
main = print (levenshtein "kitten" "sitting")
```

{{Out}}

```3
```

```procedure main()
every process(!&input)
end

procedure process(s)
s ? (s1 := tab(upto(' \t')), s2 := (tab(many(' \t')), tab(0))) | fail
write("'",s1,"' -> '",s2,"' = ", levenshtein(s1,s2))
end

procedure levenshtein(s, t)
if (n := *s+1) = 1 then return *t
if (m := *t+1) = 1 then return *s

every !(d := list(n,0)) := list(m, 0)
every i := 1 to max(n,m) do d[i,1] := d[1,i] := i
every d[1(i := 2 to n, s_i := s[iM1 := i-1]), j := 2 to m] :=
min(d[iM1,j], d[i,jM1:=j-1],
d[iM1,jM1] + if s_i == t[jM1] then -1 else 0) + 1

return d[n,m]-1
end
```

{{out|Example}}

```
->leven
kitten  sitting
'kitten' -> 'sitting' = 3
->

```

## Io

A `levenshtein` method is available on strings when the standard `Range` addon is loaded. Io 20110905 Io> Range ; "kitten" levenshtein("sitting") ==> 3 Io> "rosettacode" levenshtein("raisethysword") ==> 8 Io>

```

## J

One approach would be a literal transcription of the [[wp:Levenshtein_distance#Computing_Levenshtein_distance|wikipedia implementation]]:

```j
levenshtein=:4 :0
D=. x +/&i.&>:&# y
for_i.1+i.#x do.
for_j.1+i.#y do.
if. ((<:i){x)=(<:j){y do.
D=.(D {~<<:i,j) (<i,j)} D
else.
min=. 1+<./D{~(i,j) <@:-"1#:1 2 3
D=. min (<i,j)} D
end.
end.
end.
{:{:D
)
```

However, this is a rather slow and bulky approach. Another alternative would be:

```levD=: i.@-@>:@#@] ,~ >:@i.@-@#@[ ,.~ ~:/
lev=: [: {. {."1@((1&{ ,~ (1 1 , {.) <./@:+ }.)@,/\.)@,./@levD
```

First, we setup up an matrix of costs, with 0 or 1 for unexplored cells (1 being where the character pair corresponding to that cell position has two different characters). Note that the "cost to reach the empty string" cells go on the bottom and the right, instead of the top and the left, because this works better with J's "[http://www.jsoftware.com/help/dictionary/d420.htm insert]" operation (which we will call "reduce" in the next paragraph here. It could also be thought of as a right fold which has been constrained such the initial value is the identity value for the operation. Or, just think of it as inserting its operation between each item of its argument...).

Then we reduce the rows of that matrix using an operation that treats those two rows as columns and reduces the rows of this derived matrix with an operation that gives the (unexplored cell + the minumum of the other cells) followed by (the cell adjacent to the previously unexplored cell. {{out|Example use}}

```   'kitten' levenshtein 'sitting'
3
'kitten' lev 'sitting'
3
```

Time and space use:

```   ts=: 6!:2,7!:2
ts '''kitten'' levenshtein ''sitting'''
0.00153132 12800
ts '''kitten'' lev ''sitting'''
0.000132101 5376
```

(The J flavored variant winds up being about 10 times faster, in J, for this test case, than the explicit version.)

See the [[j:Essays/Levenshtein Distance|Levenshtein distance essay]] on the Jwiki for additional solutions.

## Java

Based on the definition for Levenshtein distance given in the Wikipedia article:

```public class Levenshtein {

public static int distance(String a, String b) {
a = a.toLowerCase();
b = b.toLowerCase();
// i == 0
int [] costs = new int [b.length() + 1];
for (int j = 0; j < costs.length; j++)
costs[j] = j;
for (int i = 1; i <= a.length(); i++) {
// j == 0; nw = lev(i - 1, j)
costs[0] = i;
int nw = i - 1;
for (int j = 1; j <= b.length(); j++) {
int cj = Math.min(1 + Math.min(costs[j], costs[j - 1]), a.charAt(i - 1) == b.charAt(j - 1) ? nw : nw + 1);
nw = costs[j];
costs[j] = cj;
}
}
return costs[b.length()];
}

public static void main(String [] args) {
String [] data = { "kitten", "sitting", "saturday", "sunday", "rosettacode", "raisethysword" };
for (int i = 0; i < data.length; i += 2)
System.out.println("distance(" + data[i] + ", " + data[i+1] + ") = " + distance(data[i], data[i+1]));
}
}
```

{{out}}

```distance(kitten, sitting) = 3
distance(saturday, sunday) = 3
distance(rosettacode, raisethysword) = 8

```

{{trans|C}}

```public class Levenshtein{
public static int levenshtein(String s, String t){
/* if either string is empty, difference is inserting all chars
* from the other
*/
if(s.length() == 0) return t.length();
if(t.length() == 0) return s.length();

/* if first letters are the same, the difference is whatever is
* required to edit the rest of the strings
*/
if(s.charAt(0) == t.charAt(0))
return levenshtein(s.substring(1), t.substring(1));

/* else try:
*      changing first letter of s to that of t,
*      remove first letter of s, or
*      remove first letter of t
*/
int a = levenshtein(s.substring(1), t.substring(1));
int b = levenshtein(s, t.substring(1));
int c = levenshtein(s.substring(1), t);

if(a > b) a = b;
if(a > c) a = c;

//any of which is 1 edit plus editing the rest of the strings
return a + 1;
}

public static void main(String[] args) {
String s1 = "kitten";
String s2 = "sitting";
System.out.println("distance between '" + s1 + "' and '"
+ s2 + "': " + levenshtein(s1, s2));
s1 = "rosettacode";
s2 = "raisethysword";
System.out.println("distance between '" + s1 + "' and '"
+ s2 + "': " + levenshtein(s1, s2));
StringBuilder sb1 = new StringBuilder(s1);
StringBuilder sb2 = new StringBuilder(s2);
System.out.println("distance between '" + sb1.reverse() + "' and '"
+ sb2.reverse() + "': "
+ levenshtein(sb1.reverse().toString(), sb2.reverse().toString()));
}
}
```

{{out}}

```distance between 'kitten' and 'sitting': 3
distance between 'rosettacode' and 'raisethysword': 8
distance between 'edocattesor' and 'drowsyhtesiar': 8
```

===Iterative space optimized (even bounded) === {{trans|Python}}

```
import static java.lang.Math.abs;
import static java.lang.Math.max;

public class Levenshtein {

public static int ld(String a, String b) {
return distance(a, b, -1);
}
public static boolean ld(String a, String b, int max) {
return distance(a, b, max) <= max;
}

private static int distance(String a, String b, int max) {
if (a == b) return 0;
int la = a.length();
int lb = b.length();
if (max >= 0 && abs(la - lb) > max) return max+1;
if (la == 0) return lb;
if (lb == 0) return la;
if (la < lb) {
int tl = la; la = lb; lb = tl;
String ts = a;  a = b; b = ts;
}

int[] cost = new int[lb+1];
for (int i=1; i<=la; i+=1) {
cost[0] = i;
int prv = i-1;
int min = prv;
for (int j=1; j<=lb; j+=1) {
int act = prv + (a.charAt(i-1) == b.charAt(j-1) ? 0 : 1);
cost[j] = min(1+(prv=cost[j]), 1+cost[j-1], act);
if (prv < min) min = prv;
}
if (max >= 0 && min > max) return max+1;
}
if (max >= 0 && cost[lb] > max) return max+1;
return cost[lb];
}

private static int min(int ... a) {
int min = Integer.MAX_VALUE;
for (int i: a) if (i<min) min = i;
return min;
}

public static void main(String[] args) {
System.out.println(
ld("kitten","kitten") + " " + // 0
ld("kitten","sitten") + " " + // 1
ld("kitten","sittes") + " " + // 2
ld("kitten","sityteng") + " " + // 3
ld("kitten","sittYing") + " " + // 4
ld("rosettacode","raisethysword") + " " + // 8
ld("kitten","kittenaaaaaaaaaaaaaaaaa") + " " + // 17
ld("kittenaaaaaaaaaaaaaaaaa","kitten") // 17
);
System.out.println(
ld("kitten","kitten", 3) + " " + // true
ld("kitten","sitten", 3) + " " + // true
ld("kitten","sittes", 3) + " " + // true
ld("kitten","sityteng", 3) + " " + // true
ld("kitten","sittYing", 3) + " " + // false
ld("rosettacode","raisethysword", 3) + " " + // false
ld("kitten","kittenaaaaaaaaaaaaaaaaa", 3) + " " + // false
ld("kittenaaaaaaaaaaaaaaaaa","kitten", 3) // false
);
}
}

```

{{out}}

```
0 1 2 3 4 8 17 17
true true true true false false false false

```

## JavaScript

### ES5

Iterative:

```function levenshtein(a, b) {
var t = [], u, i, j, m = a.length, n = b.length;
if (!m) { return n; }
if (!n) { return m; }
for (j = 0; j <= n; j++) { t[j] = j; }
for (i = 1; i <= m; i++) {
for (u = [i], j = 1; j <= n; j++) {
u[j] = a[i - 1] === b[j - 1] ? t[j - 1] : Math.min(t[j - 1], t[j], u[j - 1]) + 1;
} t = u;
} return u[n];
}

// tests
[ ['', '', 0],
['yo', '', 2],
['', 'yo', 2],
['yo', 'yo', 0],
['tier', 'tor', 2],
['saturday', 'sunday', 3],
['mist', 'dist', 1],
['tier', 'tor', 2],
['kitten', 'sitting', 3],
['stop', 'tops', 2],
['rosettacode', 'raisethysword', 8],
['mississippi', 'swiss miss', 8]
].forEach(function(v) {
var a = v[0], b = v[1], t = v[2], d = levenshtein(a, b);
if (d !== t) {
console.log('levenstein("' + a + '","' + b + '") was ' + d + ' should be ' + t);
}
});
```

### ES6

By composition of generic functions:

```(() => {
'use strict';

// levenshtein :: String -> String -> Int
const levenshtein = (sa, sb) => {
const [s1, s2] = [sa.split(''), sb.split('')];

return last(s2.reduce((ns, c) => {
const [n, ns1] = uncons(ns);

return scanl(
(z, [c1, x, y]) =>
minimum(
[y + 1, z + 1, x + fromEnum(c1 != c)]
),
n + 1,
zip3(s1, ns, ns1)
);
}, range(0, s1.length)));
};

/*********************************************************************/
// GENERIC FUNCTIONS

// minimum :: [a] -> a
const minimum = xs =>
xs.reduce((a, x) => (x < a || a === undefined ? x : a), undefined);

// fromEnum :: Enum a => a -> Int
const fromEnum = x => {
const type = typeof x;
return type === 'boolean' ? (
x ? 1 : 0
) : (type === 'string' ? x.charCodeAt(0) : undefined);
};

// uncons :: [a] -> Maybe (a, [a])
const uncons = xs => xs.length ? [xs[0], xs.slice(1)] : undefined;

// scanl :: (b -> a -> b) -> b -> [a] -> [b]
const scanl = (f, a, xs) => {
for (var lst = [a], lng = xs.length, i = 0; i < lng; i++) {
a = f(a, xs[i], i, xs), lst.push(a);
}
return lst;
};

// zip3 :: [a] -> [b] -> [c] -> [(a,b,c)]
const zip3 = (xs, ys, zs) =>
xs.slice(0, Math.min(xs.length, ys.length, zs.length))
.map((x, i) => [x, ys[i], zs[i]]);

// last :: [a] -> a
const last = xs => xs.length ? xs.slice(-1) : undefined;

// range :: Int -> Int -> [Int]
const range = (m, n) =>
Array.from({
length: Math.floor(n - m) + 1
}, (_, i) => m + i);

/*********************************************************************/
// TEST
return [
["kitten", "sitting"],
["sitting", "kitten"],
["rosettacode", "raisethysword"],
["raisethysword", "rosettacode"]
].map(pair => levenshtein.apply(null, pair));

// -> [3, 3, 8, 8]
})();
```

{{Out}}

```[3, 3, 8, 8]
```

## jq

The main point of interest about the following implementation is that it shows how the naive recursive algorithm can be tweaked within a completely functional framework to yield an efficient implementation.

'''Performance''': Here is a breakdown of the run-times on a 2.53GHz machine:

9ms overhead (invoking jq and compiling the program) 17ms for kitten/sitting 67ms for rosettacode/raisethysword 71ms for edocattesor/drowsyhtesiar

```
# lookup the distance between s and t in the nested cache,
# which uses basic properties of the Levenshtein distance to save space:
def lookup(s;t):
if (s == t) then 0
elif (s|length) == 0 then (t|length)
elif (t|length) == 0 then (s|length)
elif (s|length) > (t|length) then
.[t] as \$t | if \$t then \$t[s] else null end
else .[s] as \$s | if \$s then \$s[t] else null end
end ;

# output is the updated cache;
# basic properties of the Levenshtein distance are used to save space:
def store(s;t;value):
if (s == t) then .
else (s|length) as \$s | (t|length) as \$t
| if \$s == 0 or \$t == 0 then .
elif \$s < \$t then .[s][t] = value
elif \$t < \$s then .[t][s] = value
else (.[s][t] = value) | (.[t][s] = value)
end
end ;

# Input is a cache of nested objects; output is [distance, cache]
def ld(s1; s2):

# emit [distance, cache]
# input: cache
def cached_ld(s;t):
lookup(s;t) as \$check
| if \$check then [ \$check, . ]
else ld(s;t)
end
;

# If either string is empty,
# then distance is insertion of the other's characters.
if   (s1|length) == 0 then [(s2|length), .]
elif (s2|length) == 0 then [(s1|length), .]
elif (s1[0:1] == s2[0:1]) then
cached_ld(s1[1:]; s2[1:])
else
cached_ld(s1[1:]; s2) as \$a
| (\$a[1] | cached_ld(s1; s2[1:])) as \$b
| (\$b[1] | cached_ld(s1[1:]; s2[1:])) as \$c
| [\$a[0], \$b[0], \$c[0]] | (min + 1) as \$d
| [\$d, (\$c[1] | store(s1;s2;\$d)) ]
end ;

def levenshteinDistance(s;t):
s as \$s | t as \$t | {} | ld(\$s;\$t) | .[0];
```

```def demo:
"levenshteinDistance between \(.[0]) and \(.[1]) is \( levenshteinDistance(.[0]; .[1]) )";

(["kitten", "sitting"] | demo),
(["rosettacode","raisethysword"] | demo),
(["edocattesor", "drowsyhtesiar"] | demo),
(["this_algorithm_is_similar_to",
"Damerau-Levenshtein_distance"] | demo)
```

{{Out}} levenshteinDistance between kitten and sitting is 3 levenshteinDistance between rosettacode and raisethysword is 8 levenshteinDistance between edocattesor and drowsyhtesiar is 8

## Jsish

From Javascript, ES5 entry.

```/* Levenshtein Distance, in Jsish */

function levenshtein(a, b) {
var t = [], u, i, j, m = a.length, n = b.length;
if (!m) { return n; }
if (!n) { return m; }
for (j = 0; j <= n; j++) { t[j] = j; }
for (i = 1; i <= m; i++) {
for (u = [i], j = 1; j <= n; j++) {
u[j] = a[i - 1] === b[j - 1] ? t[j - 1] : Math.min(t[j - 1], t[j], u[j - 1]) + 1;
} t = u;
} return u[n];
}

provide('levenshtein', 1);

;levenshtein('', '');
;levenshtein('yo', '');
;levenshtein('', 'yo');
;levenshtein('yo', 'yo');
;levenshtein('tier', 'tor');
;levenshtein('saturday', 'sunday');
;levenshtein('mist', 'dist');
;levenshtein('tier', 'tor');
;levenshtein('kitten', 'sitting');
;levenshtein('stop', 'tops');
;levenshtein('rosettacode', 'raisethysword');
;levenshtein('mississippi', 'swiss miss');

/*
=!EXPECTSTART!=
levenshtein('', '') ==> 0
levenshtein('yo', '') ==> 2
levenshtein('', 'yo') ==> 2
levenshtein('yo', 'yo') ==> 0
levenshtein('tier', 'tor') ==> 2
levenshtein('saturday', 'sunday') ==> 3
levenshtein('mist', 'dist') ==> 1
levenshtein('tier', 'tor') ==> 2
levenshtein('kitten', 'sitting') ==> 3
levenshtein('stop', 'tops') ==> 2
levenshtein('rosettacode', 'raisethysword') ==> 8
levenshtein('mississippi', 'swiss miss') ==> 8
=!EXPECTEND!=
*/
```

{{out}}

```prompt\$ jsish -u levenshtein.jsi
[PASS] levenshtein.jsi
```

## Julia

'''Recursive''': {{works with|Julia|1.0}}

```function levendist(s::AbstractString, t::AbstractString)
ls, lt = length.((s, t))
ls == 0 && return lt
lt == 0 && return ls

s₁, t₁ = s[2:end], t[2:end]
ld₁ = levendist(s₁, t₁)
s[1] == t[1] ? ld₁ : 1 + min(ld₁, levendist(s, t₁), levendist(s₁, t))
end

@show levendist("kitten", "sitting") # 3
@show levendist("rosettacode", "raisethysword") # 8
```

'''Iterative''': {{works with|Julia|0.6}}

```function levendist1(s::AbstractString, t::AbstractString)
ls, lt = length(s), length(t)
if ls > lt
s, t = t, s
ls, lt = lt, ls
end
dist = collect(0:ls)
for (ind2, chr2) in enumerate(t)
newdist = Vector{Int}(ls+1)
newdist[1] = ind2
for (ind1, chr1) in enumerate(s)
if chr1 == chr2
newdist[ind1+1] = dist[ind1]
else
newdist[ind1+1] = 1 + min(dist[ind1], dist[ind1+1], newdist[end])
end
end
dist = newdist
end
return dist[end]
end
```

Let's see some benchmark:

```using BenchmarkTools
println("\n# levendist(kitten, sitting)")
s, t = "kitten", "sitting"
println(" - Recursive:")
@btime levendist(s, t)
println(" - Iterative:")
@btime levendist1(s, t)
println("\n# levendist(rosettacode, raisethysword)")
s, t = "rosettacode", "raisethysword"
println(" - Recursive:")
@btime levendist(s, t)
println(" - Iterative:")
@btime levendist1(s, t)
```

{{out}}

```
# levendist(kitten, sitting)
- Recursive:
78.788 μs (1103 allocations: 34.47 KiB)
- Iterative:
494.376 ns (9 allocations: 1.16 KiB)

# levendist(rosettacode, raisethysword)
- Recursive:
317.817 ms (3468524 allocations: 105.85 MiB)
- Iterative:
1.168 μs (15 allocations: 2.44 KiB)
```

## Kotlin

### Standard Version

```// version 1.0.6

// Uses the "iterative with two matrix rows" algorithm referred to in the Wikipedia article.

fun levenshtein(s: String, t: String): Int {
// degenerate cases
if (s == t)  return 0
if (s == "") return t.length
if (t == "") return s.length

// create two integer arrays of distances and initialize the first one
val v0 = IntArray(t.length + 1) { it }  // previous
val v1 = IntArray(t.length + 1)         // current

var cost: Int
for (i in 0 until s.length) {
// calculate v1 from v0
v1[0] = i + 1
for (j in 0 until t.length) {
cost = if (s[i] == t[j]) 0 else 1
v1[j + 1] = Math.min(v1[j] + 1, Math.min(v0[j + 1] + 1, v0[j] + cost))
}
// copy v1 to v0 for next iteration
for (j in 0 .. t.length) v0[j] = v1[j]
}
return v1[t.length]
}

fun main(args: Array<String>) {
println("'kitten' to 'sitting'            => \${levenshtein("kitten", "sitting")}")
println("'rosettacode' to 'raisethysword' => \${levenshtein("rosettacode", "raisethysword")}")
println("'sleep' to 'fleeting'            => \${levenshtein("sleep", "fleeting")}")
}
```

{{out}}

```
'kitten' to 'sitting'            => 3
'rosettacode' to 'raisethysword' => 8
'sleep' to 'fleeting'            => 5

```

### Functional/Folding Version

```
fun levenshtein(s: String, t: String,
charScore : (Char, Char) -> Int = { c1, c2 -> if (c1 == c2) 0 else 1}) : Int {

// Special cases
if (s == t)  return 0
if (s == "") return t.length
if (t == "") return s.length

val initialRow : List<Int> = (0 until t.length + 1).map { it }.toList()
return (0 until s.length).fold(initialRow, { previous, u ->
(0 until t.length).fold( mutableListOf(u+1), {
row, v -> row.add(minOf(row.last() + 1,
previous[v+1] + 1,
previous[v] + charScore(s[u],t[v])))
row
})
}).last()

}

```

{{out}}

```
'kitten' to 'sitting'            => 3
'rosettacode' to 'raisethysword' => 8
'sleep' to 'fleeting'            => 5

```

## LFE

### Simple Implementation

Suitable for short strings:

```
(defun levenshtein-simple
(('() str)
(length str))
((str '())
(length str))
(((cons a str1) (cons b str2)) (when (== a b))
(levenshtein-simple str1 str2))
(((= (cons _ str1-tail) str1) (= (cons _ str2-tail) str2))
(+ 1 (lists:min
(list
(levenshtein-simple str1 str2-tail)
(levenshtein-simple str1-tail str2)
(levenshtein-simple str1-tail str2-tail))))))

```

You can copy and paste that function into an LFE REPL and run it like so:

```
> (levenshtein-simple "a" "a")
0
> (levenshtein-simple "a" "")
1
> (levenshtein-simple "" "a")
1
> (levenshtein-simple "kitten" "sitting")
3

```

It is not recommended to test strings longer than the last example using this implementation, as performance quickly degrades.

### Cached Implementation

```
(defun levenshtein-distance (str1 str2)
(let (((tuple distance _) (levenshtein-distance
str1 str2 (dict:new))))
distance))

(defun levenshtein-distance
(((= '() str1) str2 cache)
(tuple (length str2)
(dict:store (tuple str1 str2)
(length str2)
cache)))
((str1 (= '() str2) cache)
(tuple (length str1)
(dict:store (tuple str1 str2)
(length str1)
cache)))
(((cons a str1) (cons b str2) cache) (when (== a b))
(levenshtein-distance str1 str2 cache))
(((= (cons _ str1-tail) str1) (= (cons _ str2-tail) str2) cache)
(case (dict:is_key (tuple str1 str2) cache)
('true (tuple (dict:fetch (tuple str1 str2) cache) cache))
('false (let* (((tuple l1 c1) (levenshtein-distance str1 str2-tail cache))
((tuple l2 c2) (levenshtein-distance str1-tail str2 c1))
((tuple l3 c3) (levenshtein-distance str1-tail str2-tail c2))
(len (+ 1 (lists:min (list l1 l2 l3)))))
(tuple len (dict:store (tuple str1 str2) len c3)))))))

```

As before, here's some usage in the REPL. Note that longer strings are now possible to compare without incurring long execution times:

```
> (levenshtein-distance "a" "a")
0
> (levenshtein-distance "a" "")
1
> (levenshtein-distance "" "a")
1
> (levenshtein-distance "kitten" "sitting")
3
> (levenshtein-distance "rosettacode" "raisethysword")
8

```

## Liberty BASIC

```'Levenshtein Distance translated by Brandon Parker
'08/19/10
'from http://www.merriampark.com/ld.htm#VB
'No credit was given to the Visual Basic Author on the site :-(

Print LevenshteinDistance("kitten", "sitting")
End

'Get the minum of three values
Function Minimum(a, b, c)
Minimum = Min(a, Min(b, c))
End Function

'Compute the Levenshtein Distance
Function LevenshteinDistance(string1\$, string2\$)
n = Len(string1\$)
m = Len(string2\$)
If n = 0 Then
LevenshteinDistance = m
Exit Function
End If
If m = 0 Then
LevenshteinDistance = n
Exit Function
End If
Dim d(n, m)
For i = 0 To n
d(i, 0) = i
Next i
For i = 0 To m
d(0, i) = i
Next i
For i = 1 To n
si\$ = Mid\$(string1\$, i, 1)
For ii = 1 To m
tj\$ = Mid\$(string2\$, ii, 1)
If si\$ = tj\$ Then
cost = 0
Else
cost = 1
End If
d(i, ii) = Minimum((d(i - 1, ii) + 1), (d(i, ii - 1) + 1), (d(i - 1, ii - 1) + cost))
Next ii
Next i
LevenshteinDistance = d(n, m)
End Function
```

## Limbo

{{trans|Go}}

```implement Levenshtein;

include "sys.m"; sys: Sys;
print: import sys;
include "draw.m";

Levenshtein: module {
init: fn(nil: ref Draw->Context, args: list of string);
# Export distance so that this module can be used as either a
# standalone program or as a library:
distance: fn(s, t: string): int;
};

init(nil: ref Draw->Context, args: list of string)
{
if(!(len args % 2)) {
sys->fprint(sys->fildes(2), "Provide an even number of arguments!\n");
raise "fail:usage";
}
args = tl args;

while(args != nil) {
(s, t) := (hd args, hd tl args);
args = tl tl args;
print("%s <-> %s => %d\n", s, t, distance(s, t));
}
}

distance(s, t: string): int
{
if(s == "")
return len t;
if(t == "")
return len s;
if(s[0] == t[0])
return distance(s[1:], t[1:]);
a := distance(s[1:], t);
b := distance(s, t[1:]);
c := distance(s[1:], t[1:]);
if(a > b)
a = b;
if(a > c)
a = c;
return a + 1;
}

```

{{output}} ``` % levenshtein kitten sitting rosettacode raisethysword kitten <-> sitting => 3 rosettacode <-> raisethysword => 8 ```

## LiveCode

{{trans|Go}}

```
//Code By Neurox66
function Levenshtein pString1 pString2
put 0 into tPosChar1
repeat for each char tChar1 in pString1
put tPosChar1 into tDistance[tPosChar1][0]
put 0 into tPosChar2
repeat for each char tChar2 in pString2
put tPosChar2 into tDistance[0][tPosChar2]
put 1 into tCost
if tChar1 = tChar2 then
put 0 into tCost
end if
put min((tDistance[tPosChar1-1][tPosChar2] + 1),(tDistance[tPosChar1][tPosChar2-1] + 1),(tDistance[tPosChar1-1][tPosChar2-1] + tCost)) into tDistance[tPosChar1][tPosChar2]
end repeat
end repeat
return tDistance[tPosChar1][tPosChar2]
end Levenshtein

put Levenshtein("kitten","sitting")
put Levenshtein("rosettacode","raisethysword")

```

{{out}}

```3
8
```

## Lua

```function leven(s,t)
if s == '' then return t:len() end
if t == '' then return s:len() end

local s1 = s:sub(2, -1)
local t1 = t:sub(2, -1)

if s:sub(0, 1) == t:sub(0, 1) then
return leven(s1, t1)
end

return 1 + math.min(
leven(s1, t1),
leven(s,  t1),
leven(s1, t )
)
end

print(leven("kitten", "sitting"))
print(leven("rosettacode", "raisethysword"))
```

{{out}}

```3
8
```

## M2000 Interpreter

```
Module Checkit {
\\ Iterative with two matrix rows
function LevenshteinDistance(s\$,t\$) {
if len(s\$)<len(t\$) then swap s\$, t\$
n=len(t\$)
m=len(s\$)
dim base 0, v0(n+1), v1(n+1)
Rem		dim sw()  ' we can use stack of values to make the swap.
for i=0 to n : v0(i)=i:next
for i=0 to m-1
v1(0)=i+1
for j=0 to n-1
deletioncost=v0(j+1)+1
insertioncost=v1(j)+1
if mid\$(s\$,i+1,1)=mid\$(t\$,j+1,1) then
substitutionCost=v0(j)
else
substitutionCost=v0(j)+1
end if
v1(j+1)=min.data(deletionCost, insertionCost, substitutionCost)
next
Rem			sw()=v0():v0()=v1():v1()=sw()
\\ when we push arrays, we only push a pointer to
\\ when we read array (identifier with parenthesis) then we get a copy
\\ between Push and Read any change on arrays included in copies
next
=v0(n)
}
Print LevenshteinDistance("kitten","sitting")=3  ' true
Print LevenshteinDistance("Sunday","Saturday")=3  ' true
Print LevenshteinDistance("rosettacode","raisethysword")=8  ' true
}
Checkit

Module Checkit2 {
\\ Iterative with two matrix rows, using pointers to arrays
function LevenshteinDistance(s\$,t\$) {
if len(s\$)<len(t\$) then swap s\$, t\$
n=len(t\$)
m=len(s\$)
dim base 0, v0(n+1), v1(n+1)
v0=v0()  ' v0 is pointer to v0()
v1=v1() ' v1 is pointer to v1()
for i=0 to n : v0(i)=i:next
for i=0 to m-1
return v1, 0:=i+1
for j=0 to n-1
deletioncost=Array(v0,j+1)+1
insertioncost=Array(v1,j)+1
if mid\$(s\$,i+1,1)=mid\$(t\$,j+1,1) then
substitutionCost=Array(v0,j)
else
substitutionCost=Array(v0,j)+1
end if
return v1, j+1:=min.data(deletionCost, insertionCost, substitutionCost)
next
swap v0, v1  ' just swap pointers
next
=Array(v0,n)
}
Print LevenshteinDistance("kitten","sitting")=3
Print LevenshteinDistance("Sunday","Saturday")=3
Print LevenshteinDistance("rosettacode","raisethysword")=8
}
Checkit2

```

## Maple

```
> with(StringTools):
> Levenshtein("kitten","sitting");
3

> Levenshtein("rosettacode","raisethysword");
8

```

## Mathematica

```EditDistance["kitten","sitting"]
->3
EditDistance["rosettacode","raisethysword"]
->8
```

## MATLAB

```
function score = levenshtein(s1, s2)
% score = levenshtein(s1, s2)
%
% Calculates the area under the ROC for a given set
% of posterior predictions and labels. Currently limited to two classes.
%
% s1: string
% s2: string
% score: levenshtein distance
%
% Author: Ben Hamner ([email protected])
if length(s1) < length(s2)
score = levenshtein(s2, s1);
elseif isempty(s2)
score = length(s1);
else
previous_row = 0:length(s2);
for i=1:length(s1)
current_row = 0*previous_row;
current_row(1) = i;
for j=1:length(s2)
insertions = previous_row(j+1) + 1;
deletions = current_row(j) + 1;
substitutions = previous_row(j) + (s1(i) ~= s2(j));
current_row(j+1) = min([insertions, deletions, substitutions]);
end
previous_row = current_row;
end
score = current_row(end);
end

```

Source : [https://github.com/benhamner/Metrics/blob/master/MATLAB/metrics/levenshtein.m]

## NetRexx

{{trans|ooRexx}}

```/* NetRexx */
options replace format comments java crossref symbols nobinary

n = 0
w = ''
n = n + 1; w[0] = n; w[n] = "kitten sitting"
n = n + 1; w[0] = n; w[n] = "rosettacode raisethysword"

loop n = 1 to w[0]
say w[n].word(1) "->" w[n].word(2)":" levenshteinDistance(w[n].word(1), w[n].word(2))
end n
return

method levenshteinDistance(s, t) private static
s = s.lower
t = t.lower

m = s.length
n = t.length

-- for all i and j, d[i,j] will hold the Levenshtein distance between
-- the first i characters of s and the first j characters of t;
-- note that d has (m+1)x(n+1) values
d = 0

-- source prefixes can be transformed into empty string by
-- dropping all characters (Note, ooRexx arrays are 1-based)
loop i = 2 to m + 1
d[i, 1] = 1
end i

-- target prefixes can be reached from empty source prefix
-- by inserting every characters
loop j = 2 to n + 1
d[1, j] = 1
end j

loop j = 2 to n + 1
loop i = 2 to m + 1
if s.substr(i - 1, 1) == t.substr(j - 1, 1) then do
d[i, j] = d[i - 1, j - 1]   -- no operation required
end
else do
d[i, j] =                 -
(d[i - 1, j] + 1).min(  - -- a deletion
(d[i, j - 1] + 1)).min( - -- an insertion
(d[i - 1, j - 1] + 1))    -- a substitution
end
end i
end j

return d[m + 1, n + 1]

```

'''Output:'''

```
kitten -> sitting: 3
rosettacode -> raisethysword: 8

```

## Nim

```import strutils

echo editDistance("kitten","sitting")
echo editDistance("rosettacode","raisethysword")
```

{{out}}

```3
8
```

{{trans|Python}}

```import sequtils

proc levenshteinDistance(s1, s2): int =
var (s1, s2) = (s1, s2)

if s1.len > s2.len:
swap s1, s2

var distances = toSeq(0..s1.len)

for i2, c2 in s2:
var newDistances = @[i2+1]
for i1, c1 in s1:
if c1 == c2:
else:
newDistances[newDistances.high]))

distances = newDistances
result = distances[distances.high]

echo levenshteinDistance("kitten","sitting")
echo levenshteinDistance("rosettacode","raisethysword")
```

## Objeck

{{trans|C#}}

```class Levenshtein {
function : Main(args : String[]) ~ Nil {
if(args->Size() = 2) {
s := args[0]; t := args[1]; d := Distance(s,t);
"{\$s} -> {\$t} = {\$d}"->PrintLine();
};
}

function : native : Distance(s : String,t : String) ~ Int {
d := Int->New[s->Size() + 1, t->Size() + 1];
for(i := 0; i <= s->Size(); i += 1;) {
d[i,0] := i;
};

for(j := 0; j <= t->Size(); j += 1;) {
d[0,j] := j;
};

for(j := 1; j <= t->Size(); j += 1;) {
for(i := 1; i <= s->Size(); i += 1;) {
if(s->Get(i - 1) = t->Get(j - 1)) {
d[i,j] := d[i - 1, j - 1];
}
else {
d[i,j] := (d[i - 1, j] + 1)
->Min(d[i, j - 1] + 1)
->Min(d[i - 1, j - 1] + 1);
};
};
};

return d[s->Size(), t->Size()];
}
}
```

=={{header|Objective-C}}== Translation of the C# code into a NSString category

```@interface NSString (levenshteinDistance)
- (NSUInteger)levenshteinDistanceToString:(NSString *)string;
@end

@implementation NSString (levenshteinDistance)
- (NSUInteger)levenshteinDistanceToString:(NSString *)string {
NSUInteger sl = [self length];
NSUInteger tl = [string length];
NSUInteger *d = calloc(sizeof(*d), (sl+1) * (tl+1));

#define d(i, j) d[((j) * sl) + (i)]
for (NSUInteger i = 0; i <= sl; i++) {
d(i, 0) = i;
}
for (NSUInteger j = 0; j <= tl; j++) {
d(0, j) = j;
}
for (NSUInteger j = 1; j <= tl; j++) {
for (NSUInteger i = 1; i <= sl; i++) {
if ([self characterAtIndex:i-1] == [string characterAtIndex:j-1]) {
d(i, j) = d(i-1, j-1);
} else {
d(i, j) = MIN(d(i-1, j), MIN(d(i, j-1), d(i-1, j-1))) + 1;
}
}
}

NSUInteger r = d(sl, tl);
#undef d

free(d);

return r;
}
@end
```

## OCaml

Translation of the pseudo-code of the Wikipedia article:

```let minimum a b c =
min a (min b c)

let levenshtein_distance s t =
let m = String.length s
and n = String.length t in
(* for all i and j, d.(i).(j) will hold the Levenshtein distance between
the first i characters of s and the first j characters of t *)
let d = Array.make_matrix (m+1) (n+1) 0 in

for i = 0 to m do
d.(i).(0) <- i  (* the distance of any first string to an empty second string *)
done;
for j = 0 to n do
d.(0).(j) <- j  (* the distance of any second string to an empty first string *)
done;

for j = 1 to n do
for i = 1 to m do

if s.[i-1] = t.[j-1] then
d.(i).(j) <- d.(i-1).(j-1)  (* no operation required *)
else
d.(i).(j) <- minimum
(d.(i-1).(j) + 1)   (* a deletion *)
(d.(i).(j-1) + 1)   (* an insertion *)
(d.(i-1).(j-1) + 1) (* a substitution *)
done;
done;

d.(m).(n)
;;

let test s t =
Printf.printf " %s -> %s = %d\n" s t (levenshtein_distance s t);
;;

let () =
test "kitten" "sitting";
test "rosettacode" "raisethysword";
;;
```

### A recursive functional version

This could be made faster with memoization

```let levenshtein s t =
let rec dist i j = match (i,j) with
| (i,0) -> i
| (0,j) -> j
| (i,j) ->
if s.[i-1] = t.[j-1] then dist (i-1) (j-1)
else let d1, d2, d3 = dist (i-1) j, dist i (j-1), dist (i-1) (j-1) in
1 + min d1 (min d2 d3)
in
dist (String.length s) (String.length t)

let test s t =
Printf.printf " %s -> %s = %d\n" s t (levenshtein s t)

let () =
test "kitten" "sitting";
test "rosettacode" "raisethysword";
```

{{out}}

```
kitten -> sitting = 3
rosettacode -> raisethysword = 8

```

## ooRexx

```
say "kitten -> sitting:" levenshteinDistance("kitten", "sitting")
say "rosettacode -> raisethysword:" levenshteinDistance("rosettacode", "raisethysword")

::routine levenshteinDistance
use arg s, t
s = s~lower
t = t~lower

m = s~length
n = t~length

-- for all i and j, d[i,j] will hold the Levenshtein distance between
-- the first i characters of s and the first j characters of t;
-- note that d has (m+1)x(n+1) values
d = .array~new(m + 1, n + 1)

-- clear all elements in d
loop i = 1 to d~dimension(1)
loop j = 1 to d~dimension(2)
d[i, j] = 0
end
end

-- source prefixes can be transformed into empty string by
-- dropping all characters (Note, ooRexx arrays are 1-based)
loop i = 2 to m + 1
d[i, 1] = 1
end

-- target prefixes can be reached from empty source prefix
-- by inserting every characters
loop j = 2 to n + 1
d[1, j] = 1
end

loop j = 2 to n + 1
loop i = 2 to m + 1
if s~subchar(i - 1) == t~subchar(j - 1) then
d[i, j] = d[i - 1, j - 1]   -- no operation required
else d[i, j] = min(d[i - 1, j] + 1,    - -- a deletion
d[i, j-1] + 1,      - -- an insertion
d[i - 1, j - 1] + 1)  -- a substitution
end
end

return d[m + 1, n + 1 ]

```

Output:

```
kitten -> sitting: 3
rosettacode -> raisethysword: 8

```

## PARI/GP

{{trans|JavaScript}} {{Works with|PARI/GP|2.7.4 and above}}

```
\\ Levenshtein distance between two words
\\ 6/21/16 aev
levensDist(s1,s2)={
my(n1=#s1,n2=#s2,v1=Vecsmall(s1),v2=Vecsmall(s2),c,
n11=n1+1,n21=n2+1,t=vector(n21,z,z-1),u0=vector(n21),u=u0);
if(s1==s2, return(0)); if(!n1, return(n2)); if(!n2, return(n1));
for(i=2,n11, u=u0; u[1]=i-1;
for(j=2,n21,
if(v1[i-1]==v2[j-1], c=t[j-1], c=vecmin([t[j-1],t[j],u[j-1]])+1);
u[j]=c;
);\\fend j
t=u;
);\\fend i
print(" *** Levenshtein distance = ",t[n21]," for strings: ",s1,", ",s2);
return(t[n21]);
}
{ \\ Testing:
levensDist("kitten","sitting");
levensDist("rosettacode","raisethysword");
levensDist("Saturday","Sunday");
levensDist("oX","X");
levensDist("X","oX");
}

```

{{Output}}

```
*** Levenshtein distance = 3 for strings: kitten, sitting
*** Levenshtein distance = 8 for strings: rosettacode, raisethysword
*** Levenshtein distance = 3 for strings: Saturday, Sunday
*** Levenshtein distance = 1 for strings: oX, X
*** Levenshtein distance = 1 for strings: X, oX

```

## Pascal

A fairly direct translation of the wikipedia pseudo code:

```Program LevenshteinDistanceDemo(output);

uses
Math;

function LevenshteinDistance(s, t: string): longint;
var
d: array of array of integer;
i, j, n, m: integer;
begin
n := length(t);
m := length(s);
setlength(d, m+1, n+1);

for i := 0 to m do
d[i,0] := i;
for j := 0 to n do
d[0,j] := j;
for j := 1 to n do
for i := 1 to m do
if s[i] = t[j] then
d[i,j] := d[i-1,j-1]
else
d[i,j] := min(d[i-1,j] + 1, min(d[i,j-1] + 1, d[i-1,j-1] + 1));
LevenshteinDistance := d[m,n];
end;

var
s1, s2: string;

begin
s1 := 'kitten';
s2 := 'sitting';
writeln('The Levenshtein distance between "', s1, '" and "', s2, '" is: ', LevenshteinDistance(s1, s2));
s1 := 'rosettacode';
s2 := 'raisethysword';
writeln('The Levenshtein distance between "', s1, '" and "', s2, '" is: ', LevenshteinDistance(s1, s2));
end.
```

{{out}}

```
The Levenshtein distance between "kitten" and "sitting" is: 3
The Levenshtein distance between "rosettacode" and "raisethysword" is: 8

```

## Perl

Recursive algorithm, as in the C sample. You are invited to comment out the line where it says so, and see the speed difference. By the way, there's the `Memoize` standard module, but it requires setting quite a few parameters to work right for this example, so I'm just showing the simple minded caching scheme here.

```use List::Util qw(min);

my %cache;

sub leven {
my (\$s, \$t) = @_;

return length(\$t) if \$s eq '';
return length(\$s) if \$t eq '';

\$cache{\$s}{\$t} //=    # try commenting out this line
do {
my (\$s1, \$t1) = (substr(\$s, 1), substr(\$t, 1));

(substr(\$s, 0, 1) eq substr(\$t, 0, 1))
? leven(\$s1, \$t1)
: 1 + min(
leven(\$s1, \$t1),
leven(\$s,  \$t1),
leven(\$s1, \$t ),
);
};
}

print leven('rosettacode', 'raisethysword'), "\n";
```

Iterative solution:

```use List::Util qw(min);

sub leven {
my (\$s, \$t) = @_;

my \$tl = length(\$t);
my \$sl = length(\$s);

my @d = ([0 .. \$tl], map { [\$_] } 1 .. \$sl);

foreach my \$i (0 .. \$sl - 1) {
foreach my \$j (0 .. \$tl - 1) {
\$d[\$i + 1][\$j + 1] =
substr(\$s, \$i, 1) eq substr(\$t, \$j, 1)
? \$d[\$i][\$j]
: 1 + min(\$d[\$i][\$j + 1], \$d[\$i + 1][\$j], \$d[\$i][\$j]);
}
}

\$d[-1][-1];
}

print leven('rosettacode', 'raisethysword'), "\n";
```

## Perl 6

{{works with|rakudo|2015-09-16}} Implementation of the wikipedia algorithm. Since column 0 and row 0 are used for base distances, the original algorithm would require us to compare "@s[\$i-1] eq @t[\$j-1]", and reference the \$m and \$n separately. Prepending an unused value (undef) onto @s and @t makes their indices align with the \$i,\$j numbering of @d, and lets us use .end instead of \$m,\$n.

```sub levenshtein_distance ( Str \$s, Str \$t --> Int ) {
my @s = *, |\$s.comb;
my @t = *, |\$t.comb;

my @d;
@d[\$_;  0] = \$_ for ^@s.end;
@d[ 0; \$_] = \$_ for ^@t.end;

for [email protected] X [email protected] -> (\$i, \$j) {
@d[\$i; \$j] = @s[\$i] eq @t[\$j]
??   @d[\$i-1; \$j-1]    # No operation required when eq
!! ( @d[\$i-1; \$j  ],   # Deletion
@d[\$i  ; \$j-1],   # Insertion
@d[\$i-1; \$j-1],   # Substitution
).min + 1;
}

return @d[*-1][*-1];
}

my @a = [<kitten sitting>], [<saturday sunday>], [<rosettacode raisethysword>];

for @a -> [\$s, \$t] {
say "levenshtein_distance('\$s', '\$t') == ", levenshtein_distance(\$s, \$t);
}
```

{{out}}

```levenshtein_distance('kitten', 'sitting') == 3
levenshtein_distance('saturday', 'sunday') == 3
levenshtein_distance('rosettacode', 'raisethysword') == 8
```

## Phix

Copy of [[Levenshtein_distance#Euphoria|Euphoria]]

```function levenshtein(sequence s1, sequence s2)
integer n = length(s1)+1,
m = length(s2)+1
sequence d

if n=1  then
return m-1
elsif m=1 then
return n-1
end if

d = repeat(repeat(0, m), n)
for i=1 to n do
d[i][1] = i-1
end for

for j=1 to m do
d[1][j] = j-1
end for

for i=2 to n do
for j=2 to m do
d[i][j] = min({
d[i-1][j]+1,
d[i][j-1]+1,
d[i-1][j-1]+(s1[i-1]!=s2[j-1])
})
end for
end for

return d[n][m]
end function

?levenshtein("kitten", "sitting")
?levenshtein("rosettacode", "raisethysword")
```

{{out}}

```
3
8

```

## PHP

```
echo levenshtein('kitten','sitting');
echo levenshtein('rosettacode', 'raisethysword');

```

{{out}}

```3
8
```

## PicoLisp

Translation of the pseudo-code in the Wikipedia article:

```(de levenshtein (A B)
(let D
(cons
(range 0 (length A))
(mapcar
'((I) (cons I (copy A)))
(range 1 (length B)) ) )
(for (J . Y) B
(for (I . X) A
(set
(nth D (inc J) (inc I))
(if (= X Y)
(get D J I)
(inc
(min
(get D J (inc I))
(get D (inc J) I)
(get D J I) ) ) ) ) ) ) ) )
```

or, using 'map' to avoid list indexing:

```(de levenshtein (A B)
(let D
(cons
(range 0 (length A))
(mapcar
'((I) (cons I (copy A)))
(range 1 (length B)) ) )
(map
'((B Y)
(map
'((A X P)
(set (cdr P)
(if (= (car A) (car B))
(car X)
(inc (min (cadr X) (car P) (car X))) ) ) )
A
(car Y)
B
D ) ) )
```

{{out|Output (both cases)}}

```: (levenshtein (chop "kitten") (chop "sitting"))
-> 3
```

## PL/I

### version 1

```*process source xref attributes or(!);
lsht: Proc Options(main);
Call test('kitten'      ,'sitting');
Call test('rosettacode' ,'raisethysword');
Call test('Sunday'      ,'Saturday');
Call test('this_algorithm_is_similar_to',
'Damerau-Levenshtein_distance');
Call test('','abc');

test: Proc(s,t);
Dcl (s,t) Char(*) Var;
Put Edit('          1st string  = >'!!s!!'<')(Skip,a);
Put Edit('          2nd string  = >'!!t!!'<')(Skip,a);
Put Edit('Levenshtein distance  =',LevenshteinDistance(s,t))
(Skip,a,f(3));
Put Edit('')(Skip,a);
End;

LevenshteinDistance: Proc(s,t) Returns(Bin Fixed(31));
Dcl (s,t) Char(*) Var;
Dcl (sl,tl) Bin Fixed(31);
Dcl ld      Bin Fixed(31);
/* for all i and j, d[i,j] will hold the Levenshtein distance between
*  the first i characters of s and the first j characters of t;
*  note that d has (m+1)*(n+1) values                               */
sl=length(s);
tl=length(t);
Begin;
Dcl d(0:sl,0:tl) Bin Fixed(31);
Dcl (i,j,ii,jj)  Bin Fixed(31);
d=0;
Do i=1 To sl;  /* source prefixes can be transformed into         */
d(i,0)=i;    /* empty string by dropping all characters         */
End;
Do j=1 To tl;  /* target prefixes can be reached from             */
d(0,j)=j;    /* empty source prefix by inserting every character*/
End;
Do j=1 To tl;
jj=j-1;
Do i=1 To sl;
ii=i-1;
If substr(s,i,1)=substr(t,j,1) Then
d(i,j)=d(ii,jj);                  /* no operation required  */
Else
d(i,j)=1+min(d(ii,j),             /* a deletion             */
d(i,jj),             /* an insertion           */
d(ii,jj));           /* a substitution         */
End;
End;
ld=d(sl,tl);
End;
Return(ld);
End;
End;
```

{{out}}

```          1st string  = >kitten<
2nd string  = >sitting<
Levenshtein distance  =  3

1st string  = >rosettacode<
2nd string  = >raisethysword<
Levenshtein distance  =  8

1st string  = >Sunday<
2nd string  = >Saturday<
Levenshtein distance  =  3

Levenshtein distance  =  0

1st string  = >this_algorithm_is_similar_to<
2nd string  = >Damerau-Levenshtein_distance<
Levenshtein distance  = 24

1st string  = ><
2nd string  = >abc<
Levenshtein distance  =  3
```

### version 2 recursive with memoization

```*process source attributes xref or(!);
ld3: Proc Options(main);
Dcl ld(0:30,0:30) Bin Fixed(31);
call test('kitten'      ,'sitting');
call test('rosettacode' ,'raisethysword');
call test('Sunday'      ,'Saturday');
call test('this_algorithm_is_similar_to',
'Damerau-Levenshtein_distance');
call test('','abc');

test: Proc(s,t);
Dcl (s,t) Char(*);
ld=-1;
Put Edit('          1st string  = >'!!s!!'<')(Skip,a);
Put Edit('          2nd string  = >'!!t!!'<')(Skip,a);
Put Edit('Levenshtein distance  =',
LevenshteinDistance(s,length(s),t,length(t)))
(Skip,a,f(3));
Put Edit('')(Skip,a);
End;

LevenshteinDistance: Proc(s,sl,t,tl) Recursive Returns(Bin Fixed(31));
Dcl (s,t) Char(*);
Dcl (sl,tl) Bin Fixed(31);
Dcl cost    Bin Fixed(31);
If ld(sl,tl)^=-1 Then
Return(ld(sl,tl));
Select;
When(sl=0) ld(sl,tl)=tl;
When(tl=0) ld(sl,tl)=sl;
Otherwise Do;
/* test if last characters of the strings match */
cost=(substr(s,sl,1)^=substr(t,tl,1));
/* return minimum of delete char from s, delete char from t,
and delete char from both */
ld(sl,tl)=min(LevenshteinDistance(s,sl-1,t,tl  )+1,
LevenshteinDistance(s,sl  ,t,tl-1)+1,
LevenshteinDistance(s,sl-1,t,tl-1)+cost));
End;
End;
Return(ld(sl,tl));
End;
End;
```

Output is the same as for version 1.

## PowerShell

This version does not allow empty strings.

```
function Get-LevenshteinDistance
{
[CmdletBinding()]
[OutputType([PSCustomObject])]
Param
(
[Parameter(Mandatory=\$true, Position=0)]
[ValidateNotNullOrEmpty()]
[Alias("s")]
[string]
\$ReferenceObject,

[Parameter(Mandatory=\$true, Position=1)]
[ValidateNotNullOrEmpty()]
[Alias("t")]
[string]
\$DifferenceObject
)

[int]\$n = \$ReferenceObject.Length
[int]\$m = \$DifferenceObject.Length

\$d = New-Object -TypeName 'System.Object[,]' -ArgumentList (\$n + 1),(\$m + 1)

\$outputObject = [PSCustomObject]@{
ReferenceObject  = \$ReferenceObject
DifferenceObject = \$DifferenceObject
Distance         = \$null
}

for (\$i = 0; \$i -le \$n; \$i++)
{
\$d[\$i, 0] = \$i
}

for (\$i = 0; \$i -le \$m; \$i++)
{
\$d[0, \$i] = \$i
}

for (\$i = 1; \$i -le \$m; \$i++)
{
for (\$j = 1; \$j -le \$n; \$j++)
{
if (\$ReferenceObject[\$j - 1] -eq \$DifferenceObject[\$i - 1])
{
\$d[\$j, \$i] = \$d[(\$j - 1), (\$i - 1)]
}
else
{
\$d[\$j, \$i] = [Math]::Min([Math]::Min((\$d[(\$j - 1), \$i] + 1), (\$d[\$j, (\$i - 1)] + 1)), (\$d[(\$j - 1), (\$i - 1)] + 1))
}
}
}

\$outputObject.Distance = \$d[\$n, \$m]

\$outputObject
}

```
```
Get-LevenshteinDistance "kitten" "sitting"
Get-LevenshteinDistance rosettacode raisethysword

```

{{Out}}

```
ReferenceObject DifferenceObject Distance
--------------- ---------------- --------
kitten          sitting                 3
rosettacode     raisethysword           8

```

## Processing

```void setup() {
println(distance("kitten", "sitting"));
}
int distance(String a, String b) {
int [] costs = new int [b.length() + 1];
for (int j = 0; j < costs.length; j++)
costs[j] = j;
for (int i = 1; i <= a.length(); i++) {
costs[0] = i;
int nw = i - 1;
for (int j = 1; j <= b.length(); j++) {
int cj = min(1 + min(costs[j], costs[j - 1]), a.charAt(i - 1) == b.charAt(j - 1) ? nw : nw + 1);
nw = costs[j];
costs[j] = cj;
}
}
return costs[b.length()];
}
```

## Prolog

Works with SWI-Prolog.

Based on Wikipedia's pseudocode.

```levenshtein(S, T, R) :-
length(S, M),
M1 is M+1,
length(T, N),
N1 is N+1,
length(Lev, N1),
maplist(init(M1), Lev),
numlist(0, N, LN),
maplist(init_n, LN, Lev),
nth0(0, Lev, Lev0),
numlist(0, M, Lev0),

% compute_levenshtein distance
numlist(1, N, LN1),
maplist(work_on_T(Lev, S), LN1, T),
last(Lev, LevLast),
last(LevLast, R).

work_on_T(Lev, S, J, TJ) :-
length(S, M),
numlist(1, M, LM),
maplist(work_on_S(Lev, J, TJ), LM, S).

work_on_S(Lev, J, C, I, C) :-
% same char
!,
I1 is I-1, J1 is J-1,
nth0(J1, Lev, LevJ1),
nth0(I1, LevJ1, V),
nth0(J, Lev, LevJ),
nth0(I, LevJ, V).

work_on_S(Lev, J, _C1, I, _C2) :-
I1 is I-1, J1 is J - 1,
% compute the value for deletion
nth0(J, Lev, LevJ),
nth0(I1, LevJ, VD0),
VD is VD0 + 1,

% compute the value for insertion
nth0(J1, Lev, LevJ1),
nth0(I, LevJ1, VI0),
VI is VI0 + 1,

% compute the value for substitution
nth0(I1, LevJ1, VS0),
VS is VS0 + 1,

% set the minimum value to cell(I,J)
sort([VD, VI, VS], [V|_]),

nth0(I, LevJ, V).

init(Len, C) :-
length(C, Len).

init_n(N, L) :-
nth0(0, L, N).
```

{{out|Output examples}}

``` ?- levenshtein("kitten", "sitting", R).
R = 3.

?- levenshtein("saturday", "sunday", R).
R = 3.

?- levenshtein("rosettacode", "raisethysword", R).
R = 8.

```

## PureBasic

Based on Wikipedia's pseudocode.

```Procedure LevenshteinDistance(A_string\$, B_String\$)
Protected m, n, i, j, min, k, l
m = Len(A_string\$)
n = Len(B_String\$)
Dim D(m, n)

For i=0 To m: D(i,0)=i: Next
For j=0 To n: D(0,j)=j: Next

For j=1 To n
For i=1 To m
If Mid(A_string\$,i,1) = Mid(B_String\$,j,1)
D(i,j) = D(i-1, j-1); no operation required
Else
min = D(i-1, j)+1   ; a deletion
k   = D(i, j-1)+1   ; an insertion
l   = D(i-1, j-1)+1 ; a substitution
If k < min: min=k: EndIf
If l < min: min=l: EndIf
D(i,j) = min
EndIf
Next
Next
ProcedureReturn D(m,n)
EndProcedure

;- Testing
n = LevenshteinDistance("kitten", "sitting")
MessageRequester("Info","Levenshtein Distance= "+Str(n))
```

## Python

### Iterative

Implementation of the wikipedia algorithm, optimized for memory

```def minimumEditDistance(s1,s2):
if len(s1) > len(s2):
s1,s2 = s2,s1
distances = range(len(s1) + 1)
for index2,char2 in enumerate(s2):
newDistances = [index2+1]
for index1,char1 in enumerate(s1):
if char1 == char2:
newDistances.append(distances[index1])
else:
newDistances.append(1 + min((distances[index1],
distances[index1+1],
newDistances[-1])))
distances = newDistances
return distances[-1]

print(minimumEditDistance("kitten","sitting"))
print(minimumEditDistance("rosettacode","raisethysword"))

```

{{out}}

```3
8
```
```def levenshteinDistance(str1, str2):
m = len(str1)
n = len(str2)
lensum = float(m + n)
d = []
for i in range(m+1):
d.append([i])
del d[0][0]
for j in range(n+1):
d[0].append(j)
for j in range(1,n+1):
for i in range(1,m+1):
if str1[i-1] == str2[j-1]:
d[i].insert(j,d[i-1][j-1])
else:
minimum = min(d[i-1][j]+1, d[i][j-1]+1, d[i-1][j-1]+2)
d[i].insert(j, minimum)
ldist = d[-1][-1]
ratio = (lensum - ldist)/lensum
return {'distance':ldist, 'ratio':ratio}

print(levenshteinDistance("kitten","sitting"))
print(levenshteinDistance("rosettacode","raisethysword"))

```

{{out}}

```{'distance': 5, 'ratio': 0.6153846153846154}
{'distance': 12, 'ratio': 0.5}
```

===Iterative space optimized (even bounded) ===

```
def ld(a, b, mx=-1):
def result(d): return d if mx < 0 else False if d > mx else True

if a == b: return result(0)
la, lb = len(a), len(b)
if mx >= 0 and abs(la - lb) > mx: return result(mx+1)
if la == 0: return result(lb)
if lb == 0: return result(la)
if lb > la: a, b, la, lb = b, a, lb, la

cost = array('i', range(lb + 1))
for i in range(1, la + 1):
cost[0] = i; ls = i-1; mn = ls
for j in range(1, lb + 1):
ls, act = cost[j], ls + int(a[i-1] != b[j-1])
cost[j] = min(ls+1, cost[j-1]+1, act)
if (ls < mn): mn = ls
if mx >= 0 and mn > mx: return result(mx+1)
if mx >= 0 and cost[lb] > mx: return result(mx+1)
return result(cost[lb])

print(
ld('kitten','kitten'), # 0
ld('kitten','sitten'), # 1
ld('kitten','sittes'), # 2
ld('kitten','sityteng'), # 3
ld('kitten','sittYing'), # 4
ld('rosettacode','raisethysword'), # 8
ld('kitten','kittenaaaaaaaaaaaaaaaaa'), # 17
ld('kittenaaaaaaaaaaaaaaaaa','kitten') # 17
)

print(
ld('kitten','kitten',3), # True
ld('kitten','sitten',3), # True
ld('kitten','sittes',3), # True
ld('kitten','sityteng',3), # True
ld('kitten','sittYing',3), # False
ld('rosettacode','raisethysword',3), # False
ld('kitten','kittenaaaaaaaaaaaaaaaaa',3), # False
ld('kittenaaaaaaaaaaaaaaaaa','kitten',3) # False
)

```

{{out}}

```
0 1 2 3 4 8 17 17
True True True True False False False False

```

### =Memoized recursion=

(Uses [http://docs.python.org/dev/library/functools.html?highlight=functools.lru_cache#functools.lru_cache this] cache from the standard library).

``` from functools import lru_cache
>>> @lru_cache(maxsize=4095)
def ld(s, t):
if not s: return len(t)
if not t: return len(s)
if s[0] == t[0]: return ld(s[1:], t[1:])
l1 = ld(s, t[1:])
l2 = ld(s[1:], t)
l3 = ld(s[1:], t[1:])
return 1 + min(l1, l2, l3)

>>> print( ld("kitten","sitting"),ld("rosettacode","raisethysword") )
3 8
```

====Non-recursive: reduce and scanl==== {{Works with|Python|3.7}}

```'''Levenshtein distance'''

from itertools import (accumulate, chain, islice)
from functools import reduce

# levenshtein :: String -> String -> Int
def levenshtein(sa):
'''Levenshtein distance between
two strings.'''
s1 = list(sa)

# go :: [Int] -> Char -> [Int]
def go(ns, c):
n, ns1 = ns[0], ns[1:]

# gap :: Int -> (Char, Int, Int) -> Int
def gap(z, c1xy):
c1, x, y = c1xy
return min(
succ(y),
succ(z),
succ(x) if c != c1 else x
)
return scanl(gap)(succ(n))(
zip(s1, ns, ns1)
)
return lambda sb: reduce(
go, list(sb), enumFromTo(0)(len(s1))
)[-1]

# TEST ----------------------------------------------------
# main :: IO ()
def main():
'''Tests'''

pairs = [
('rosettacode', 'raisethysword'),
('kitten', 'sitting'),
('saturday', 'sunday')
]

print(
tabulated(
'Levenshtein minimum edit distances:\n'
)(str)(str)(
uncurry(levenshtein)
)(concat(map(
list,
zip(pairs, map(swap, pairs))
)))
)

# GENERIC -------------------------------------------------

# compose (<<<) :: (b -> c) -> (a -> b) -> a -> c
def compose(g):
'''Right to left function composition.'''
return lambda f: lambda x: g(f(x))

# concat :: [[a]] -> [a]
# concat :: [String] -> String
def concat(xxs):
'''The concatenation of all the elements in a list.'''
xs = list(chain.from_iterable(xxs))
unit = '' if isinstance(xs, str) else []
return unit if not xs else (
''.join(xs) if isinstance(xs[0], str) else xs
)

# enumFromTo :: (Int, Int) -> [Int]
def enumFromTo(m):
'''Integer enumeration from m to n.'''
return lambda n: list(range(m, 1 + n))

# scanl :: (b -> a -> b) -> b -> [a] -> [b]
def scanl(f):
'''scanl is like reduce, but returns a succession of
intermediate values, building from the left.'''
return lambda a: lambda xs: (
list(accumulate(chain([a], xs), f))
)

# swap :: (a, b) -> (b, a)
def swap(tpl):
'''The swapped components of a pair.'''
return (tpl[1], tpl[0])

# succ :: Int => Int -> Int
def succ(x):
'''The successor of a value.
For numeric types, (1 +).'''
return 1 + x

# tabulated :: String -> (a -> String) ->
#                        (b -> String) ->
#                        (a -> b) -> [a] -> String
def tabulated(s):
'''Heading -> x display function ->
fx display function ->
f -> value list -> tabular string.'''
def go(xShow, fxShow, f, xs):
w = max(map(compose(len)(xShow), xs))
return s + '\n' + '\n'.join([
xShow(x).rjust(w, ' ') + ' -> ' + fxShow(f(x))
for x in xs

])
return lambda xShow: lambda fxShow: (
lambda f: lambda xs: go(
xShow, fxShow, f, xs
)
)

# take :: Int -> [a] -> [a]
# take :: Int -> String -> String
def take(n):
'''The prefix of xs of length n,
or xs itself if n > length xs.'''
return lambda xs: (
xs[0:n]
if isinstance(xs, list)
else list(islice(xs, n))
)

# uncurry :: (a -> b -> c) -> ((a, b) -> c)
def uncurry(f):
'''A function over a tuple
derived from a curried function.'''
return lambda xy: f(xy[0])(
xy[1]
)

# MAIN ---
if __name__ == '__main__':
main()
```

{{Out}}

```Levenshtein minimum edit distances:

('rosettacode', 'raisethysword') -> 8
('raisethysword', 'rosettacode') -> 8
('kitten', 'sitting') -> 3
('sitting', 'kitten') -> 3
('saturday', 'sunday') -> 3
('sunday', 'saturday') -> 3
```

## Racket

A memoized recursive implementation.

```#lang racket

(define (levenshtein a b)
(define (ls0 a-index b-index)
(cond [(or (= a-index -1) (= b-index -1)) (abs (- a-index b-index))]
[else
(define a-char (string-ref a a-index))
(define b-char (string-ref b b-index))
(if (equal? a-char b-char)
(ls (sub1 a-index) (sub1 b-index))
(min (add1 (ls (sub1 a-index) b-index))
(add1 (ls (sub1 a-index) (sub1 b-index)))))]))
(define memo (make-hash))
(define (ls a-i b-i)
(hash-ref! memo (cons a-i b-i) (λ() (ls0 a-i b-i))))
(ls (sub1 (string-length a)) (sub1 (string-length b))))

(levenshtein "kitten" "sitting")
(levenshtein "rosettacode" "raisethysword")
```

{{out}}

```3
8
```

## REXX

### version 1

As per the task's requirements, this version includes a driver to display the results.

```/*REXX program  calculates and displays the  Levenshtein distance  between two strings. */
call Levenshtein   'kitten'                        ,     "sitting"
call Levenshtein   'rosettacode'                   ,     "raisethysword"
call Levenshtein   'Sunday'                        ,     "Saturday"
call Levenshtein   'this algorithm is similar to'  ,     "Damerau─Levenshtein distance"
exit                                             /*stick a fork in it,  we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
Levenshtein: procedure; parse arg o,t;  oL= length(o);   tL= length(t);     @.= 0
say '        original string  = '    o                          /*show   old  string*/
say '          target string  = '    t                          /*  "   target   "  */
do #=1  for tL;   @.0.#= #;   end  /*#*/       /*the   drop  array.*/
do #=1  for oL;   @.#.0= #;   end  /*#*/       /* "   insert   "   */
do    j=1  for tL;   jm= j-1;    q= substr(t, j, 1)        /*obtain character. */
do k=1  for oL;   km= k-1
if q==substr(o, k, 1)  then @.k.j= @.km.jm              /*use previous char.*/
else @.k.j= 1   +   min(@.km.j,  @.k.jm,  @.km.jm)
end   /*k*/
end      /*j*/                                             /* [↑]  best choice.*/
say '   Levenshtein distance  = '  @.oL.tL;    say;      return
```

{{out|output|text= when using the internal default inputs:}}

```
original string  =  kitten
target string  =  sitting
Levenshtein distance  =  3

original string  =  rosettacode
target string  =  raisethysword
Levenshtein distance  =  8

original string  =  Sunday
target string  =  Saturday
Levenshtein distance  =  3

Levenshtein distance  =  0

original string  =  this algorithm is similar to
target string  =  Damerau─Levenshtein distance
Levenshtein distance  =  24

```

### version 2

same as version 1 (but does not include a driver for testing), reformatted and commented

```Levenshtein: Procedure
Parse Arg s,t
/* for all i and j, d[i,j] will hold the Levenshtein distance between     */
/* the first i characters of s and the first j characters of t;           */
/* note that d has (m+1)*(n+1) values                                     */
m=length(s)
n=length(t)
d.=0
Do i=1 To m  /* source prefixes can be transformed into empty string by */
d.i.0=i    /* dropping all characters                                 */
End
Do j=1 To n  /* target prefixes can be reached from empty source prefix */
d.0.j=j    /* by inserting every character                            */
End
Do j=1 To n
jj=j-1
Do i=1 To m
ii=i-1
If substr(s,i,1)=substr(t,j,1) Then
d.i.j=d.ii.jj          /* no operation required                   */
else
d.i.j=min(d.ii.j+1,,   /* a deletion                              */
d.i.jj+1,,   /* an insertion                            */
d.ii.jj+1)   /* a substitution                          */
End
End
Say '          1st string  = '    s
Say '          2nd string  = '    t
say 'Levenshtein distance  = ' d.m.n;   say ''
Return d.m.n
```

### version 3

Alternate algorithm from Wikipedia (but does not include a driver for testing).

```LevenshteinDistance: Procedure
Parse Arg s,t
If s==t Then Return 0;
sl=length(s)
tl=length(t)
If sl=0 Then Return tl
If tl=0 Then Return sl
Do i=0 To tl
v0.i=i
End
Do i=0 To sl-1
v1.0=i+1
Do j=0 To tl-1
jj=j+1
cost=substr(s,i+1,1)<>substr(t,j+1,1)
v1.jj=min(v1.j+1,v0.jj+1,v0.j+cost)
End
Do j=0 to tl-1
v0.j=v1.j
End
End
return v1.tl
```

===version 4 (recursive)=== Recursive algorithm from Wikipedia with memoization

```call test 'kitten'      ,'sitting'
call test 'rosettacode' ,'raisethysword'
call test 'Sunday'      ,'Saturday'
call test 'this_algorithm_is_similar_to',,
'Damerau-Levenshtein_distance'
call test '','abc'
Exit

test: Procedure
Parse Arg s,t
ld.=''
Say '          1st string  = >'s'<'
Say '          2nd string  = >'t'<'
Say 'Levenshtein distance  =' LevenshteinDistance(s,length(s),t,length(t))
Say ''
Return

LevenshteinDistance: Procedure Expose ld.
/* sl and tl are the number of characters in string s and t respectively */
Parse Arg s,sl,t,tl
If ld.sl.tl<>'' Then
Return ld.sl.tl
Select
When sl=0 Then ld.sl.tl=tl
When tl=0 Then ld.sl.tl=sl
Otherwise Do
/* test if last characters of the strings match */
cost=substr(s,sl,1)<>substr(t,tl,1)
/* return minimum of delete char from s, delete char from t,
and delete char from both */
ld.sl.tl=min(LevenshteinDistance(s,sl-1,t,tl  )+1,,
LevenshteinDistance(s,sl  ,t,tl-1)+1,,
LevenshteinDistance(s,sl-1,t,tl-1)+cost)
End
End
Return ld.sl.tl
```

## Ring

```
# Project : Levenshtein distance

see "" + "distance(kitten, sitting) = " + levenshteindistance("kitten", "sitting") + nl
see "" + "distance(saturday, sunday) = " + levenshteindistance("saturday", "sunday") + nl
see "" + "distance(rosettacode, raisethysword) = " + levenshteindistance("rosettacode", "raisethysword") + nl

func levenshteindistance(s1, s2)
n = len(s1)
m = len(s2)
if n = 0
levenshteindistance = m
return
ok
if m = 0
levenshteindistance = n
return
ok
d = newlist(n, m)
for i = 1 to n
d[i][1] = i
next i
for i = 1 to m
d[1][i] = i
next
for i = 2 to n
si = substr(s1, i, 1)
for j = 2 to m
tj = substr(s2, j, 1)
if si = tj
cost = 0
else
cost = 1
ok
d[i][ j] = min((d[i - 1][ j]), min((d[i][j - 1] + 1), (d[i - 1][j - 1] + cost)))
next
next
levenshteindistance = d[n][m]
return levenshteindistance

```

Output:

```
distance(kitten, sitting) = 3
distance(saturday, sunday) = 3
distance(rosettacode, raisethysword) = 8

```

## Ruby

Implementation of the wikipedia algorithm. Invariant is that for current loop indices `i` and `j`, `costs[k]` for `k < j` contains ''lev(i, k)'' and for `k >= j` contains ''lev(i-1, k)''. The inner loop body restores the invariant for the new value of `j`.

```module Levenshtein

def self.distance(a, b)
a, b = a.downcase, b.downcase
costs = Array(0..b.length) # i == 0
(1..a.length).each do |i|
costs[0], nw = i, i - 1  # j == 0; nw is lev(i-1, j)
(1..b.length).each do |j|
costs[j], nw = [costs[j] + 1, costs[j-1] + 1, a[i-1] == b[j-1] ? nw : nw + 1].min, costs[j]
end
end
costs[b.length]
end

def self.test
%w{kitten sitting saturday sunday rosettacode raisethysword}.each_slice(2) do |a, b|
puts "distance(#{a}, #{b}) = #{distance(a, b)}"
end
end

end

Levenshtein.test
```

{{out}}

```
distance(kitten, sitting) = 3
distance(saturday, sunday) = 3
distance(rosettacode, raisethysword) = 8
```

A variant can be found used in Rubygems [https://github.com/rubygems/rubygems/blob/master/lib/rubygems/text.rb]

```def levenshtein_distance(str1, str2)
n = str1.length
m = str2.length
max = n/2

return m if 0 == n
return n if 0 == m
return n if (n - m).abs > max

d = (0..m).to_a
x = nil

str1.each_char.with_index do |char1,i|
e = i+1

str2.each_char.with_index do |char2,j|
cost = (char1 == char2) ? 0 : 1
x = [ d[j+1] + 1, # insertion
e + 1,      # deletion
d[j] + cost # substitution
].min
d[j] = e
e = x
end

d[m] = x
end

x
end

%w{kitten sitting saturday sunday rosettacode raisethysword}.each_slice(2) do |a, b|
puts "distance(#{a}, #{b}) = #{levenshtein_distance(a, b)}"
end
```

same output

## Run BASIC

```print levenshteinDistance("kitten", "sitting")
print levenshteinDistance("rosettacode", "raisethysword")
end
function levenshteinDistance(s1\$, s2\$)
n = len(s1\$)
m = len(s2\$)
if n = 0 then
levenshteinDistance = m
goto [ex]
end if
if m = 0 then
levenshteinDistance = n
goto [ex]
end if
dim d(n, m)
for i = 0 to n
d(i, 0) = i
next i
for i = 0 to m
d(0, i) = i
next i
for i = 1 to n
si\$ = mid\$(s1\$, i, 1)
for j = 1 to m
tj\$ = mid\$(s2\$, j, 1)
if si\$ = tj\$ then cost = 0 else cost = 1
d(i, j) = min((d(i - 1, j) + 1),min((d(i, j - 1) + 1),(d(i - 1, j - 1) + cost)))
next j
next i
levenshteinDistance = d(n, m)
[ex]
end function
```

Output:

```3
8
```

## Rust

Implementation of the wikipedia algorithm. {{works with|Rust|1.1}}

```fn main() {
println!("{}", levenshtein_distance("kitten", "sitting"));
println!("{}", levenshtein_distance("saturday", "sunday"));
println!("{}", levenshtein_distance("rosettacode", "raisethysword"));
}

fn levenshtein_distance(word1: &str, word2: &str) -> usize {
let w1 = word1.chars().collect::<Vec<_>>();
let w2 = word2.chars().collect::<Vec<_>>();

let word1_length = w1.len() + 1;
let word2_length = w2.len() + 1;

let mut matrix = vec![vec![0]];

for i in 1..word1_length { matrix[0].push(i); }
for j in 1..word2_length { matrix.push(vec![j]); }

for j in 1..word2_length {
for i in 1..word1_length {
let x: usize = if w1[i-1] == w2[j-1] {
matrix[j-1][i-1]
} else {
1 + std::cmp::min(
std::cmp::min(matrix[j][i-1], matrix[j-1][i])
, matrix[j-1][i-1])
};
matrix[j].push(x);
}
}
matrix[word2_length-1][word1_length-1]
}
```

{{out}}

```3
3
8
```

## Scala

### Translated Wikipedia algorithm.

```object Levenshtein0 extends App {

def distance(s1: String, s2: String): Int = {
val dist = Array.tabulate(s2.length + 1, s1.length + 1) { (j, i) => if (j == 0) i else if (i == 0) j else 0 }

@inline
def minimum(i: Int*): Int = i.min

for {j <- dist.indices.tail
i <- dist(0).indices.tail} dist(j)(i) =
if (s2(j - 1) == s1(i - 1)) dist(j - 1)(i - 1)
else minimum(dist(j - 1)(i) + 1, dist(j)(i - 1) + 1, dist(j - 1)(i - 1) + 1)

dist(s2.length)(s1.length)
}

def printDistance(s1: String, s2: String) {
println("%s -> %s : %d".format(s1, s2, distance(s1, s2)))
}

printDistance("kitten", "sitting")
printDistance("rosettacode", "raisethysword")

}
```

{{out}}

```kitten -> sitting : 3
rosettacode -> raisethysword : 8
```

===Functional programmed, memoized=== {{Out}}Best seen running in your browser either by [https://scalafiddle.io/sf/zj7bHC7/0 (ES aka JavaScript, non JVM)] or [https://scastie.scala-lang.org/qHhDWl68QgWv1uwOYzzNqw Scastie (remote JVM)].

```import scala.collection.mutable
import scala.collection.parallel.ParSeq

object Levenshtein extends App {

def printDistance(s1: String, s2: String) =
println(f"\$s1%s -> \$s2%s : \${levenshtein(s1, s2)(s1.length, s2.length)}%d")

def levenshtein(s1: String, s2: String): mutable.Map[(Int, Int), Int] = {
val memoizedCosts = mutable.Map[(Int, Int), Int]()

def lev: ((Int, Int)) => Int = {
case (k1, k2) =>
memoizedCosts.getOrElseUpdate((k1, k2), (k1, k2) match {
case (i, 0) => i
case (0, j) => j
case (i, j) =>
ParSeq(1 + lev((i - 1, j)),
1 + lev((i, j - 1)),
lev((i - 1, j - 1))
+ (if (s1(i - 1) != s2(j - 1)) 1 else 0)).min
})
}

lev((s1.length, s2.length))
memoizedCosts
}

printDistance("kitten", "sitting")
printDistance("rosettacode", "raisethysword")
printDistance("Here's a bunch of words", "to wring out this code")
printDistance("sleep", "fleeting")

}
```

## Scheme

Recursive version from wikipedia article.

```
(define (levenshtein s t)
(define (%levenshtein s sl t tl)
(cond ((zero? sl) tl)
((zero? tl) sl)
(else
(min (+ (%levenshtein (cdr s) (- sl 1) t tl) 1)
(+ (%levenshtein s sl (cdr t) (- tl 1)) 1)
(+ (%levenshtein (cdr s) (- sl 1) (cdr t) (- tl 1))
(if (char=? (car s) (car t)) 0 1))))))
(%levenshtein (string->list s)
(string-length s)
(string->list t)
(string-length t)))

```

{{out}}

```
> (levenshtein "kitten" "sitting")
3
> (levenshtein "rosettacode" "raisethysword")
8

```

## Seed7

```\$ include "seed7_05.s7i";

const func integer: levenshteinDistance (in string: s, in string: t) is func
result
var integer: distance is 0;
local
var array array integer: d is 0 times 0 times 0;
var integer: i is 0;
var integer: j is 0;
begin
d := [0 .. length(s)] times [0 .. length(t)] times 0;
for key i range s do
d[i][0] := i;
end for;
for key j range t do
d[0][j] := j;
for key i range s do
if s[i] = t[j] then
d[i][j] := d[pred(i)][pred(j)];
else
d[i][j] := min(min(succ(d[pred(i)][j]), succ(d[i][pred(j)])), succ(d[pred(i)][pred(j)]));
end if;
end for;
end for;
distance := d[length(s)][length(t)];
end func;

const proc: main is func
begin
writeln("kitten -> sitting: " <& levenshteinDistance("kitten", "sitting"));
writeln("rosettacode -> raisethysword: " <& levenshteinDistance("rosettacode", "raisethysword"));
end func;
```

{{out}}

```
kitten -> sitting: 3
rosettacode -> raisethysword: 8

```

## SequenceL

This implementation is based on the "Iterative with two matrix rows" version on Wikipedia.

```
import <Utilities/Sequence.sl>;
import <Utilities/Math.sl>;

main(args(2)) := LenenshteinDistance(args[1], args[2]);

LenenshteinDistance(s(1), t(1)) :=
0 when equalList(s,t) else
size(t) when size(s) = 0 else
size(s) when size(t) = 0 else
LenenshteinDistanceIterative(s, t, 0 ... size(t), duplicate(0, size(t) + 1), 1);

LenenshteinDistanceIterative(s(1), t(1), v0(1), v1(1), n) :=
v0[size(t) + 1] when n > size(s) else
LenenshteinDistanceIterative(s, t, iterate(s[n], t, v0, setElementAt(v1, 1, n + 0), 1), v0, n + 1);

iterate(s, t(1), v0(1), v1(1), n) :=
v1 when n > size(t) else
iterate(s, t, v0,
setElementAt(v1, n + 1,
min(min(v1[n] + 1, v0[n + 1] + 1), v0[n] + (0 when s = t[n] else 1))),
n + 1);

```

## Sidef

### Recursive

```func lev(s, t) is cached {

s || return t.len
t || return s.len

var s1 = s.ft(1)
var t1 = t.ft(1)

s[0] == t[0] ? __FUNC__(s1, t1)
: 1+Math.min(
__FUNC__(s1, t1),
__FUNC__(s,  t1),
__FUNC__(s1, t )
)
}
```

### Iterative

```func lev(s, t) {
var d = [@(0 .. t.len), s.len.of {[_]}...]
for i,j in (^s ~X ^t) {
d[i+1][j+1] = (
s[i] == t[j]
? d[i][j]
: 1+Math.min(d[i][j+1], d[i+1][j], d[i][j])
)
}
d[-1][-1]
}
```

Calling the function:

```say lev(%c'kitten', %c'sitting');               # prints: 3
say lev(%c'rosettacode', %c'raisethysword');    # prints: 8
```

## Simula

```BEGIN

INTEGER PROCEDURE LEVENSHTEINDISTANCE(S1, S2); TEXT S1, S2;
BEGIN
INTEGER N, M;
N := S1.LENGTH;
M := S2.LENGTH;
IF N = 0 THEN LEVENSHTEINDISTANCE := M ELSE
IF M = 0 THEN LEVENSHTEINDISTANCE := N ELSE
BEGIN
INTEGER ARRAY D(0:N, 0:M);
INTEGER I, J;
FOR I := 0 STEP 1 UNTIL N DO D(I, 0) := I;
FOR I := 0 STEP 1 UNTIL M DO D(0, I) := I;
S1.SETPOS(1);
FOR I := 1 STEP 1 UNTIL N DO
BEGIN
CHARACTER SI, TJ;
SI := S1.GETCHAR;
S2.SETPOS(1);
FOR J := 1 STEP 1 UNTIL M DO
BEGIN
INTEGER COST;
TJ := S2.GETCHAR;
COST := IF SI = TJ THEN 0 ELSE 1;
D(I, J) := MIN(D(I - 1, J) + 1, MIN(D(I, J - 1) + 1, D(I - 1, J - 1) + COST));
END;
END;
LEVENSHTEINDISTANCE := D(N, M);
END;
END LEVENSHTEINDISTANCE;

OUTINT(LEVENSHTEINDISTANCE("kitten", "sitting"), 0); OUTIMAGE;
OUTINT(LEVENSHTEINDISTANCE("rosettacode", "raisethysword"), 0); OUTIMAGE;

END

```

{{out}}

```
3
8

```

## Smalltalk

{{works with|Smalltalk/X}} ST/X provides a customizable levenshtein method in the String class (weights for individual operations can be passed in):

```'kitten' levenshteinTo: 'sitting' s:1 k:1 c:1 i:1 d:1 -> 3
'rosettacode' levenshteinTo: 'raisethysword' s:1 k:1 c:1 i:1 d:1 -> 8
```

## Swift

Version using entire matrix:

```func levDis(w1: String, w2: String) -> Int {

let (t, s) = (w1.characters, w2.characters)

let empty = Repeat(count: s.count, repeatedValue: 0)
var mat = [[Int](0...s.count)] + (1...t.count).map{[\$0] + empty}

for (i, tLett) in t.enumerate() {
for (j, sLett) in s.enumerate() {
mat[i + 1][j + 1] = tLett == sLett ?
mat[i][j] : min(mat[i][j], mat[i][j + 1], mat[i + 1][j]).successor()
}
}
return mat.last!.last!
}
```

Version using only two rows at a time:

```func levDis(w1: String, w2: String) -> Int {

let (t, s) = (w1.characters, w2.characters)

let empty = Repeat(count: s.count, repeatedValue: 0)
var last = [Int](0...s.count)

for (i, tLett) in t.enumerate() {
var cur = [i + 1] + empty
for (j, sLett) in s.enumerate() {
cur[j + 1] = tLett == sLett ? last[j] : min(last[j], last[j + 1], cur[j]).successor()
}
last = cur
}
return last.last!
}
```

## Tcl

```proc levenshteinDistance {s t} {
# Edge cases
if {![set n [string length \$t]]} {
return [string length \$s]
} elseif {![set m [string length \$s]]} {
return \$n
}
# Fastest way to initialize
for {set i 0} {\$i <= \$m} {incr i} {
lappend d 0
lappend p \$i
}
# Loop, computing the distance table (well, a moving section)
for {set j 0} {\$j < \$n} {} {
set tj [string index \$t \$j]
lset d 0 [incr j]
for {set i 0} {\$i < \$m} {} {
set a [expr {[lindex \$d \$i]+1}]
set b [expr {[lindex \$p \$i]+([string index \$s \$i] ne \$tj)}]
set c [expr {[lindex \$p [incr i]]+1}]
# Faster than min(\$a,\$b,\$c)
lset d \$i [expr {\$a<\$b ? \$c<\$a ? \$c : \$a : \$c<\$b ? \$c : \$b}]
}
# Swap
set nd \$p; set p \$d; set d \$nd
}
# The score is at the end of the last-computed row
return [lindex \$p end]
}
```

{{out|Usage}}

```puts [levenshteinDistance "kitten" "sitting"];   # Prints 3
```

## TSE SAL

``` (filenamemacro=getmadle.s) [kn, ri, th, 08-09-2011 23:04:55]
INTEGER PROC FNMathGetDamerauLevenshteinDistanceI( STRING s1, STRING s2 )
INTEGER L1 = Length( s1 )
INTEGER L2 = Length( s2 )
INTEGER substitutionCostI = 0
STRING h1[255] = ""
STRING h2[255] = ""
IF ( ( L1 == 0 ) OR ( L2 == 0 ) )
// Trivial case: one string is 0-length
RETURN( Max( L1, L2 ) )
ELSE
// The cost of substituting the last character
IF   ( ( s1[ L1 ] ) == ( s2[ L2 ] ) )
substitutionCostI = 0
ELSE
substitutionCostI = 1
ENDIF
// h1 and h2 are s1 and s2 with the last character chopped off
h1 = SubStr( s1, 1,  L1 - 1 )
h2 = SubStr( s2, 1,  L2 - 1 )
IF ( ( L1 > 1 ) AND  ( L2 > 1 ) AND  ( s1[ L1 - 0 ] == s2[ L2 - 1 ] ) AND ( s1[ L1 - 1 ] == s2[ L2 - 0 ] ) )
RETURN( Min( Min( FNMathGetDamerauLevenshteinDistanceI( h1, s2 ) + 1, FNMathGetDamerauLevenshteinDistanceI( s1, h2 ) + 1 ), Min( FNMathGetDamerauLevenshteinDistanceI( h1 , h2 ) + substitutionCostI, FNMathGetDamerauLevenshteinDistanceI( SubStr( s1, 1,  L1 - 2 ), SubStr( s2, 1, L2 - 2 ) ) + 1 ) ) )
ENDIF
RETURN( Min( Min( FNMathGetDamerauLevenshteinDistanceI( h1, s2 ) + 1, FNMathGetDamerauLevenshteinDistanceI( s1, h2 ) + 1 ), FNMathGetDamerauLevenshteinDistanceI( h1 ,  h2 ) + substitutionCostI ) )
ENDIF
END

PROC Main()
STRING s1[255] = "arcain"
STRING s2[255] = "arcane"
Warn( "Minimum amount of steps to convert ", s1, " to ", s2, " = ", FNMathGetDamerauLevenshteinDistanceI( s1, s2 ) ) // gives e.g. 2
s1 = "algorithm"
s2 = "altruistic"
Warn( "Minimum amount of steps to convert ", s1, " to ", s2, " = ", FNMathGetDamerauLevenshteinDistanceI( s1, s2 ) ) // gives e.g. 6
END
```

## TUSCRIPT

```
\$\$ MODE TUSCRIPT
distance=DISTANCE ("kitten", "sitting")
PRINT distance

```

Output:

```
3

```

## Vala

```class LevenshteinDistance : Object {
public static int compute (owned string s, owned string t, bool case_sensitive = false) {
var n = s.length;
var m = t.length;
var d = new int[n + 1, m + 1];
if (case_sensitive == false) {
s = s.down ();
t = t.down ();
}
if (n == 0) {
return m;
}
if (m == 0) {
return n;
}
for (var i = 0; i <= n; d[i, 0] = i++) {}
for (var j = 0; j <= m; d[0, j] = j++) {}
for (var i = 1; i <= n; i++) {
for (var j = 1; j <= m; j++) {
var cost = (t[j - 1] == s[i - 1]) ? 0 : 1;
d[i, j] = int.min (int.min (d[i - 1, j] + 1, d[i, j - 1] + 1), d[i - 1, j - 1] + cost);
}
}
return d[n, m];
}
}

```

## VBA

{{trans|Phix}}

```Option Base 1
Function levenshtein(s1 As String, s2 As String) As Integer
Dim n As Integer: n = Len(s1) + 1
Dim m As Integer: m = Len(s2) + 1
Dim d() As Integer, i As Integer, j As Integer
ReDim d(n, m)

If n = 1 Then
levenshtein = m - 1
Exit Function
Else
If m = 1 Then
levenshtein = n - 1
Exit Function
End If
End If

For i = 1 To n
d(i, 1) = i - 1
Next i

For j = 1 To m
d(1, j) = j - 1
Next j

For i = 2 To n
For j = 2 To m
d(i, j) = WorksheetFunction.Min( _
d(i - 1, j) + 1, _
d(i, j - 1) + 1, _
(d(i - 1, j - 1) - (Mid(s1, i - 1, 1) <> Mid(s2, j - 1, 1))) _
)
Next j
Next i

levenshtein = d(n, m)
End Function
Public Sub main()
Debug.Print levenshtein("kitten", "sitting")
Debug.Print levenshtein("rosettacode", "raisethysword")
End Sub
```

{{out}}

``` 3
8
```

## Visual Basic

{{Trans|FreeBASIC}} {{works with|Visual Basic|5}} {{works with|Visual Basic|6}} {{works with|VBA|Access 97}} {{works with|VBA|6.5}} {{works with|VBA|7.1}}

```Function min(x As Integer, y As Integer) As Integer
If x < y Then
min = x
Else
min = y
End If
End Function

Function levenshtein(s As String, t As String) As Integer
Dim ls As Integer, lt As Integer
Dim i As Integer, j As Integer, cost As Integer
' degenerate cases
ls = Len(s)
lt = Len(t)
If ls = lt Then
If s = t Then
Exit Function ' return 0
End If
ElseIf ls = 0 Then
levenshtein = lt
Exit Function
ElseIf lt = 0 Then
levenshtein = ls
Exit Function
End If

' create two integer arrays of distances
ReDim v0(0 To lt) As Integer  '' previous
ReDim v1(0 To lt) As Integer  '' current

' initialize v0
For i = 0 To lt
v0(i) = i
Next i

For i = 0 To ls - 1
' calculate v1 from v0
v1(0) = i + 1

For j = 0 To lt - 1
cost = Abs(CInt(Mid\$(s, i + 1, 1) <> Mid\$(t, j + 1, 1)))
v1(j + 1) = min(v1(j) + 1, min(v0(j + 1) + 1, v0(j) + cost))
Next j

' copy v1 to v0 for next iteration
For j = 0 To lt
v0(j) = v1(j)
Next j
Next i

levenshtein = v1(lt)
End Function

Sub Main()
' tests
Debug.Print "'kitten' to 'sitting'            => "; levenshtein("kitten", "sitting")
Debug.Print "'sitting' to 'kitten'            => "; levenshtein("sitting", "kitten")
Debug.Print "'rosettacode' to 'raisethysword' => "; levenshtein("rosettacode", "raisethysword")
Debug.Print "'sleep' to 'fleeting'            => "; levenshtein("sleep", "fleeting")
End Sub

```

{{out}}

```'kitten' to 'sitting'            =>  3
'sitting' to 'kitten'            =>  3
'rosettacode' to 'raisethysword' =>  8
'sleep' to 'fleeting'            =>  5
```

## Visual Basic .NET

``` Function LevenshteinDistance(ByVal String1 As String, ByVal String2 As String) As Integer
Dim Matrix(String1.Length, String2.Length) As Integer
Dim Key As Integer
For Key = 0 To String1.Length
Matrix(Key, 0) = Key
Next
For Key = 0 To String2.Length
Matrix(0, Key) = Key
Next
For Key1 As Integer = 1 To String2.Length
For Key2 As Integer = 1 To String1.Length
If String1(Key2 - 1) = String2(Key1 - 1) Then
Matrix(Key2, Key1) = Matrix(Key2 - 1, Key1 - 1)
Else
Matrix(Key2, Key1) = Math.Min(Matrix(Key2 - 1, Key1) + 1, Math.Min(Matrix(Key2, Key1 - 1) + 1, Matrix(Key2 - 1, Key1 - 1) + 1))
End If
Next
Next
Return Matrix(String1.Length - 1, String2.Length - 1)
End Function
```

## zkl

{{trans|D}}

```fcn levenshtein(s1,s2){
sz2,costs:=s2.len() + 1, List.createLong(sz2,0);  // -->zero filled List
foreach i in (s1.len() + 1){
lastValue:=i;
foreach j in (sz2){
if (i==0) costs[j]=j;
else if (j>0){
newValue:=costs[j-1];
if (s1[i-1]!=s2[j-1])
newValue=newValue.min(lastValue, costs[j]) + 1;
costs[j-1]=lastValue;
lastValue =newValue;
}
}
if (i>0) costs[-1]=lastValue;
}
costs[-1]
}
```
```foreach a,b in (T(T("kitten","sitting"), T("rosettacode","raisethysword"),
T("yo",""), T("","yo"), T("abc","abc")) ){
println(a," --> ",b,": ",levenshtein(a,b));
}
```

{{out}}

```
kitten --> sitting: 3
rosettacode --> raisethysword: 8
yo --> : 2
--> yo: 2
abc --> abc: 0

```