Display the complete lyrics for the song "99 Bottles of Beer on the Wall".
The lyrics follow this form:
99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall
98 bottles of beer on the wall
98 bottles of beer
Take one down, pass it around
97 bottles of beer on the wall
… and so on, until reaching 0.
Grammatical support for "1 bottle of beer" is optional.
As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).
Related tasks:
See also:
0815
See 99 Bottles of Beer/EsoLang
360 Assembly
See 99 Bottles of Beer/Assembly
6502 Assembly
See 99 Bottles of Beer/Assembly
6800 Assembly
See 99 Bottles of Beer/Assembly
8th
\ 99 bottles of beer on the wall:
: allout "no more bottles" ;
: just-one "1 bottle" ;
: yeah! dup . " bottles" ;
[
' allout ,
' just-one ,
' yeah! ,
] var, bottles
: .bottles dup 2 n:min bottles @ swap caseof ;
: .beer .bottles . " of beer" . ;
: .wall .beer " on the wall" . ;
: .take " Take one down and pass it around" . ;
: beers .wall ", " . .beer '; putc cr
n:1- 0 max .take ", " .
.wall '. putc cr drop ;
' beers 1 99 loop- bye
ABAP
REPORT z99bottles.
DATA lv_no_bottles(2) TYPE n VALUE 99.
DO lv_no_bottles TIMES.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer on the wall'.
NEW-LINE.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer'.
NEW-LINE.
WRITE 'Take one down, pass it around'.
NEW-LINE.
SUBTRACT 1 FROM lv_no_bottles.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer on the wall'.
WRITE /.
ENDDO.
or (With ABAP 7.40)
REPORT YCL_99_BOTTLES.
DATA it_99_bottles TYPE TABLE OF string WITH EMPTY KEY.
DATA(cr_lf) = cl_abap_char_utilities=>cr_lf.
it_99_bottles = VALUE #(
FOR i = 99 THEN i - 1 UNTIL i = 0 ( COND string( LET lv = ( i - 1 )
lr = i && | bottles of beer on the wall|
&& cr_lf
&& i && | bottles of beer|
&& cr_lf
&& |Take one down, pass it around|
&& cr_lf
&& lv && | bottles of beer on the wall|
&& cr_lf IN WHEN 1 = 1 THEN lr )
)
).
cl_demo_output=>write( it_99_bottles ).
cl_demo_output=>display( ).
ACL2
ActionScript
for(var numBottles:uint = 99; numBottles > 0; numBottles--) { trace(numBottles, " bottles of beer on the wall"); trace(numBottles, " bottles of beer"); trace("Take one down, pass it around"); trace(numBottles - 1, " bottles of beer on the wall\n"); }
Ada
Simple Version
with Ada.Text_Io; use Ada.Text_Io;
procedure Bottles is
begin
for X in reverse 1..99 loop
Put_Line(Integer'Image(X) & " bottles of beer on the wall");
Put_Line(Integer'Image(X) & " bottles of beer");
Put_Line("Take one down, pass it around");
Put_Line(Integer'Image(X - 1) & " bottles of beer on the wall");
New_Line;
end loop;
end Bottles;
Concurrent Version
with 1 task to print out the information and 99 tasks to specify the number of bottles.
with Ada.Text_Io; use Ada.Text_Io;
procedure Tasking_99_Bottles is
subtype Num_Bottles is Natural range 1..99;
task Print is
entry Set (Num_Bottles);
end Print;
task body Print is
Num : Natural;
begin
for I in reverse Num_Bottles'range loop
select
accept
Set(I) do -- Rendezvous with Counter task I
Num := I;
end Set;
Put_Line(Integer'Image(Num) & " bottles of beer on the wall");
Put_Line(Integer'Image(Num) & " bottles of beer");
Put_Line("Take one down, pass it around");
Put_Line(Integer'Image(Num - 1) & " bottles of beer on the wall");
New_Line;
or terminate; -- end when all Counter tasks have completed
end select;
end loop;
end Print;
task type Counter(I : Num_Bottles);
task body Counter is
begin
Print.Set(I);
end Counter;
type Task_Access is access Counter;
Task_List : array(Num_Bottles) of Task_Access;
begin
for I in Task_List'range loop -- Create 99 Counter tasks
Task_List(I) := new Counter(I);
end loop;
end Tasking_99_Bottles;
Aime
integer bottles;
bottles = 99;
do {
o_(bottles, " bottles of beer on the wall\n");
o_(bottles, " bottles of beer\n");
o_("Take one down, pass it around\n");
o_(bottles -= 1, " bottles of beer on the wall\n\n");
} while (bottles);
Algae
# 99 Bottles of Beer on the Wall
# in Algae
# bottles.A
for (i in 99:1:1) {
if (i != 1) {
printf("%d bottles of beer on the wall\n";i);
printf("%d bottles of beer...\n";i);
printf("you take on down and pass it around...\n");
if ( i == 2) {
printf("%d bottles of beer on the wall\n\n";i-1);
else
printf("%d bottles of beer on the wall\n\n";i-1);
}
else
printf("1 bottle of beer on the wall\n");
printf("1 bottle of beer...\n");
printf("you take on down and pass it around..\n");
printf("no more bottles of beer on the wall!\n\n");
}
}
ALGOL 68
Works with ALGOL 68|Standard - no extensions to language used. Works with ALGOL 68G|Any - tested with release mk15-0.8b.fc9.i386.
main:(
FOR bottles FROM 99 TO 1 BY -1 DO
printf(($z-d" bottles of beer on the wall"l$, bottles));
printf(($z-d" bottles of beer"l$, bottles));
printf(($"Take one down, pass it around"l$));
printf(($z-d" bottles of beer on the wall"ll$, bottles-1))
OD
)
ALGOL-M
BEGIN
COMMENT PRINT LYRICS TO "99 BOTTLES OF BEER ON THE WALL";
STRING FUNCTION BOTTLE(N); % GIVE CORRECT GRAMMATICAL FORM %
INTEGER N;
BEGIN
IF N = 1 THEN
BOTTLE := " BOTTLE"
ELSE
BOTTLE := " BOTTLES";
END;
INTEGER N;
N := 99;
WHILE N > 0 DO
BEGIN
WRITE(N, BOTTLE(N), " OF BEER ON THE WALL,");
WRITEON(N, BOTTLE(N), " OF BEER");
WRITE("TAKE ONE DOWN AND PASS IT AROUND, ");
N := N - 1;
IF N = 0 THEN
WRITEON("NO MORE")
ELSE
WRITEON(N);
WRITEON(BOTTLE(N), " OF BEER ON THE WALL");
WRITE(" "); % BLANK LINE BETWEEN STANZAS %
END;
WRITE("THANKS FOR SINGING ALONG!");
END
AmigaE
PROC main()
DEF t: PTR TO CHAR,
s: PTR TO CHAR,
u: PTR TO CHAR, i, x
t := 'Take one down, pass it around\n'
s := '\d bottle\s of beer\s\n'
u := ' on the wall'
FOR i := 99 TO 0 STEP -1
ForAll({x}, [u, NIL], `WriteF(s, i, IF i <> 1 THEN 's' ELSE NIL,
x))
IF i > 0 THEN WriteF(t)
ENDFOR
ENDPROC
Apache Ant
Implementation in Apache Ant, due to the limitations of Ant, this requires ant-contrib for arithmetic operations and a dummy target to keep Ant from detecting the loop.
<?xml version="1.0"?> <project name="n bottles" default="99_bottles"> <!-- ant-contrib.sourceforge.net for arithmetic and if --> <taskdef resource="net/sf/antcontrib/antcontrib.properties"/> <!-- start count of bottles, you can set this with e.g. ant -f 99.xml -Dcount=10 --> <property name="count" value="99"/> <target name="99_bottles"> <antcall target="bottle"> <param name="number" value="${count}"/> </antcall> </target> <target name="bottle"> <echo message="${number} bottles of beer on the wall"/> <echo message="${number} bottles of beer"/> <echo message="Take one down, pass it around"/> <math result="result" operand1="${number}" operation="-" operand2="1" datatype="int"/> <echo message="${result} bottles of beer on the wall"/> <if> <not><equals arg1="${result}" arg2="0" /></not> <then> <antcall target="bottleiterate"> <param name="number" value="${result}"/> </antcall> </then> </if> </target> <target name="bottleiterate"> <antcall target="bottle"> <param name="number" value="${number}"/> </antcall> </target> </project>
Apex
for(Integer i = 99; i=0; i--){
system.debug(i + ' bottles of beer on the wall');
system.debug('\n');
system.debug(i + ' bottles of beer on the wall');
system.debug(i + ' bottles of beer');
system.debug('take one down, pass it around');
}
APL
Works with Dyalog APL.
Translated from J.
bob ← { (⍕⍵), ' bottle', (1=⍵)↓'s of beer'}
bobw ← {(bob ⍵) , ' on the wall'}
beer ← { (bobw ⍵) , ', ', (bob ⍵) , '; take one down and pass it around, ', bobw ⍵-1}
↑beer¨ ⌽(1-⎕IO)+⍳99
App Inventor
Using a 'for each ' block (simplest)
Note that the output label text is not displayed until the entire lyrics text has been built and there is some delay between button press and display.
Using a Clock Timer block (preferrred)
Output can be sent directly to a label with this preferred method as there is no noticeable delay between button press and output.
AppleScript
Iteration
repeat with beerCount from 99 to 1 by -1 set bottles to "bottles" if beerCount < 99 then if beerCount = 1 then set bottles to "bottle" end log "" & beerCount & " " & bottles & " of beer on the wall" log "" end log "" & beerCount & " " & bottles & " of beer on the wall" log "" & beerCount & " " & bottles & " of beer" log "Take one down, pass it around" end log "No more bottles of beer on the wall!"
Declaration
-- BRIEF ----------------------------------------------------------------------- on run set localisations to ¬ {"on the wall", ¬ "Take one down, pass it around", ¬ "Better go to the store to buy some more", "bottle"} intercalate("\n\n", ¬ (map(curry(incantation)'s |λ|(localisations), enumFromTo(99, 0)))) end run -- DECLARATIVE ----------------------------------------------------------------- -- incantation :: [String] -> Int -> String on incantation(xs, n) script asset on |λ|(n) unwords({(n as string), item -1 of xs & cond(n ≠ 1, "s", "")}) end |λ| end script script store on |λ|(n) unwords({asset's |λ|(n), item 1 of xs}) end |λ| end script set {distribute, solve} to items 2 thru 3 of xs if n > 0 then unlines({store's |λ|(n), asset's |λ|(n), distribute, store's |λ|(n - 1)}) else solve end if end incantation -- GENERICALLY DYSFUNCTIONAL --------------------------------------------------- -- cond :: Bool -> a -> a -> a on cond(bln, f, g) if bln then f else g end if end cond -- curry :: (Script|Handler) -> Script on curry(f) script on |λ|(a) script on |λ|(b) |λ|(a, b) of mReturn(f) end |λ| end script end |λ| end script end curry -- enumFromTo :: Int -> Int -> [Int] on enumFromTo(m, n) if m > n then set d to -1 else set d to 1 end if set lst to {} repeat with i from m to n by d set end of lst to i end repeat return lst end enumFromTo -- intercalate :: Text -> [Text] -> Text on intercalate(strText, lstText) set {dlm, my text item delimiters} to {my text item delimiters, strText} set strJoined to lstText as text set my text item delimiters to dlm return strJoined end intercalate -- map :: (a -> b) -> [a] -> [b] on map(f, xs) tell mReturn(f) set lng to length of xs set lst to {} repeat with i from 1 to lng set end of lst to |λ|(item i of xs, i, xs) end repeat return lst end tell end map -- Lift 2nd class handler function into 1st class script wrapper -- mReturn :: Handler -> Script on mReturn(f) if class of f is script then f else script property |λ| : f end script end if end mReturn -- unlines :: [String] -> String on unlines(xs) intercalate(linefeed, xs) end unlines -- unwords :: [String] -> String on unwords(xs) intercalate(space, xs) end unwords
Arbre
bottle(x):
template: '
$x bottles of beer on the wall.
$x bottles of beer.
Take one down and pass it around,
$y bottles of beer on the wall.
'
if x==0
template~{x: 'No more', y: 'No more'}
else
if x==1
template~{x: x, y: 'No more'}
else
template~{x: x, y: x-1}
bottles(n):
for x in [n..0]
bottle(x)
99bottles():
bottles(99) -> io
Argile
use std
let X be an int
for each X from 99 down to 1
prints X bottles of beer on the wall
prints X bottles of beer
prints "Take one down, pass it" around
if X == 1
echo No more "beer." Call da "amber lamps"
break
X--
prints X bottles of beer on the wall "\n"
X++
.:around :. -> text {X>59 ? "around", "to me"}
.:bottles:. -> text {X> 5 ? "bottles", (X>1 ? "buttles", "wall")}
.:of beer:. -> text {X>11 ? "of beer", "ov beeer"}
.:on the wall:. -> text {
X>17 ? "on the wall", (X>1 ? "on the bwall", "in the buttle")
}
ARM Assembly
See 99 Bottles of Beer/Assembly
ArnoldC
As ArnoldC does not feature string concatenation, the numbers of bottles and the rest of the parts of the lyrics are printed on separate lines.
IT'S SHOWTIME
HEY CHRISTMAS TREE is0
YOU SET US UP @NO PROBLEMO
HEY CHRISTMAS TREE bottles
YOU SET US UP 99
STICK AROUND is0
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer on the wall"
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer"
TALK TO THE HAND "Take one down, pass it around"
GET TO THE CHOPPER bottles
HERE IS MY INVITATION bottles
GET DOWN 1
ENOUGH TALK
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer on the wall"
GET TO THE CHOPPER is0
HERE IS MY INVITATION bottles
LET OFF SOME STEAM BENNET 0
ENOUGH TALK
CHILL
YOU HAVE BEEN TERMINATED
Astro
fun bottles(n): match __args__: (0) => "No more bottles" (1) => "1 bottle" (_) => "$n bottles" for n in 99..-1..1: print @format""" {bottles n} of beer on the wall {bottles n} of beer Take one down, pass it around {bottles n-1} of beer on the wall\n """
ATS
//
#include
"share/atspre_staload.hats"
//
(* ****** ****** *)
fun bottles
(n0: int): void = let
//
fun loop (n: int): void =
(
if n > 0 then
(
if n0 > n then println! ();
println! (n, " bottles of beer on the wall");
println! (n, " bottles of beer");
println! ("Take one down, pass it around");
println! (n-1, " bottles of beer on the wall");
loop (n - 1)
) (* end of [if] *)
)
//
in
loop (n0)
end // end of [bottles]
(* ****** ****** *)
implement main0 () = bottles (99)
AutoHotkey
AutoIt
AWK
Regular version
If you don't want so many beers, here you can specify the starting amount.
For example, just a sixpack:
# usage: gawk -v i=6 -f beersong.awk
function bb(n) {
b = " bottles of beer"
if( n==1 ) { sub("s","",b) }
if( n==0 ) { n="No more" }
return n b
}
BEGIN {
if( !i ) { i = 99 }
ow = "on the wall"
td = "Take one down, pass it around."
print "The beersong:\n"
while (i > 0) {
printf( "%s %s,\n%s.\n%s\n%s %s.\n\n",
bb(i), ow, bb(i), td, bb(--i), ow )
if( i==1 ) sub( "one","it", td )
}
print "Go to the store and buy some more!"
}
Output:
The beersong:
99 bottles of beer on the wall,
99 bottles of beer.
Take one down, pass it around.
98 bottles of beer on the wall.
...
3 bottles of beer on the wall,
3 bottles of beer.
Take one down, pass it around.
2 bottles of beer on the wall.
2 bottles of beer on the wall,
2 bottles of beer.
Take one down, pass it around.
1 bottle of beer on the wall.
1 bottle of beer on the wall,
1 bottle of beer.
Take it down, pass it around.
No more bottles of beer on the wall.
Go to the store and buy some more!
Bottled version
See http://www.99-bottles-of-beer.net/language-awk-1910.html
Axe
Pauses are added to accommodate the small calculator screen so all of the text can be read.
99→B
While B
Disp B▶Dec," BOTTLES OF","BEER ON THE WALL"
Disp B▶Dec," BOTTLES OF","BEER",i,i
getKeyʳ
Disp "TAKE ONE DOWN",i,"PASS IT AROUND",i
B--
Disp B▶Dec," BOTTLES OF","BEER ON THE WALL",i
getKeyʳ
End
Babel
-- beer.sp
{b " bottles of beer" <
bi { itoa << } <
bb { bi ! b << w << "\n" << } <
w " on the wall" <
beer
{<-
{ iter 1 + dup
<- bb ! ->
bi ! b << "\n" <<
"Take one down, pass it around\n" <<
iter bb ! "\n" << }
->
times}
< }
-- At the prompt, type 'N beer !' (no quotes), where N is the number of stanzas you desire
BASIC
Applesoft BASIC
BaCon
Commodore BASIC
FBSL
FreeBASIC
FUZE BASIC
Integer BASIC
Liberty BASIC
Microsoft Small Basic
OxygenBasic
PowerBASIC
PureBasic
REALbasic
Run BASIC
Smart BASIC
TI-83 BASIC
TI-89 BASIC
True BASIC
Visual Basic
Visual Basic .NET
ZX Spectrum Basic
Batch File
Battlestar
const bottle = " bottle" const plural = "s" const ofbeer = " of beer" const wall = " on the wall" const sep = ", " const takedown = "Take one down and pass it around, " const u_no = "No" const l_no = "no" const more = " more bottles of beer" const store = "Go to the store and buy some more, " const dotnl = ".\n" const nl = "\n" // Reserve 1024 bytes in the .bss section var x 1024 // Write two digits, based on the value in a fun printnum b = a a >= 10 a /= 10 // modulo is in the d register after idiv b = d a += 48 // ASCII value for '0' print(chr(a)) end a = b a += 48 // ASCII value for '0' print(chr(a)) end fun main loop 99 // Save loop counter for later, twice c -> stack c -> stack // Print the loop counter (passed in the a register) a = c printnum() // N, "bottles of beer on the wall, " x = bottle x += plural x += ofbeer x += wall x += sep print(x) // Retrieve and print the number stack -> a printnum() // N, "bottles of beer.\nTake one down and pass it around," x = bottle x += plural x += ofbeer x += dotnl x += takedown print(x) // N-1, "bottles of beer on the wall." stack -> a a-- // Store N-1, used just a few lines down a -> stack printnum() print(bottle) // Retrieve N-1 stack -> a // Write an "s" if the count is not 1 a != 1 print(plural) end // Write the rest + a blank line x = ofbeer x += wall x += dotnl x += nl print(x) // Skip to the top of the loop while the counter is >= 2 continue (c >= 2) // At the last two // "1 bottle of beer on the wall," a = 1 printnum() x = bottle x += ofbeer x += wall x += sep print(x) // "1" a = 1 printnum() // "bottle of beer. Take one down and pass it around," // "no more bottles of beer on the wall." // Blank line // "No more bottles of beer on the wall," // "no more bottles of beer." // "Go to the store and buy some more," x = bottle x += ofbeer x += dotnl x += takedown x += l_no x += more x += wall x += dotnl x += nl x += u_no x += more x += wall x += sep x += l_no x += more x += dotnl x += store print(x) // "99" a = 99 printnum() // "bottles of beer on the wall." x = bottle x += plural x += ofbeer x += wall x += dotnl print(x) end end // vim: set syntax=c ts=4 sw=4 et:
Bc
Works with GNU bc 1.06.
i = 99;
while ( 1 ) {
print i , " bottles of beer on the wall\n";
print i , " bottles of beer\nTake one down, pass it around\n";
if (i == 2) {
break
}
print --i , " bottles of beer on the wall\n";
}
print --i , " bottle of beer on the wall\n";
print i , " bottle of beer on the wall\n";
print i , " bottle of beer\nTake it down, pass it around\nno more bottles of beer on the wall\n";
quit
Beeswax
Straight forward implementation, displaying the full lyrics given on http://99-bottles-of-beer.net
> NN p
> d#_8~2~(P~3~.~1~>{` bottles of beer on the wall, `{` bottles of beer.`q
d`.llaw eht no reeb fo selttob `{pLM` ,dnuora ti ssap dna nwod eno ekaT`N<
q`.llaw eht no reeb fo elttob ` {<
> NN >{` bottle of beer on the wall, `{` bottle of beer.`N q
pN `.llaw eht no reeb fo selttob erom on ,dnuora ti ssap dna nwod eno ekaT`<
>N`No more bottles of beer on the wall, no more bottles of beer.`N q
;`.llaw eht no reeb fo selttob 99 ,erom emos yub dna erots eht ot oG`<
A much more “economic” version that tries to avoid repetition at the price of complicated conditional jumps and self-modifying code that takes up more place than the actual strings themselves. Output is the same as in the straightforward version.
#[email protected][email protected]~P9zE `N`p
[email protected]@.~2~.++~5zE `n`>`o`p
>0f1ff# q `erom `< #h3~1z< #h3~1z< #h3~1z<
d_8~2~(P~3~. ~1~>"b{>X^^^` bottle` ` of beer`@g"pX` on the wall`g"pX `, ` @p #
> d <#XL#^^^^^`s`# # ## # > `.`NN@ X#
b < < <
>~L#^^^^`s`# #h3~1zX #h3~1z<# # # # #
d #h3~1z<# #> `.` g"pXN @"p `Take one down and `p
>^^^^^^^^^; .# b XgNN < bM` ,dnuora ti ssap`<
d^^^^^^^^^^^^^^^^X~3~P(~2~8` ,erom emos yub dna erots eht ot`` oG`<
Befunge
See 99 Bottles of Beer/EsoLang
BlooP
Output is always in caps in the interpreter I use, but I typed the input in correct case to spare those whose interpreter might do lowercase and don't want to have this song shouted at them ;D.
DEFINE PROCEDURE ''MINUS'' [A,B]:
BLOCK 0: BEGIN
IF A < B, THEN:
QUIT BLOCK 0;
LOOP AT MOST A TIMES:
BLOCK 1: BEGIN
IF OUTPUT + B = A, THEN:
QUIT BLOCK 0;
OUTPUT <= OUTPUT + 1;
BLOCK 1: END;
BLOCK 0: END.
DEFINE PROCEDURE ''BOTTLES'' [COUNT]:
BLOCK 0: BEGIN
CELL(0) <= COUNT;
LOOP COUNT + 1 TIMES:
BLOCK 1: BEGIN
IF CELL(0) > 1, THEN:
PRINT[CELL(0), ' bottles of beer on the wall, ', CELL(0), ' bottles of beer. Take one down, pass it around, ', MINUS[CELL(0), 1], ' bottles of beer on the wall.'];
IF CELL(0) = 1, THEN:
PRINT['1 botle of beer on the wall, 1 bottle of beer. Take one down, pass it around, No more bottles of beer on the wall.'];
IF CELL(0) = 0, THEN:
PRINT['No more bottles of beer on the wall, no more bottles of beer. Go to the store, buy 99 more, 99 bottles of beer on the wall!'];
CELL(0) <= MINUS[CELL(0), 1];
BLOCK 1: END;
BLOCK 0: END.
BOTTLES[99];
Bracmat
Copy the code to a file called BottlesOfBeer.bra.
Start Bracmat and after the {?}
prompt write get$"BottlesOfBeer.bra" <Enter>.
Then, after the next prompt, write
!r <Enter>.
Notice that the lyrics has two more lines at the end:
No more bottles of beer on the wall, no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall.
Code to save to BottlesOfBeer.bra:
{BottlesOfBeer.bra
See http://99-bottles-of-beer.net/}
X=
new
= n upper nbottles lyrics
. 99:?n
& ( upper
= .@(!arg:%@?a ?z)&str$(upp$!a !z)
)
& ( nbottles
=
. str
$ ( ( !arg:>0
& !arg
" bottle"
(!arg:1&|s)
| "no more bottles"
)
" of beer"
)
)
& ( lyrics
= (upper$(nbottles$!n:?x) " on the wall, " !x ".\n")
( !n+-1:?n:~<0
& "Take one down and pass it around, "
nbottles$!n
" on the wall.
"
!lyrics
| "Go to the store and buy some more, "
nbottles$99
" on the wall.
"
)
)
& put$(str$!lyrics);
r=
get'"BottlesOfBeer.bra"
& rmv$(str$(BottlesOfBeer ".bak"))
& ren$("BottlesOfBeer.bra".str$(BottlesOfBeer ".bak"))
& put
$ ( "{BottlesOfBeer.bra
See http://99-bottles-of-beer.net/}
"
, "BottlesOfBeer.bra"
, NEW
)
& lst'(X,"BottlesOfBeer.bra",APP)
& put'(\n,"BottlesOfBeer.bra",APP)
& lst'(r,"BottlesOfBeer.bra",APP)
& put$(str$("\nnew'" X ";\n"),"BottlesOfBeer.bra",APP);
new'X;
Brainfuck
See 99 Bottles of Beer/EsoLang
Brat
99.to 2 { n |
p "#{n} bottles of beer on the wall, #{n} bottles of beer!"
p "Take one down, pass it around, #{n - 1} bottle#{true? n > 2 's' ''} of beer on the wall."
}
p "One bottle of beer on the wall, one bottle of beer!"
p "Take one down, pass it around, no more bottles of beer on the wall."
C
Translated from C++.
The simple solution
/* * 99 Bottles, C, KISS (i.e. keep it simple and straightforward) version */ #include <stdio.h> int main(void) { int n; for( n = 99; n > 2; n-- ) printf( "%d bottles of beer on the wall, %d bottles of beer.\n" "Take one down and pass it around, %d bottles of beer on the wall.\n\n", n, n, n - 1); printf( "2 bottles of beer on the wall, 2 bottles of beer.\n" "Take one down and pass it around, 1 bottle of beer on the wall.\n\n" "1 bottle of beer on the wall, 1 bottle of beer.\n" "Take one down and pass it around, no more bottles of beer on the wall.\n\n" "No more bottles of beer on the wall, no more bottles of beer.\n" "Go to the store and buy some more, 99 bottles of beer on the wall.\n"); return 0; }
A recursive solution
#include <stdio.h> int main(int argc, char *argv[]) { if(argc == 99) return 99; if(argv[0] != NULL){ argv[0] = NULL; argc = 0; } argc = main(argc + 1, argv); printf("%d bottle%c of beer on the wall\n", argc, argc == 1?'\0': 's'); printf("%d bottle%c of beer\n", argc, argc == 1?'\0': 's'); printf("Take one down, pass it around\n"); printf("%d bottle%c of beer on the wall\n\n", argc - 1, (argc - 1) == 1?'\0': 's'); return argc - 1; }
Code golf
#include <stdio.h> main(){_=100;while(--_)printf("%i bottle%s of beer in the wall,\n%i bottle%" "s of beer.\nTake one down, pass it round,\n%s%s\n\n",_,_-1?"s":"",_,_-1?"s" :"",_-1?(char[]){(_-1)/10?(_-1)/10+48:(_-1)%10+48,(_-1)/10?(_-1)%10+48:2+30, (_-1)/10?32:0,0}:"",_-1?"bottles of beer in the wall":"No more beers");}
A preprocessor solution
Of course, with the template metaprogramming solution, the program has still do the conversion of numbers to strings at runtime, and those function calls also cost unnecessary time. Couldn't we just compose the complete text at compile time, and just output it at run time? Well, with the preprocessor, that's indeed possible:
#include <iostream> #include <stdio.h> #define BOTTLE(nstr) nstr " bottles of beer" #define WALL(nstr) BOTTLE(nstr) " on the wall" #define PART1(nstr) WALL(nstr) "\n" BOTTLE(nstr) \ "\nTake one down, pass it around\n" #define PART2(nstr) WALL(nstr) "\n\n" #define MIDDLE(nstr) PART2(nstr) PART1(nstr) #define SONG PART1("100") CD2 PART2("0") #define CD2 CD3("9") CD3("8") CD3("7") CD3("6") CD3("5") \ CD3("4") CD3("3") CD3("2") CD3("1") CD4("") #define CD3(pre) CD4(pre) MIDDLE(pre "0") #define CD4(pre) MIDDLE(pre "9") MIDDLE(pre "8") MIDDLE(pre "7") \ MIDDLE(pre "6") MIDDLE(pre "5") MIDDLE(pre "4") MIDDLE(pre "3") \ MIDDLE(pre "2") MIDDLE(pre "1") int main(void) { (void) printf(SONG); return EXIT_SUCCESS; }
An inspection of the generated executable proves that it indeed contains the complete text of the song in one block.
The bottled version
WYSIWYG (with correct plurals and can buy some more):
int b =99,u =1; #include<stdio.h> char *d[16],y[] = "#:ottle/ of" ":eer_ a_Go<o5" "st>y\x20some6" "_Take8;down4p" "a=1rou7_17 _<" "h;_ m?_nd_ on" "_085wal" "l_ " "b_e _ t_ss it" "_?4bu_ore_9, " "\060.""@, 9$"; # define x c ^= #include <string.h> #define or(t,z) else\ if(c==t && !(c = 0) &&\ (c =! z)); int p(char *t) { char *s = t; int c; for ( d[c = 0] = y; !t && (d[c +1 ]= strchr(s = d[c], '_'));* (d[++c]++) = 0); for(t = s? s:t;(c= *s++); c && putchar (c)) { if (!((( x 48)& ~0xf ) && ( x 48)) ) p(d[c]), c= 0 ; or('$', p(b - 99?".\n": "." ) && p(b - 99? t : "")) or ('\x40', c && p( d[!!b-- + 2])) or('/', c && p( b^1? "s": "")) or ('\043', b++ ? p("So6" + --b):!printf("%d" , b ? --b : (b += 99))) or( 'S',!(++u % 3) * 32+ 78) or ('.', puts("."))}return c;} int main() {return p(0);}
C++
The simple solution
Works with g++ 4.8.1.
#include <iostream using std::cout; int main() { for(int bottles(99); bottles > 0; bottles -= 1){ cout << bottles << " bottles of beer on the wall\n" << bottles << " bottles of beer\n" << "Take one down, pass it around\n" << bottles - 1 << " bottles of beer on the wall\n\n"; } }
An object-oriented solution
See: 99 Bottles of Beer/C++/Object Oriented
A template metaprogramming solution
Of course, the output of the program always looks the same. One may therefore question why the program has to do all that tedious subtracting during runtime. Couldn't the compiler just generate the code to output the text, with ready-calculated constants? Indeed, it can, and the technique is called template metaprogramming. The following short code gives the text without containing a single variable, let alone a loop:
#include <iostream template<int max, int min> struct bottle_countdown { static const int middle = (min + max)/2; static void print() { bottle_countdown<max, middle+1>::print(); bottle_countdown<middle, min>::print(); } }; template<int value> struct bottle_countdown<value, value> { static void print() { std::cout << value << " bottles of beer on the wall\n" << value << " bottles of beer\n" << "Take one down, pass it around\n" << value-1 << " bottles of beer\n\n"; } }; int main() { bottle_countdown<100, 1>::print(); return 0; }
A Recursive solution
#include <iostream using namespace std; void rec(int bottles) { if ( bottles!=0) { cout << bottles << " bottles of beer on the wall" << endl; cout << bottles << " bottles of beer" << endl; cout << "Take one down, pass it around" << endl; cout << --bottles << " bottles of beer on the wall\n" << endl; rec(bottles); } } int main() { rec(99); system("pause"); return 0; }
A preprocessor solution
Of course, with the template metaprogramming solution, the program has still do the conversion of numbers to strings at runtime, and those function calls also cost unnecessary time. Couldn't we just compose the complete text at compile time, and just output it at run time? Well, with the preprocessor, that's indeed possible:
#include <iostream #include <ostream> #define BOTTLE(nstr) nstr " bottles of beer" #define WALL(nstr) BOTTLE(nstr) " on the wall" #define PART1(nstr) WALL(nstr) "\n" BOTTLE(nstr) \ "\nTake one down, pass it around\n" #define PART2(nstr) WALL(nstr) "\n\n" #define MIDDLE(nstr) PART2(nstr) PART1(nstr) #define SONG PART1("100") CD2 PART2("0") #define CD2 CD3("9") CD3("8") CD3("7") CD3("6") CD3("5") \ CD3("4") CD3("3") CD3("2") CD3("1") CD4("") #define CD3(pre) CD4(pre) MIDDLE(pre "0") #define CD4(pre) MIDDLE(pre "9") MIDDLE(pre "8") MIDDLE(pre "7") \ MIDDLE(pre "6") MIDDLE(pre "5") MIDDLE(pre "4") MIDDLE(pre "3") \ MIDDLE(pre "2") MIDDLE(pre "1") int main() { std::cout << SONG; return 0; }
Bottled Version
//>,_ //Beer Song>,_ #include <iostream> using namespace std; int main(){ for( int b=-1; b<99; cout << '\n') for ( int w=0; w<3; cout << ".\n"){ if (w==2) cout << (( b--) ?"Take one dow" "n and pass it arou" "nd":"Go to the sto" "re and buy some mo" "re"); if (b<0) b=99 ; do{ if (w) cout << ", "; if (b) cout << b; else cout << ( (w) ? 'n' : 'N') << "o more"; cout << " bottle" ; if (b!=1) cout << 's' ; cout << " of beer"; if (w!=1) cout << " on th" "e wall" ;} while (!w++);} return 0 ; } // // by barrym 2011-05-01 // no bottles were harmed in the // making of this program!!!
C#
using System; class Program { static void Main(string[] args) { for (int i = 99; i > -1; i--) { if (i == 0) { Console.WriteLine("No more bottles of beer on the wall, no more bottles of beer."); Console.WriteLine("Go to the store and buy some more, 99 bottles of beer on the wall."); break; } if (i == 1) { Console.WriteLine("1 bottle of beer on the wall, 1 bottle of beer."); Console.WriteLine("Take one down and pass it around, no more bottles of beer on the wall."); Console.WriteLine(); } else { Console.WriteLine("{0} bottles of beer on the wall, {0} bottles of beer.", i); Console.WriteLine("Take one down and pass it around, {0} bottles of beer on the wall.", i - 1); Console.WriteLine(); } } } }
C#6 Implementation
Works with C# 6+.
using System; class Program { static void Main() { Func<int, bool, string> f = (x, y) => $"{(x == 0 ? "No more" : x.ToString())} bottle{(x == 1 ? "" : "s")} of beer{(y ? " on the wall" : "")}\r\n"; for (int i = 99; i > 0; i--) Console.WriteLine($"{f(i, true)}{f(i, false)}Take one down, pass it around\r\n{f(i - 1, true)}"); } }
Linq Implementation
Works with C# 3+.
using System; using System.Linq; class Program { static void Main() { var query = from total in Enumerable.Range(0,100).Reverse() select (total > 0) ? string.Format("{0} bottles of beer on the wall\n{0} bottles of beer\nTake one down, pass it around", total) : string.Format("{0} bottles left", total); foreach (var item in query) { Console.WriteLine(item); } } }
Flexible Version
using System; using System.Globalization; class Program { const string Vessel = "bottle"; const string Beverage = "beer"; const string Location = "on the wall"; private static string DefaultAction(ref int bottles) { bottles--; return "take one down, pass it around,"; } private static string FallbackAction(ref int bottles) { bottles += 99; return "go to the store, buy some more,"; } private static string Act(ref int bottles) { return bottles > 0 ? DefaultAction(ref bottles) : FallbackAction(ref bottles); } static void Main() { Func<int, string> plural = b => b == 1 ? "" : "s"; Func<int, string> describeCount = b => b == 0 ? "no more" : b.ToString(); Func<int, string> describeBottles = b => string.Format("{0} {1}{2} of {3}", describeCount(b), Vessel, plural(b), Beverage); Action<string> write = s => Console.WriteLine(CultureInfo.CurrentCulture.TextInfo.ToTitleCase(s)); int bottles = 99; while (true) { write(string.Format("{0} {1}, {0},", describeBottles(bottles), Location)); write(Act(ref bottles)); write(string.Format("{0} {1}.", describeBottles(bottles), Location)); write(string.Empty); } } }
Using Formatting
Works with C# 3+.
class songs { static void Main(string[] args) { beer(3); } private static void beer(int bottles) { for (int i = bottles; i > 0; i--) { if (i > 1) { Console.Write("{0}\n{1}\n{2}\n{3}\n\n", i + " bottles of beer on the wall", i + " bottles of beer", "Take one down, pass it around", (i - 1) + " bottles of beer on the wall"); } else Console.Write("{0}\n{1}\n{2}\n{3}\n\n", i + " bottle of beer on the wall", i + " bottle of beer", "Take one down, pass it around", (i - 1) + " bottles of beer on the wall...."); } } }
Output:
3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottles of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
0 bottles of beer on the wall....
Using iterator blocks
Works with C# 3+.
using System; using System.Linq; class Program { static void Main() { BeerBottles().Take(99).ToList().ForEach(Console.WriteLine); } static IEnumerable<String> BeerBottles() { int i = 100; String f = "{0}, {1}. Take one down, pass it around, {2}"; Func<int, bool, String> booze = (c , b) => String.Format("{0} bottle{1} of beer{2}", c>0 ? c.ToString() : "no more", (c==1 ? "" : "s"), b ? " on the wall" : ""); while (--i >= 1) yield return String.Format(f, booze(i, true), booze(i, false), booze(i - 1, true)); } }
A Fun One
string[] bottles = { "80 Shilling", "Abita Amber", "Adams Broadside Ale", "Altenmünster Premium", "August Schell's SnowStorm", "Bah Humbug! Christmas Ale", "Beck's Oktoberfest", "Belhaven Wee Heavy", "Bison Chocolate Stout", "Blue Star Wheat Beer", "Bridgeport Black Strap Stout", "Brother Thelonius Belgian-Style Abbey Ale", "Capital Blonde Doppelbock", "Carta Blanca", "Celis Raspberry Wheat", "Christian Moerlein Select Lager", "Corona", "Czechvar", "Delirium Tremens", "Diamond Bear Southern Blonde", "Don De Dieu", "Eastside Dark", "Eliot Ness", "Flying Dog K-9 Cruiser Altitude Ale", "Fuller's London Porter", "Gaffel Kölsch", "Golden Horseshoe", "Guinness Pub Draught", "Hacker-Pschorr Weisse", "Hereford & Hops Black Spring Double Stout", "Highland Oatmeal Porter", "Ipswich Ale", "Iron City", "Jack Daniel's Amber Lager", "Jamaica Sunset India Pale Ale", "Killian's Red", "König Ludwig Weiss", "Kronenbourg 1664", "Lagunitas Hairy Eyball Ale", "Left Hand Juju Ginger", "Locktender Lager", "Magic Hat Blind Faith", "Missing Elf Double Bock", "Muskoka Cream Ale ", "New Glarus Cherry Stout", "Nostradamus Bruin", "Old Devil", "Ommegang Three Philosophers", "Paulaner Hefe-Weizen Dunkel", "Perla Chmielowa Pils", "Pete's Wicked Springfest", "Point White Biere", "Prostel Alkoholfrei", "Quilmes", "Rahr's Red", "Rebel Garnet", "Rickard's Red", "Rio Grande Elfego Bock", "Rogue Brutal Bitter", "Roswell Alien Amber Ale", "Russian River Pliny The Elder", "Samuel Adams Blackberry Witbier", "Samuel Smith's Taddy Porter", "Schlafly Pilsner", "Sea Dog Wild Blueberry Wheat Ale", "Sharp's", "Shiner 99", "Sierra Dorada", "Skullsplitter Orkney Ale", "Snake Chaser Irish Style Stout", "St. Arnold Bock", "St. Peter's Cream Stout", "Stag", "Stella Artois", "Stone Russian Imperial Stout", "Sweetwater Happy Ending Imperial Stout", "Taiwan Gold Medal", "Terrapin Big Hoppy Monster", "Thomas Hooker American Pale Ale", "Tie Die Red Ale", "Toohey's Premium", "Tsingtao", "Ugly Pug Black Lager", "Unibroue Qatre-Centieme", "Victoria Bitter", "Voll-Damm Doble Malta", "Wailing Wench Ale", "Warsteiner Dunkel", "Wellhead Crude Oil Stout", "Weyerbacher Blithering Idiot Barley-Wine Style Ale", "Wild Boar Amber", "Würzburger Oktoberfest", "Xingu Black Beer", "Yanjing", "Younger's Tartan Special", "Yuengling Black & Tan", "Zagorka Special", "Zig Zag River Lager", "Zywiec" }; int bottlesLeft = 99; const int FIRST_LINE_SINGULAR = 98; const int FINAL_LINE_SINGULAR = 97; string firstLine = ""; string finalLine = ""; for (int i = 0; i < 99; i++) { firstLine = bottlesLeft.ToString() + " bottle"; if (i != FIRST_LINE_SINGULAR) firstLine += "s"; firstLine += " of beer on the wall, " + bottlesLeft.ToString() + " bottle"; if (i != FIRST_LINE_SINGULAR) firstLine += "s"; firstLine += " of beer"; Console.WriteLine(firstLine); Console.WriteLine("Take the " + bottles[i] + " down, pass it around,"); bottlesLeft--; finalLine = bottlesLeft.ToString() + " bottle"; if (i != FINAL_LINE_SINGULAR) finalLine += "s"; finalLine += " of beer on the wall!"; Console.WriteLine(finalLine); Console.WriteLine(); Console.ReadLine(); }
Using recursion
public static void BottlesSong(int numberOfBottles) { if (numberOfBottles > 0) { Console.WriteLine("{0} bottles of beer on the wall", numberOfBottles); Console.WriteLine("{0} bottles of beer ", numberOfBottles); Console.WriteLine("Take one down, pass it around"); Console.WriteLine("{0} bottles of beer ", numberOfBottles - 1); Console.WriteLine(); BottlesSong(--numberOfBottles); } }
Using a While Loop
static void Main(string[] args) { int numBottles = 99; while (numBottles > 0) { if (numBottles > 1) { WriteLine("{0} bottles of beer on the wall, {0} bottles of beer.", numBottles); numBottles -= 1; WriteLine("Take one down, pass it around, {0} bottles of beer on the wall.\n", numBottles); } else { WriteLine("{0} bottle of beer on the wall, {0} bottle of beer.", numBottles); numBottles -= 1; WriteLine("Take one down, pass it around, no more bottles of beer on the wall.\n"); } } WriteLine("No more bottles of beer on the wall, no more bottles of beer."); WriteLine("Go to the store to buy some more, 99 bottles of beer on the wall..."); }
Ceylon
shared void ninetyNineBottles() {
String bottles(Integer count) =>
"``count == 0 then "No" else count``
bottle``count == 1 then "" else "s"``".normalized;
for(i in 99..1) {
print("``bottles(i)`` of beer on the wall
``bottles(i)`` of beer!
Take one down, pass it around
``bottles(i - 1)`` of beer on the wall!\n");
}
}
Clay
/* A few options here: I could give n type Int; or specify that n is of any
numeric type; but here I just let it go -- that way it'll work with anything
that compares with 1 and that printTo knows how to convert to a string. And
all checked at compile time, remember. */
getRound(n) {
var s = String();
var bottle = if (n == 1) " bottle " else " bottles ";
printTo(s,
n, bottle, "of beer on the wall\n",
n, bottle, "of beer\n",
"take one down, pass it around\n",
n, bottle, "of beer on the wall!\n");
return s;
}
main() {
println(join("\n", mapped(getRound, reversed(range(100)))));
}
Clio
fn bottle n:
n -> if = 0: 'no more bottles'
elif = 1: n + ' bottle'
else: n + ' bottles'
[99:0] -> * (@eager) fn i:
i -> bottle -> print (transform i: sentence-case) 'of beer on the wall,' @ 'of beer.'
if i = 0:
'Go to the store, buy some more, 99 bottles of beer on the wall.' -> print
else:
i - 1 -> bottle -> print 'Take one down and pass it around,' @ 'of beer on the wall.\n'
Chapel
Copied from http://99-bottles-of-beer.net/language-chapel-1215.html, with minor modifications for chapel 1.7
Works with Chapel 1.7.0.
/***********************************************************************
* Chapel implementation of "99 bottles of beer"
*
* by Brad Chamberlain and Steve Deitz
* 07/13/2006 in Knoxville airport while waiting for flight home from
* HPLS workshop
* compiles and runs with chpl compiler version 1.7.0
* for more information, contact: [email protected]
*
*
* Notes:
* o as in all good parallel computations, boundary conditions
* constitute the vast bulk of complexity in this code (invite Brad to
* tell you about his zany boundary condition simplification scheme)
* o uses type inference for variables, arguments
* o relies on integer->string coercions
* o uses named argument passing (for documentation purposes only)
***********************************************************************/
// allow executable command-line specification of number of bottles
// (e.g., ./a.out -snumBottles=999999)
config const numBottles = 99;
const numVerses = numBottles+1;
// a domain to describe the space of lyrics
var LyricsSpace: domain(1) = {1..numVerses};
// array of lyrics
var Lyrics: [LyricsSpace] string;
// parallel computation of lyrics array
[verse in LyricsSpace] Lyrics(verse) = computeLyric(verse);
// as in any good parallel language, I/O to stdout is serialized.
// (Note that I/O to a file could be parallelized using a parallel
// prefix computation on the verse strings' lengths with file seeking)
writeln(Lyrics);
// HELPER FUNCTIONS:
proc computeLyric(verseNum) {
var bottleNum = numBottles - (verseNum - 1);
var nextBottle = (bottleNum + numVerses - 1)%numVerses;
return "\n" // disguise space used to separate elements in array I/O
+ describeBottles(bottleNum, startOfVerse=true) + " on the wall, "
+ describeBottles(bottleNum) + ".\n"
+ computeAction(bottleNum)
+ describeBottles(nextBottle) + " on the wall.\n";
}
proc describeBottles(bottleNum, startOfVerse:bool = false) {
// NOTE: bool should not be necessary here (^^^^); working around bug
var bottleDescription = if (bottleNum) then bottleNum:string
else (if startOfVerse then "N"
else "n")
+ "o more";
return bottleDescription
+ " bottle" + (if (bottleNum == 1) then "" else "s")
+ " of beer";
}
proc computeAction(bottleNum) {
return if (bottleNum == 0) then "Go to the store and buy some more, "
else "Take one down and pass it around, ";
}
Chef
See 99 Bottles of Beer/EsoLang
Cind
execute() {
// this class provides synchronization
// to get unique number of the bottle
class monitor giver {
int number = 100;
.get() { return --number; }
}
var g = new giver();
// start 99 concurrently worked threads
// each thread gets own number of the bottle and prints out his own verse
// (notice that the output lines from the threads will be mixed together)
{#[99]
int nr = g.get(); // get own number
host.println(nr," bottles of beer on the wall, "+nr+" bottles of beer");
host.print("Take one down, pass it around,");
if (nr > 1) {
host.println((nr-1)," bottles of beer on the wall.");
}
else {
host.println("no more bottles of beer on the wall.");
}
}
host.println("No more bottles of beer on the wall, no more bottles of beer.");
host.println("Go to the store and buy some more, 99 bottles of beer on the wall.");
return 0;
}
CLIPS
(deffacts beer-bottles
(bottles 99))
(deffunction bottle-count
(?count)
(switch ?count
(case 0 then "No more bottles of beer")
(case 1 then "1 more bottle of beer")
(default (str-cat ?count " bottles of beer"))))
(defrule stanza
?bottles <- (bottles ?count)
=>
(retract ?bottles)
(printout t (bottle-count ?count) " on the wall," crlf)
(printout t (bottle-count ?count) "." crlf)
(printout t "Take one down, pass it around," crlf)
(printout t (bottle-count (- ?count 1)) " on the wall." crlf crlf)
(if (> ?count 1) then (assert (bottles (- ?count 1)))))
Clojure
(defn paragraph [num] (str num " bottles of beer on the wall\n" num " bottles of beer\n" "Take one down, pass it around\n" (dec num) " bottles of beer on the wall.\n")) (defn lyrics [] (let [numbers (range 99 0 -1) paragraphs (map paragraph numbers)] (clojure.string/join "\n" paragraphs))) (print (lyrics))
Or, using cl-format: Translated from Common Lisp.
(clojure.pprint/cl-format true "~{~[~^~]~:*~D bottle~:P of beer on the wall~%~:*~D bottle~:P of beer Take one down, pass it around,~%~D bottle~:P~:* of beer on the wall.~2%~}" (range 99 0 -1))
COBOL
Works with OpenCOBOL 1.1.
Free form version.
identification division.
program-id. ninety-nine.
environment division.
data division.
working-storage section.
01 counter pic 99.
88 no-bottles-left value 0.
88 one-bottle-left value 1.
01 parts-of-counter redefines counter.
05 tens pic 9.
05 digits pic 9.
01 after-ten-words.
05 filler pic x(7) value spaces.
05 filler pic x(7) value "Twenty".
05 filler pic x(7) value "Thirty".
05 filler pic x(7) value "Forty".
05 filler pic x(7) value "Fifty".
05 filler pic x(7) value "Sixty".
05 filler pic x(7) value "Seventy".
05 filler pic x(7) value "Eighty".
05 filler pic x(7) value "Ninety".
05 filler pic x(7) value spaces.
01 after-ten-array redefines after-ten-words.
05 atens occurs 10 times pic x(7).
01 digit-words.
05 filler pic x(9) value "One".
05 filler pic x(9) value "Two".
05 filler pic x(9) value "Three".
05 filler pic x(9) value "Four".
05 filler pic x(9) value "Five".
05 filler pic x(9) value "Six".
05 filler pic x(9) value "Seven".
05 filler pic x(9) value "Eight".
05 filler pic x(9) value "Nine".
05 filler pic x(9) value "Ten".
05 filler pic x(9) value "Eleven".
05 filler pic x(9) value "Twelve".
05 filler pic x(9) value "Thirteen".
05 filler pic x(9) value "Fourteen".
05 filler pic x(9) value "Fifteen".
05 filler pic x(9) value "Sixteen".
05 filler pic x(9) value "Seventeen".
05 filler pic x(9) value "Eighteen".
05 filler pic x(9) value "Nineteen".
05 filler pic x(9) value spaces.
01 digit-array redefines digit-words.
05 adigits occurs 20 times pic x(9).
01 number-name pic x(15).
procedure division.
100-main section.
100-setup.
perform varying counter from 99 by -1 until no-bottles-left
perform 100-show-number
display " of beer on the wall"
perform 100-show-number
display " of beer"
display "Take " with no advancing
if one-bottle-left
display "it " with no advancing
else
display "one " with no advancing
end-if
display "down and pass it round"
subtract 1 from counter giving counter
perform 100-show-number
display " of beer on the wall"
add 1 to counter giving counter
display space
end-perform.
display "No more bottles of beer on the wall"
display "No more bottles of beer"
display "Go to the store and buy some more"
display "Ninety Nine bottles of beer on the wall"
stop run.
100-show-number.
if no-bottles-left
display "No more" with no advancing
else
if counter < 20
display function trim( adigits( counter ) ) with no advancing
else
if counter < 100
move spaces to number-name
string atens( tens ) delimited by space, space delimited by size, adigits( digits ) delimited by space into number-name
display function trim( number-name) with no advancing
end-if
end-if
end-if.
if one-bottle-left
display " bottle" with no advancing
else
display " bottles" with no advancing
end-if.
100-end.
end-program.
Another free-form version, without using DISPLAY NO ADVANCING.
identification division.
program-id. ninety-nine.
environment division.
data division.
working-storage section.
01 counter pic 99.
88 no-bottles-left value 0.
88 one-bottle-left value 1.
01 parts-of-counter redefines counter.
05 tens pic 9.
05 digits pic 9.
01 after-ten-words.
05 filler pic x(7) value spaces.
05 filler pic x(7) value "Twenty".
05 filler pic x(7) value "Thirty".
05 filler pic x(7) value "Forty".
05 filler pic x(7) value "Fifty".
05 filler pic x(7) value "Sixty".
05 filler pic x(7) value "Seventy".
05 filler pic x(7) value "Eighty".
05 filler pic x(7) value "Ninety".
05 filler pic x(7) value spaces.
01 after-ten-array redefines after-ten-words.
05 atens occurs 10 times pic x(7).
01 digit-words.
05 filler pic x(9) value "One".
05 filler pic x(9) value "Two".
05 filler pic x(9) value "Three".
05 filler pic x(9) value "Four".
05 filler pic x(9) value "Five".
05 filler pic x(9) value "Six".
05 filler pic x(9) value "Seven".
05 filler pic x(9) value "Eight".
05 filler pic x(9) value "Nine".
05 filler pic x(9) value "Ten".
05 filler pic x(9) value "Eleven".
05 filler pic x(9) value "Twelve".
05 filler pic x(9) value "Thirteen".
05 filler pic x(9) value "Fourteen".
05 filler pic x(9) value "Fifteen".
05 filler pic x(9) value "Sixteen".
05 filler pic x(9) value "Seventeen".
05 filler pic x(9) value "Eighteen".
05 filler pic x(9) value "Nineteen".
05 filler pic x(9) value spaces.
01 digit-array redefines digit-words.
05 adigits occurs 20 times pic x(9).
01 number-name pic x(15).
01 stringified pic x(30).
01 outline pic x(50).
01 other-numbers.
03 n pic 999.
03 r pic 999.
procedure division.
100-main section.
100-setup.
perform varying counter from 99 by -1 until no-bottles-left
move spaces to outline
perform 100-show-number
string stringified delimited by "|", space, "of beer on the wall" into outline end-string
display outline end-display
move spaces to outline
string stringified delimited by "|", space, "of beer" into outline end-string
display outline end-display
move spaces to outline
move "Take" to outline
if one-bottle-left
string outline delimited by space, space, "it" delimited by size, space, "|" into outline end-string
else
string outline delimited by space, space, "one" delimited by size, space, "|" into outline end-string
end-if
string outline delimited by "|", "down and pass it round" delimited by size into outline end-string
display outline end-display
move spaces to outline
subtract 1 from counter giving counter end-subtract
perform 100-show-number
string stringified delimited by "|", space, "of beer on the wall" into outline end-string
display outline end-display
add 1 to counter giving counter end-add
display space end-display
end-perform.
display "No more bottles of beer on the wall"
display "No more bottles of beer"
display "Go to the store and buy some more"
display "Ninety-Nine bottles of beer on the wall"
stop run.
100-show-number.
if no-bottles-left
move "No more|" to stringified
else
if counter < 20
string function trim( adigits( counter ) ), "|" into stringified
else
if counter < 100
move spaces to number-name
string atens( tens ) delimited by space, space delimited by size, adigits( digits ) delimited by space into number-name end-string
move function trim( number-name) to stringified
divide counter by 10 giving n remainder r end-divide
if r not = zero
inspect stringified replacing first space by "-"
end-if
inspect stringified replacing first space by "|"
end-if
end-if
end-if.
if one-bottle-left
string stringified delimited by "|", space, "bottle|" delimited by size into stringified end-string
else
string stringified delimited by "|", space, "bottles|" delimited by size into stringified end-string
end-if.
100-end.
end-program.
A more concise version that adheres to the minimum guidelines. Leading zeros are not suppressed. (OpenCOBOL - 1.1.0)
program-id. ninety-nine.
data division.
working-storage section.
01 cnt pic 99.
procedure division.
perform varying cnt from 99 by -1 until cnt < 1
display cnt " bottles of beer on the wall"
display cnt " bottles of beer"
display "Take one down, pass it around"
subtract 1 from cnt
display cnt " bottles of beer on the wall"
add 1 to cnt
display space
end-perform.
CoffeeScript
bottlesOfBeer = (n) ->
"#{n} bottle#{if n is 1 then '' else 's'} of beer"
console.log """
#{bottlesOfBeer n} on the wall
#{bottlesOfBeer n}
Take one down, pass it around
#{bottlesOfBeer n - 1} on the wall
\n""" for n in [99..1]
With completely different approach...
for j in [99..1]
x=''
x += [j,j-1,'\nTake one down, pass it around\n'," bottles of beer",' on the wall\n'][i] for i in [0,3,4,0,3,2,1,3,4]
console.log x.replace /(1.+)s/g, '$1'
or as a one liner...
console.log( if (j+2)%4 then (x=Math.round j/4)+" bottle#{if x-1 then 's' else ''} of beer#{if (j+1)%4 then ' on the wall' else ''}" else "Take one down, pass it around" ) for j in [396..1]
or another completely different one liner
((console.log if i is 2 then "Take one down, pass it around" else "#{b-!(i-1%4)} bottle#{if 4*b+i<10 and b-i then '' else 's'} of beer#{if i%3 then ' on the wall' else ''}") for i in [4..1]) for b in [99..1]
ColdFusion
Classic tag based CFML
<cfloop index="x" from="99" to="0" step="-1">
<cfset plur = iif(x is 1,"",DE("s"))>
#x# bottle#plur# of beer on the wall
#x# bottle#plur# of beer
Take one down, pass it around
#iif(x is 1,DE("No more"),"x-1")# bottle#iif(x is 2,"",DE("s"))# of beer on the wall
</cfloop>
</cfoutput>
or if you prefer: (identical output, grammatically correct to the last stanza)
CFScript
for (x=99; x gte 1; x--) {
plur = iif(x==1,'',DE('s'));
WriteOutput("#x# bottle#plur# of beer on the wall
#x# bottle#plur# of beer
Take one down, pass it around
#iif(x is 1,DE('No more'),'x-1')# bottle#iif(x is 2,'',DE('s'))# of beer on the wall
");
}
</cfscript>
Comefrom0x10
bottles = ' bottles '
remaining = 99
one_less_bottle = remaining
depluralize
comefrom drinking if one_less_bottle is 1
bottles = ' bottle '
drinking
comefrom if remaining is one_less_bottle
remaining bottles 'of beer on the wall'
remaining bottles 'of beer'
'Take one down, pass it around'
one_less_bottle = remaining - 1
one_less_bottle bottles 'of beer on the wall`n'
remaining = remaining - 1
comefrom if one_less_bottle is 0
'No more bottles of beer on the wall'
Output:
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No more bottles of beer on the wall
Common Lisp
Component Pascal
Crystal
99.downto(1) do |n| puts "#{n} bottle#{n > 1 ? "s" : ""} of beer on the wall" puts "#{n} bottle#{n > 1 ? "s" : ""} of beer" puts "Take one down, pass it around" puts "#{n-1} bottle#{n > 2 ? "s" : ""} of beer on the wall\n\n" if n > 1 end puts "No more bottles of beer on the wall"
D
Simple Solution
Works with D|2.
Based on Steward Gordon's code at: http://99-bottles-of-beer.net/language-d-721.html.
import std.stdio; void main() { int bottles = 99; while (bottles > 1) { writeln(bottles, " bottles of beer on the wall,"); writeln(bottles, " bottles of beer."); writeln("Take one down, pass it around,"); if (--bottles > 1) { writeln(bottles, " bottles of beer on the wall.\n"); } } writeln("1 bottle of beer on the wall.\n"); writeln("No more bottles of beer on the wall,"); writeln("no more bottles of beer."); writeln("Go to the store and buy some more,"); writeln("99 bottles of beer on the wall."); }
CTFE Solution
CTFE (Compile-Time Function Execution) is a feature of D that allows for pure functions of arbitrary complexity to be completely evaluated at compile time when every parameter is known. Note that this is distinct from the template meta-programming tricks used by some other languages, and this bottles() function could just as easily be executed during run-time. The compiled result of this program simply prints the pre-generated lyrics to the song, using a standard compiler pragma directive.
import std.stdio, std.conv; string bottles(in size_t num) pure { static string bottlesRecurse(in size_t num) pure { return num.text ~ " bottles of beer on the wall,\n" ~ num.text ~ " bottles of beer!\n" ~ "Take one down, pass it around,\n" ~ (num - 1).text ~ " bottle" ~ ((num - 1 == 1) ? "" : "s") ~ " of beer on the wall.\n\n" ~ ((num > 2) ? bottlesRecurse(num - 1) : "1 bottle of beer on the wall,\n" ~ "1 bottle of beer!\n" ~ "Take one down, pass it around,\n" ~ "No bottles of beer on the wall!\n\n"); } return bottlesRecurse(num) ~ "Go to the store and buy some more...\n" ~ num.text ~ " bottles of beer on the wall!"; } pragma(msg, 99.bottles); void main() {}
=== Template Meta-Programming Solution ===
Uses D template meta-programming and recursion to pre-generate the song lyrics and prints it at compile via pragma(msg,...)
module bottles; template BeerSong(int Bottles) { static if (Bottles == 1) { enum BeerSong = "1 bottle of beer on the wall\n" ~ "1 bottle of beer\ntake it down, pass it around\n" ~ " no more bottles of beer on the wall\n"; } else { enum BeerSong = Bottles.stringof ~ " bottles of beer on the wall\n" ~ Bottles.stringof ~ " bottles of beer\ntake it down, pass it around\n" ~ BeerSong!(Bottles-1); } } pragma(msg,BeerSong!99); void main(){}
Dart
main() { for(int x=99;x>0;x--) { print("$x bottles of beer on the wall"); print("$x bottles of beer"); print("Take one down, pass it around"); print("${x-1} bottles of beer on the wall"); print(""); } }
Dc
Works with GNU dc. Works with OpenBSD dc.
[
dnrpr
dnlBP
lCP
1-dnrp
rd2r >L
]sL
[Take one down, pass it around
]sC
[ bottles of beer
]sB
[ bottles of beer on the wall]
99
lLx
dnrpsA
dnlBP
lCP
1-
dn[ bottle of beer on the wall]p
rdnrpsA
n[ bottle of beer
]P
[Take it down, pass it around
]P
[no more bottles of beer on the wall
]P
Similar to the program above, but without 'n' and 'r' commands. It prints the numbers on separate lines than the strings.
Works with AT&T dc.
[
plAP
plBP
lCP
1-dplAP
d2r >L
]sL
[Take one down, pass it around
]sC
[bottles of beer
]sB
[bottles of beer on the wall
]sA
99
lLx
plAP
plBP
lCP
1-
p
[bottle of beer on the wall
]P
p
[bottle of beer
]P
[Take it down, pass it around
]P
[no more bottles of beer on the wall
]P
Delphi
Déjà Vu
plural i:
if = 1 i "" "s"
bottles i:
local :s plural i
!print( to-str i " bottle"s" of beer on the wall, " to-str i " bottle"s" of beer," )
!print\ "You take one down, pass it around, "
set :i -- i
if i:
set :s plural i
!print( to-str i " bottle"s" of beer on the wall." )
bottles i
else:
!print "no more bottles of beer on the wall, no more bottles of beer."
!print "Go to the store and buy some more, 99 bottles of beer on the wall."
bottles 99
Dyalect
Translated from Swift.
for i in 99..1 {
print("\(i) bottles of beer on the wall, \(i) bottles of beer.")
const next = if i == 1 {
"no"
} else {
(i - 1).toString()
}
print("Take one down and pass it around, \(next) bottles of beer on the wall.")
}
Dylan
Module: bottles
define method bottles (n :: <integer>)
for (n from 99 to 1 by -1)
format-out("%d bottles of beer on the wall,\n"
"%d bottles of beer\n"
"Take one down, pass it around\n"
"%d bottles of beer on the wall\n",
n, n, n - 1);
end
end method
E
def bottles(n) {
return switch (n) {
match ==0 { "No bottles" }
match ==1 { "1 bottle" }
match _ { `$n bottles` }
}
}
for n in (1..99).descending() {
println(`${bottles(n)} of beer on the wall,
${bottles(n)} of beer.
Take one down, pass it around,
${bottles(n.previous())} of beer on the wall.
`)
}
ECL
Layout := RECORD
UNSIGNED1 RecID1;
UNSIGNED1 RecID2;
STRING30 txt;
END;
Beers := DATASET(99,TRANSFORM(Layout,
SELF.RecID1 := COUNTER,SELF.RecID2 := 0,SELF.txt := ''));
Layout XF(Layout L,INTEGER C) := TRANSFORM
IsOneNext := L.RecID1-1 = 1;
IsOne := L.RecID1 = 1;
SELF.txt := CHOOSE(C,
(STRING)(L.RecID1-1) + ' bottle'+IF(IsOneNext,'','s')+' of beer on the wall',
'Take one down, pass it around',
(STRING)(L.RecID1) + ' bottle'+IF(IsOne,'','s')+' of beer',
(STRING)(L.RecID1) + ' bottle'+IF(IsOne,'','s')+' of beer on the wall','');
SELF.RecID2 := C;
SELF := L;
END;
Rev := NORMALIZE(Beers,5,XF(LEFT,COUNTER));
OUTPUT(SORT(Rev,-Recid1,-RecID2),{txt},ALL);
Egel
import "prelude.eg"
import "io.ego"
using System
using IO
def print_rhyme =
[ 0 ->
print "better go to the store, and buy some more\n"
| N ->
let _ = print N " bottles of beer on the wall\n" in
let _ = print N " bottles of beer\n" in
let _ = print "take one down, pass it around\n" in
print_rhyme (N - 1) ]
def main = print_rhyme 99
EGL
program TestProgram type BasicProgram {}
function main()
for (count int from 99 to 1 decrement by 1)
SysLib.writeStdout( bottleStr( count ) :: " of beer on the wall." );
SysLib.writeStdout( bottleStr( count ) :: " of beer." );
SysLib.writeStdout( "Take one down, pass it around." );
SysLib.writeStdout( bottleStr( count - 1) :: " of beer on the wall.\n");
end
end
private function bottleStr( count int in) returns( string )
case ( count )
when ( 1 )
return( "1 bottle" );
when ( 0 )
return( "No more bottles" );
otherwise
return( count :: " bottles" );
end
end
end
Eiffel
class
APPLICATION
create
make
feature {NONE} -- Initialization
make
local
bottles: INTEGER
do
from
bottles := 99
invariant
bottles <= 99 and bottles >= 1
until
bottles = 1
loop
print (bottles)
print (" bottles of beer on the wall,%N")
print (bottles)
print (" bottles of beer.%N")
print ("Take one down, pass it around,%N")
bottles := bottles - 1
if bottles > 1 then
print (bottles)
print (" bottles of beer on the wall.%N%N")
end
variant
bottles
end
print ("1 bottle of beer on the wall.%N%N");
print ("No more bottles of beer on the wall,%N");
print ("no more bottles of beer.%N");
print ("Go to the store and buy some more,%N");
print ("99 bottles of beer on the wall.%N");
end
end
An alternative version written using the across-loop construct.
output_lyrics
-- Output the lyrics to 99-bottles-of-beer.
local
l_bottles: LINKED_LIST [INTEGER]
do
create l_bottles.make
across (1 |..| 99) as ic loop l_bottles.force (ic.item) end
across l_bottles.new_cursor.reversed as ic_bottles loop
print (ic_bottles.item)
print (" bottles of beer on the wall, ")
print (ic_bottles.item)
print (" bottles of beer.%N")
print ("Take one down, pass it around, ")
if ic_bottles.item > 1 then
print (ic_bottles.item)
print (" bottles of beer on the wall.%N%N")
end
end
print ("1 bottle of beer on the wall.%N")
print ("No more bottles of beer on the wall, no more bottles of beer.%N")
print ("Go to the store and buy some more, 99 bottles of beer on the wall.%N")
end
Ela
open list
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++" bottles of beer\nTake one down, pass it around\n"
map beer [99,98..0]
Elena
ELENA 4.1 :
import system'routines;
import extensions;
import extensions'routines;
import extensions'text;
extension bottleOp
{
bottleDescription()
= self.Printable + (self != 1).iif(" bottles"," bottle");
bottleEnumerator() = new Variable(self).doWith:(n)
{
^ new Enumerator::
{
bool next() = n > 0;
get() = new StringWriter()
.printLine(n.bottleDescription()," of beer on the wall")
.printLine(n.bottleDescription()," of beer")
.printLine("Take one down, pass it around")
.printLine((n.reduce:1).bottleDescription()," of beer on the wall");
reset() {}
enumerable() = __target;
}
};
}
public program()
{
var bottles := 99;
bottles.bottleEnumerator().forEach:printingLn
}
Output:
5 bottles of beer on the wall
5 bottles of beer
Take one down, pass it around
4 bottles of beer on the wall
4 bottles of beer on the wall
4 bottles of beer
Take one down, pass it around
3 bottles of beer on the wall
3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
0 bottles of beer on the wall
Emacs Lisp
(let ((i 99)) (while (> i 0) (princ-list i " bottles of beer on the wall" "\n Take one down, pass it around") (setq i (1- i))))
Elixir
defmodule Bottles do def run do Enum.each 99..1, fn idx -> IO.puts "#{idx} bottle#{plural(idx)} of beer on the wall" IO.puts "#{idx} bottle#{plural(idx)} of beer" IO.puts "Take one down, pass it around" IO.puts "#{idx - 1} bottle#{plural(idx-1)} of beer on the wall" IO.puts "" end end def plural(1), do: "" def plural(num), do: "s" end Bottles.run
Erlang
-module(beersong). -export([sing/0]). -define(TEMPLATE_0, "~s of beer on the wall, ~s of beer.~nGo to the store and buy some more, 99 bottles of beer on the wall.~n"). -define(TEMPLATE_N, "~s of beer on the wall, ~s of beer.~nTake one down and pass it around, ~s of beer on the wall.~n~n"). create_verse(0) -> {0, io_lib:format(?TEMPLATE_0, phrase(0))}; create_verse(Bottle) -> {Bottle, io_lib:format(?TEMPLATE_N, phrase(Bottle))}. phrase(0) -> ["No more bottles", "no more bottles"]; phrase(1) -> ["1 bottle", "1 bottle", "no more bottles"]; phrase(2) -> ["2 bottles", "2 bottles", "1 bottle"]; phrase(Bottle) -> lists:duplicate(2, integer_to_list(Bottle) ++ " bottles") ++ [integer_to_list(Bottle-1) ++ " bottles"]. bottles() -> lists:reverse(lists:seq(0,99)). sing() -> lists:foreach(fun spawn_singer/1, bottles()), sing_verse(99). spawn_singer(Bottle) -> Pid = self(), spawn(fun() -> Pid ! create_verse(Bottle) end). sing_verse(Bottle) -> receive {_, Verse} when Bottle == 0 -> io:format(Verse); {N, Verse} when Bottle == N -> io:format(Verse), sing_verse(Bottle-1) after 3000 -> io:format("Verse not received - re-starting singer~n"), spawn_singer(Bottle), sing_verse(Bottle) end.
Euphoria
Works with Euphoria|4.0.0.
constant
bottles = "bottles",
bottle = "bottle"
procedure beers (integer how_much)
sequence word1 = bottles, word2 = bottles
switch how_much do
case 2 then
word2 = bottle
case 1 then
word1 = bottle
word2 = bottle
end switch
printf (1,
"%d %s of beer on the wall \n" &
"%d %s of beer \n" &
"Take one down, and pass it around \n" &
"%d %s of beer on the wall \n\n",
{ how_much, word1,
how_much, word1,
how_much-1, word2 }
)
end procedure
for a = 99 to 1 by -1 do
beers (a)
end for
Extended Brainfuck
See 99 Bottles of Beer/EsoLang
F_Sharp|F#
#light let rec bottles n = let (before, after) = match n with | 1 -> ("bottle", "bottles") | 2 -> ("bottles", "bottle") | n -> ("bottles", "bottles") printfn "%d %s of beer on the wall" n before printfn "%d %s of beer" n before printfn "Take one down, pass it around" printfn "%d %s of beer on the wall\n" (n - 1) after if n > 1 then bottles (n - 1)
Factor
USING: io kernel make math math.parser math.ranges sequences ;
: bottle ( -- quot )
[
[
[
[ # " bottles of beer on the wall,\n" % ]
[ # " bottles of beer.\n" % ] bi
] keep
"Take one down, pass it around,\n" %
1 - # " bottles of beer on the wall\n" %
] " " make print
] ; inline
: last-verse ( -- )
"Go to the store and buy some more,"
"no more bottles of beer on the wall!" [ print ] bi@ ;
: bottles ( n -- )
1 [a,b] bottle each last-verse ;
! Usage: 99 bottles
Falcon
for i in [99:1]
> i, " bottles of beer on the wall"
> i, " bottles of beer"
> "Take one down, pass it around"
> i-1, " bottles of beer on the wall\n"
end
A more robust version to handle plural/not plural conditions
for i in [99:1]
plural = (i != 1) ? 's' : ""
> @ "$i bottle$plural of beer on the wall"
> @ "$i bottle$plural of beer"
> "Take one down, pass it around"
> i-1, @ " bottle$plural of beer on the wall\n"
end
FALSE
See 99 Bottles of Beer/EsoLang
ferite
copied from http://99-bottles-of-beer.net/language-ferite-1281.html?PHPSESSID=b563ec9a2791f6c3cc917c22b17dc542.
uses "console";
number bottles = 99;
boolean looping = true;
object counter = closure {
if (--bottles > 0) {
return true;
} else {
return false;
}
};
while (looping) {
Console.println("${bottles} bottles of beer on the wall,");
Console.println("${bottles} bottles of beer,");
Console.println("Take one down, pass it around,");
looping = counter.invoke();
Console.println("${bottles} bottles of beer on the wall.");
Fexl
\suffix=(\n eq n 1 "" "s")
\sing_count=(\n put [n " bottle" (suffix n) " of beer"])
\sing_line1=(\n sing_count n say " on the wall")
\sing_line2=(\n sing_count n nl)
\sing==
(\n
le n 0 ();
sing_line1 n
sing_line2 n
say "Take one down, pass it around"
\n=(- n 1)
sing_line1 n
nl
sing n
)
sing 3
Output:
3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
0 bottles of beer on the wall
Forth
:noname dup . ." bottles" ;
:noname ." 1 bottle" ;
:noname ." no more bottles" ;
create bottles , , ,
: .bottles dup 2 min cells bottles + @ execute ;
: .beer .bottles ." of beer" ;
: .wall .beer ." on the wall" ;
: .take ." Take one down, pass it around" ;
: .verse .wall cr .beer cr
1- .take cr .wall cr ;
: verses begin cr .verse ?dup 0= until ;
99 verses
Version 2: create a beer language and write the program
DECIMAL
: BOTTLES ( n -- )
DUP
CASE
1 OF ." One more bottle " DROP ENDOF
0 OF ." NO MORE bottles " DROP ENDOF
. ." bottles " \ DEFAULT CASE
ENDCASE ;
: , [CHAR] , EMIT SPACE 100 MS CR ;
: . [CHAR] . EMIT 300 MS CR CR CR ;
: OF ." of " ; : BEER ." beer " ;
: ON ." on " ; : THE ." the " ;
: WALL ." wall" ; : TAKE ." take " ;
: ONE ." one " ; : DOWN ." down, " ;
: PASS ." pass " ; : IT ." it " ;
: AROUND ." around" ;
: POPONE 1 SWAP CR ;
: DRINK POSTPONE DO ; IMMEDIATE
: ANOTHER S" -1 +LOOP" EVALUATE ; IMMEDIATE
: HOWMANY S" I " EVALUATE ; IMMEDIATE
: ONELESS S" I 1- " EVALUATE ; IMMEDIATE
: HANGOVER ." :-(" CR QUIT ;
: BEERS ( n -- ) \ Usage: 99 BEERS
POPONE
DRINK
HOWMANY BOTTLES OF BEER ON THE WALL ,
HOWMANY BOTTLES OF BEER ,
TAKE ONE DOWN PASS IT AROUND ,
ONELESS BOTTLES OF BEER ON THE WALL .
ANOTHER
HANGOVER ;
Forth Console Output
2 beers
2 bottles of beer on the wall,
2 bottles of beer ,
take one down, pass it around,
One more bottle of beer on the wall.
One more bottle of beer on the wall,
One more bottle of beer ,
take one down, pass it around,
No more bottles of beer on the wall.
ok
Fortran
F90 version
program bottlestest
implicit none
integer :: i
character(len=*), parameter :: bwall = " on the wall", &
bottles = "bottles of beer", &
bottle = "bottle of beer", &
take = "Take one down, pass it around", &
form = "(I0, ' ', A)"
do i = 99,0,-1
if ( i /= 1 ) then
write (*,form) i, bottles // bwall
if ( i > 0 ) write (*,form) i, bottles
else
write (*,form) i, bottle // bwall
write (*,form) i, bottle
end if
if ( i > 0 ) write (*,*) take
end do
end program bottlestest
MPI version
program bottlesMPI
implicit none
integer :: ierr,rank,nproc
character(len=*), parameter :: bwall = " on the wall", &
bottles = "bottles of beer", &
bottle = "bottle of beer", &
take = "Take one down, pass it around", &
form = "(I0, ' ', A)"
call mpi_init(ierr)
call mpi_comm_size(MPI_COMM_WORLD,nproc, ierr)
call mpi_comm_rank(MPI_COMM_WORLD,rank,ierr)
if ( rank /= 1 ) then
write (*,form) rank, bottles // bwall
if ( rank > 0 ) write (*,form) rank, bottles
else
write (*,form) rank, bottle // bwall
write (*,form) rank, bottle
end if
if ( rank > 0 ) write (*,*) take
call mpi_finalize(ierr)
end program bottlesMPI
Usage:
mpif90 filename.f90
mpiexec -np 99 a.out
Fortran 2003/2008 OOP version
Works with GNU gfortran 5.0.0 and Intel ifort 15.0.2
module song_typedefs
implicit none
private ! all
public :: TBottles
type, abstract :: TContainer
integer :: quantity
contains
! deferred method i.e. abstract method = must be overridden in extended type
procedure(take_one), deferred, pass :: take_one
procedure(show_quantity), deferred, pass :: show_quantity
end type TContainer
abstract interface
subroutine take_one(this)
import TContainer
implicit none
class(TContainer) :: this
end subroutine take_one
subroutine show_quantity(this)
import TContainer
implicit none
class(TContainer) :: this
end subroutine show_quantity
end interface
! extended derived type
type, extends(TContainer) :: TBottles
contains
procedure, pass :: take_one => take_one_bottle
procedure, pass :: show_quantity => show_bottles
final :: finalize_bottles
end type TBottles
contains
subroutine show_bottles(this)
implicit none
class(TBottles) :: this
! integer :: show_bottles
character(len=*), parameter :: bw0 = "No more bottles of beer on the wall,"
character(len=*), parameter :: bwx = "bottles of beer on the wall,"
character(len=*), parameter :: bw1 = "bottle of beer on the wall,"
character(len=*), parameter :: bb0 = "no more bottles of beer."
character(len=*), parameter :: bbx = "bottles of beer."
character(len=*), parameter :: bb1 = "bottle of beer."
character(len=*), parameter :: fmtxdd = "(I2,1X,A28,1X,I2,1X,A16)"
character(len=*), parameter :: fmtxd = "(I1,1X,A28,1X,I1,1X,A16)"
character(len=*), parameter :: fmt1 = "(I1,1X,A27,1X,I1,1X,A15)"
character(len=*), parameter :: fmt0 = "(A36,1X,A24)"
select case (this % quantity)
case (10:)
write(*,fmtxdd) this % quantity, bwx, this % quantity, bbx
case (2:9)
write(*,fmtxd) this % quantity, bwx, this % quantity, bbx
case (1)
write(*,fmt1) this % quantity, bw1, this % quantity, bb1
case (0)
write(*,*)
write(*,fmt0) bw0, bb0
case default
write(*,*)"Warning! Number of bottles exception, error 42. STOP"
stop
end select
! show_bottles = this % quantity
end subroutine show_bottles
subroutine take_one_bottle(this) ! bind(c, name='take_one_bottle')
implicit none
class(TBottles) :: this
! integer :: take_one_bottle
character(len=*), parameter :: t1 = "Take one down and pass it around,"
character(len=*), parameter :: remx = "bottles of beer on the wall."
character(len=*), parameter :: rem1 = "bottle of beer on the wall."
character(len=*), parameter :: rem0 = "no more bottles of beer on the wall."
character(len=*), parameter :: fmtx = "(A33,1X,I2,1X,A28)"
character(len=*), parameter :: fmt1 = "(A33,1X,I2,1X,A27)"
character(len=*), parameter :: fmt0 = "(A33,1X,A36)"
this % quantity = this % quantity -1
select case (this%quantity)
case (2:)
write(*,fmtx) t1, this%quantity, remx
case (1)
write(*,fmt1) t1, this%quantity, rem1
case (0)
write(*,fmt0) t1, rem0
case (-1)
write(*,'(A66)') "Go to the store and buy some more, 99 bottles of beer on the wall."
case default
write(*,*)"Warning! Number of bottles exception, error 42. STOP"
stop
end select
end subroutine take_one_bottle
subroutine finalize_bottles(bottles)
implicit none
type(TBottles) :: bottles
! here can be more code
end subroutine finalize_bottles
end module song_typedefs
!-----------------------------------------------------------------------
!Main program
!-----------------------------------------------------------------------
program bottles_song
use song_typedefs
implicit none
integer, parameter :: MAGIC_NUMBER = 99
type(TBottles), target :: BTLS
BTLS = TBottles(MAGIC_NUMBER)
call make_song(BTLS)
contains
subroutine make_song(bottles)
type(TBottles) :: bottles
do while(bottles%quantity >= 0)
call bottles%show_quantity()
call bottles%take_one()
enddo
end subroutine make_song
end program bottles_song
Frege
Translated from Haskell}} (''identical'' to the Haskell, apart from adding the module declaratio. Works with Frege|3.21.586-g026e8d7.
module Beer where
main = mapM_ (putStrLn . beer) [99, 98 .. 0]
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++ " bottles of beer\nTake one down, pass it around\n"
++ head (lines $ beer $ v-1) ++ "\n"
friendly interactive shell
Frink
Frink tracks units of measure through all calculations. It has a large library of built-in units of measure, including volume. The following program prints out the remaining volume of beer (assuming we start with 99 bottles of beer, each containing 12 fluid ounces) in different random units of volume, never repeating a unit.
units = array[units[volume]]
showApproximations[false]
for n = 99 to 0 step -1
{
unit = units.removeRandom[]
str = getBottleString[n, unit]
println["$str of beer on the wall, $str."]
if (n == 0)
println["Go to the store and buy some more, 99 bottles of beer on the wall."]
else
println["Take one down and pass it around, " + getBottleString[n-1, unit] + " on the wall.\n"]
}
getBottleString[n, unit] := format[n*12 floz, unit, 6] + "s"
Sample randomized output:
0.019386 facecords of beer on the wall, 0.019386 facecords.
Take one down and pass it around, 0.019190 facecords on the wall.
36.750000 quarts of beer on the wall, 36.750000 quarts.
Take one down and pass it around, 36.375000 quarts on the wall.
581539.650545 brminims of beer on the wall, 581539.650545 brminims.
Take one down and pass it around, 575544.396416 brminims on the wall.
10.377148 scotsoatlippys of beer on the wall, 10.377148 scotsoatlippys.
Take one down and pass it around, 10.269053 scotsoatlippys on the wall.
7.416004 cangallons of beer on the wall, 7.416004 cangallons.
Take one down and pass it around, 7.337941 cangallons on the wall.
3335.894135 dessertspoons of beer on the wall, 3335.894135 dessertspoons.
Take one down and pass it around, 3300.405899 dessertspoons on the wall.
0.233105 barrelbulks of beer on the wall, 0.233105 barrelbulks.
Take one down and pass it around, 0.230599 barrelbulks on the wall.
21.766118 magnums of beer on the wall, 21.766118 magnums.
Take one down and pass it around, 21.529530 magnums on the wall.
1092.000000 fluidounces of beer on the wall, 1092.000000 fluidounces.
Take one down and pass it around, 1080.000000 fluidounces on the wall.
...
12.000000 ponys of beer on the wall, 12.000000 ponys.
Take one down and pass it around, 0.000000 ponys on the wall.
0.000000 brfluidounces of beer on the wall, 0.000000 brfluidounces.
Go to the store and buy some more, 99 bottles of beer on the wall.
FunL
val
numbers = {1:'one', 2:'two', 3:'three', 4:'four', 5:'five', 6:'six', 7:'seven',
8:'eight', 9:'nine', 10:'ten', 11:'eleven', 12:'twelve'}
alt = {3:'thir', 5:'fif'}
def
suffix( a, b ) = (if a.endsWith( 't' ) then a.substring( 0, a.length()-1 ) else a) + b
number( n@(13 | 15) ) = suffix( alt(n%10), 'teen' )
number( 20 ) = 'twenty'
number( n@(30 | 50) ) = suffix( alt(n\10), 'ty' )
number( n )
| n <= 12 = numbers(n)
| n <= 19 = suffix( numbers(n%10), 'teen' )
| 10|n = suffix( numbers(n\10), 'ty' )
| otherwise = number( n\10*10 ) + '-' + number( n%10 )
cap( s ) = s.substring( 0, 1 ).toUpperCase() + s.substring( 1, s.length() )
bottles( 0 ) = 'no more bottles'
bottles( 1 ) = 'one bottle'
bottles( n ) = number( n ) + ' bottles'
verse( 0 ) = ('No more bottles of beer on the wall, no more bottles of beer.\n'
+ 'Go to the store and buy some more, ninety-nine bottles of beer on the wall.')
verse( n ) = (cap( bottles(n) ) + ' of beer on the wall, ' + bottles( n ) + ' of beer.\n'
+ 'Take one down and pass it around, ' + bottles( n-1 )
+ ' of beer on the wall.\n')
for i <- 99..0 by -1 do println( verse(i) )
FutureBasic
include "ConsoleWindow"
dim as short i
for i = 99 to 1 step -1
print i; " bottles of beer on the wall,"
print i; " bottles of beer."
print
print "Take one down, pass it around,"
print i-1; " bottles of beer on the wall."
print
next
GAP
Bottles := function(n)
local line, i, j, u;
line := function(n)
s := String(n);
if n < 2 then
return Concatenation(String(n), " bottle of beer");
else
return Concatenation(String(n), " bottles of beer");
fi;
end;
for i in [1 .. n] do
j := n - i + 1;
u := line(j);
Display(Concatenation(u, " on the wall"));
Display(u);
Display("Take one down, pass it around");
Display(Concatenation(line(j - 1), " on the wall"));
if i <> n then
Display("");
fi;
od;
end;
Genie
[indent=4]
def plural(n:uint):string
return (n == 1) ? "" : "s"
def no(n:uint):string
return (n == 0) ? "No" : n.to_string()
init
bottles:uint = 99;
do
print "%u bottle%s of beer on the wall", bottles, plural(bottles)
print "%u bottle%s of beer", bottles, plural(bottles)
print "Take one down, pass it around"
--bottles
print "%s bottle%s of beer on the wall\n", no(bottles), plural(bottles)
while bottles != 0
Output:
prompt$ valac 99bottles.gs
prompt$ ./99bottles | tail -10
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No bottles of beer on the wall
gnuplot
if (!exists("bottles")) bottles = 99
print sprintf("%i bottles of beer on the wall", bottles)
print sprintf("%i bottles of beer", bottles)
print "Take one down, pass it around"
bottles = bottles - 1
print sprintf("%i bottles of beer on the wall", bottles)
print ""
if (bottles > 0) reread
Go
No sense of humor
package main import "fmt" func main() { bottles := func(i int) string { switch i { case 0: return "No more bottles" case 1: return "1 bottle" default: return fmt.Sprintf("%d bottles", i) } } for i := 99; i > 0; i-- { fmt.Printf("%s of beer on the wall\n", bottles(i)) fmt.Printf("%s of beer\n", bottles(i)) fmt.Printf("Take one down, pass it around\n") fmt.Printf("%s of beer on the wall\n", bottles(i-1)) } }
Typoglycemic
With code from RC tasks Number names, Knuth shuffle.
package main import ( "fmt" "math/rand" "strings" "time" ) func main() { rand.Seed(time.Now().UnixNano()) for i := 99; i > 0; i-- { fmt.Printf("%s %s %s\n", slur(numberName(i), i), pluralizeFirst(slur("bottle of", i), i), slur("beer on the wall", i)) fmt.Printf("%s %s %s\n", slur(numberName(i), i), pluralizeFirst(slur("bottle of", i), i), slur("beer", i)) fmt.Printf("%s %s %s\n", slur("take one", i), slur("down", i), slur("pass it around", i)) fmt.Printf("%s %s %s\n", slur(numberName(i-1), i), pluralizeFirst(slur("bottle of", i), i-1), slur("beer on the wall", i)) } } // adapted from Number names task func numberName(n int) string { switch { case n < 0: case n < 20: return small[n] case n < 100: t := tens[n/10] s := n % 10 if s > 0 { t += " " + small[s] } return t } return "" } var small = []string{"no", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"} var tens = []string{"ones", "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"} // pluralize first word of s by adding an s, but only if n is not 1. func pluralizeFirst(s string, n int) string { if n == 1 { return s } w := strings.Fields(s) w[0] += "s" return strings.Join(w, " ") } // p is string to slur, d is drunkenness, from 0 to 99 func slur(p string, d int) string { // shuffle only interior letters a := []byte(p[1 : len(p)-1]) // adapted from Knuth shuffle task. // shuffle letters with probability d/100. for i := len(a) - 1; i >= 1; i-- { if rand.Intn(100) >= d { j := rand.Intn(i + 1) a[i], a[j] = a[j], a[i] } } // condense spaces w := strings.Fields(p[:1] + string(a) + p[len(p)-1:]) return strings.Join(w, " ") }
Output:
ninety nine bottles of beer on the wall
ninety nine bottles of beer
take one down pass it around
ninety eight bottles of beer on the wall
ninety eight bottles of beer on the wall
ninety eight bottles of beer
take one down pass it around
ninety seven bottles of beer on the wall
ninety seven boetlts of beer on the wall
ninety seven bottles of beer
take one down pass it around
ninety six botelts of beer on the wall
Soon,
eighty four bottles of bere wn the oall
ehigty four bottles of beer
tkae one down pnssti arouad
eihhty tgree bttoles of beer en tho wall
eighty three blottes of beet on rhe wall
eighty three bottles of beer
taen oke down pass it around
eiwyth tgo bttoles of beew on lhr eatl
It ends very well, if you're drinking along.
two btloots ef bre enehta wo ll
two bs tleootf beer
tnoeka e dwon pts ou nsaaird
one bolote tf betwr le ao enhl
one beoo ttlf blwtenr ehoa el
one bltooe tf beer
tne okae down pasaostiu rnd
no bletts oof beloethw r ea nl
Go!
Copied from http://99-bottles-of-beer.net/language-go!-289.html with a minor bug fix.
--
-- 99 Bottles of Beer in Go!
-- John Knottenbelt
--
-- Go! is a multi-paradigm programming language that is oriented
-- to the needs of programming secure, production quality, agent
-- based applications.
--
-- http://www.doc.ic.ac.uk/~klc/dalt03.html
--
main .. {
include "sys:go/io.gof".
include "sys:go/stdlib.gof".
main() ->
drink(99);
stdout.outLine("Time to buy some more beer...").
drink(0) -> {}.
drink(i) -> stdout.outLine(
bottles(i) <> " on the wall,\n" <>
bottles(i) <> ".\n" <>
"take one down, pass it around,\n" <>
bottles(i-1) <> " on the wall.\n");
drink(i-1).
bottles(0) => "no bottles of beer".
bottles(1) => "1 bottle of beer".
bottles(i) => i^0 <> " bottles of beer".
}
Golo
module Bottles
augment java.lang.Integer {
function bottles = |self| -> match {
when self == 0 then "No bottles"
when self == 1 then "One bottle"
otherwise self + " bottles"
}
}
function main = |args| {
99: downTo(1, |i| {
println(i: bottles() + " of beer on the wall,")
println(i: bottles() + " of beer!")
println("Take one down, pass it around,")
println((i - 1): bottles() + " of beer on the wall!")
println("--------------------------------------")
})
}
Gosu
for (i in 99..0) {
print("${i} bottles of beer on the wall")
if (i > 0) {
print("${i} bottles of beer")
print("Take one down, pass it around")
}
print("");
}
Golfscript
[296,{3/)}%-1%["No more"]+[" bottles":b]294*[b-1<]2*+[b]+[" of beer on the wall\n".8<"\nTake one down, pass it around\n"+1$n+]99*]zip
Groovy
Basic Solution
With a closure to handle special cardinalities of bottles.
def bottles = { "${it==0 ? 'No more' : it} bottle${it==1 ? '' : 's' }" } 99.downto(1) { i -> print """ ${bottles(i)} of beer on the wall ${bottles(i)} of beer Take one down, pass it around ${bottles(i-1)} of beer on the wall """ }
Single Print Version
Uses a single print algorithm for all four lines. Handles cardinality on bottles, uses 'No more' instead of 0.
298.downto(2) { def (m,d) = [it%3,(int)it/3] print "${m==1?'\n':''}${d?:'No more'} bottle${d!=1?'s':''} of beer" + "${m?' on the wall':'\nTake one down, pass it around'}\n" }
Bottomless Beer Solution
Using more closures to create a richer lyrical experience.
def bottles = { "${it==0 ? 'No more' : it} bottle${it==1 ? '' : 's' }" } def initialState = { """${result(it)} ${resultShort(it)}""" } def act = { it > 0 ? "Take ${it==1 ? 'it' : 'one'} down, pass it around" : "Go to the store, buy some more" } def delta = { it > 0 ? -1 : 99 } def resultShort = { "${bottles(it)} of beer" } def result = { "${resultShort(it)} on the wall" } // //// uncomment commented lines to create endless drunken binge //// // // while (true) { 99.downto(0) { i -> print """ ${initialState(i)} ${act(i)} ${result(i+delta(i))} """ } // Thread.sleep(1000) // }
GUISS
We will just use the calculator and keep taking one off. We do not get the full text here, but the number of the calculator shows how many bottles we still have left to drink:
Start,Programs,Accessories,Calculator,Button:9,Button:9,
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals]
We haven't drank all of the bottles at this point, but we can keep going, if we want.
GW-BASIC
Just a basic loop counting down to one. No big deal. Note that at BOTTLES=1, it is not grammatically correct.
10 FOR BOTTLES = 99 TO 1 STEP -1
20 PRINT BOTTLES " bottles of beer on the wall"
30 PRINT BOTTLES " bottles of beer"
40 PRINT "Take one down, pass it around"
50 PRINT BOTTLES-1 " bottles of beer on the wall"
60 NEXT BOTTLES
Halon
$plural = "s";
$x = 99;
while ($x > 0) {
echo "$x bottle$plural of beer on the wall";
echo "$x bottle$plural of beer";
echo "Take one down, pass it around";
$x -= 1;
if ($x == 1)
$plural = "";
if ($x > 0)
echo "$x bottle$plural of beer on the wall\n";
else
echo "No more bottles of beer on the wall!";
}
Haskell
Brevity
A relatively concise solution:
main = mapM_ (putStrLn . beer) [99, 98 .. 0] beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around" beer 0 = "better go to the store and buy some more." beer v = show v ++ " bottles of beer on the wall\n" ++ show v ++" bottles of beer\nTake one down, pass it around\n" ++ head (lines $ beer $ v-1) ++ "\n"
List comprehension
As a list comprehension:
import qualified Char main = putStr $ concat [up (bob n) ++ wall ++ ", " ++ bob n ++ ".\n" ++ pass n ++ bob (n - 1) ++ wall ++ ".\n\n" | n <- [99, 98 .. 0]] where bob n = (num n) ++ " bottle" ++ (s n) ++ " of beer" wall = " on the wall" pass 0 = "Go to the store and buy some more, " pass _ = "Take one down and pass it around, " up (x : xs) = Char.toUpper x : xs num (-1) = "99" num 0 = "no more" num n = show n s 1 = "" s _ = "s"
Writer monad and Template Haskell
Another version, which uses a Writer monad to collect each part of the song. It also uses Template Haskell to generate the song at compile time.
{-# LANGUAGE TemplateHaskell #-} -- build with "ghc --make beer.hs" module Main where import Language.Haskell.TH import Control.Monad.Writer -- This is calculated at compile time, and is equivalent to -- songString = "99 bottles of beer on the wall\n99 bottles..." songString = $(let sing = tell -- we can't sing very well... someBottles 1 = "1 bottle of beer " someBottles n = show n ++ " bottles of beer " bottlesOfBeer n = (someBottles n ++) verse n = do sing $ n `bottlesOfBeer` "on the wall\n" sing $ n `bottlesOfBeer` "\n" sing $ "Take one down, pass it around\n" sing $ (n - 1) `bottlesOfBeer` "on the wall\n\n" song = execWriter $ mapM_ verse [99,98..1] in return $ LitE $ StringL $ song) main = putStr songString
Avoiding append by spelling bottle backwards
Is there something just a little prickly and displeasing about (++) ? Monoid (<>) is less spiky, but neither is needed when 'bottle' is written backwards.
location, distribution, solution :: String [location, distribution, solution] = [ "on the wall" , "Take one down, pass it around" , "Better go to the store to buy some more" ] asset :: Int -> String asset n = let suffix n | 1 == n = [] | otherwise = ['s'] in unwords [show n, (reverse . concat) $ suffix n : ["elttob"]] incantation :: Int -> String incantation n = let inventory = unwords . (: [location]) . asset in case n of 0 -> solution _ -> unlines [inventory n, asset n, distribution, inventory $ pred n] main :: IO () main = putStrLn $ unlines (incantation <$> [99,98 .. 0])
Haxe
Simple Solution
class RosettaDemo
{
static public function main()
{
singBottlesOfBeer(100);
}
static function singBottlesOfBeer(bottles : Int)
{
var plural : String = 's';
while (bottles >= 1)
{
Sys.println(bottles + " bottle" + plural + " of beer on the wall,");
Sys.println(bottles + " bottle" + plural + " of beer!");
Sys.println("Take one down, pass it around,");
if (bottles - 1 == 1)
{
plural = '';
}
if (bottles > 1)
{
Sys.println(bottles-1 + " bottle" + plural + " of beer on the wall!\n");
}
else
{
Sys.println("No more bottles of beer on the wall!");
}
bottles--;
}
}
}
Macro solution
All those counters, loops and conditinal blocks are pretty expensive in runtime compared to single print of fully inlined text of the song. Let's generate that print with macro.
class Bottles {
static public function main () : Void {
singBottlesOfBeer(100);
}
macro static public function singBottlesOfBeer (bottles:Int) {
var lines = [];
var s : String = 's';
var song : String = '';
while( bottles >= 1 ){
song += '$bottles bottle$s of beer on the wall,\n';
song += '$bottles bottle$s of beer!\n';
song += 'Take one down, pass it around,\n';
bottles --;
if( bottles > 1 ){
song += '$bottles bottles of beer on the wall!\n\n';
}else if( bottles == 1 ){
s = '';
song += '$bottles bottle of beer on the wall!\n\n';
}else{
song += 'No more bottles of beer on the wall!\n';
}
}
return macro Sys.print($v{song});
}
}
hexiscript
fun bottles amount beverage location
let bottle " bottles of "
if amount = 0; let amount "No more"
elif amount = 1; let bottle " bottle of "; endif
return amount + bottle + beverage + " " + location
endfun
fun take amount location
return "Take " + amount + " " + location
endfun
fun pass entity destination
return ", pass " + entity + " " + destination
endfun
let amount 99
while amount > 0
println bottles amount "beer" "on the wall"
println bottles amount "beer" ""
println take "one" "down" + pass "it" "around"
println bottles (--amount) "beer" "on the wall\n"
endwhile
HicEst
DO x = 99, 1, -1
WRITE() x , "bottles of beer on the wall"
BEEP("T16 be be be bH bH bH be be be 2be ")
WRITE() x , "bottles of beer"
BEEP("2p f f f c c c 2f ")
WRITE() "take one down, pass it around"
BEEP("2p 2d d d 2p d d d 2d ")
WRITE() x , "bottles of beer on the wall"
BEEP("2p #A #A #A c c d #d #d #d 2#d 2p")
ENDDO
HQ9+
See 99 Bottles of Beer/EsoLang
Huginn
#! /bin/sh
exec huginn --no-argv -E "${0}" "${@}"
#! huginn
import Algorithms as algo;
main() {
x = "{} bottle{} of beer on the wall,\n"
"{} bottle{} of beer.\n"
"Take one down, pass it around,\n"
"{} bottle{} of beer on the wall.\n\n";
for ( n : algo.range( 99, 0, -1 ) ) {
bot = n > 0 ? n : "No";
plu = n != 1 ? "s" : "";
print( x.format( bot, plu, bot, plu, n > 1 ? n - 1 : "No", n != 2 ? "s" : "" ) );
}
print(
"No bottles of beer on the wall,\n"
"No bottles of beer.\n"
"Go to the store, buy some more,\n"
"99 bottles of beer on the wall.\n"
);
return ( 0 );
}
HolyC
The default is 99 bottles, but it can be modified by the parameter.
U0 BottlesOfBeer (I64 initial=99) {
// This is made I64 rather than U64
// Because, a U64 would overflow
// At the end of the loop, thus it would loop forever (i-- would be 0-1 so it overflows and is always greater than or equal to 0)
I64 i = initial;
for (; i >= 0; i--) {
if (i == 1) {
// Just a string on it's own will pass it to an inbuilt HolyC function that puts it to terminal
"1 Bottle of Beer on the wall, 1 bottle of beer.\n";
"Take one down and pass it around, no more bottles of beer on the wall.\n";
} else if (i == 0) {
"No more bottles of beer on the wall, no more bottles of beer.\n";
"Go to the store and buy some more, 99 bottles of beer on the wall.\n";
} else {
"%d bottles of beer on the wall, %d bottles of beer.\n",i,i;
"Take one down and pass it around, %d bottle",(i-1);
// Only add the s if it's not 1
if ((i-1) != 1) {
"s";
}
" of beer on the wall.\n";
}
}
}
// Calls the function, which goes to the default parameters
BottlesOfBeer;
Icon}} and {{header|Unicon
The default is 99 bottles, but you can change this on the command line for really long trips...
procedure main(args)
numBeers := integer(args[1]) | 99
drinkUp(numBeers)
end
procedure drinkUp(beerMax)
static beerMap
initial {
beerMap := table(" bottles")
beerMap[1] := " bottle"
}
every beerCount := beerMax to 1 by -1 do {
writes( beerCount,beerMap[beerCount]," of beer on the wall, ")
write( beerCount,beerMap[beerCount]," of beer.")
writes("Take one down and pass it around, ")
write(case x := beerCount-1 of {
0 : "no more bottles"
default : x||beerMap[x]
}," of beer on the wall.\n")
}
write("No more bottles of beer on the wall, no more bottles of beer.")
write("Go to the store and buy some more, ",
beerMax," bottles of beer on the wall.")
end
IDL
Pro bottles
for i=1,99 do begin
print, 100-i, " bottles of beer on the wall.", 100-i, $
" bottles of beer.", " Take one down, pass it around," , $
99-i, " bottles of beer on the wall."
endfor
End
Since in IDL "FOR"-loops are the embodiment of pure evil (see http://www.idlcoyote.com/tips/forloops.html and http://www.idlcoyote.com/tips/forloops2.html) there is also a loop free IDL way:
Pro bottles_noloop
b=(reverse(shift(sindgen(100),-1)))[1:99]
b2=reverse(sindgen(99))
wallT=replicate(' bottles of beer on the wall.', 100)
wallT2=replicate(' bottles of beer.', 100)
takeT=replicate('Take one down, pass it around,', 100)
print, b+wallT+string(10B)+b+wallT2+string(10B)+takeT+string(10B)+b2+wallT+string(10B)
End
I found the above example very helpful but overdone. This is a more simple version:
Pro bottles_noloop2
n_bottles=99
b1 = reverse(SINDGEN(n_bottles,START=1))
b2= reverse(SINDGEN(n_bottles))
wallT=replicate(' bottles of beer on the wall.', n_bottles)
wallT2=replicate(' bottles of beer.', n_bottles)
takeT=replicate('Take one down, pass it around,', n_bottles)
print, b1+wallT+string(10B)+b1+wallT2+string(10B)+takeT+string(10B)+b2+wallT+string(10B)
End
Idris
beerSong : Fin 100 -> String
beerSong x = verses x where
bottlesOfBeer : Fin n -> String
bottlesOfBeer fZ = "No more bottles of beer"
bottlesOfBeer (fS fZ) = "1 bottle of beer"
bottlesOfBeer k = (show (finToInteger k)) ++ " bottles of beer"
verse : Fin n -> String
verse fZ = ""
verse (fS n) =
(bottlesOfBeer (fS n)) ++ " on the wall,\n" ++
(bottlesOfBeer (fS n)) ++ "\n" ++
"Take one down, pass it around\n" ++
(bottlesOfBeer n) ++ " on the wall\n"
verses : Fin n -> String
verses fZ = ""
verses (fS n) = (verse (fS n)) ++ (verses n)
Inform 6
[ Bottles i;
if(i == 1) return "bottle";
return "bottles";
];
[ Beer i;
print i, " ", (string) Bottles(i), " of beer on the wall^";
print i, " ", (string) Bottles(i), " of beer^";
print "Take one down, pass it around^";
i--;
print i, " ", (string) Bottles(i), " of beer on the wall^^";
if(i ~= 0) Beer(i);
];
[ Main;
Beer(99);
];
Inform 7
Programmatic solution
Beer Hall is a room.
When play begins:
repeat with iteration running from 1 to 99:
let N be 100 - iteration;
say "[N] bottle[s] of beer on the wall[line break]";
say "[N] bottle[s] of beer[line break]";
say "Take one down, pass it around[line break]";
say "[N - 1] bottle[s] of beer on the wall[paragraph break]";
end the story.
World model solution
This solution uses in-game objects to represent the wall and the bottles.
Beer Hall is a room.
The plural of bottle of beer is bottles of beer. A bottle of beer is a kind of thing.
The wall is a scenery supporter in Beer Hall. 99 bottles of beer are on the wall.
When play begins:
while something is on the wall:
say "[what's on the wall] on the wall[line break]";
say "[what's on the wall][line break]";
say "Take one down, pass it around[line break]";
remove a random thing on the wall from play;
say "[what's on the wall] on the wall[paragraph break]";
end the story.
To say what's on the wall:
if more than one thing is on the wall, say list of things on the wall;
otherwise say "[number of things on the wall in words] bottle[s] of beer".
Intercal
See 99 Bottles of Beer/EsoLang
Io
bottles := method(i,
if(i==0, return "no more bottles of beer")
if(i==1, return "1 bottle of beer")
"" .. i .. " bottles of beer"
)
for(i, 99, 1, -1,
write(
bottles(i), " on the wall, ",
bottles(i), ",\n",
"take one down, pass it around,\n",
bottles(i - 1), " on the wall.\n\n"
)
)
Ioke
bottle = method(i,
case(i,
0, "no more bottles of beer",
1, "1 bottle of beer",
"#{i} bottles of beer"))
(99..1) each(i,
"#{bottle(i)} on the wall, " println
"take one down, pass it around," println
"#{bottle(i - 1)} on the wall.\n" println
)
J
As posted at the http://www.jsoftware.com/jwiki/Essays/99_Bottles_of_Beer
bob =: ": , ' bottle' , (1 = ]) }. 's of beer'"_
bobw=: bob , ' on the wall'"_
beer=: bobw , ', ' , bob , '; take one down and pass it around, ' , bobw@<:
beer"0 >:i.-99
Output:
99 bottles of beer on the wall, 99 bottles of beer; take one down and pass it around, 98 bottles of beer on the wall
98 bottles of beer on the wall, 98 bottles of beer; take one down and pass it around, 97 bottles of beer on the wall
...
3 bottles of beer on the wall, 3 bottles of beer; take one down and pass it around, 2 bottles of beer on the wall
2 bottles of beer on the wall, 2 bottles of beer; take one down and pass it around, 1 bottle of beer on the wall
1 bottle of beer on the wall, 1 bottle of beer; take one down and pass it around, 0 bottles of beer on the wall
Java
Console
MessageFormat's choice operator is used to properly format plurals.
import java.text.MessageFormat; public class Beer { static String bottles(int n) { return MessageFormat.format("{0,choice,0#No more bottles|1#One bottle|2#{0} bottles} of beer", n); } public static void main(String[] args) { String bottles = bottles(99); for (int n = 99; n > 0; ) { System.out.println(bottles + " on the wall"); System.out.println(bottles); System.out.println("Take one down, pass it around"); bottles = bottles(--n); System.out.println(bottles + " on the wall"); System.out.println(); } } }
'''Optimized for speed and few I/O operations'''
public class Beer { public static void main(String[] args) { int bottles = 99; StringBuilder sb = new StringBuilder(); String verse1 = " bottles of beer on the wall\n"; String verse2 = " bottles of beer.\nTake one down, pass it around,\n"; String verse3 = "Better go to the store and buy some more."; while (bottles > 0) sb.append(bottles).append(verse1).append(bottles).append(verse2).append(--bottles).append(verse1).append("\n"); System.out.println(sb.append(verse3)); } }
'''Recursive'''
public class Beer { public static void main(String args[]) { song(99); } public static void song(int bottles) { if (bottles >= 0) { if (bottles > 1) System.out.println(bottles + " bottles of beer on the wall\n" + bottles + " bottles of beer\nTake one down, pass it around\n" + (bottles - 1) + " bottles of beer on the wall.\n"); else if (bottles == 1) System.out.println(bottles + " bottle of beer on the wall\n" + bottles + " bottle of beer\nTake one down, pass it around\n" + (bottles - 1) + " bottles of beer on the wall.\n"); else System.out.println(bottles + " bottles of beer on the wall\n" + bottles + " bottles of beer\nBetter go to the store and buy some more!"); song(bottles - 1); } } }
=== An object-oriented solution === Translated from C++.
See: [[99 Bottles of Beer/Java/Object Oriented]]
GUI
{{libheader|Swing}} {{libheader|AWT}} This version requires user interaction. The first two lines are shown in a text area on a window. The third line is shown on a button which you need to click to see the fourth line in a message box. The numbers update and the process repeats until "0 bottles of beer on the wall" is shown in a message box, when the program ends.
import java.awt.BorderLayout; import java.awt.event.ActionEvent; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JOptionPane; import javax.swing.JTextArea; public class Beer extends JFrame { private int x; private JTextArea text; public static void main(String[] args) { new Beer().setVisible(true); } public Beer() { x = 99; JButton take = new JButton("Take one down, pass it around"); take.addActionListener(this::onTakeClick); text = new JTextArea(4, 30); text.setText(x + " bottles of beer on the wall\n" + x + " bottles of beer"); text.setEditable(false); setLayout(new BorderLayout()); add(text, BorderLayout.CENTER); add(take, BorderLayout.PAGE_END); pack(); setLocationRelativeTo(null); setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE); } private void onTakeClick(ActionEvent event) { JOptionPane.showMessageDialog(null, --x + " bottles of beer on the wall"); text.setText(x + " bottles of beer on the wall\n" + x + " bottles of beer"); if (x == 0) { dispose(); } } }
JavaScript
===ES3-5===
var beer = 99; while (beer > 0) { var verse = [ beer + " bottles of beer on the wall,", beer + " bottles of beer!", "Take one down, pass it around", (beer - 1) + " bottles of beer on the wall!" ].join("\n"); console.log(verse); beer--; }
ES6
let beer = 99; while (beer > 0) { let verse = `${beer} bottles of beer on the wall, ${beer} bottles of beer! Take one down, pass it around ${beer-1} bottles of beer on the wall`; console.log(verse); beer--; }
Functional / Recursive
var bottles = 99; var songTemplate = "{X} bottles of beer on the wall \n" + "{X} bottles of beer \n"+ "Take one down, pass it around \n"+ "{X-1} bottles of beer on the wall \n"; function song(x, txt) { return txt.replace(/\{X\}/gi, x).replace(/\{X-1\}/gi, x-1) + (x > 1 ? song(x-1, txt) : ""); } console.log(song(bottles, songTemplate));
Other Examples
More skilled solution "one-liner" with grammar check
Comment: This being a "one-liner" is arguable. The author has chosen not to put a line break after the declaration of the beer variable. By using the authors definition, most of the other solutions could pass as a "one-liner".
// Line breaks are in HTML var beer; while ((beer = typeof beer === "undefined" ? 99 : beer) > 0) document.write( beer + " bottle" + (beer != 1 ? "s" : "") + " of beer on the wall " + beer + " bottle" + (beer != 1 ? "s" : "") + " of beer Take one down, pass it around " + (--beer) + " bottle" + (beer != 1 ? "s" : "") + " of beer on the wall " );
Legitimate "one-liner" with grammar check, using declarative methods.
Array.from(Array(100).keys()).splice(1).reverse().forEach(n => console.log(`${n} bottle${n !== 1 ? 's' : ''} of beer on the wall\n${n} bottle${n !== 1 ? 's' : ''} of beer\nTake one down, pass it around\n${n - 1} bottle${n - 1 !== 1 ? 's' : ''} of beer on the wall\n\n`));
Object Oriented
function Bottles(count) { this.count = count || 99; } Bottles.prototype.take = function() { var verse = [ this.count + " bottles of beer on the wall,", this.count + " bottles of beer!", "Take one down, pass it around", (this.count - 1) + " bottles of beer on the wall!" ].join("\n"); console.log(verse); this.count--; }; Bottles.prototype.sing = function() { while (this.count) { this.take(); } }; var bar = new Bottles(99); bar.sing();
An alternative version:
function bottleSong(n) { if (!isFinite(Number(n)) || n == 0) n = 100; var a = '%% bottles of beer', b = ' on the wall', c = 'Take one down, pass it around', r = ' ' p = document.createElement('p'), s = [], re = /%%/g; while(n) { s.push((a+b+r+a+r+c+r).replace(re, n) + (a+b).replace(re, --n)); } p.innerHTML = s.join(r+r); document.body.appendChild(p); } window.onload = bottleSong;
Joy
LIBRA
_beerlib == true ;
HIDE
beer == "of beer " putchars ;
wall == "on the wall" putchars ;
take1 == "Take one down and pass it around, " putchars ;
dup3 == dup dup dup ;
comma == ", " putchars ;
period == '. putch ;
bottles == [dup small]
[ [null] [pop "no more bottles " putchars] [put "bottle " putchars] ifte]
[put "bottles " putchars] ifte ;
sing-verse == dup3 bottles beer wall comma
bottles beer ".\n" putchars
take1 1 - bottles beer wall period newline newline ;
sing-verse-0 == "No more bottles of beer on the wall, no more bottles of beer\n" putchars
"Go to the store and buy some more, " putchars
99 bottles pop beer wall period newline ;
IN
(* n -- *)
sing-verses == [null]
[sing-verse-0]
[sing-verse 1 -] tailrec .
jq
'''Minimalist:'''
99
| (. - range(0;.+1) )
| "
\(.) bottles of beer on the wall
\(.) bottles of beer
Take one down, pass it around
\(.) bottles of beer on the wall"
Output:
$ jq -n -r -f 99_bottles.jq ... 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 1 bottles of beer on the wall 1 bottles of beer Take one down, pass it around 1 bottles of beer on the wall 0 bottles of beer on the wall 0 bottles of beer Take one down, pass it around 0 bottles of beer on the wall
'''Variant''':
def sing:
def s: if . == 1 then "" else "s" end;
def bottles:
if . == 0 then "No more"
else "\(.)"
end + " bottle\(s)";
(. - range(0;.+1) )
| "
\(bottles) of beer on the wall
\(bottles) of beer
Take one down, pass it around
\(bottles) of beer on the wall."
;
$bottles | tonumber | sing
Output:
$ jq -r --arg bottles 99 -f 99_bottles_variant.jq ... 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 2 bottles of beer on the wall. 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 1 bottle of beer on the wall. No more bottles of beer on the wall No more bottles of beer Take one down, pass it around No more bottles of beer on the wall.
Jsish
/* 99 Bottles, in Jsish */
function plural(n:number):string { return (bottles == 1) ? "" : "s"; }
function no(n:number):string { return (bottles == 0) ? "No" : n.toString(); }
var bottles = 99;
do {
printf("%d bottle%s of beer on the wall\n", bottles, plural(bottles));
printf("%d bottle%s of beer\n", bottles, plural(bottles));
puts("Take one down, pass it around");
bottles--;
printf("%s bottle%s of beer on the wall\n\n", no(bottles), plural(bottles));
} while (bottles > 0);
Julia
'''one-liner'''
for i = 99:-1:1 print("\n$i bottles of beer on the wall\n$i bottles of beer\nTake one down, pass it around\n$(i-1) bottles of beer on the wall\n") end
another solution, handling grammar cases "No more bottles", "1 bottle", "
bottles(n) = n==0 ? "No more bottles" : n==1 ? "1 bottle" : "$n bottles" for n = 99:-1:1 println(""" $(bottles(n)) of beer on the wall $(bottles(n)) of beer Take one down, pass it around $(bottles(n-1)) of beer on the wall """) end
shorter, but more cryptic, version of the previous bottles function
bottles(n) = "$(n==0 ? "No more" : n) bottle$(n==1 ? "" : "s")"
K
`0:\:{x[z],y,a,x[z],a,"Take one down, pass it around",a,x[z-1],y,a,a:"\n"}[{($x)," bottle",:[x=1;"";"s"]," of beer"};" on the wall"]'|1_!100
Kabap
// Loop that spits lyrics to "99 Bottles of Beer"
$n = 99;
$out = "";
:loop;
$out = $out << $n << " bottles of beer on the wall, " << $n << " bottles of beer. Take one down, pass it around, " << $n - 1 << " bottles of beer on the wall… ";
$n = $n - 1;
if $n > 0;
goto loop;
return = $out;
Kitten
99 bottles_of_beer_on_the_wall
define bottles_of_beer_on_the_wall (Int32 -> +IO):
-> n;
n th_verse
if (n > 1): (n - 1) bottles_of_beer_on_the_wall
define th_verse (Int32 -> +IO):
-> n;
n bottles_of_beer on_the_wall say
n bottles_of_beer say
take_one_down_pass_it_around say
(n - 1) bottles_of_beer on_the_wall say
newline
define bottles_of_beer (Int32 -> List<Char>):
bottles " of beer" cat
define on_the_wall (List<Char> -> List<Char>):
" on the wall" cat
define take_one_down_pass_it_around (-> List<Char>):
"take one down, pass it around"
define bottles (Int32 -> List<Char>):
-> n;
if (n = 0):
"no more bottles"
elif (n = 1):
"one bottle"
else:
n show " bottles" cat
Klong
bottles::{:[x=1;"bottle";"bottles"]}
itone::{:[x=1;"it";"one"]}
numno::{:[x=0;"no";x]}
drink::{.d(numno(x));
.d(" ");
.d(bottles(x));
.p(" of beer on the wall");
.d(numno(x));
.d(" ");
.d(bottles(x));
.p(" of beer");
.d("take ");
.d(itone(x));
.p(" down and pass it round");
.d(numno(x-1));
.d(" ");
.d(bottles(x-1));
.p(" of beer on the wall");.p("")}
drink'1+|!99
Kotlin
fun main(args: Array<String>) { for (i in 99.downTo(1)) { println("$i bottles of beer on the wall") println("$i bottles of beer") println("Take one down, pass it around") } println("No more bottles of beer on the wall!") }
LabVIEW
See [[99 Bottles of Beer/VPL]]
Lambda Prolog
The signature file:
sig bottles.
type println string -> o.
type round int -> o.
type bottles_song int -> o.
The module file:
module bottles.
println Str :- print Str, print "\n".
round N :- M is N - 1,
NStr is int_to_string N,
MStr is int_to_string M,
BOB = " bottles of beer ",
Line1 is NStr ^ BOB ^ "on the wall",
Line2 is NStr ^ BOB,
Line3 is "take one down, pass it around",
Line4 is MStr ^ BOB ^ "on the wall",
println Line1,
println Line2,
println Line3,
println Line4.
bottles_song 0.
bottles_song N :- N > 0,
round N,
M is N - 1,
bottles_song M.
Then we produce the desired output by setting the system to solve for this goal:
[bottles] ?- bottles_song 99.
Lasso
Simple loop
local(
beer = 99,
song = ''
)
while(#beer > 0) => {
#song->append(
#beer + ' bottles of beer on the wall\n' +
#beer + ' bottles of beer\n' +
'Take one down, pass it around\n' +
(#beer-1) + ' bottles of beer on the wall\n\n'
)
#beer--
}
#song
Query Expression
(with beer in 99 to 1 by -1 select
#beer + ' bottles of beer on the wall' +
#beer + ' bottles of beer\n' +
'Take one down, pass it around\n' +
--#beer + ' bottles of beer on the wall\n'
)->join('\n')
Query Expression with Autocollect
// this example adds an "s" to bottle until there is only 1 bottle left on the wall
local(s = 's')
with n in 99 to 1 by -1 do {^
#n + ' bottle' + #s + ' of beer on the wall,
'
#n + ' bottle' + #s + ' of beer,
'
#n = #n - 1
#s = (#n != 1 ? 's' | '')
'Take one down, pass it around,
'
#n + ' bottle' + #s + ' of beer on the wall.
'
^}
LaTeX
Recursive
\documentclass{article} \newcounter{beer} \newcommand{\verses}[1]{ \setcounter{beer}{#1} \par\noindent \arabic{beer} bottles of beer on the wall,\\ \arabic{beer} bottles of beer!\\ Take one down, pass it around---\\ \addtocounter{beer}{-1} \arabic{beer} bottles of beer on the wall!\\ \ifnum#1>0 \verses{\value{beer}} \fi } \begin{document} \verses{99} \end{document}
Iterative
The \loop macro is tail-recursive (Knuth 1984, page 219). Just for fun, this version uses Roman numerals.
\documentclass{article} \newcounter{beer} \newcounter{showC} \newcommand{\verses}[1]{ \setcounter{beer}{#1} \loop \par\noindent \Roman{beer} bottles of beer on the wall,\\ \Roman{beer} bottles of beer!\\ Take one down, pass it around---\\ \addtocounter{beer}{-1} % Romans didn't know how to write zero ;-) \ifnum\value{beer}=0 ZERO \else\Roman{beer} \fi bottles of beer on the wall!\\ \ifnum\value{beer}>0 \repeat } \begin{document} \verses{99} \end{document}
References
*Knuth, Donald E. (1984). ''The TeXbook'', Addison Wesley.
lang5
: ~ 2 compress "" join ;
: verses(*)
dup " bottles of beer on the wall\n" ~ .
dup " bottles of beer\n" ~ .
"Take one down, pass it around\n" .
1 - " bottles of beer on the wall\n\n" ~ .
;
99 iota 1 + reverse verses
LDPL
DATA:
bottles-in-the-wall is number
plural is text
PROCEDURE:
store 99 in bottles-in-the-wall
sub-procedure check-plural
if bottles-in-the-wall is not equal to 1 then
store "s" in plural
else
store "" in plural
end if
end sub-procedure
while bottles-in-the-wall is greater than 0 do
call sub-procedure check-plural
display bottles-in-the-wall " bottle" plural " of beer on the wall," crlf
display bottles-in-the-wall " bottle" plural " of beer." crlf
display "Take one down, pass it around," crlf
subtract 1 from bottles-in-the-wall in bottles-in-the-wall
call sub-procedure check-plural
if bottles-in-the-wall is greater than 0 then
display bottles-in-the-wall " bottle" plural " of beer on the wall." crlf crlf
else
display "No bottles of beer on the wall." crlf
end if
repeat
Lhogho
to bottle :i
if :i = 0 [output "|No more bottles of beer|]
if :i = 1 [output "|One bottle of beer|]
output word :i "| bottles of beer|
end
to it_one :n
if :n = 1 [output "it][output "one]
end
to verse :i
(print bottle :i "| on the wall,|)
(print word bottle :i ".)
(print "Take it_one :i "|down, pass it round|)
(print bottle :i - 1 "| on the wall.|)
print
end
to sing :i
if :i = 0
[
print "|No more bottles of beer on the wall,
No more bottles of beer.
Go to the store and buy some more.
99 bottles of beer on the wall.|
stop
]
verse :i
sing :i - 1
end
;Using it:
sing 99
Limbo
implement Beer;
include "sys.m";
include "draw.m";
sys: Sys;
Beer : module
{
init : fn(ctxt : ref Draw->Context, args : list of string);
};
init (ctxt: ref Draw->Context, args: list of string)
{
sys = load Sys Sys->PATH;
beers := 99;
for (; beers > 1; --beers) {
sys->print("%d bottles of beer on the wall\n", beers);
sys->print("%d bottles of beer\n", beers);
sys->print("Take one down, pass it around,\n");
sys->print("%d bottles of beer on the wall\n\n", beers-1);
};
sys->print("1 bottle of beer on the wall\n1 bottle of beer\n");
sys->print("Take it down, pass it around\nand nothing is left!\n\n");
}
Lingo
repeat with i = 99 down to 2
put i & " bottles of beer on the wall"
put i & " bottles of beer"
put "Take one down, pass it around"
put (i-1) & " bottles of beer on the wall"
put
end repeat
put "1 bottle of beer on the wall"
put "1 bottle of beer"
put "Take one down, pass it around"
put "No more bottles of beer on the wall"
put
put "No more bottles of beer on the wall"
put "No more bottles of beer"
put "Go to the store and buy some more"
put "99 bottles of beer on the wall"
LiveCode
function beerMe numberOfBottles
put "XX bottles of beer on the wall" into verseA
put "Take one down, pass it around" into verseB
repeat with N = numberOfBottles down to 1
put replaceText(verseA,"XX",N) & cr & word 1 to 4 of \
replaceText(verseA,"XX",N) & cr & verseB & cr & replaceText(verseA,"XX",N-1) \
& cr & cr after theSong
end repeat
return theSong
end beerMe
Lisp
LLVM
See 99 Bottles of Beer/Assembly
Logo
to bottles :n
if :n = 0 [output [No more bottles]]
if :n = 1 [output [1 bottle]]
output sentence :n "bottles
end
to verse :n
print sentence bottles :n [of beer on the wall]
print sentence bottles :n [of beer]
print [Take one down, pass it around]
print sentence bottles :n-1 [of beer on the wall]
end
for [n 99 1] [verse :n (print)]
Logtalk
:- object(bottles).
:- initialization(sing(99)).
sing(0) :-
write('No more bottles of beer on the wall, no more bottles of beer.'), nl,
write('Go to the store and buy some more, 99 bottles of beer on the wall.'), nl, nl.
sing(N) :-
N > 0,
N2 is N -1,
beers(N), write(' of beer on the wall, '), beers(N), write(' of beer.'), nl,
write('Take one down and pass it around, '), beers(N2), write(' of beer on the wall.'), nl, nl,
sing(N2).
beers(0) :-
write('no more bottles').
beers(1) :-
write('1 bottle').
beers(N) :-
N > 1,
write(N), write(' bottles').
:- end_object.
LOLCODE
See 99 Bottles of Beer/EsoLang
Lua
local bottles = 99 local function plural (bottles) if bottles == 1 then return '' end return 's' end while bottles > 0 do print (bottles..' bottle'..plural(bottles)..' of beer on the wall') print (bottles..' bottle'..plural(bottles)..' of beer') print ('Take one down, pass it around') bottles = bottles - 1 print (bottles..' bottle'..plural(bottles)..' of beer on the wall') print () end
With a numeric for-loop and string formatting:
verse = [[%i bottle%s of beer on the wall %i bottle%s of beer Take one down, pass it around %i bottle%s of beer on the wall ]] function suffix(i) return i ~= 1 and 's' or '' end for i = 99, 1, -1 do print(verse:format(i, suffix(i), i, suffix(i), i-1, suffix(i-1))) end
Using Lua relational operators and multiple return values:
function bottles(i) local s = i == 1 and "1 bottle of beer" or i == 0 and "no more bottles of beer" or tostring(i) .. " bottles of beer" return s, s end for i = 99, 1, -1 do print( string.format("%s on the wall,\n%s,\ntake one down, pass it around,", bottles(i)), string.format("\n%s on the wall.\n", bottles(i-1)) ) end
Lucid
// Run luval with -s inside the lucid shell script
// The print out is a list of lines. So the output is not separated by new lines, rather
// by '[' and ']' -- I cant figure out how to do string concatenation with numbers in lucid.
// beer(N) ^ bottle(N) ^ wall ^ beer(N) ^ bottle(N) ^ pass ^ beer(N-1) ^ bottle(N-1) ^ wall
// should have worked but doesn't
[%beer(N),bottle(N),wall,beer(N),bottle(N),pass,beer(N-1),bottle(N-1),wall%]
where
N = 100 fby N - 1;
wall = if N > 0 then ` On the wall ' else eod fi;
pass = `Take one down and pass it around.';
beer(A) = if A > 0 then A else `No more' fi;
bottle(A) = if A eq 1 then `bottle of beer' else `bottles of beer' fi;
end
M4
define(`BOTTLES', `bottles of beer')dnl
define(`BOTTLE', `bottle of beer')dnl
define(`WALL', `on the wall')dnl
define(`TAKE', `take one down, pass it around')dnl
define(`NINETEEN', `$1 ifelse(`$1',`1',BOTTLE,BOTTLES) WALL
$1 ifelse(`$1',`1',BOTTLE,BOTTLES)
ifelse(`$1',`0',,`TAKE')
ifelse(`$1',`0',,`NINETEEN(eval($1-1))')')dnl
NINETEEN(99)
make
BSD make
{{libheader|jot}} Works with BSD make.
START = 99 UP != jot - 2 `expr $(START) - 1` 1 0-bottles-of-beer: 1-bottle-of-beer @echo No more bottles of beer on the wall! 1-bottle-of-beer: 2-bottles-of-beer @echo One last bottle of beer on the wall! @echo @echo One last bottle of beer on the wall, @echo One last bottle of beer, @echo Take it down, pass it around. .for COUNT in $(UP) ONE_MORE != expr 1 + $(COUNT) $(COUNT)-bottles-of-beer: $(ONE_MORE)-bottles-of-beer @echo $(COUNT) bottles of beer on the wall! @echo @echo $(COUNT) bottles of beer on the wall, @echo $(COUNT) bottles of beer, @echo Take one down, pass it around. .endfor $(START)-bottles-of-beer: @echo $(START) bottles of beer on the wall, @echo $(START) bottles of beer. @echo Take one down, pass it around.
Usage: make or make START=99
GNU make
Works with GNU make 3.81.
PRED=`expr $* - 1` 1-bottles: 1-beer pass @echo "No more bottles of beer on the wall" %-bottles: %-beer pass @echo "$(PRED) bottles of beer on the wall\n" @-$(MAKE) $(PRED)-bottles 1-beer: @echo "One bottle of beer on the wall, One bottle of beer" %-beer: @echo "$* bottles of beer on the wall, $* bottles of beer" pass: @echo "Take one down and pass it around,"
Usage: make 99-bottles
This will fork 99 make processes.
You might need to raise your process limit (ulimit -p).
Without using a shell command to decrement the counter
Works with GNU make 3.81.
digits:=9 8 7 6 5 4 3 2 1 0 numbers:=$(foreach x,$(filter-out 0,$(digits)),$(foreach y,$(digits),$x$y)) numbers+=$(digits) bottles=bottle$(if $(findstring /1/,$@),,s) num=$(if $(findstring /0/,$@),$(empty),$(@F)) action=$(if $(findstring /0/,$@),$(buy),$(pass)) beer:=of beer wall:=on the wall empty:=No more pass:=Take one down and pass it around. buy:=Go to the store and buy some more. # Function to generate targets for each verse of the song. define verse .PHONY: $1 $1: verse/$1/$1 prelude/$2/$2 $2 .PHONY: $1-bottles $1-bottles: $1 most?=$1 endef # Recursive function that loops through the 100 numbers. define verses $$(eval $$(call verse,$$(word 1,$1),$$(word 2,$1))) $$(if $$(word 2,$1),$$(eval $$(call verses,$$(filter-out $$(word 1,$1),$1)))) endef # Generate the targets for the 100 numbers. $(eval $(call verses,$(numbers))) # Main lines in the verse. .PHONY: verse/% verse/%: @echo "$(num) $(bottles) $(beer) $(wall)." @echo "$(num) $(bottles) $(beer)." @echo "$(action)" # Last line of a verse, which is a prelude to the next verse. .PHONY: prelude/% prelude/%: @echo "$(num) $(bottles) $(beer) $(wall)." @echo "" # Special target for the last line of the song. .PHONY: prelude/ prelude/: @echo "$(most) $(bottles) $(beer) $(wall)!" @echo ""
Usage: make or make N-bottles or make N
Malbolge
'''Long version''' (a real loop version made by Hisashi Iizawa)''':'''
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h.ledcba'_^$o
Maple
seq( printf( "%d %s of beer on the wall,\n%d %s of beer.\nTake one down, pass it around,\n%d %s of beer on the wall.\n\n",
i, `if`( i<>1, "bottles", "bottle" ),
i, `if`( i<>1, "bottles", "bottle" ),
i-1, `if`( i-1<>1, "bottles", "bottle") ),
i = 99..1, -1 );
Mathematica / Wolfram Language
Bottle[n_] := ToString[n] <> If[n==1," bottle"," bottles"] <> " of beer"
BottleSong[n_] := Speak[
Bottle[n] <> " on the wall," <>
Bottle[n] <>
", take one down, pass it around," <>
Bottle[n-1] <> " on the wall."
]
BottleSong /@ Range[99,1,-1]
MATLAB
function ninetyNineBottlesOfBeer() disp( [ sprintf(['%d bottles of beer on the wall, %d bottles of beer.\n'... 'Take one down, pass it around...\n'],[(99:-1:2);(99:-1:2)])... sprintf(['1 bottle of beer on the wall, 1 bottle of beer.\nTake'... 'one down, pass it around;\nNo more bottles of beer on the wall.']) ] ); %The end of this song makes me sad. The shelf should always have more %beer...like college. end
Maxima
bottles(n) := for i from n thru 1 step -1 do (
printf(true, "~d bottle~p of beer on the wall~%", i, i),
printf(true, "~d bottle~p of beer~%", i, i),
printf(true, "Take one down, pass it around~%"),
printf(true, "~d bottle~p of beer on the wall~%", i - 1, i - 1),
disp(""))$
bottles(3);
/*
3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
0 bottles of beer on the wall
*/
MAXScript
escapeEnable = true
resetMaxFile #noPrompt
viewport.setType #view_top
max tool maximize
viewport.SetRenderLevel #smoothhighlights
delay = 1.6
a = text size:30
a.wirecolor = white
theMod = extrude()
addModifier a theMod
for i in 99 to 1 by -1 do -- this will iterate through 99 times use the escape key to terminate.
(
a.text = (i as string + " bottles of beer on the wall")
redrawViews()
sleep delay
a.text = (i as string + " bottles of beer")
redrawViews()
sleep delay
a.text = "Take one down, pass it around"
redrawViews()
sleep delay
a.text = ((i-1) as string + " bottles of beer on the wall")
redrawViews()
sleep delay
)
=== A one-line version === Since MAXscript is an expression based language (everything returns a value), it is relatively easy to write long expressions that are only one line long. the following single-line snippet (broken for clarity on the webpage) produces a grammatically correct printout of the song.
for i = 99 to 1 by -1 do (print (i as string + (if i == 1 then " bottle" else " bottles") + " of beer on the wall\n" + i as string +\
(if i == 1 then " bottle" else " bottles") + " of beer\nTake one down, pass it around\n" + (i - 1) as string + (if i - 1 == 1 then "\
bottle" else " bottles") + " of beer on the wall\n" + (if i - 1 == 0 then "\nno more beer" else "")))
Mercury
% file: beer.m
% author:
% Fergus Henderson <[email protected]> Thursday 9th November 1995
% Re-written with new syntax standard library calls:
% Paul Bone <[email protected]> 2015-11-20
%
% This beer song is more idiomatic Mercury than the original, I feel bad
% saying that since Fergus is a founder of the language.
:- module beer.
:- interface.
:- import_module io.
:- pred main(io::di, io::uo) is det.
:- implementation.
:- import_module int.
:- import_module list.
:- import_module string.
main(!IO) :-
beer(99, !IO).
:- pred beer(int::in, io::di, io::uo) is det.
beer(N, !IO) :-
io.write_string(beer_stanza(N), !IO),
( N > 0 ->
io.nl(!IO),
beer(N - 1, !IO)
;
true
).
:- func beer_stanza(int) = string.
beer_stanza(N) = Stanza :-
( N = 0 ->
Stanza = "Go to the store and buy some more!\n"
;
NBottles = bottles_line(N),
N1Bottles = bottles_line(N - 1),
Stanza =
NBottles ++ " on the wall.\n" ++
NBottles ++ ".\n" ++
"Take one down, pass it around,\n" ++
N1Bottles ++ " on the wall.\n"
).
:- func bottles_line(int) = string.
bottles_line(N) =
( N = 0 ->
"No more bottles of beer"
; N = 1 ->
"1 bottle of beer"
;
string.format("%d bottles of beer", [i(N)])
).
min
Works with min|0.19.3.
(swap quote interpolate puts!) :line
(
(
("$1 bottles of beer on the wall" line)
("$1 bottles of beer" line)
(pop "Take one down, pass it around" puts!)
(pred dup "$1 bottles of beer on the wall" line newline)
) cleave
) :verse
99 'verse over times
MiniScript
Going for the simple/obvious solution here...
bottles = function(n)
if n == 0 then return "no bottles"
if n == 1 then return "1 bottle"
return n + " bottles"
end function
verse = function(n)
print bottles(n) + " of beer on the wall"
print bottles(n) + " of beer"
print "Take one down, pass it around"
print bottles(n-1) + " of beer on the wall"
print
end function
for i in range(99, 1)
verse i
end for
Output:
99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall
98 bottles of beer on the wall
98 bottles of beer
Take one down, pass it around
97 bottles of beer on the wall
...
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
no bottles of beer on the wall
MIPS Assembly
##################################
# 99 bottles of beer on the wall #
# MIPS Assembly targeting MARS #
# By Keith Stellyes #
# August 24, 2016 #
##################################
#It is simple, a loop that goes as follows:
#if accumulator is not 1:
#PRINT INTEGER: accumulator
#PRINT lyrica
#PRINT INTEGER: accumulator
#PRINT lyricb
#PRINT INTEGER: accumulator
#PRINT lyricc
#DECREMENT accumulator
#else:
#PRINT FINAL LYRICS
.data
lyrica: .asciiz " bottles of beer on the wall, "
lyricb: " bottles of beer.\nTake one down and pass it around, "
lyricc: " bottles of beer on the wall. \n\n"
#normally, I don't like going past 80 columns, but that was done here.
# there's an argument to be had for breaking this up. I chose not to
# for simpler instructions.
final_lyrics: "1 bottle of beer on the wall, 1 bottle of beer.\nTake one down and pass it around, no more bottles of beer on the wall.\n\nNo more bottles of beer on the wall, no more bottles of beer.\nGo to the store and buy some more, 99 bottles of beer on the wall."
.text
#lw $a0,accumulator #load address of accumulator into $a0 (or is it getting val?)
li $a1,99 #set the inital value of the counter to 99
loop:
###99
li $v0, 1 #specify print integer system service
move $a0,$a1
syscall #print that integer
### bottles of beer on the wall,
la $a0,lyrica
li $v0,4
syscall
###99
li $v0, 1 #specify print integer system service
move $a0,$a1
syscall #print that integer
### bottles of beer.\n Take one down and pass it around,
la $a0,lyricb
li $v0,4
syscall
###99
li $v0, 1 #specify print integer system service
move $a0,$a1
syscall #print that integer
### "bottles of beer on the wall. \n\n"
la $a0,lyricc
li $v0,4
syscall
#decrement counter, if at 1, print the final and exit.
subi $a1,$a1,1
bne $a1,1,loop
### PRINT FINAL LYRIC, THEN TERMINATE.
final: la $a0,final_lyrics
li $v0,4
syscall
li $v0,10
syscall
Mirah
plural = 's'
99.downto(1) do |i|
puts "#{i} bottle#{plural} of beer on the wall,"
puts "#{i} bottle#{plural} of beer"
puts "Take one down, pass it around!"
plural = '' if i - 1 == 1
if i > 1
puts "#{i-1} bottle#{plural} of beer on the wall!"
puts
else
puts "No more bottles of beer on the wall!"
end
end
mIRC Scripting Language
var %x = 99
while (%x) {
echo -ag %x bottles of beer on the wall
echo -ag %x bottles of beer
echo -ag Take one down, pass it around
dec %x
echo -ag %x bottles of beer on the wall
}
mLite
val NL = implode [#"newline"]
fun itone 1 = "it"
| n = "one"
fun plural (s, 0) = ("no " @ s @ "s")
| (s, 1) = ("1 " @ s)
| (s, n) = (ntos n @ " " @ s @ "s")
fun verse 0 = "no bottles of beer on the wall" @ NL @
"no bottles of beer" @ NL @
"go to the store and buy some more" @ NL @
"99 bottles of beer on the wall" @ NL @ NL
| x = plural ("bottle",x) @ " of beer on the wall" @ NL @
plural ("bottle",x) @ " of beer" @ NL @
"take " @ (itone x) @ " down and pass it round" @ NL @
plural ("bottle", (x-1)) @ " of beer on the wall" @ NL @ NL
fun bottles x = map (print o verse) (rev (0 :: iota (1, x)))
fun default (false, y) = y | (x, _) = x
;
bottles ` ston ` default (argv 0, "99")
Allows for number of bottles to be specified on command line with the default being 99, viz
mlite -f 99bob.m 2
Which, having specified 2 bottles, gives
2 bottles of beer on the wall
2 bottles of beer
take one down and pass it round
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
take it down and pass it round
no bottles of beer on the wall
no bottles of beer on the wall
no bottles of beer
go to the store and buy some more
99 bottles of beer on the wall
ML/I
Simple iterative version
MCSKIP "WITH" NL
"" 99 bottles - simple iterative version
MCSKIP MT,<>
MCINS %.
"" Macro to generate singular or plural bottle(s)
MCDEF BOT WITHS () AS <bottle<>MCGO L0 IF %A1. EN 1
s>
"" Main macro - argument is initial number of bottles
MCDEF BOTTLES NL AS <MCSET T1=%A1.
%L1.%T1. BOT(%T1.) of beer on the wall
%T1. BOT(%T1.) of beer
Take one down, pass it around
MCSET T1=T1-1
%T1. BOT(%T1.) of beer on the wall
MCGO L0 IF T1 EN 0
MCGO L1
>
"" Do it
BOTTLES 99
Recursive version
MCSKIP "WITH" NL
"" 99 bottles - recursive version
MCSKIP MT,<>
MCINS %.
"" Macro to generate singular or plural bottle(s)
MCDEF BOT WITHS () AS <bottle<>MCGO L0 IF %A1. EN 1
s>
"" Main macro - recurses for each verse - argument is initial number of bottles
MCDEF BOTTLES NL AS <MCSET T1=%A1.
%T1. BOT(%T1.) of beer on the wall
%T1. BOT(%T1.) of beer
Take one down, pass it around
MCSET T1=T1-1
%T1. BOT(%T1.) of beer on the wall
MCGO L0 IF T1 EN 0
BOTTLES %T1.
>
"" Do it
BOTTLES 99
Macro Processing generalized version
This version demonstrates the macro text replacement capabilities central to ML/I.
The code defines a macro
'''Sing''' ''n'' ''containers'' '''of''' ''contents'' ''somewhere'' ''':''' ''deed'' '''!''' ''replenish'' '''.'''
where the text (macro call)
'''Sing''' ''99'' ''bottles'' '''of''' ''beer'' '''on''' ''the wall''''':''' ''Take one down, pass it around'' '''!''' ''Go to the store and buy some more'' '''.'''
is macro substituted with the specified 99 bottles of beer song. The text
'''Sing''' ''7'' ''bottles'' '''of''' ''Armagnac'' '''on''' ''the table''''':''' ''Take a swig, throw it down'' '''!''' ''Emilie vists, she brings some more'' '''.'''
would be substituted with a shorter, more expensive, less social and sexier lyric.
Internal macros define English word replacements for decimal numbers from 0 to 99.
MCSKIP - WITH - NL
-- The line above defines the comment syntax: -- through to newline is completely deleted.
-- 99 Bottles of beer in 99 lines of ML/I by Parzival Herzog.
-- ML/I is P.J. Brown's famous general purpose macro processor designed in 1967.
--
-- Define nestable quotes {...}, replaced by the unevaluated text within:
MCSKIP MT, {}
-- Define non-nestable quotes "...", replaced by the unevaluated text within:
MCSKIP T, ""
-- Define the argument insertion and expression evaluation syntax:
-- ?e. is replaced by the value of macro expression e:
MCINS ?.
--
-- Top level macro: Sing N CONTAINERS of CONTENTS SOMEWHERE : DO THE DEED! REPLENISH.
MCDEF "Sing WITH SPACE SPACE of WITH SPACE SPACE : ! ." AS --
{MCDEF "CONTAINERS" AS "{"?A2."}"
MCDEF "CONTAINER" AS "{"MCSUB(CONTAINERS,1,-1)"}"
MCDEF "CONTENTS" AS "{"?A3."}"
MCDEF "SOMEWHERE" AS "{"?A4."}"
MCDEF "DO WITHS THE WITHS DEED" AS "{"?A5."}"
MCDEF "REPLENISH" AS "{"?A6."}"
MCSET T1 = ?A1.
MCDEF "n" AS "("?T1.")"
MCDEF "N" AS "{"n"}"
?L1.n of CONTENTS SOMEWHERE,
n of CONTENTS.
MCGO L2 UNLESS ?T1. GR 0
MCSET T1 = T1 - 1
MCDEF "n" AS "("?T1.")"
DO THE DEED:
n of CONTENTS SOMEWHERE.
MCGO L1
?L2.REPLENISH:
N of CONTENTS SOMEWHERE!}
--
-- (n): Wordify 0 to 99 CONTAINERS
MCDEF "()" AS {MCSET T1=?A1.
MCGO L1 UNLESS T1 GR 99
?T1. CONTAINERS-- Return the decimal number instead of words.
MCGO L0
?L1.MCGO L2 IF T1 GR 9
MCDEF "0units" AS ?T1."Unit"
MCGO L3
?L2.MCSET T3 = T1 - T1/10*10
MCDEF "0units" AS ?T3."unit"
MCSET T1 = T1 / 10
MCDEF "0tens" AS ?T1."Ten"
0tens?L3.0units CONTAINERS}
-- Exceptions:
MCDEF "(WITH 0 WITH)" AS {"No more" CONTAINERS}
MCDEF "(WITH 1 WITH)" AS {"One more" CONTAINER}
MCDEF "(WITH 11 WITH)" AS {"Eleven" CONTAINERS}
MCDEF "(WITH 12 WITH)" AS {"Twelve" CONTAINERS}
MCDEF "(WITH 13 WITH)" AS {"Thirteen" CONTAINERS}
MCDEF "(WITH 14 WITH)" AS {"Fourteen" CONTAINERS}
MCDEF "(WITH 15 WITH)" AS {"Fifteen" CONTAINERS}
MCDEF "(WITH 16 WITH)" AS {"Sixteen" CONTAINERS}
MCDEF "(WITH 17 WITH)" AS {"Seventeen" CONTAINERS}
MCDEF "(WITH 18 WITH)" AS {"Eighteen" CONTAINERS}
MCDEF "(WITH 19 WITH)" AS {"Nineteen" CONTAINERS}
-- Regular cases:
MCDEF "2Unit" AS {"Two"}
MCDEF "3Unit" AS {"Three"}
MCDEF "4Unit" AS {"Four"}
MCDEF "5Unit" AS {"Five"}
MCDEF "6Unit" AS {"Six"}
MCDEF "7Unit" AS {"Seven"}
MCDEF "8Unit" AS {"Eight"}
MCDEF "9Unit" AS {"Nine"}
MCDEF "0unit" AS
MCDEF "1unit" AS {" one"}
MCDEF "2unit" AS {" two"}
MCDEF "3unit" AS {" three"}
MCDEF "4unit" AS {" four"}
MCDEF "5unit" AS {" five"}
MCDEF "6unit" AS {" six"}
MCDEF "7unit" AS {" seven"}
MCDEF "8unit" AS {" eight"}
MCDEF "9unit" AS {" nine"}
MCDEF "1Ten" AS {"Ten"}
MCDEF "2Ten" AS {"Twenty"}
MCDEF "3Ten" AS {"Thirty"}
MCDEF "4Ten" AS {"Forty"}
MCDEF "5Ten" AS {"Fifty"}
MCDEF "6Ten" AS {"Sixty"}
MCDEF "7Ten" AS {"Seventy"}
MCDEF "8Ten" AS {"Eighty"}
MCDEF "9Ten" AS {"Ninety"}
--
-- The specified song:
Sing 99 bottles of beer on the wall: Take one down, pass it around! --
Go to the store and buy some more.
--
--
-- Try uncommenting the next two lines:
-- Sing 7 flasks of Armagnac on the table: Take a swig, throw it down!
-- Emilie vists, she brings some more.
Usage: ml1 "Bottles of Beer.ml1"
Output:
Ninety nine bottles of beer on the wall,
Ninety nine bottles of beer.
Take one down, pass it around:
Ninety eight bottles of beer on the wall.
Ninety eight bottles of beer on the wall,
Ninety eight bottles of beer.
Take one down, pass it around:
Ninety seven bottles of beer on the wall.
...
One more bottle of beer on the wall,
One more bottle of beer.
Take one down, pass it around:
No more bottles of beer on the wall.
No more bottles of beer on the wall,
No more bottles of beer.
Go to the store and buy some more:
Ninety nine bottles of beer on the wall!
Modula-2
MODULE b99;
IMPORT InOut;
VAR nr : CARDINAL;
BEGIN
nr := 99;
REPEAT
InOut.WriteCard (nr, 4);
InOut.WriteString (" bottles of beer on the wall");
InOut.WriteLn;
InOut.WriteCard (nr, 4);
InOut.WriteString (" bottles of beer");
InOut.WriteLn;
InOut.WriteString ("Take one down, pass it around");
InOut.WriteLn;
DEC (nr);
InOut.WriteCard (nr, 4);
InOut.WriteString (" bottles of beer on the wall");
InOut.WriteLn;
InOut.WriteLn
UNTIL nr = 0
END b99.
Modula-3
MODULE Bottles EXPORTS Main;
IMPORT IO, Fmt;
BEGIN
FOR i := 99 TO 1 BY -1 DO
IO.Put(Fmt.Int(i) & " bottles of beer on the wall\n");
IO.Put(Fmt.Int(i) & " bottles of beer\n");
IO.Put("Take one down, pass it around\n");
IO.Put(Fmt.Int(i - 1) & " bottles of beer on the wall\n");
IO.Put("\n");
END;
END Bottles.
Monkey
Tic's every one and a half seconds and sings(text's) the song out.
Import mojo
Function Main () New NintyNineBottles End
Class NintyNineBottles Extends App
Field _bottles:Int = 99 Field _y:Int=640 Field tic:Int Field duration:Int = 1500 Field lyric:Int = 1 Method OnCreate () SetUpdateRate 60 End ' Stuff to do while running... Method OnUpdate () If Millisecs()-Self.tic > Self.duration Self.tic=Millisecs() If Self.lyric= 4 Then Self._bottles-=1 Self.lyric+=1 End If End ' Drawing code... Method OnRender () Cls Select Self.lyric Case 1 DrawText(_bottles+" bottles of beer on the wall",10,10) Case 2 DrawText(_bottles+" bottles of beer",10,10) Case 3 If Self._bottles > 1 DrawText("take one down",10,10) Else DrawText("take it down",10,10) End If Case 4 DrawText("Pass it around",10,10) Case 5 If Self._bottles>0 DrawText(Self._bottles+" bottles of beer on the wall",10,10) Else DrawText("no more bottles of beer on the wall",10,10) End If Case 6 If Self._bottles>0 Self.lyric=1'DrawText(Self._bottles+" bottles of beer on the wall",10,10) Else DrawText("no more bottles of beer",10,10) End if Case 7 DrawText("go to the store",10,10) Case 8 DrawText("and buy some more",10,10) Case 9 Self._bottles=99 DrawText(_bottles+" more bottles of beer on the wall",10,10) Case 10 Self.lyric=1 End Select End
End
## MOO
```moo
bottles = 99;
while (bottles > 0)
unit = (bottles == 1 ? "bottle" | "bottles");
player:tell(bottles, " ", unit, " of beer on the wall.");
player:tell(bottles, " ", unit, " of beer.");
player:tell("Take one down, pass it around.");
bottles = bottles - 1;
endwhile
player:tell("0 bottles of beer on the wall.");
MoonScript
p = (i) ->
i != 1 and 's' or ''
for b = 99,1,-1
for i = 1,4
print if i == 3
'Take one down, pass it around'
else
string.format '%s bottle%s of beer%s',
i < 4 and b or b-1,
i < 4 and (p b) or (p b-1),
i%3 == 1 and ' on the wall' or ''
io.write '\n'
MUMPS
Recursive
beer(n) If n<1 Write "No bottles of beer on the wall... " Quit
Write !!,n," bottle",$Select(n=1:"",1:"s")," of beer on the wall."
Write !,n," bottle",$Select(n=1:"",1:"s")," of beer."
Write !,"Take one down, pass it around."
Do beer(n-1)
Quit
Do beer(99)
Iterative
beer(n) If n<1 Write "No bottles of beer on the wall... " Quit
Write !!,n," bottle",$Select(n=1:"",1:"s")," of beer on the wall."
Write !,n," bottle",$Select(n=1:"",1:"s")," of beer."
Write !,"Take one down, pass it around."
Quit
For ii=99:-1:0 Do beer(ii)
===Brain-damaging===
bottles
set template1="i_n_""of beer on the wall. ""_i_n_"" of beer. """
set template2="""Take""_n2_""down, pass it around. """
set template3="j_n3_""of beer on the wall."""
for i=99:-1:1 do write ! hang 1
. set:i>1 n=" bottles ",n2=" one " set:i=1 n=" bottle ",n2=" it "
. set n3=" bottle " set j=i-1 set:(j>1)!(j=0) n3=" bottles " set:j=0 j="No"
. write @template1,@template2,@template3
repeat
write "One more time!",! hang 5
goto bottles
MontiLang
99 VAR i .
WHILE i
i TOSTR OUT . | bottles of beer on the wall| PRINT .
i TOSTR OUT . | bottles of beer| PRINT .
|Take one down, pass it around| PRINT .
i 1 - VAR i .
ENDWHILE
Another way to solve the task that shows some more features of the language.
&DEFINE botellas 99&
def rima
OUT | bottles of beer on the wall| PRINT .
OUT | bottles of beer| PRINT .
enddef
botellas
for :
rima
|Take one down, pass it around| PRINT .
1 -
endfor
|No more| rima
|Press ENTER to end | INPUT clear
Infinite loop
99 var botellas .
def rima /# n -- n #/
OUT | bottles of beer on the wall| PRINT .
OUT | bottles of beer| PRINT .
enddef
def song /# n -- #/
for :
rima
|Take one down, pass it around| PRINT .
1 -
endfor
|No more| rima
clear
enddef
while 1
botellas
song
|Go to the store and buy some more, | print
botellas out | bottles of beer on the wall.| print
|Press ENTER to continue | INPUT clear
endwhile
MyDef
Compile with:
mydef_page -mgeneral bottles.def
It outputs bottles.txt, which contains the lyrics.
bottles
$(for:i in 99-1)
$(i) bottles of beer on the wall
$(i) bottles of beer
Take one down, pass it around
$(set:i-=1)
$(i) bottles of beer on the wall
NEWLINE
N/t/roff
Classical version
Compatible with classical Bell Lab's TROFF.
Subroutine L1 calls upon itself recursively.
Works with All TROFF.
.nr BS 99 1
.de L1
.ie \\n(BS>1 \{ \
\\n(BS bottles of beer on the wall,
\\n(BS bottles of beer.\c
\}
.el \{ \
\\n(BS bottle of beer on the wall,
\\n(BS bottle of beer.\c
\}
Take one down, pass it around,
\\n-(BS bottles of beer on the wall.
.if \\n(BS>0 .L1
..
.nf
.L1
.fi
New version
Compatible only with GNU TROFF.
Instead of recursion, a while construct can be used instead,
to achieve the same results.
Technically, the program runs differently.
Works with GNU TROFF 1.22.2.
.nr beers 99 1
.nf
.while \n[beers]>0 \{ \
.ie \n[beers]>1 \{ \
\n[beers] bottles of beer on the wall,
\n[beers] bottles of beer.\c
\} \" ie \n[beers]>1
.el \{ \
\n[beers] bottle of beer on the wall,
\n[beers] bottle of beer.\c
\} \" el
Take one down, pass it around,
\n-[beers] bottles of beer on the wall.
\} \" while \n[beers]>0
.fi
Nanoquery
Translated from Ursa.
//
// 99 bottles of beer
//
for ($bottles = 99) ($bottles > 0) ($bottles = $bottles-1)
$bottlestr = ""
if $bottles = 1
$bottlestr = "bottle"
else
$bottlestr = "bottles"
end if
println ($bottles + " " + $bottlestr + " of beer on the wall")
println ($bottles + " " + $bottlestr + " of beer")
println "Take one down, pass it around."
if !($bottles = 2)
println ($bottles - 1 + " bottles of beer on the wall.\n")
else
println "1 bottle of beer on the wall.\n"
end if
end for
NASL
bottles = 99;
repeat {
display(bottles, ' bottles of beer on the wall\n');
display(bottles, ' bottles of beer\n');
display('Take one down, pass it around\n');
display(--bottles, ' bottles of beer on the wall\n\n');
} until bottles < 1;
Neko
/** <doc> <h3>RosettaGit, 99 bottles of beer on the wall, in Neko</h3> <pre> Tectonics: nekoc 99bottles.neko neko 99bottles </pre> </doc> **/ var message = " of beer on the wall\n"; var beers = 99; var plural = function(n) { return if (n == 1) " bottle" else " bottles"; } var nonesome = function(n) { return if (n > 0) n else "No more"; } while (beers > 0) { $print(nonesome(beers), plural(beers), message); $print(nonesome(beers), plural(beers), " of beer\n"); $print("Take one down, pass it around\n"); beers -= 1; $print(nonesome(beers), plural(beers), message); if (beers > 0) $print("\n"); }
Output:
prompt$ nekoc 99bottles.neko
prompt$ neko 99bottles | { head -n 4; echo "..."; tail -n 4; }
99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall
...
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No more bottles of beer on the wall
Nemerle
using System;
using System.Console;
module Bottles
{
Sing(x : int, bev = "beer", surface = "wall") : void
{
match(x)
{
|0 => WriteLine($"No more bottles of $bev on the $surface, no more bottles of $bev");
WriteLine($"Go to the store and get some more $bev, 99 bottles of $bev on the $surface")
|1 => WriteLine($"One bottle of $bev on the $surface, one bottle of $bev");
WriteLine($"Take it down, pass it around, no more bottles of $bev on the $surface")
|_ => WriteLine($"$x bottles of $bev on the $surface, $x bottles of $bev");
WriteLine($"Take one down and pass it around, $(x-1) bottles of $bev on the $surface")
}
}
Main() : void
{
foreach (i in [99, 98 .. 0])
Sing(i)
}
}
NetRexx
beer = "bottles of beer on the wall"
removeOne = "Take one down, pass it arround,"
say 99 beer","
say 99 beer.subword(1,3)","
loop i = 98 to 2 by -1
say removeOne
say i beer"."
say
say i beer","
say i beer.subword(1,3)","
end
lastCall = "bottle" beer.delword(1,1)
say removeOne
say i lastCall"."
say
say i lastCall","
say i lastCall.subword(1,3)","
say removeOne
say "No more" beer
NewLISP
Nial
line is fork [
0=, 'No more bottles of beer' first,
1=, 'One bottle of beer' first,
link [string,' bottles of beer' first]
]
verse is link [
line, ' on the wall, ' first,line,
'. Take it down and pass it around, ' first,
line (-1+),'on the wall. ' first
]
bottles is iterate (write verse) reverse count
Nim
proc GetBottleNumber(n: int): string = var bs: string if n == 0: bs = "No more bottles" elif n == 1: bs = "1 bottle" else: bs = $n & " bottles" return bs & " of beer" for bn in countdown(99, 1): var cur = GetBottleNumber(bn) echo(cur, " on the wall, ", cur, ".") echo("Take one down and pass it around, ", GetBottleNumber(bn-1), " on the wall.\n") echo "No more bottles of beer on the wall, no more bottles of beer." echo "Go to the store and buy some more, 99 bottles of beer on the wall."
other:
from strutils import format for i in countdown(99, 1): case i of 3..99: echo format("""$1 bottles of beer on the wall $1 bottles of beer Take one down, pass it around $2 bottles of beer on the wall""", i, i-1) of 2: echo format("""$1 bottles of beer on the wall $1 bottles of beer Take one down, pass it around $2 bottle of beer on the wall""", i, i-1) of 1: echo format("""$1 bottle of beer on the wall $1 bottle of beer Take one down, pass it around No more bottles of beer on the wall""", i) else: discard
compact:
from strutils import format proc pluralize(a: int): string = if a > 1 or a == 0: return "s" else: return "" for i in countdown(99, 1): echo format("""$1 bottle$3 of beer on the wall $1 bottle$3 of beer Take one down, pass it around $2 bottle$4 of beer on the wall""", i, i-1, pluralize(i), pluralize(i-1))
organized:
from strutils import format var verse = """$1 bottle$3 of beer on the wall $1 bottle$3 of beer Take one down, pass it around $2 bottle$4 of beer on the wall""" proc pluralize(a: int): string = if a > 1 or a == 0: return "s" else: return "" for i in countdown(99, 1): echo format(verse, i, i-1, pluralize(i), pluralize(i-1))
NS-HUBASIC
With grammatical support for "1 bottle of beer":
10 WALL$=" ON THE WALL"
20 FOR BOTTLES=99 TO 1 STEP -1
30 BOTTLES$=" BOTTLES OF BEER"
40 IF BOTTLES=1 THEN BOTTLE$=" BOTTLE OF BEER"
50 PRINT BOTTLES BOTTLES$ WALL$
60 PRINT BOTTLES BOTTLES$
70 PRINT "TAKE ONE DOWN, PASS IT AROUND"
80 IF BOTTLES-1=1 THEN BOTTLE$=" BOTTLE OF BEER"
90 IF BOTTLES-1=0 THEN BOTTLE$=" BOTTLES OF BEER"
100 PRINT BOTTLES-1 BOTTLES$ WALL$
110 NEXT
Without grammatical support for "1 bottle of beer":
10 BOTTLES$=" BOTTLES OF BEER"
20 WALL$=" ON THE WALL"
30 FOR BOTTLES=99 TO 1 STEP -1
40 PRINT BOTTLES BOTTLES$ WALL$
50 PRINT BOTTLES BOTTLES$
60 PRINT "TAKE ONE DOWN, PASS IT AROUND"
70 PRINT BOTTLES-1 BOTTLES$ WALL$
80 NEXT
OASYS
class player {}
int count
property int dummy
method quit verbs {{quit}} {
quit
}
method beer verbs {{beer}} {
count = 99
while count {
print count
print " bottles of beer on the wall.\n"
print count
print " bottles of beer.\nTake one down and pass it around,\n"
count = count - 1
if count {
print count
print " bottles of beer on the wall.\n\n"
}
}
print "No more bottles of beer on the wall.\n"
}
method init {
player = create player
print "Type 'beer' for beer.\nType 'quit' to quit.\n"
}
OASYS Assembler
See 99 Bottles of Beer/Assembly
Objeck
class Bottles {
function : Main(args : String[]) ~ Nil {
bottles := 99;
do {
"{$bottles} bottles of beer on the wall"->PrintLine();
"{$bottles} bottles of beer"->PrintLine();
"Take one down, pass it around"->PrintLine();
bottles--;
"{$bottles} bottles of beer on the wall"->PrintLine();
} while(bottles > 0);
}
}
Objective-C
int main()
{
@autoreleasepool {
int bottles = 99;
do
{
NSLog(@"%i bottles of beer on the wall\n", bottles);
NSLog(@"%i bottles of beer\n", bottles);
NSLog(@"Take one down, pass it around\n");
NSLog(@"%i bottles of beer on the wall\n\n", --bottles);
} while (bottles > 0);
}
return 0;
}
Oberon-2
MODULE b99;
IMPORT Out;
VAR nr : INTEGER;
BEGIN
nr := 99;
REPEAT
Out.Int (nr, 4);
Out.String (" bottles of beer on the wall");
Out.Ln;
Out.Int (nr, 4);
Out.String (" bottles of beer");
Out.Ln;
Out.String ("Take one down, pass it around");
Out.Ln;
DEC (nr);
Out.Int (nr, 4);
Out.String (" bottles of beer on the wall");
Out.Ln;
Out.Ln
UNTIL nr = 0
END b99.
OCaml
===For-loop===
for n = 99 downto 1 do Printf.printf "%d bottles of beer on the wall\n" n; Printf.printf "%d bottles of beer\n" n; Printf.printf "Take one down, pass it around\n"; Printf.printf "%d bottles of beer on the wall\n\n" (pred n); done
Recursive
Recursive version that handles plurals.
let verse n = let line2 = function | 0 -> "No more bottles of beer" | 1 -> "1 bottle of beer" | n -> string_of_int n ^ " bottles of beer" in let line1or4 y = line2 y ^ " on the wall" in let line3 = function | 1 -> "Take it down, pass it around" | _ -> "Take one down, pass it around" in line1or4 n ^ "\n" ^ line2 n ^ "\n" ^ line3 n ^ "\n" ^ line1or4 (n-1) ^ "\n";; let rec beer n = print_endline (verse n); if n > 1 then beer (n-1);; beer 99;;
Monadic
Monadic version, expressing actions which evolve the program state and log output. Special cases and grammar rules are handled.
(* A basic "Writer" monoid with emit *) module Writer = struct type 'a t = 'a * string let ( >>= ) (x,s) f = let (y,s') = f x in (y, s ^ s') let return x = (x,"") let emit (x,s) = print_string s; x end (* Utility functions for handling strings and grammar *) let line s = (String.capitalize s) ^ ".\n" let count = function 0 -> "no more" | n -> string_of_int n let plural = function 1 -> "" | _ -> "s" let specify = function 1 -> "it" | _ -> "one" let bottles n = count n ^ " bottle" ^ plural n ^ " of beer" (* Actions, expressed as an int * string, for Writer *) let report n = (n, line (bottles n ^ " on the wall, " ^ bottles n)) let take n = (n-1, "Take " ^ specify n ^ " down and pass it around") let summary n = (n, ", " ^ bottles n ^ " on the wall.\n\n") let shop = (99, "Go to the store and buy some more") let rec verse state = Writer.(state >>= report >>= function 0 -> shop >>= summary (* ends here *) | n -> take n >>= summary |> verse) let sing start = Writer.(emit (verse (return start)))
Output for initial beer-count of two:
1 bottle of beer on the wall, 1 bottle of beer. Take it down and pass it around, no more bottles of beer on the wall.
No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall.
- : int = 99
Note the output value is 99... reflecting the state at termination.
## Octave
```octave
function bottles(n)
bottle = "bottle";
ofbeer = "of beer";
wall = "on the wall";
for i = n:-1:0
if ( i == 1 )
s = "";
else
s = "s";
endif
for j = 0:1
w = wall;
if ( j == 1 )
w = "";
endif
printf("%d %s%s %s %s\n",\
i, bottle, s, ofbeer, w);
endfor
printf("Take one down, pass it around\n");
endfor
endfunction
bottles(99);
Oforth
"bottles of beer on the wall\n" const: B
"bottles of beer\nTake one down, pass it around\n" const: T
#[ 100 swap - dup . B print dup . T print 1- . B .cr ] 99 each
Ol
Onyx
$Bottles {
dup cvs ` bottle' cat exch 1 ne {`s' cat} if
` of beer' cat
} def
$GetPronoun {
1 eq {`it'}{`one'} ifelse cat
} def
$WriteStanza {
dup dup Bottles ` on the wall. ' cat exch Bottles `.\n' cat cat
exch `Take ' 1 idup GetPronoun ` down. Pass it around.\n' cat
exch dec Bottles ` on the wall.\n\n' 3 {cat} repeat print flush
} def
99 -1 1 {WriteStanza} for
Output:
99 bottles of beer on the wall. 99 bottles of beer.
Take one down. Pass it around.
98 bottles of beer on the wall.
. . .
2 bottles of beer on the wall. 2 bottles of beer.
Take one down. Pass it around.
1 bottle of beer on the wall.
1 bottle of beer on the wall. 1 bottle of beer.
Take it down. Pass it around.
0 bottles of beer on the wall.
OOC
sing_line: func (b: Int, suffix: Bool) {
"#{b > 0 ? "#{b}" : "No more"} bottle#{b == 1 ? "" : "s"}" print()
" of beer#{suffix ? " on the wall" : ""}" println()
}
sing_verse: func (b: Int) {
println()
sing_line(b, true)
sing_line(b, false)
if (b > 0) {
"Take one down, pass it around" println()
} else {
"Go to the store and buy some more" println()
b += 100
}
sing_line(b-1, true)
}
main: func {
b := 100
while (b > 0) {
sing_verse(--b)
}
}
ooRexx
The rexx example below runs unchanged on ooRexx
OpenEdge/Progress
DEFINE VARIABLE amountofbottles AS INTEGER NO-UNDO INITIAL 99.
&GLOBAL-DEFINE bbm bottles of beer
&GLOBAL-DEFINE bbs bottle of beer
&GLOBAL-DEFINE otw on the wall
&GLOBAL-DEFINE tow Take one down and pass it around,
&GLOBAL-DEFINE gts Go to the store and buy some more,
FUNCTION drinkBottle RETURNS INTEGER PRIVATE (INPUT bc AS INTEGER) FORWARD.
OUTPUT TO OUTPUT.txt.
drinkBottle(amountofbottles).
OUTPUT CLOSE.
FUNCTION drinkBottle RETURNS INTEGER.
IF bc >= 0 THEN DO:
CASE bc:
WHEN 2 THEN
PUT UNFORMATTED bc " {&bbm} {&otw}, " bc " {&bbm}" SKIP
"{&tow} " bc - 1 " {&bbs} {&otw}" SKIP.
WHEN 1 THEN
PUT UNFORMATTED bc " {&bbs} {&otw}, " bc " {&bbs}" SKIP
"{&tow} no more {&bbm} {&otw}" SKIP.
WHEN 0 THEN
PUT UNFORMATTED "no more" " {&bbm} {&otw}, no more {&bbm}" SKIP
"{>s} " amountofbottles " {&bbm} {&otw}" SKIP.
OTHERWISE
PUT UNFORMATTED bc " {&bbm} {&otw}, " bc " {&bbm}" SKIP
"{&tow} " bc - 1 " {&bbm} {&otw}" SKIP.
END CASE.
drinkBottle(bc - 1).
RETURN bc.
END.
RETURN 0.
END FUNCTION.
Order
These examples are taken directly from a much longer tutorial in the Order documentation, which explains the construction of the solution to this problem in great detail.
"Pure" Order
This solution uses only Order language constructs to generate and manipulate tokens:
#include "order/interpreter.h" ORDER_PP (8let((8B, 8fn(8N, 8cond((8greater(8N, 1), 8separate(8N, 8quote(bottles))) (8equal(8N, 1), 8quote(1 bottle)) (8else, 8quote(no more bottles))))), 8for_each_in_range (8fn(8N, 8print(8ap(8B, 8N) (of beer on the wall,) 8space 8ap(8B, 8N) (of beer,) 8space (take one down, pass it around,) 8space 8ap(8B, 8dec(8N)) (of beer on the wall.))), 100, 1)))
C Preprocessor
...but since most of the logic is simple substitution, it makes more sense (and is significantly more efficient) to make the C Preprocessor do most of the work without the help of the Order interpreter. This version shows how to integrate normal C Preprocessor macros into an Order program:
#include "order/interpreter.h" #define GEN_phrase(N_bottles, N_minus_1_bottles) \ N_bottles of beer on the wall, \ N_bottles of beer, take one down, pass it around, \ N_minus_1_bottles of beer on the wall. #define ORDER_PP_DEF_8bottles \ ORDER_PP_FN(8fn(8N, \ 8cond((8greater(8N, 1), \ 8separate(8N, 8quote(bottles))) \ (8equal(8N, 1), \ 8quote(1 bottle)) \ (8else, \ 8quote(no more bottles))))) ORDER_PP(8for_each_in_range (8fn(8N, 8emit(8quote(GEN_phrase), 8tuple(8bottles(8N), 8bottles(8dec(8N))))), 100, 1)) #undef GEN_phrase
Either example could obviously also form the core of a C solution (demonstrating the intended use of Order).
Oxygene
namespace ConsoleApplication2;
interface
type
ConsoleApp = class
public
class method Main(args: array of String);
end;
implementation
method bottles(number: Integer): String;
begin
if (number = 1) then
Result := "bottle"
else
Result := "bottles";
end;
class method ConsoleApp.Main(args: array of String);
begin
for n: Integer := 99 downto 1 do
begin
Console.WriteLine("{0} {1} of beer on the wall,",n,bottles(n));
Console.WriteLine("{0} {1} of beer,",n,bottles(n));
Console.WriteLine("Take one down, and pass it around,");
Console.WriteLine("{0} {1} of beer on the wall.",n-1,bottles(n-1));
Console.WriteLine();
end;
Console.ReadKey();
end;
end.
Oz
Constraint Programming
Note: In real life, you would never solve a simple iterative task like this with constraint programming. This is just for fun.
declare
%% describe the possible solutions of the beer 'puzzle'
proc {BeerDescription Solution}
N = {FD.int 1#99} %% N is an integer in [1, 99]
in
%% distribute starting with highest value
{FD.distribute generic(value:max) [N]}
Solution =
{Bottles N}#" of beer on the wall\n"#
{Bottles N}#" bottles of beer\n"#
"Take one down, pass it around\n"#
{Bottles N-1}#" of beer on the wall\n"
end
%% pluralization
proc {Bottles N Txt}
cond N = 1 then Txt ="1 bottle"
else Txt = N#" bottles"
end
end
in
%% show all solutions to the 'puzzle'
{ForAll {SearchAll BeerDescription}
System.showInfo}
Iterative
declare
fun {Bottles N}
if N == 1 then "1 bottle"
else N#" bottles"
end
end
in
for I in 99..1;~1 do
{System.showInfo
{Bottles I}#" of beer on the wall\n"#
{Bottles I}#" bottles of beer\n"#
"Take one down, pass it around\n"#
{Bottles I-1}#" of beer on the wall\n"}
end
PARI/GP
forstep(n=99,3,-1,
print(n" bottles of beer on the wall");
print(n" bottles of beer");
print("Take one down, pass it around");
print(n-1," bottles of beer on the wall\n")
);
print("2 bottles of beer on the wall\n2 bottles of beer\nTake one down, pass it around\n1 bottle of beer on the wall\n");
print("1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around\nNo more bottles of beer on the wall")
Pascal
Perl
#!/usr/bin/perl -w my $verse = <<"VERSE"; 100 bottles of beer on the wall, 100 bottles of beer! Take one down, pass it around! 99 bottles of beer on the wall! VERSE { $verse =~ s/(\d+)/$1-1/ge; $verse =~ s/\b1 bottles/1 bottle/g; my $done = $verse =~ s/\b0 bottle/No bottles/g; # if we make this replacement, we're also done. print $verse; redo unless $done; }
Alternatively:
for $n (reverse(0..99)) { $bottles = sprintf("%s bottle%s of beer on the wall\n",(($n==0)?"No":$n), (($n==1)?"":"s")); print( (($n==99)?"":"$bottles\n") . (($n==0)?"":(substr(${bottles}x2,0,-12) . "\nTake one down, pass it around\n")) ); }
Correct grammar and nice spacing in modern perl:
use 5.10.0; $num = 99; while ($num > 0) { my $s = "s" unless ($num == 1); say "$num bottle$s of beer on the wall, $num bottle$s of beer"; $num--; my $s = "s" unless ($num == 1); $num = "No more" if ($num == 0); say "Take one down, pass it around, $num bottle$s of beer on the wall\n" } say "No more bottles of beer on the wall, no more bottles of beer."; say "Go to the store and buy some more, 99 bottles of beer on the wall.";
Using Perl 5 as a DSL factory leveraging $_'s global nature:
#!/usr/bin/env perl use strict; use warnings; sub bottles() { sprintf qq{%s bottle%s of beer} , $_ || 'No' , $_==1 ? '' : 's'; } sub store() { $_=99; qq{Go to the store, buy some more...\n}; } sub wall() { qq{ on the wall\n} } sub take() { $_-- ? qq{Take one down, pass it around\n} : store } do { print bottles, wall , bottles, qq{\n} , take , bottles, qq{\n\n} } for reverse 0..99;
Perl 6
A Simple Way
my $b = 99;
repeat while --$b {
say "{b $b} on the wall";
say "{b $b}";
say "Take one down, pass it around";
say "{b $b-1} on the wall";
say "";
}
sub b($b) {
"$b bottle{'s' if $b != 1} of beer";
}
A Clearer Way
Similar to "A Simple Way", but with proper variable and subroutine naming, declarator documentation, strongly-typed function definition, better code reuse, and external ternary logic.
for 99...1 -> $bottles {
sing $bottles, :wall;
sing $bottles;
say "Take one down, pass it around";
sing $bottles - 1, :wall;
say "";
}
#| Prints a verse about a certain number of beers, possibly on a wall.
sub sing(
Int $number, #= Number of bottles of beer.
Bool :$wall, #= Mention that the beers are on a wall?
) {
my $quantity = $number == 0 ?? "No more" !! $number;
my $plural = $number == 1 ?? "" !! "s";
my $location = $wall ?? " on the wall" !! "";
say "$quantity bottle$plural of beer$location"
}
A More Extravagant Way
Works with Rakudo 2015.09.
my @quantities = flat (99 ... 1), 'No more', 99;
my @bottles = flat 'bottles' xx 98, 'bottle', 'bottles' xx 2;
my @actions = flat 'Take one down, pass it around' xx 99,
'Go to the store, buy some more';
for @quantities Z @bottles Z @actions Z
@quantities[1 .. *] Z @bottles[1 .. *]
-> ($a, $b, $c, $d, $e) {
say "$a $b of beer on the wall";
say "$a $b of beer";
say $c;
say "$d $e of beer on the wall\n";
}
Phix
constant ninetynine = 99 -- (set this to 9 for testing)
function bottles(integer count)
if count=0 then return "no more bottles "
elsif count=1 then return "1 bottle " end if
if count=-1 then count = ninetynine end if
return sprintf("%d bottles ",count)
end function
function bob(integer count)
return bottles(count)&"of beer"
end function
function up1(string bob)
-- Capitalise sentence start (needed just the once, "no more"=>"No more")
bob[1] = upper(bob[1])
return bob
end function
string this = bob(ninetynine)
string that = "Take one down, pass it around,\n"
for i=ninetynine to 0 by -1 do
puts(1,up1(this)&" on the wall,\n")
puts(1,this&".\n")
if i=0 then that = "Go to the store, buy some more,\n"
elsif i=1 then that[6..8] = "it" end if
this = bob(i-1)
puts(1,that&this&" on the wall.\n\n")
end for
if getc(0) then end if
PHL
Translated from C.
module bottles;
extern printf;
@Integer main [
@Integer bottles = 99;
do
{
printf("%u bottles of beer on the wall\n", bottles);
printf("%u bottles of beer\n", bottles);
printf("Take one down, pass it around\n");
bottles = bottles::dec;
printf("%u bottles of beer on the wall\n\n", bottles);
} while(bottles > 0);
return 0;
]
PHP
<?php $plural = 's'; foreach (range(99, 1) as $i) { echo "$i bottle$plural of beer on the wall,\n"; echo "$i bottle$plural of beer!\n"; echo "Take one down, pass it around!\n"; if ($i - 1 == 1) $plural = ''; if ($i > 1) echo ($i - 1) . " bottle$plural of beer on the wall!\n\n"; else echo "No more bottles of beer on the wall!\n"; } ?>
Shorter way
<?php foreach(range(99,1) as $i) { $p = ($i>1)?"s":""; echo <<< EOV $i bottle$p of beer on the wall $i bottle$p of beer Take one down, pass it around EOV; } echo "No more Bottles of beer on the wall"; ?>
Modifing way
<?php $verse = <<<VERSE 100 bottles of beer on the wall, 100 bottles of beer! Take one down, pass it around! 99 bottles of beer on the wall! VERSE; foreach (range(1,99) as $i) { // loop 99 times $verse = preg_replace('/\d+/e', '$0 - 1', $verse); $verse = preg_replace('/\b1 bottles/', '1 bottle', $verse); $verse = preg_replace('/\b0 bottle/', 'No bottles', $verse); echo $verse; } ?>
Ultra compact alternative
supports grammar and has no leading and trailing new lines or spaces. Also one does not have to close the <?php tag, it is even recommended not to close it, if closing it is not necessary
<?php for($i=100;$i>0;$i--){ $p2=$i." bottle".(($i>1)?"s":"")." of beer"; $p1=$p2." on the wall\n"; $p3="Take one down, pass it around\n"; echo (($i<100)?$p1."\n":"").$p1.$p2."\n".$p3.(($i<2)?($i-1).substr($p1,1,28):""); }
Gettext alternative
Supports grammar and translations.
<?php $bottles = 99; while ($bottles > 0) { printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer on the wall\n", $bottles); //X bottles of beer on the wall printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer\n", $bottles); //X bottles of beer printf("Take one down, pass it around\n"); //Take one down, pass it around $bottles--; if ($bottles > 0) { printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer on the wall\n\n", $bottles); //X bottles of beer on the wall } } printf('No more bottles of beer on the wall'); //No more bottles of beer on the wall
Using printf
Fun with HEREDOC and printf placeholders
<?php $lyrics = <<<ENDVERSE %2\$d bottle%1\$s of beer on the wall %2\$d bottle%1\$s of beer Take one down, pass it around %4\$s bottle%3\$s of beer on the wall ENDVERSE; $x = 99; while ( $x > 0 ) { printf( $lyrics, $x != 1 ? 's' : '', $x--, $x != 1 ? 's' : '', $x > 0 ? $x : 'No more' ); }
Output:
99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall
98 bottles of beer on the wall
98 bottles of beer
Take one down, pass it around
97 bottles of beer on the wall
97 bottles of beer on the wall
97 bottles of beer
Take one down, pass it around
96 bottles of beer on the wall
96 bottles of beer on the wall
96 bottles of beer
Take one down, pass it around
95 bottles of beer on the wall
95 bottles of beer on the wall
95 bottles of beer
Take one down, pass it around
94 bottles of beer on the wall
<!-- yada -->
4 bottles of beer on the wall
4 bottles of beer
Take one down, pass it around
3 bottles of beer on the wall
3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No more bottles of beer on the wall
Picat
beer1(N) =>
Beer = N,
while (Beer > 0)
printf("%d bottles of beer on the wall,\n", Beer),
printf("%d bottles of beer.\n", Beer),
printf("Take one down, pass it around.\n"),
printf("%d bottles of beer.\n", Beer-1),
Beer := Beer -1
end,
print("0 more bottles of beer on the wall.\n"),
nl.
% With plurals.
beer2(B) = S =>
BS = B.to_string(),
BB = " bottle",
BT = BB,
if B > 1 then BB := BB ++ "s" end,
OB = " of beer",
NL = "\n",
BW = OB ++ " on the wall." ++ NL,
T = "Take one down, pass it around." ++ NL,
S1 = BS ++ BT ++ BW ++ BS ++ BT ++ OB ++ T ++
cond(B > 0, (B-1).to_string() ++ BT ++ BW ++ NL, ""),
S = S1.
Piet
See 99 Bottles of Beer/EsoLang
Pike
int main(){
for(int i = 99; i > 0; i--){
write(i + " bottles of beer on the wall, " + i + " bottles of beer.\n");
write("Take one down and pass it around, " + (i-1) + " bottles of beer on the wall.\n\n");
}
write("No more bottles of beer on the wall, no more bottles of beer.\n");
write("Go to the store and buy some more, 99 bottles of beer on the wall.\n");
}
alternate version:
// disclaimer: i prefer gingerale
void main()
{
array numbers = ({ "no more", "one", "two", "three", "four", "five", "six", "seven",
"eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen" });
array decades = ({ "twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty",
"ninety" });
foreach (decades;; string decade)
{
numbers += decade+(({ "" }) + numbers[1..9])[*];
}
numbers = reverse(numbers);
array bottles = ((numbers[*]+" bottles of ale on the wall, ")[*] +
(numbers[*]+" bottles of ale.\n")[*]);
bottles[-2] = replace(bottles[-2], "one bottles", "one bottle");
string song = bottles * "take one down, pass it around,\n";
write(song);
}
PIR
Works with Parrot|Tested with 2.4.0.
.sub sounding_smart_is_hard_after_drinking_this_many
.param int b
if b == 1 goto ONE
.return(" bottles ")
ONE:
.return(" bottle ")
end
.end
.sub main :main
.local int bottles
.local string b
bottles = 99
LUSH:
if bottles == 0 goto DRUNK
b = sounding_smart_is_hard_after_drinking_this_many( bottles )
print bottles
print b
print "of beer on the wall\n"
print bottles
print b
print "of beer\nTake one down, pass it around\n"
dec bottles
b = sounding_smart_is_hard_after_drinking_this_many( bottles )
print bottles
print b
print "of beer on the wall\n\n"
goto LUSH
DRUNK:
end
.end
PlainTeX
\def\ifbeer{\ifnum\number\bottles} \def\beers{ \par\ifbeer>0 \the\bottles~\else No more \fi bottle\ifbeer=1\else s\fi~of beer% } \def\take #1 down,{ \par\advance\bottles by -#1 Take #1 down, pass it around,\par } \long\def\verse{ \beers~on the wall, \beers. \take 1 down, % curious TeX \def syntax \beers~on the wall. \bigskip } \newcount\bottles\bottles99 \loop\verse \ifnum\number\bottles>0\repeat \bye
Pop11
define bootles(n);
while n > 0 do
printf(n, '%p bottles of beer on the wall\n');
printf(n, '%p bottles of beer\n');
printf('Take one down, pass it around\n');
n - 1 -> n;
printf(n, '%p bottles of beer on the wall\n');
endwhile;
enddefine;
bootles(99);
PostScript
%!PS
/Helvetica findfont 9 scalefont setfont
/printBeer {
dup
20 string cvs show
( bottle) show
1 ne
{ (s) show } if
( of beer) show
} def
/printVerse {
dup
dup
dup
7 mul
50 add
/yPos exch def
15 yPos moveto
printBeer
( on the wall, ) show
printBeer
(. ) show
(Take one down, pass it around, ) show
1 sub
printBeer
( on the wall. ) show
} def
/song {
100 -1 1 { printVerse } for
} def
song
showpage
%%EOF
PowerShell
Processing
Simple approach
for (int i = 99; i > 0; i--) {
print(i + " bottles of beer on the wall\n" + i + " bottles of beer\nTake one down, pass it around\n" + (i - 1) + " bottles of beer on the wall\n\n");
}
ProDOS
Prolog
Python
===Python 3, a readable version=== Most people solving this task iterate from 99 to 0. But 2, 1 and 0 are special cases, therefore they write conditional expressions to split flow control. Anyway the "if" instruction is unnecessary at all. The special cases could be excluded as separate block outside loop. A "busisness logic" to write bottle/bottles (and to recognize that 0 bottles should be "no more") would be not so simple to code. Therefore a copy-paste of the last three verses of the song is much more KISS. It is enough to focus on the first 97 verses to achieve essential savings.
"""Pythonic 99 beer song (readability counts).""" regular_verse = '''\ {n} bottles of beer on the wall, {n} bottles of beer Take one down and pass it around, {n_minus_1} bottles of beer on the wall. ''' ending_verses = '''\ 2 bottles of beer on the wall, 2 bottles of beer. Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take one down and pass it around, no more bottles of beer on the wall. No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall. ''' # @todo: It is possible to refactor the code to avoid n-1 in the code, # notice that the last line of any verse and the first line of the next # verse share the same number of bottles. Nevertheless the code # would be less readliable. for n in range(99, 2, -1): print(regular_verse.format(n=n, n_minus_1=n - 1)) print(ending_verses)
=== Python 3, solution without unnecessary subtraction===
"""Pythonic 99 beer song (readability counts).""" first = '''\ 99 bottles of beer on the wall, 99 bottles of beer ''' middle = '''\ Take one down and pass it around, {n} bottles of beer on the wall. {n} bottles of beer on the wall, {n} bottles of beer ''' last = '''\ Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take one down and pass it around, no more bottles of beer on the wall. No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall. ''' print(first) for n in range(98, 1, -1): print(middle.format(n=n)) print(last)
===Python 3 (dys)Functional=== Translated from Haskell. Works with Python|3.7.
'''99 Units of Disposable Asset''' from itertools import chain # main :: IO () def main(): '''Modalised asset dispersal procedure.''' # localisation :: (String, String, String) localisation = ( 'on the wall', 'Take one down, pass it around', 'Better go to the store to buy some more' ) print(unlines(map( incantation(localisation), enumFromThenTo(99)(98)(0) ))) # incantation :: (String, String, String) -> Int -> String def incantation(localisation): '''Versification of asset disposal and inventory update.''' location, distribution, solution = localisation def inventory(n): return unwords([asset(n), location]) return lambda n: solution if 0 == n else ( unlines([ inventory(n), asset(n), distribution, inventory(pred(n)) ]) ) # asset :: Int -> String def asset(n): '''Quantified asset.''' def suffix(n): return [] if 1 == n else 's' return unwords([ str(n), concat(reversed(concat(cons(suffix(n))(["elttob"])))) ]) # GENERIC ------------------------------------------------- # concat :: [[a]] -> [a] # concat :: [String] -> String def concat(xxs): '''The concatenation of all the elements in a list.''' xs = list(chain.from_iterable(xxs)) unit = '' if isinstance(xs, str) else [] return unit if not xs else ( ''.join(xs) if isinstance(xs[0], str) else xs ) # cons :: a -> [a] -> [a] def cons(x): '''Construction of a list from x as head, and xs as tail.''' return lambda xs: [x] + xs if ( isinstance(xs, list) ) else chain([x], xs) # enumFromThenTo :: Int -> Int -> Int -> [Int] def enumFromThenTo(m): '''Integer values enumerated from m to n with a step defined by nxt-m.''' def go(nxt, n): d = nxt - m return list(range(m, d + n, d)) return lambda nxt: lambda n: ( go(nxt, n) ) # pred :: Enum a => a -> a def pred(x): '''The predecessor of a value. For numeric types, (- 1).''' return x - 1 if isinstance(x, int) else ( chr(ord(x) - 1) ) # unlines :: [String] -> String def unlines(xs): '''A single string derived by the intercalation of a list of strings with the newline character.''' return '\n'.join(xs) # unwords :: [String] -> String def unwords(xs): '''A space-separated string derived from a list of words.''' return ' '.join(xs) if __name__ == '__main__': main()
===Python 3, functional pythonic version=== Inspired by the "(dys)Functional" version but follows Python's best practices. Main function accepts a number of parameters, so you can specify a name of the drink, its container and other things as can be seen in the example output.
"""99 Bottles of Beer on the Wall made functional""" from functools import partial from typing import Callable def regular_plural(noun: str) -> str: """Regular rule to get the plural form of a word""" return noun + "s" def beer_song(*, location: str = 'on the wall', distribution: str = 'Take one down, pass it around', solution: str = 'Better go to the store to buy some more!', container: str = 'bottle', plurifier: Callable[[str], str] = regular_plural, liquid: str = "beer", initial_count: int = 99) -> None: """ Displays the lyrics of the beer song :param location: initial location of the drink :param distribution: specifies the process of its distribution :param solution: what happens when we run out of drinks :param container: bottle/barrel/flask or other containers :param plurifier: function converting a word to its plural form :param liquid: the name of the drink in the given container :param initial_count: how many containers available initially """ verse = partial(get_verse, location=location, distribution=distribution, solution=solution, container=container, plurifier=plurifier, liquid=liquid) verses = map(verse, range(initial_count, -1, -1)) print(*verses, sep='\n\n') def get_verse(count: int, *, location: str, distribution: str, solution: str, container: str, plurifier: Callable[[str], str], liquid: str) -> str: """Returns the verse for the given initial amount of drinks""" inventory = partial(get_inventory, location=location) asset = partial(get_asset, container=container, plurifier=plurifier, liquid=liquid) initial_asset = asset(count) final_asset = asset(count - 1) standard_verse = '\n'.join([inventory(initial_asset), initial_asset, distribution, inventory(final_asset)]) return solution if count == 0 else standard_verse def get_inventory(asset: str, *, location: str) -> str: """ Used to return the first or the fourth line of the verse >>> get_inventory("10 bottles of beer", location="on the wall") "10 bottles of beer on the wall" """ return ' '.join([asset, location]) def get_asset(count: int, *, container: str, plurifier: Callable[[str], str], liquid: str) -> str: """ Quantified asset >>> get_asset(0, container="jar", plurifier=regular_plural, liquid='milk') "No more jars of milk" """ containers = container if count == 1 else plurifier(container) spelled_out_quantity = "No more" if count == 0 else str(count) return ' '.join([spelled_out_quantity, containers, "of", liquid]) if __name__ == '__main__': beer_song()
Output:
>>> beer_song(liquid='milk',
location='in the fridge',
container='jug',
distribution='Take one out, pass it around',
initial_count=2)
2 jugs of milk in the fridge
2 jugs of milk
Take one out, pass it around
1 jug of milk in the fridge
1 jug of milk in the fridge
1 jug of milk
Take one out, pass it around
No more jugs of milk in the fridge
Better go to the store to buy some more!
Other solutions
See [[99 Bottles of Beer/Python]]
Q
bobw:{[n] {x," bottles of beer on the wall\n",x," bottles of beer\nTake one down, pass it around\n",y," bottles of beer on the wall\n\n"} . string (n;n-1)}
-1 bobw each reverse 1 + til 99
QB64
SCREEN _NEWIMAGE(800, 600, 32)
CONST BottleSpeed = 3
PLAY "<"
MakeBottle
ScaleImage bottle&, .5, .5
t1 = _FREETIMER
ON TIMER(t1, 0.01) DrawBottle
TIMER(t1) ON
FOR x = 99 TO 1 STEP -1
CLS
LOCATE , 35: PRINT x; "bottles of beer on the wall"
: PLAY "e-8e-8e-8<b-8b-8b-8>e-8e-8e-8e-4"
LOCATE , 35: PRINT x; "bottles of beer"
PLAY "f8f8f8c8c8c8f4"
LOCATE , 35: PRINT " Take one down, pass it around"
PLAY "d4d8d8 d8d8d8d4"
LOCATE , 35: PRINT x - 1; "bottles of beer on the wall"
PLAY "<a+8a+8a+8>c8c8d8d+8d+8d+8d+4"
IF INKEY$ <> "" THEN SYSTEM
NEXT x
CLS
LOCATE , 35: PRINT "Da fatman drunk all da beer on the wall!"
PLAY "e-8e-8e-8<b-8b-8b-8>e-8e-8e-8e-4"
LOCATE , 35: PRINT "Da fatman drunk it all!"
PLAY "f8f8f8c8c8c8f4"
LOCATE , 35: PRINT "Cuss da fatman, send him for more!"
PLAY "d4d8d8 d8d8d8d4"
LOCATE , 35: PRINT "Someone show him the way out the door!"
PLAY "<a+8a+8a+8>c8c8d8d+8d+8d+8d+4"
SUB MakeBottle
SHARED bottle&
bottle& = _NEWIMAGE(56, 144, 32)
_DEST bottle&
LOCATE 1, 1: PRINT " [=]";
LOCATE 2, 1: PRINT " | |";
LOCATE 3, 1: PRINT " }@{";
LOCATE 4, 1: PRINT " / \";
LOCATE 5, 1: PRINT ":_____;";
LOCATE 6, 1: PRINT "|&&&&&|";
LOCATE 7, 1: PRINT "|&&&&&|";
LOCATE 8, 1: PRINT "|-----|";
LOCATE 9, 1: PRINT "'-----'";
_DEST 0
END SUB
SUB ScaleImage (Image AS LONG, xscale AS SINGLE, yscale AS SINGLE)
w = _WIDTH(Image): h = _HEIGHT(Image)
w2 = w * xscale: h2 = h * yscale
NewImage& = _NEWIMAGE(w2, h2, 32)
_PUTIMAGE , Image&, NewImage&
_FREEIMAGE Image&
Image& = NewImage&
END SUB
SUB DrawBottle
SHARED x
SHARED bottle&
STATIC angle
LINE (0, 150)-(800, 600), _RGB32(0, 0, 0), BF
angle = angle + BottleSpeed
FOR i = 1 TO 20
FOR h = 1 TO 5
IF (h - 1) * 20 + (i - 1) < x THEN DisplayImage bottle&, i * 40 - 20, h * 75 + 150, angle, 0
NEXT
NEXT
_DISPLAY
END SUB
SUB DisplayImage (Image AS LONG, x AS INTEGER, y AS INTEGER, angle AS SINGLE, mode AS _BYTE)
'Image is the image handle which we use to reference our image.
'x,y is the X/Y coordinates where we want the image to be at on the screen.
'angle is the angle which we wish to rotate the image.
'mode determines HOW we place the image at point X,Y.
'Mode 0 we center the image at point X,Y
'Mode 1 we place the Top Left corner of oour image at point X,Y
'Mode 2 is Bottom Left
'Mode 3 is Top Right
'Mode 4 is Bottom Right
DIM px(3) AS INTEGER, py(3) AS INTEGER, w AS INTEGER, h AS INTEGER
DIM sinr AS SINGLE, cosr AS SINGLE, i AS _BYTE
w = _WIDTH(Image): h = _HEIGHT(Image)
SELECT CASE mode
CASE 0 'center
px(0) = -w \ 2: py(0) = -h \ 2: px(3) = w \ 2: py(3) = -h \ 2
px(1) = -w \ 2: py(1) = h \ 2: px(2) = w \ 2: py(2) = h \ 2
CASE 1 'top left
px(0) = 0: py(0) = 0: px(3) = w: py(3) = 0
px(1) = 0: py(1) = h: px(2) = w: py(2) = h
CASE 2 'bottom left
px(0) = 0: py(0) = -h: px(3) = w: py(3) = -h
px(1) = 0: py(1) = 0: px(2) = w: py(2) = 0
CASE 3 'top right
px(0) = -w: py(0) = 0: px(3) = 0: py(3) = 0
px(1) = -w: py(1) = h: px(2) = 0: py(2) = h
CASE 4 'bottom right
px(0) = -w: py(0) = -h: px(3) = 0: py(3) = -h
px(1) = -w: py(1) = 0: px(2) = 0: py(2) = 0
END SELECT
sinr = SIN(angle / 57.2957795131): cosr = COS(angle / 57.2957795131)
FOR i = 0 TO 3
x2 = (px(i) * cosr + sinr * py(i)) + x: y2 = (py(i) * cosr - px(i) * sinr) + y
px(i) = x2: py(i) = y2
NEXT
_MAPTRIANGLE (0, 0)-(0, h - 1)-(w - 1, h - 1), Image TO(px(0), py(0))-(px(1), py(1))-(px(2), py(2))
_MAPTRIANGLE (0, 0)-(w - 1, 0)-(w - 1, h - 1), Image TO(px(0), py(0))-(px(3), py(3))-(px(2), py(2))
END SUB
Qore
Simple Solution
#!/usr/bin/env qore
%enable-all-warnings
for (my $i = 99; $i > 0; $i--) {
printf("%d bottles of beer on the wall\n", $i);
printf("%d bottles of beer\n", $i);
printf("take one down, pass it around\n");
printf("%d bottles of beer on the wall\n", $i);
}
===Concurrent (Unordered) Solution===
#!/usr/bin/env qore
%enable-all-warnings
%require-types
# global variables (truly shared among threads) must be declared with "our" keyword
%require-our
our Counter $count();
sub t() {
on_exit {
$count.dec();
}
my int $i = gettid()-1;
printf("%d bottles of beer on the wall\n", $i);
printf("%d bottles of beer\n", $i);
printf("take one down, pass it around\n");
printf("%d bottles of beer on the wall\n", $i);
}
#-- following run by main thread
for (my int $i = 99; $i > 0; $i--) {
$count.inc();
background t();
}
$count.waitForZero();
Quill
bottles := void(int count) {
(count > 0) if {
new_count := count - 1;
(
count, " bottles of beer on the wall", nl,
count, " bottles of beer", nl,
"Take one down, pass it around", nl,
new_count, " bottles of beer on the wall"
) print;
new_count bottles
} else {
"No more bottles of beer on the wall!" print
}
};
99 bottles
R
Simple looping solution
#a naive function to sing for N bottles of beer...
song = function(bottles){
for(i in bottles:1){ #for every integer bottles, bottles-1 ... 1
cat(bottles," bottles of beer on the wall \n",bottles," bottles of beer \nTake one down, pass it around \n",
bottles-1, " bottles of beer on the wall \n"," \n" ,sep="") #join and print the text (\n means new line)
bottles = bottles - 1 #take one down...
}
}
song(99)#play the song by calling the function
Vector solutions
#only one line!
cat(paste(99:1,ifelse((99:1)!=1," bottles"," bottle")," of beer on the wall\n",99:1,ifelse((99:1)!=1," bottles"," bottle")," of beer\n","Take one down, pass it around\n",98:0,ifelse((98:0)!=1," bottles"," bottle")," of beer on the wall\n\n",sep=""),sep="")
#alternative
cat(paste(lapply(99:1,function(i){paste(paste(rep(paste(i,' bottle',if(i!=1)'s',' of beer',sep=''),2),collapse =' on the wall\n'),'Take one down, pass it around',paste(i-1,' bottle',if(i!=2)'s',' of beer on the wall',sep=''), sep='\n')}),collapse='\n\n'))
Ra
class BottlesOfBeer
**Prints the "99 Bottles of Beer" song"**
on start
args := program arguments
# If no arguments given, print the song once
if args empty
.printSong
# Otherwise, print the song the given number of times
else
.printSong(integer.parse(args[0]))
shared
define printSong(times := 1)
**Print the song the given number of times**
for times, _printSong
define _printSong
**Print the song**
# Print for bottles 99 to 1
for bottle in 99 to 0 by -1
print "[_bottles(bottle)] of beer on the wall
[_bottles(bottle)] of beer
Take one down, pass it around
[_bottles(bottle - 1)] of beer on the wall
"
print "No more bottles of beer on the wall
No more bottles of beer
Go to the store, buy some more
99 bottles of beer on the wall"
define _bottles(bottle as integer) as String
**
If bottle is 0, returns "No more bottles"
If bottle is 1, returns "1 bottle"
Otherwise, returns "[bottle] bottles"
**
if bottle = 0, return "No more bottles"
if bottle = 1, return "1 bottle"
return "[bottle] bottles"
Racket
#lang racket
(define (sing bottles)
(define (plural n) (~a n " bottle" (if (= n 1) "" "s")))
(printf "~a of beer on the wall\n~a of beer\n~
Take one down, pass it around\n~a of beer on the wall\n\n"
(plural bottles) (plural bottles) (plural (sub1 bottles)))
(unless (= 1 bottles) (sing (sub1 bottles))))
(sing 99)
RapidQ
dim nBott as integer
nBott = 99
While nBott > 0
Print(str$(nBott ) + " bottle" + iif(nBott=1, "", "s") + " of beer on the wall")
Print(str$(nBott ) + " bottle" + iif(nBott=1, "", "s") + " of beer")
Print("Take one down, pass it around")
nBott--
Print(str$(nBott ) + " bottle" + iif(nBott=1, "", "s") + " of beer on the wall" + chr$(10))
Wend
while inkey$="":wend
end
Rascal
module demo::basic::Bottles
import IO;
str bottles(0) = "no more bottles";
str bottles(1) = "1 bottle";
default str bottles(int n) = "<n> bottles";
public void sing(){
for(n <- [99 .. 1]){
println("<bottles(n)> of beer on the wall, <bottles(n)> of beer.");
println("Take one down, pass it around, <bottles(n-1)> of beer on the wall.\n");
}
println("No more bottles of beer on the wall, no more bottles of beer.");
println("Go to the store and buy some more, 99 bottles of beer on the wall.");
}
Raven
99 0 1 range each as $i
$i 1 = if
"bottle" as $b
else
"bottles" format as $b
$b $i "%d %s of beer on the wall,\n" print
$b $i "%d %s of beer,\n" print
"Take one down, pass it around,\n" print
$i 2 = if
"1 bottle"
else
$i 1 - "%d bottles" format
"%s of beer on the wall.\n\n" print
Output: Last couple of stanzas are:
3 bottles of beer on the wall,
3 bottles of beer,
Take one down, pass it around,
2 bottles of beer on the wall.
2 bottles of beer on the wall,
2 bottles of beer,
Take one down, pass it around,
1 bottle of beer on the wall.
1 bottle of beer on the wall,
1 bottle of beer,
Take one down, pass it around,
0 bottles of beer on the wall.
REBOL
rebol [
Title: "99 Bottles of Beer"
URL: http://rosettacode.org/wiki/99_Bottles_of_Beer
]
; The 'bottles' function maintains correct grammar.
bottles: func [n /local b][
b: either 1 = n ["bottle"]["bottles"]
if 0 = n [n: "no"]
reform [n b]
]
for n 99 1 -1 [print [
bottles n "of beer on the wall" crlf
bottles n "of beer" crlf
"Take one down, pass it around" crlf
bottles n - 1 "of beer on the wall" crlf
]]
Output ''(selected highlights)'':
99 bottles of beer on the wall 2 bottles of beer on the wall
99 bottles of beer 2 bottles of beer
Take one down, pass it around Take one down, pass it around
98 bottles of beer on the wall 1 bottle of beer on the wall
...Continues... 1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
no bottles of beer on the wall
This one prints with proper grammar. "Bottles" changed to "bottle" at the end of the 2 line, and throughout the 1 line. 0 changed to "No" in the last line:
for i 99 1 -1 [
x: rejoin [
i b: " bottles of beer" o: " on the wall. " i b
". Take one down, pass it around. " (i - 1) b o "^/"
]
r: :replace j: "bottles" k: "bottle"
switch i [1 [r x j k r at x 10 j k r x "0" "No"] 2 [r at x 40 j k]]
print x
] halt
Here's a simple 1 line console version:
for i 99 1 -1[print rejoin[i b:" bottles of beer"o:" on the wall. "i b". Take one down, pass it around. "(i - 1)b o"^/"]]
Red
Red [
Title: "99 Bottles of Beer"
Original-Author: oofoe
]
; The 'bottles' function maintains correct grammar.
bottles: function [n] [
b: either 1 = n ["bottle"]["bottles"]
if 0 = n [n: "no"]
form reduce [n b]
]
repeat x 99 [
n: 100 - x
print [
bottles n "of beer on the wall" crlf
bottles n "of beer" crlf
"Take one down, pass it around" crlf
bottles n - 1 "of beer on the wall" crlf
]]
Retro
This is based on the [[Forth]] example.
# 99 Bottles
Display the text for the *99 Bottles of Beer* song.
~~~
{ 'bottle 'bottles 'of 'beer 'on 'the 'wall 'no 'more
'Take 'one 'down, 'pass 'it 'around }
[ dup ':%s_'%s_s:put_sp_; s:format s:evaluate ] a:for-each
{ [ no more bottles ]
[ #1 n:put sp bottle ]
[ dup n:put sp bottles ]
} 'BOTTLES const
:number-bottles
dup #2 n:min BOTTLES swap a:fetch call ;
:display-verse
number-bottles of beer on the wall nl
number-bottles of beer nl
n:dec Take one down, pass it around nl
number-bottles of beer on the wall nl ;
:verses (n-)
repeat 0; nl display-verse again ;
#99 verses
~~~
REXX
Complete with a PSA (Public Service Announcement) comment.
/*REXX program displays lyrics to the infamous song "99 Bottles of Beer on the Wall". */
parse arg N .; if N=='' | N=="," then N=99 /*allow number of bottles be specified.*/
/* [↓] downward count of beer bottles.*/
do #=N by -1 for N /*start the countdown and singdown. */
say # 'bottle's(#) "of beer on the wall," /*sing the number bottles of beer. */
say # 'bottle's(#) "of beer." /* ··· and also the song's refrain.*/
say 'Take one down, pass it around,' /*take a beer bottle ─── and share it.*/
m= # - 1 /*M: the number of bottles we have now*/
if m==0 then m= 'no' /*use word "no" instead of numeric 0.*/
say m 'bottle's(m) "of beer on the wall." /*sing the beer bottle inventory. */
say /*show a blank line between the verses.*/
end /*#*/ /*PSA: Please drink responsibly. */
/*Not quite tanked? Then sing it. */
say 'No more bottles of beer on the wall,' /*Finally! The last verse. */
say 'no more bottles of beer.' /*this is sooooooo sad and forlorn ··· */
say 'Go to the store and buy some more,' /*obtain replenishment of the beer. */
say N 'bottles of beer on the wall.' /*all is well in the ole town tavern. */
exit /*we're all done, and also sloshed !. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
s: if arg(1)=1 then return ''; return 's' /*simple pluralizer for gooder English.*/
{{out|output|text= Below is the first and last three verses of the song:}}
99 bottles of beer on the wall,
99 bottles of beer.
Take one down, pass it around,
98 bottles of beer on the wall.
98 bottles of beer on the wall,
98 bottles of beer.
Take one down, pass it around,
97 bottles of beer on the wall.
97 bottles of beer on the wall,
97 bottles of beer.
Take one down, pass it around,
96 bottles of beer on the wall.
∙
∙
∙
2 bottles of beer on the wall,
2 bottles of beer.
Take one down, pass it around,
1 bottle of beer on the wall.
1 bottle of beer on the wall,
1 bottle of beer.
Take one down, pass it around,
no bottles of beer on the wall.
No more bottles of beer on the wall,
no more bottles of beer.
Go to the store and buy some more,
99 bottles of beer on the wall.
Ring
This is a simple solution
for i = 99 to 0 step -1
switch i
on 0
see "No more bottles of beer on the wall,
no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall."
on 1
see "1 bottle of beer on the wall,
1 bottle of beer.
Take one down and pass it around,
No more bottles of beer on the wall.
"
other
see string(i) + " bottles of beer on the wall,
" + string(i) + " bottles of beer.
Take one down and pass it around,
" + string(i-1) + " bottles of beer on the wall.
"
off
next
Output:
99 bottles of beer on the wall,
99 bottles of beer.
Take one down, pass it around,
98 bottles of beer on the wall.
∙
∙
∙
1 bottle of beer on the wall,
1 bottle of beer.
Take one down, pass it around,
no bottles of beer on the wall.
No more bottles of beer on the wall,
no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall.
Rockstar
Rockstar solution without special cases for the last 2 verses.
Love is " bottles of beer on the wall"
Problems are " bottles of beer"
Carol says Take one down, pass it around
The beers were numbering fa'too'many
While the beers ain't nothing
Shout it with Love
Shout it with Problems
Say Carol,
Knock the beers down
Say it with Love
RPG
Works with RPGIII|.
H/TITLE 99 Bottles of Beer on the Wall - RPGIII (IBM System/38)
F********************************************************************
F*
F* Lines with an asterisk in column 7 (such as this one) are comments.
F*
F* The character in column 6 specifies the form type. Before the first
F* use of each form type is a comment with the template for the form.
F*
F********************************************************************
F* File Description Specifications
F*
F* Specify a default printer file for output, program described,
F* 132 columns wide, and an overflow indicator OV. The overflow
F* indicator is turned on when data is output to the last usable
F* line (line 60, for the default printer file QSYSPRT).
F*
F*ilenameIPEAF....RlenLK1AIOvKlocEDevice+......KExit++Entry+A....U1
FQSYSPRT O F 132 OV PRINTER
F*
C********************************************************************
C* If there were an input file, the RPG cycle would automatically
C* execute the output lines; since there is no input file, output
C* lines are produced as "exception" output with the EXCPT opcode.
C*
C* Calculation Specifications
C* vvvvvvvvv-- conditionally executes lines if indicators are on/off
C*0N01N02N03Factor1+++OpcdeFactor2+++ResultLenDHHiLoEqComments+++++++
C*
C* Zero, then add 99 to a variable named #BOTLS, which is defined
C* as packed decimal, 3 positions, 0 decimal places.
C Z-ADD99 #BOTLS 30
C*
C* Do until #BOTLS = 0. Each loop produces one complete verse.
C #BOTLS DOUEQ0
C*
C* When the overflow indicator is turned on, start a new page.
C* The indicator is automatically turned on when the overflow
C* line is printed on, and it is automatically turned off
C* when the heading is printed.
C OV EXCPTNEWPAG
C*
C* Print exception lines with names "LYRIC1" and "LYRIC2".
C EXCPTLYRIC1
C EXCPTLYRIC2
C*
C* Subtract 1 from #BOTLS, and turn on indicator LR (Last Record)
C* if the result is equal to zero (Eq); if LR is on, the program
C* will terminate at the end of the current cycle.
C SUB 1 #BOTLS LR
C*
C* Compare #BOTLS to 1, and turn on indicator 01 if equal.
C #BOTLS COMP 1 01
C*
C* Print exception lines with name "LYRIC1".
C EXCPTLYRIC1
C*
C* If LR is not on, print exception lines with name "SKIPLN"
C* (which, in this case, will produce a blank line between verses).
C NLR EXCPTSKIPLN
C*
C END end do
C*
O********************************************************************
O* Output Specifications
O* .-- E means "Exception" ("H" Header, "D" Detail, "T" Total)
O* v vv-- before printing, skip to line # 1 (of the next page)
O*ame++++DFBASbSaN01N02N03Excnam...........................................
OQSYSPRT E 1 NEWPAG
O* v-- space 1 line after printing
O E 1 LYRIC1
O*
O* .........-- conditionally print lines if indicators on/off
O* vvvvvvvvv v-- edit code Z (suppress leading Zeroes)
O*...............N01N02N03Field+YBEnd+PConstant/editword+++++++++
O #BOTLSZ 3
O N01NLR 11 'bottles'
O N01NLR 31 'of beer on the wall'
O 01NLR 10 'bottle'
O 01NLR 30 'of beer on the wall'
O LR 16 'No more bottles'
O LR 36 'of beer on the wall'
O E 1 LYRIC2
O #BOTLSZ 3
O N01 19 'bottles of beer'
O 01 18 'bottle of beer'
O E 1 LYRIC2
O 14 'Take one down'
O E 1 LYRIC2
O 15 'Pass it around'
O E 1 SKIPLN
RPL/2
Simple solution
BEER
<<
99 do
dup ->str PLURAL " on the wall," + disp
dup ->str PLURAL "." + disp
"Take one down, pass it around," disp
1 -
if dup then
dup ->str
else
"No more"
end
PLURAL " on the wall." + disp
"" disp
until dup 0 == end
drop
>>
PLURAL
<<
" bottle" + over if 1 <> then "s" + end " of beer" +
>>
Recursive and multithreaded solution
BOTTLES
<<
// Child process is started.
100 'RECURSIVE' detach
-> PROC
<<
do PROC recv until end drop2
do
// Parent waits for datas sent by child.
do PROC recv until end
list-> drop dup " on the wall," + disp "." + disp
"Take one down, pass it around," disp
if dup 1 same not then
do PROC recv until end list-> drop
else
1 "No more bottles of beer"
end
" on the wall." + disp drop "" disp
until
1 same
end
// Parent waits for Child's death.
PROC wfproc
>>
>>
RECURSIVE
<<
while
dup
repeat
1 - dup dup ->str
if over 1 > then " bottles " else " bottle " end +
"of beer" + 2 ->list dup
// Child send datas to parent process.
send send
// Recursive function is caught.
RECURSIVE
end
>>
Ruby
plural = 's' 99.downto(1) do |i| puts "#{i} bottle#{plural} of beer on the wall," puts "#{i} bottle#{plural} of beer" puts "Take one down, pass it around!" plural = '' if i - 1 == 1 if i > 1 puts "#{i-1} bottle#{plural} of beer on the wall!" puts else puts "No more bottles of beer on the wall!" end end
Ruby has variable traces, so we can do
trace_var :$bottle_num do |val| $bottles = %Q{#{val == 0 ? 'No more' : val.to_s} bottle#{val == 1 ? '' : 's'}} end ($bottle_num = 99).times do puts "#{$bottles} of beer on the wall" puts "#{$bottles} of beer" puts "Take one down, pass it around" $bottle_num -= 1 puts "#{$bottles} of beer on the wall" puts "" end
or...
def bottles(of_beer, ending) puts "#{of_beer} bottle#{ending} of beer on the wall," puts "#{of_beer} bottle#{ending} of beer" puts "Take one down, pass it around!" end 99.downto(0) do |left| if left > 1 bottles(left, "s") elsif left == 1 bottles(left, "") else puts "No more bottles of beer on the wall!" end end
or...
def bottles(beer, wall = false) "#{beer>0 ? beer : "no more"} bottle#{"s" if beer!=1} of beer#{" on the wall" if wall}" end 99.downto(0) do |remaining| puts "#{bottles(remaining,true).capitalize}, #{bottles(remaining)}." if remaining==0 print "Go to the store and buy some more" remaining=100 else print "Take one down, pass it around" end puts ", #{bottles(remaining-1,true)}.\n\n" end
Simple solution
99.downto(1) do |bottles| puts "#{bottles} bottle#{"s" if bottles != 1} of beer on the wall.", "#{bottles} bottle#{"s" if bottles != 1} of beer.", "Take one down, pass it around.", "#{bottles - 1} bottle#{"s" if bottles - 1 != 1} of beer on the wall.\n\n" end
Rust
Simple Solution
fn main() { for n in (0..100).rev() { match n { 0 => { println!("No more bottles of beer on the wall, no more bottles of beer."); println!("Go to the store and buy some more, 99 bottles of beer on the wall."); }, 1 => { println!("1 bottle of beer on the wall, 1 bottle of beer."); println!("Take one down and pass it around, no more bottles of beer on the wall.\n"); }, _ => { println!("{0:?} bottles of beer on the wall, {0:?} bottles of beer.", n); println!("Take one down and pass it around, {} bottles of beer on the wall.\n", n-1); }, } } }
Using a trait and impl
trait Bottles { fn bottles_of_beer(&self) -> Self; fn on_the_wall(&self); } impl Bottles for u32 { fn bottles_of_beer(&self) -> u32 { match *self { 0 => print!("No bottles of beer"), 1 => print!("{} bottle of beer", self), _ => print!("{} bottles of beer", self) } *self // return a number for chaining } fn on_the_wall(&self) { println!(" on the wall!"); } } fn main() { for i in (1..100).rev() { i.bottles_of_beer().on_the_wall(); i.bottles_of_beer(); println!("\nTake one down, pass it around..."); (i - 1).bottles_of_beer().on_the_wall(); println!("-----------------------------------"); } }
Sather
class MAIN is
main is
s :STR;
p1 ::= "<##> bottle<#> of beer";
w ::= " on the wall";
t ::= "Take one down, pass it around\n";
loop i ::= 99.downto!(0);
if i /= 1 then s := "s" else s := ""; end;
#OUT + #FMT(p1 + w + "\n", i, "s");
#OUT + #FMT(p1 + "\n", i, "s");
if i > 0 then #OUT + t; end;
end;
end;
end;
S-BASIC
rem - print lyrics to "99 Bottles of Beer on the Wall"
$constant maxbottles = 99
function bottle_str(n = integer) = string
var b = string
if n = 1 then
b = " bottle"
else
b = " bottles"
end = b
procedure delay
var i = integer
for i = 1 to 500 do
rem - nothing
next
end
rem - begin main program
var n = integer
n = maxbottles
while n > 0 do
begin
print n; bottle_str(n); " of beer on the wall,";
print n; bottle_str(n); " of beer"
print "Take one down, and pass it around,";
n = n - 1
if (n = 0) then
print " No more bottles";
else
print n; bottle_str(n);
print " of beer on the wall"
print
delay
end
rem - finish up
print "No more bottles of beer on the wall, no more bottles of beer"
print "Go to the store and buy some more,";
print maxbottles; " bottles of beer on the wall"
end
Scala
See [[99 Bottles of Beer/Scala]]
Scheme
Works with Chicken Scheme.
(define (bottles x)
(format #t "~a bottles of beer on the wall~%" x)
(format #t "~a bottles of beer~%" x)
(format #t "Take one down, pass it around~%")
(format #t "~a bottles of beer on the wall~%" (- x 1))
(if (> (- x 1) 0)
(bottles (- x 1))))
Scheme
(define (sing)
(define (sing-to-x n)
(if (> n -1)
(begin
(display n)
(display "bottles of beer on the wall")
(newline)
(display "Take one down, pass it around")
(newline)
(sing-to-x (- n 1)))
(display "would you wanna me to sing it again?")))
(sing-to-x 99))
Scratch
See [[99 Bottles of Beer/VPL]]
sed
s/.*/99 bottles of beer on the wall/
h
: b
s/^0//
/^0/q
s/^1 bottles/1 bottle/
p
s/on.*//
p
s/.*/Take one down, pass it around/
p
g
/^.[1-9]/{
h
s/^.//
y/123456789/012345678/
x
s/^\(.\).*$/\1/
G
s/\n//
h
bb
}
y/0123456789/9012345678/
h
bb
Seed7
$ include "seed7_05.s7i";
const proc: main is func
local
var integer: number is 0;
begin
for number range 99 downto 2 do
write( number <& " bottles of beer on the wall, ");
writeln( number <& " bottles of beer.");
write( "Take one down and pass it around, ");
writeln( pred(number) <& " bottles of beer on the wall.");
writeln;
end for;
writeln("1 bottle of beer on the wall, 1 bottle of beer.");
writeln("Take one down and pass it around, no more bottles of beer on the wall.");
writeln;
writeln("No more bottles of beer on the wall, no more bottles of beer.");
writeln("Go to the store and buy some more, 99 bottles of beer on the wall.")
end func;
SequenceL
;
import <Utilities/Sequence.sl>;
main(args(2)) :=
join(phrase(reverse(0 ... 99)));
phrase(num) :=
let
action :=
"Take one down and pass it around" when num > 0
else
"Go to the store and buy some more";
in
describeCount(num, true) ++ " on the wall, " ++
describeCount(num, false) ++ ".\n" ++
action ++ ", " ++
describeCount(num - 1, false) ++ " on the wall.\n\n";
describeCount(num, capitalize) :=
let
count :=
intToString(num) when num > 0
else
intToString(99) when num < 0
else
("N" when capitalize else "n") ++ "o more";
plural := "s" when num /= 1 else "";
in
count ++ " bottle" ++ plural ++ " of beer";
Set lang
EOF
## Shiny
```shiny
for 99 i:99-a
s: if i > 1 's' end
if i > 0 and i < 99 switch
if i = 6 say "A six-pack on the wall!\n" break
if i = 24 say "A carton on the wall!\n" break
say "$i bottle$s of beer on the wall!\n"
ends
say "$i bottle$s of beer on the wall,"
say "$i bottle$s of beer!"
say "Take one down, pass it around!"
end
say "Aww...no more bottles of beer on the wall... it must be your shout :)"
Sidef
for i in (100 ^.. 0) { var bottles = "#{i == 0 ? 'No' : i} bottle#{i == 1 ? '' : 's'}" var sentence = "#{bottles} of beer on the wall" -> say if (i > 0) { say sentence.substr(0, bottles.length + 8) say "Take one down, pass it around\n" } }
'''Simpler:'''
for n in (100 ^.. 2) { say "#{n} bottles of beer on the wall, #{n} bottles of beer!" say "Take one down, pass it around, #{n - 1} bottle#{n > 2 ? 's' : ''} of beer on the wall.\n" } say "One bottle of beer on the wall, one bottle of beer!" say "Take one down, pass it around, no more bottles of beer on the wall."
Simula
COMMENT HTTP://99-BOTTLES-OF-BEER.NET ;
COMMENT AUTHOR: TIM GOODWIN ;
COMMENT DATE: 04/20/05 ;
BEGIN
PROCEDURE BOTTLES(N); INTEGER N;
BEGIN
IF N = 0 THEN OUTTEXT("NO MORE BOTTLES") ELSE
IF N = 1 THEN OUTTEXT("ONE BOTTLE") ELSE
BEGIN
OUTINT(N, 0);
OUTTEXT(" BOTTLES");
END;
OUTTEXT(" OF BEER");
END OF BOTTLES;
PROCEDURE BEER(N); INTEGER N;
BEGIN
WHILE N > 0 DO BEGIN
BOTTLES(N);
OUTTEXT(" ON THE WALL");
OUTIMAGE;
BOTTLES(N);
OUTIMAGE;
OUTTEXT( "TAKE ONE DOWN, PASS IT AROUND");
OUTIMAGE;
BOTTLES(N - 1);
OUTTEXT( " ON THE WALL");
OUTIMAGE;
OUTIMAGE;
N := N - 1;
END;
END OF BEER;
BEER(99);
END;
'''Simpler:'''
COMMENT http://99-bottles-of-beer.net
author: Jack Leunissen
date: 03/10/07;
BEGIN
INTEGER BOTTLES;
INTEGER NUM;
NUM := 2;
FOR BOTTLES := 99 STEP -1 UNTIL 1 DO
BEGIN
IF BOTTLES < 10 THEN
NUM := 1;
OUTINT(BOTTLES, NUM);
OUTTEXT(" BOTTLE(S) OF BEER ON THE WALL, ");
OUTINT(BOTTLES, NUM);
OUTTEXT(" BOTTLE(S) OF BEER");
OUTIMAGE;
OUTTEXT("TAKE ONE DOWN, PASS IT AROUND, ");
OUTINT(BOTTLES - 1, NUM);
OUTTEXT(" BOTTLE(S) OF BEER ON THE WALL.");
OUTIMAGE;
OUTIMAGE;
END;
OUTTEXT("1 BOTTLE OF BEER ON THE WALL, ONE BOTTLE OF BEER.");
OUTIMAGE;
OUTTEXT("TAKE ONE DOWN, PASS IT AROUND, ");
OUTTEXT("NO MORE BOTTLES OF BEER ON THE WALL.");
OUTIMAGE;
END;
SkookumScript
!bottles: (Integer num) [num.String += if num=1 [" bottle"] else [" bottles"]] 99.to 1 [ print( bottles(idx) " of beer on the wall\n" bottles(idx) " of beer\n" "Take one down, pass it around\n" bottles(idx-1) " of beer on the wall\n") ]
Slate
n@(Integer traits) bottleVerse
[| nprinted |
nprinted: n printString ; ' bottle' ; (n > 1 ifTrue: ['s'] ifFalse: ['']) ; ' of beer'.
inform: nprinted ; ' on the wall.'.
inform: nprinted.
inform: 'Take one down, pass it around.'.
inform: nprinted ; ' on the wall.'.
].
x@(Integer traits) bottles
[
x downTo: 0 do: #bottleVerse `er
].
99 bottles.
Smalltalk
A straightforward approach:
Smalltalk at: #sr put: 0 ; at: #s put: 0 !
sr := Dictionary new.
sr at: 0 put: ' bottle' ;
at: 1 put: ' bottles' ;
at: 2 put: ' of beer' ;
at: 3 put: ' on the wall' ;
at: 4 put: 'Take one down, pass it around' !
99 to: 0 by: -1 do: [:v | v print.
( v == 1 ) ifTrue: [ s := 0. ]
ifFalse: [ s := 1. ].
Transcript show: (sr at:s) ; show: (sr at:2) ; show: (sr at:3) ; cr.
v print.
Transcript show: (sr at:s) ; show: (sr at:2) ; cr.
(v ~~ 0) ifTrue: [ Transcript show: (sr at:4) ; cr. ].
].
SmileBASIC
Pretty comical version. MML tunes based on QB64 version.
DEF NUM(N)
IF N==-1 THEN
RETURN "99"
ELSEIF N==0 THEN
RETURN "No more"
ELSE
RETURN STR$(N)
ENDIF
END
DEF BTL(N)
IF N==1 THEN
RETURN " bottle"
ELSE
RETURN " bottles"
ENDIF
END
DEF ACT(N)
IF N==0 THEN
RETURN "Go to the store, buy some more,"
ELSEIF N==1 THEN
RETURN "Take it down, pass it around,"
ELSE
RETURN "Take one down, pass it around,"
ENDIF
END
DEF WAITPLAY TUNE
BGMPLAY TUNE
WHILE BGMCHK(0):WEND
END
BGMSET 128,"T180@6E-8E-8E-8>B-8B-8B-8<E-8E-8E-8E-4R8"
BGMSET 129,"T180@6F8F8F8C8C8C8F4R4."
BGMSET 130,"T180@6D4D8D8R4D8D8D8D4R8"
BGMSET 131,"T180@6>A+8A+8A+8<C8C8D8D+8D+8D+8D+4R8"
FOR I=99 TO 0 STEP -1
CLS
PRINT NUM(I);BTL(I);" of beer on the wall,"
WAITPLAY 128
PRINT NUM(I);BTL(I);" of beer."
WAITPLAY 129
PRINT ACT(I)
WAITPLAY 130
PRINT NUM(I-1);BTL(I-1);" of beer on the wall."
WAITPLAY 131
NEXT
SNOBOL4
x = 99
again output = X " bottles of beer on the wall"
output = X " bottles of beer" ?eq(X,0) :s(zero)
output = "Take one down, pass it around"
output = (X = gt(x,0) X - 1) " bottle of beer on the wall..." :s(again)
zero output = "Go to store, get some more"
output = "99 bottles of beer on the wall"
end
Function
Works with Macro Spitbol. Works with CSnobol. Function version with string composition. Function returns one verse for x bottles. Correctly handles bottle/bottles.
define('bottles(x)')
nl = char(13) char(10) ;* Win/DOS, change as needed
s2 = ' of beer'; s3 = ' on the wall'
s4 = 'Take one down, pass it around'
s5 = 'Go to the store, get some more' :(bottles_end)
bottles s1 = (s1 = ' Bottle') ne(x,1) 's'
output = nl x s1 s2 s3 nl x s1 s2
x = gt(x,0) x - 1 :f(done)
s1 = (s1 = ' Bottle') ne(x,1) 's'
output = s4 nl x s1 s2 s3 :(return)
done output = s5 nl 99 s1 s2 s3 :(return)
bottles_end
* # Test and display, only 2 bottles!
n = 2
loop bottles(n); n = gt(n,0) n - 1 :s(loop)
end
Output:
2 Bottles of beer on the wall
2 Bottles of beer
Take one down, pass it around
1 Bottle of beer on the wall
1 Bottle of beer on the wall
1 Bottle of beer
Take one down, pass it around
0 Bottles of beer on the wall
0 Bottles of beer on the wall
0 Bottles of beer
Go to the store, get some more
99 Bottles of beer on the wall
SNUSP
See 99 Bottles of Beer/EsoLang
Sparkling
var bottles = 99;
do {
printf("%u bottles of beer on the wall\n", bottles);
printf("%u bottles of beer\n", bottles);
printf("Take one down, pass it around\n");
printf("%u bottles of beer on the wall\n\n", --bottles);
} while(bottles > 1);
printf("1 bottle of beer on the wall\n1 bottle of beer\nTake it down, pass it around\n0 bottles of beer on the wall\n");
SQL
select ( 100 - level ) || ' bottle' || case when level != 99 then 's' end || ' of beer on the wall' || chr(10) || ( 100 - level ) || ' bottle' || case when level != 99 then 's' end || ' of beer' || chr(10) || 'Take one down, pass it around' || chr(10) || ( 99 - level ) || ' bottle' || case when level != 98 then 's' end || ' of beer on the wall' from dual connect by level <= 99;
DELIMITER $$ DROP PROCEDURE IF EXISTS bottles_$$ CREATE pROCEDURE `bottles_`(inout bottle_count int, inout song text) BEGIN declare bottles_text varchar(30); IF bottle_count > 0 THEN if bottle_count != 1 then set bottles_text := ' bottles of beer '; else set bottles_text = ' bottle of beer '; end if; SELECT concat(song, bottle_count, bottles_text, ' \n') INTO song; SELECT concat(song, bottle_count, bottles_text, 'on the wall\n') INTO song; SELECT concat(song, 'Take one down, pass it around\n') into song; SELECT concat(song, bottle_count -1 , bottles_text, 'on the wall\n\n') INTO song; set bottle_count := bottle_count -1; CALL bottles_( bottle_count, song); END IF; END$$ set @bottles=99; set max_sp_recursion_depth=@bottles; set @song=''; call bottles_( @bottles, @song); select @song;
This Statement does also work with T-SQL, but only up to 32 beers
CREATE PROCEDURE bottles @bottle_count int, @song varchar(MAX) AS BEGIN declare @bottles_text VARCHAR(MAX); IF @bottle_count > 0 BEGIN IF @bottle_count != 1 BEGIN SET @bottles_text = ' bottles of beer '; END ELSE BEGIN SET @bottles_text = ' bottle of beer '; END SET @song = @song + CAST(@bottle_count AS VARCHAR) + @bottles_text + '\n'; SET @song = @song + CAST(@bottle_count AS VARCHAR) + @bottles_text + 'on the wall\n' SET @song = @song + 'Take one down, pass it around\n' SET @song = @song + CAST((@bottle_count - 1) AS VARCHAR) + @bottles_text + 'on the wall\n' SET @bottle_count = (@bottle_count - 1); EXEC bottles @bottle_count, @song END ELSE select @song AS 'RESULT' END /***** AND IN ORDER TO CALL PROCEDURE: ****/ EXECUTE bottles 31, '';
/*These statements work in PostgreSQL (tested in 9.4)*/ SELECT generate_series || ' bottles of beer on the wall' || chr(10) || generate_series || ' bottles of beer' || chr(10) || 'Take one down, pass it around' || chr(10) || coalesce(lead(generate_series) OVER (ORDER BY generate_series DESC),0) || ' bottles of beer on the wall' AS song FROM generate_series(1,99) ORDER BY generate_series DESC; /*The next statement takes also into account the grammatical support for "1 bottle of beer".*/ SELECT generate_series || ' bottle' || CASE WHEN generate_series>1 THEN 's' ELSE '' END || ' of beer on the wall' || chr(10) || generate_series || ' bottle' || CASE WHEN generate_series>1 THEN 's' ELSE '' END || ' of beer' || chr(10) || 'Take one down, pass it around' || chr(10) || coalesce(lead(generate_series) OVER (ORDER BY generate_series DESC),0) || ' bottle' || CASE WHEN coalesce(lead(generate_series) OVER (ORDER BY generate_series DESC),0) <>1 THEN 's' ELSE '' END || ' of beer on the wall' AS song FROM generate_series(1,99) ORDER BY generate_series DESC; /*The next statement uses recursive query.*/ WITH RECURSIVE t(n) AS ( VALUES (1) UNION ALL SELECT n+1 FROM t WHERE n < 99 ) SELECT n || ' bottle' || CASE WHEN n>1 THEN 's' ELSE '' END || ' of beer on the wall' || chr(10) || n || ' bottle' || CASE WHEN n>1 THEN 's' ELSE '' END || ' of beer' || chr(10) || 'Take one down, pass it around' || chr(10) || coalesce(lead(n) OVER (ORDER BY n DESC),0) || ' bottle' || CASE WHEN coalesce(lead(n) OVER (ORDER BY n DESC),0) <>1 THEN 's' ELSE '' END || ' of beer on the wall' AS song FROM t ORDER BY n DESC;
Squirrel
function rec(bottles)
{
if (bottles > 0)
{
print(bottles+" bottles of beer on the wall\n")
print(bottles+" bottles of beer\n");
print("Take one down, pass it around\n");
print(--bottles+" bottles of beer on the wall\n\n")
return rec(bottles);
}
print("No more bottles of beer on the wall, no more bottles of beer\n");
print("Go to the store and get some more beer, 99 bottles of beer on the wall\n");
}
rec(99);
Standard ML
fun bottles 0 = ()
| bottles x = ( print (Int.toString x ^ " bottles of beer on the wall\n");
print (Int.toString x ^ " bottles of beer\n");
print "Take one down, pass it around\n";
print (Int.toString (x-1) ^ " bottles of beer on the wall\n");
bottles (x-1)
)
Stata
program drink
local s s
forvalues i=`1'(-1)0 {
if `i'>0 {
display "`i' bottle`s' of beer on the wall"
display "`i' bottle`s' of beer"
display "Take one down, pass it around"
if `i'==2 {
local s ""
}
if `i'>1 {
display "`=`i'-1' bottle`s' of beer on the wall..."
}
else {
display "No more bottles of beer on the wall"
}
display
}
else {
display "No more bottles of beer on the wall"
display "No more bottles of beer"
display "Go to the store and buy some more"
display "`1' bottles of beer on the wall..."
}
}
end
drink 2
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall...
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No more bottles of beer on the wall
No more bottles of beer on the wall
No more bottles of beer
Go to the store and buy some more
2 bottles of beer on the wall...
Suneido
i = 99
while (i > 0)
{
Print(i $ ' bottles of beer on the wall')
Print(i $ ' bottles of beer')
Print('Take one down, pass it around')
--i
if i is 0
Print('Ahh poo, we are out of beer\n')
else
Print(i $ ' bottles of beer on the wall\n')
}
Swift
for i in (1...99).reversed() { print("\(i) bottles of beer on the wall, \(i) bottles of beer.") let next = i == 1 ? "no" : (i-1).description print("Take one down and pass it around, \(next) bottles of beer on the wall.") }
SuperCollider
// post to the REPL directly
(
(99..0).do { |n|
"% bottles of beer on the wall\n% bottles of beer\nTake one down, pass it around\n% bottles of beer on the wall\n".postf(n, n, n)
};
)
// post over time
(
fork {
100.reverseDo { |n|
n.post; " bottles of beer on the wall".postln; 0.5.wait;
n.post; " bottles of beer".postln; 0.5.wait;
"Take one down, pass it around".postln; 0.5.wait;
n.post; " bottles of beer on the wall".postln; 0.5.wait;
1.wait;
};
}
)
Symsyn
BBW : ' Bottles of beer on the wall '
TOD : 'Take one down and pass it around '
if 99 GT 0 | numbers are variables initialized to value
~ 99 $S | convert to string
+ BBW $S | add phrase to end of string
+ $S $S | add string to itself
#$S N | size to N
- 12 N | decrement size by 12
N #$S | change size of string
$S [] | output string
- 99 | decrement counter
TOD $S | phrase to string
~ 99 $R | convert to string
+ $R $S | add to end of string $S
+ BBW $S | add phrase to end of $S
$S [] | output string
goif | go back to if
endif
Tailspin
templates sayBottleCount
<1>
'1 bottle' !
<0>
'No bottles' !
<>
'$; bottles' !
end sayBottleCount
99..1:-1 ->
'$->sayBottleCount; of beer on the wall,
$->sayBottleCount; of beer.
Take one down, pass it around,
$:$ - 1 -> sayBottleCount; of beer on the wall.
' -> !OUT::write
Output:
99 bottles of beer on the wall,
99 bottles of beer.
Take one down, pass it around,
98 bottles of beer on the wall.
...
2 bottles of beer on the wall,
2 bottles of beer.
Take one down, pass it around,
1 bottle of beer on the wall.
1 bottle of beer on the wall,
1 bottle of beer.
Take one down, pass it around,
No bottles of beer on the wall.
Tcl
See [[99 Bottles of Beer/Tcl]]
Thyrd
See [[99 Bottles of Beer/VPL]]
TIScript
var beer = 99; while (beer > 0) { stdout.printf( "%d bottles of beer on the wall\n", beer); stdout.printf( "%d bottles of beer\n", beer); stdout.println( "Take one down, pass it around" ); stdout.printf( "%d bottles of beer on the wall\n", --beer ); }
TorqueScript
for(%i = 99; %i >= 0; %i--)
{
%n = %i - 1;
echo(%i SPC (%n == 1 ? "bottle" : "bottles") SPC "of beer on the wall ~");
echo("Take one down, pass it around,");
echo(%n SPC (%i == 1 ? "bottle" : "bottles") SPC "of beer on the wall.");
}
TUSCRIPT
$$ MODE TUSCRIPT
LOOP bottle=1,100
SET bottlenr=100-bottle
IF (bottlenr==0) THEN
PRINT "no bottle of beer on the wall"
EXIT
ELSEIF (bottlenr==1) THEN
PRINT bottlenr, " bottle of beer on the wall"
PRINT bottlenr, " bottle of beer"
ELSE
PRINT bottlenr, " bottles of beer on the wall"
PRINT bottlenr, " bottles of beer"
ENDIF
PRINT "Take one down, pass it around"
ENDLOOP
TypeScript
function beerSong(){ function nbottles(howMany:number){ return `${howMany?howMany:'no'} bottle${howMany!=1?'s':''}`; } let song=[]; let beer = 99; while (beer > 0) { song.push(` ${nbottles(beer)} of beer on the wall, ${nbottles(beer)} of beer! Take one down, pass it around ${nbottles(--beer)} of beer on the wall `); } return song.join(''); } console.log(beerSong());
TXR
The (range 99 -1 -1) expression produces a lazy list of integers
from 99 down to -1.
The mapcar* function lazily maps these numbers to strings,
and the rest of the code treats this lazy list as text stream to process,
extracting the numbers with some pattern matching cases
and interpolating them into the song's text.
Functional programming with lazy semantics meets text processing,
pattern matching and here documents.
@(next :list @(mapcar* (fun tostring) (range 99 -1 -1)))
@(collect)
@number
@ (trailer)
@number_less_1
@ (cases)
@ (bind number "1")
@ (output)
1 bottle of beer one the wall
1 bottle of beer
@ (end)
@ (or)
@ (output)
@number bottles of beer one the wall
@number bottles of beer
@ (end)
@ (end)
@ (cases)
@ (bind number "0")
@ (output)
Go to the store and get some more,
99 bottles of beer on the wall!
@ (end)
@ (or)
@ (output)
Take one down and pass it around
@number_less_1 bottles of beer on the wall
@ (end)
@ (end)
@(end)
To make the song repeat indefinitely, change the first line to:
@(next :list @(mapcar* (fun tostring) (repeat (range 99 0 -1))))
Now it's processing an infinite lazy lists consisting of repetitions of the integer sequences 99 98 ... 0.
uBasic/4tH
A very vanilla BASIC implementation.
0005 LET I=99
0006 PRINT "Lyrics of the song 99 Bottles of Beer"
0010 REM main
0011 IF I>2 THEN GOTO 20
0012 IF I=2 THEN GOTO 30
0013 IF I=1 THEN GOTO 40
0014 GOTO 50
0020 REM if greater than two
0021 PRINT I;" Bottles of beer on the wall, ";I;" bottles of beer."
0022 LET I=I-1
0023 PRINT "Take one down and pass it around, ";
0024 PRINT I;" bottles of beer on the wall."
0025 GOTO 10
0030 REM if equals two
0031 PRINT I;" Bottles of beer on the wall, ";I;" bottles of beer."
0032 LET I=I-1
0033 PRINT "Take one down and pass it around, ";
0034 PRINT I;" bottle of beer on the wall."
0035 GOTO 10
0040 REM if equals one
0041 PRINT I;" Bottle of beer on the wall, ";I;" bottle of beer."
0042 LET I=I-1
0043 PRINT "Take one down and pass it around,";
0044 PRINT " no more bottles of beer on the wall."
0045 GOTO 10
0050 REM if equals zero then exit
0051 PRINT "No more bottles of beer on the wall. No more bottles of beer..."
0052 PRINT "Go to the store and buy some more...99 bottles of beer."
UNIX Shell
UnixPipes
Ursa
#
# 99 bottles of beer
#
decl int bottles
decl string bottlestr
for (set bottles 99) (> bottles 0) (dec bottles)
if (= bottles 1)
set bottlestr "bottle"
else
set bottlestr "bottles"
end if
out bottles " " bottlestr " of beer on the wall" endl console
out bottles " " bottlestr " of beer" endl console
out "Take one down, pass it around." endl console
if (not (= bottles 2))
out (int (- bottles 1)) " bottles of beer on the wall." endl endl console
else
out (int (- bottles 1)) " bottle of beer on the wall." endl endl console
end if
end for
Ursala
#import nat
# each function takes a natural number to a block of text
quantity = # forms the plural as needed
~&iNC+ --' of beer'+ ~&?(
1?=/'1 bottle'! --' bottles'+ ~&h+ %nP,
'no more bottles'!)
verse =
^(successor,~&); ("s","n"). -[
-[quantity "s"]- on the wall, -[quantity "s"]-,
Take one down and pass it around, -[quantity "n"]- on the wall.]-
refrain "n" =
-[
No more bottles of beer on the wall, -[quantity 0]-.
Go to the store and buy some more, -[quantity "n"]- on the wall.]-
whole_song "n" = ~&ittt2BSSL (verse*x iota "n")--<refrain "n">
#show+
main = whole_song 99
UTFool
···
http://rosettacode.org/wiki/99_Bottles_of_Beer
···
■ BottlesOfBeer
§ static
▶ main
• args⦂ String[]
∀ bottles ∈ 99 ⋯> 0
System.out.println ‷
⸨x bottles⸩ on the wall
⸨x bottles⸩
Take one down, pass it around
⸨x bottles - 1⸩ on the wall
‴
▶ x⦂ String
• many⦂ int
s⦂ String: many > 1 ? "s" ! ""
return "⸨many⸩ bottle⸨s⸩ of beer"
V
[bottles
[newline '' puts].
[beer
[0 =] ['No more bottles of beer' put] if
[1 =] ['One bottle of beer' put] if
[1 >] [dup put ' bottles of beer' put] if].
[0 =] [newline]
[beer ' on the wall, ' put beer newline
'Take one down and pass it around, ' put pred beer ' on the wall' puts newline]
tailrec].
99 bottles
Vala
void main() {
uint bottles = 99;
do {
print("%u bottles of beer on the wall.\n", bottles);
print("%u bottles of beer!\n", bottles);
print("Take one down, pass it around!\n");
--bottles;
if (bottles == 0) {
print("No bottles");
}
else if (bottles == 1) {
print("1 bottle");
}
else {
print("%u bottles", bottles);
}
print(" of beer on the wall!\n\n");
} while (bottles != 0);
}
VBA
VBScript
Verbexx
fb @FN [x] { @IF (x == 1) then:{ 'bottle } else:{ 'bottles } };
@LOOP init:{@VAR n = 99} until:(n == 0)
{
@SAY n (@fb n) "of beer on the wall" ;
@SAY n (@fb n) "of beer." ;
n-- ;
@SAY "Take one down, pass it around" ;
@SAY n (@fb n) "of beer on the wall\n" ;
};
Visual Prolog
Viua VM assembly
.function: bottles_of_beer_text/1 .name: %iota number_of_bottles arg %number_of_bottles %0 .name: %iota bottles_of_beer ; support for "1 bottle of beer" and "N bottles of beer" if (eq %iota %number_of_bottles (istore %iota 1)) +1 +3 text %bottles_of_beer " bottle of beer" jump +2 text %bottles_of_beer " bottles of beer" move %0 %bottles_of_beer return .end .function: first_print/1 ; this function prints the ; ; N bottles of beer on the wall ; N bottles of beer ; Take one down, pass it around ; .name: %iota number_of_bottles arg %number_of_bottles %0 .name: %iota bottles_of_beer frame ^[(param %0 %number_of_bottles)] call %bottles_of_beer bottles_of_beer_text/1 echo %number_of_bottles echo %bottles_of_beer print (text %iota " on the wall") echo %number_of_bottles print %bottles_of_beer print (text %iota "Take one down, pass it around") return .end .function: second_print/1 ; this function prints the ; ; No more bottles of beer on the wall / ; N bottles of beer on the wall ; ; i.e. the last line of a paragraph .name: %iota number_of_bottles arg %number_of_bottles %0 .name: %iota bottles_of_beer frame ^[(param %0 %number_of_bottles)] call %bottles_of_beer bottles_of_beer_text/1 .name: %iota on_the_wall text %on_the_wall " on the wall" ; say "No more" instead of "0 bottles" if %number_of_bottles +1 +3 echo %number_of_bottles jump +3 echo (text %iota "No more") echo %bottles_of_beer print %on_the_wall if %number_of_bottles +1 +3 print (text %iota "") return .end .function: bottles_of_beer/1 .name: %iota total_number_of_bottles arg %total_number_of_bottles %0 ; display first three lines of a paragraph frame ^[(param %0 %total_number_of_bottles)] call void first_print/1 ; decrement the number of bottles idec %total_number_of_bottles ; display last line of a paragraph frame ^[(param %0 %total_number_of_bottles)] call void second_print/1 ; immediately return if there are no more bottles if %total_number_of_bottles theres_more +1 return .mark: theres_more ; if there are more bottles ; call the function once more frame ^[(pamv %0 %total_number_of_bottles)] tailcall bottles_of_beer/1 .end .function: main/0 .name: %iota total_number_of_bottles istore %total_number_of_bottles 9 frame ^[(pamv %0 %total_number_of_bottles)] call void bottles_of_beer/1 izero %0 local return .end
Vox
// translated from <http://rosettacode.org/wiki/99_Bottles_of_Beer#JavaScript>
local beer;
while((beer = typeof beer == "null" ? 99 : beer) > 0)
println(
beer + " bottle" +
(beer != 1 ? "s" : "") +
" of beer on the wall\n" + beer + " bottle" +
(beer != 1 ? "s" : "") +
" of beer\nTake one down, pass it around\n" +
(--beer) + " bottle" +
(beer != 1 ? "s" : "") + " of beer on the wall\n"
);
Wart
Whenever
See 99 Bottles of Beer/EsoLang
Wortel
!console.log @unlines ~!* 99..0 !? {
0 "0 bottles of beer on the wall\n0 bottles of beer\nbetter go to the store and buy some more."
"{@x} bottle{@?@x{1 @e 's}} of beer on the wall\n{@x} bottle{@?@x{1 @e 's}} of beer\nTake one down, pass it around"
}
Wrapl
MOD Bottles;
IMP IO.Terminal USE Out;
IMP Std.String;
VAR i, s <- "s", ob <- "of beer", otw <- "on the wall",
more <- "Take one down and pass it around", verse <- [];
EVERY i <- 99:to(0,-1) DO (
(i = 1) & (s <- "");
(i = 0) & (s <- "s"; i <- "No more"; more <- "Go to the store and buy some more");
verse:put('. {i} bottle{s} {ob} {otw}.\n');
verse:put('\n{i} bottle{s} {ob} {otw}, {([email protected]):lower} bottle{s} {ob}.\n{more}');
);
Out:write(verse[2,0]@(String.T, "") + verse[1]);
END Bottles.
Wren
for (i in 99...0) {
System.print("%(i) bottles of beer on the wall,")
System.print("%(i) bottles of beer,")
System.print("Take one down, pass it around,")
System.print("%(i - 1) bottles of beer on the wall.\n")
}
X86 Assembly
See 99 Bottles of Beer/Assembly
xEec
Xojo
Place the following in the '''Run''' event handler of a Console application:
Dim bottles As Integer = 99
While bottles > 0
Print(bottles.ToText + " bottles of beer on the wall,")
Print(bottles.ToText + " bottles of beer.")
Print("Take one down, pass it around.")
bottles = bottles - 1
Print(bottles.ToText + " bottles of beer on the wall.")
Print ""
Wend
XPL0
code IntOut=11, Text=12;
int B;
[B:= 99;
repeat IntOut(0, B); Text(0, " bottles of beer on the wall^M^J");
IntOut(0, B); Text(0, " bottles of beer^M^J");
Text(0, "Take one down, pass it around^M^J");
B:= B-1;
IntOut(0, B); Text(0, " bottles of beer on the wall^M^J^J");
until B=0;
]
XPath
A solution written in pure XPath 3.0 (using XSLT as a host language).
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="3.0"> <xsl:output method="text"/> <xsl:template match="/"> <xsl:value-of select=" for $x in reverse(1 to 99) return let $suf := if ($x = 1) then '' else 's' return concat($x, ' bottle', $suf, ' of beer on the wall ', $x, ' bottle', $suf, ' of beer Take one down, pass it around ', $x - 1, ' bottle', if ($x = 2) then '' else 's', ' of beer on the wall')" separator=" " /> </xsl:template> </xsl:stylesheet>
XSLT
XSLT 1.0
To run, transform any document with this stylesheet (the input document is ignored).
<?xml version="1.0" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="text" encoding="utf-8"/> <!-- Main procedure --> <xsl:template match="/"> <!-- Default parameters are used --> <xsl:call-template name="sing-all-verses-in-range"/> </xsl:template> <!-- Calls sing-verse-starting-with-number over each value in a range. --> <xsl:template name="sing-all-verses-in-range"> <!-- Default parameters: From 99 through 1 --> <xsl:param name="first" select="99"/> <xsl:param name="final" select="1"/> <!-- Simulate a loop with tail recursion. --> <xsl:if test="$first >= $final"> <!-- Process $first --> <xsl:call-template name="sing-verse-starting-with-number"> <xsl:with-param name="n" select="$first"/> </xsl:call-template> <!-- Process $first - 1 through $final --> <xsl:call-template name="sing-all-verses-in-range"> <xsl:with-param name="first" select="$first - 1"/> <xsl:with-param name="final" select="$final"/> </xsl:call-template> </xsl:if> </xsl:template> <!-- Outputs a single verse. Each verse starts with $n bottles and ends with $n - 1 bottles. --> <xsl:template name="sing-verse-starting-with-number"> <xsl:param name="n"/> <!-- "$n bottles of beer on the wall" --> <xsl:call-template name="sing-line-containing-number"> <xsl:with-param name="n" select="$n"/> </xsl:call-template> <!-- "$n bottles of beer" --> <xsl:call-template name="sing-line-containing-number"> <xsl:with-param name="n" select="$n"/> <!-- For the second line, specify blank suffix --> <xsl:with-param name="suffix"/> </xsl:call-template> <xsl:text>Take one down, pass it around </xsl:text> <!-- "($n - 1) bottles of beer on the wall" --> <xsl:call-template name="sing-line-containing-number"> <!-- End verse with one less bottle --> <xsl:with-param name="n" select="$n - 1"/> </xsl:call-template> <xsl:text> </xsl:text> </xsl:template> <!-- Outputs "[number] bottle[s] of beer[ on the wall]" --> <xsl:template name="sing-line-containing-number"> <xsl:param name="n"/> <!-- If no suffix is specified, use " on the wall" --> <xsl:param name="suffix"> on the wall</xsl:param> <xsl:value-of select="$n"/> <xsl:text> bottle</xsl:text> <!-- Add "s" iff appropriate --> <xsl:if test="$n != 1">s</xsl:if> <xsl:text> of beer</xsl:text> <xsl:value-of select="$suffix"/> <xsl:text> </xsl:text> </xsl:template> </xsl:stylesheet>
XSLT 3.0
To run, transform any document with this stylesheet.
There are fewer XSLT 3 parsers out there than for XSLT 1, but it is '''so''' much less painful to program with XSLT 3 (or 2). This code uses several features not available in XSLT 1 to produce output identical to that for the XSLT 1 code provided.
- xsl:iterate, more versatile than xsl:for-each [first available in XSLT 3.0]
- reverse() function [first available in XPath 2.0 / XSLT 2]
- "if ... then ... else" construction [ditto]
- use of text value templates (using "{ XPath code }") [first available XSLT 3, see https://www.w3.org/TR/xslt-30/#text-value-templates]
<?xml version="1.0" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="3.0"> <xsl:output method="text"/> <xsl:variable name="startingNumberOfBottles" select="99"/> <!-- Main procedure. --> <xsl:template match="/" expand-text="true"> <xsl:iterate select="reverse(1 to $startingNumberOfBottles)"> <xsl:variable name="currentBottles" select="." as="xs:integer"/> <xsl:variable name="newBottles" select=". - 1" as="xs:integer"/> <xsl:text>{$currentBottles} bottle{if ($currentBottles ne 1) then 's' else ()} of beer on the wall </xsl:text> <xsl:text>{$currentBottles} bottle{if ($currentBottles ne 1) then 's' else ()} of beer </xsl:text> <xsl:text>Take one down, pass it around </xsl:text> <xsl:text>{$newBottles} bottle{if ($newBottles ne 1) then 's' else ()} of beer on the wall </xsl:text> </xsl:iterate> </xsl:template> </xsl:stylesheet>
Yabasic
sub bottle$(i)
if i=0 return "no more bottles of beer"
if i=1 return "1 bottle of beer"
return str$(i) + " bottles of beer"
end sub
for i = 99 to 1 step -1
print bottle$(i), " on the wall, \n", bottle$(i), "\n", "take one down, pass it around,\n", bottle$(i - 1), " on the wall.\n"
next
Yorick
Looped version
bottles = 99;
while(bottles) {
write, format=" %d bottles of beer on the wall\n", bottles;
write, format=" %d bottles of beer\n", bottles;
write, "Take one down, pass it around";
write, format=" %d bottles of beer on the wall\n\n", --bottles;
}
Vectorized version
song = "%d bottles of beer on the wall\n";
song += "%d bottles of beer\n";
song += "Take one down, pass it around\n";
song += "%d bottles of beer on the wall\n";
beer = indgen(99:1:-1);
write, format=song, beer, beer, beer-1;
Z80 Assembly
See 99 Bottles of Beer/Assembly
zkl
[99..0,-1].pump(fcn(n){
println(beers(n), " on the wall, ", beers(n).toLower(), ".\n",
n==0 and ("Go to the store and buy some more, 99 bottles of beer") or
("Take one down and pass it around, " + beers(n-1).toLower()),
" on the wall.\n")
});
fcn beers(n){
(n==0 and "No more bottles" or (n==1 and "1 bottle" or "" + n + " bottles"))
+ " of beer"
}
Output:
99 bottles of beer on the wall, 99 bottles of beer.
Take one down and pass it around, 98 bottles of beer on the wall.
...
1 bottle of beer on the wall, 1 bottle of beer.
Take one down and pass it around, no more bottles of beer on the wall.
No more bottles of beer on the wall, no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall.